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    INTRODUCTORY MATHEMATICAL ANALYSISINTRODUCTORY MATHEMATICAL ANALYSISFor Business, Economics, and the Life and Social Sciences

    Chapter 2Chapter 2Functions and GraphsFunctions and Graphs

    2011 Pearson Education, Inc.

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    To understand what functions and domains are.

    To introduce different types of functions.

    To introduce addition, subtraction,multiplication, division, and multiplication by a

    Chapter 2: Functions and Graphs

    Chapter ObjectivesChapter Objectives

    2011 Pearson Education, Inc.

    . To introduce inverse functions and properties.

    To graph equations and functions.

    To study symmetry about the x- and y-axis.

    To be familiar with shapes of the graphs of six

    basic functions.

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    Functions

    Special Functions

    Combinations of Functions

    Inverse Functions

    Chapter 2: Functions and Graphs

    Chapter OutlineChapter Outline

    2.1)

    2.2)

    2.3)

    2.4

    2011 Pearson Education, Inc.

    Graphs in Rectangular Coordinates

    Symmetry

    Translations and Reflections

    2.8) Functions of Several Variables

    2.5)

    2.6)

    2.7)

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    A function assigns each input number to oneoutput number.

    The set of all input numbers is the domain ofthe function.

    Chapter 2: Functions and Graphs

    2.1 Functions2.1 Functions

    2011 Pearson Education, Inc.

    .Equality of Functions

    Two functions f and g are equal (f = g):

    1.Domain of f = domain of g;

    2.f(x) = g(x).

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    Chapter 2: Functions and Graphs2.1 Functions

    Example 1 Determining Equality of Functions

    Determine which of the following functions are equal.

    +=

    +

    =

    2)(b.

    )1(

    )1)(2(

    )(a.

    xxg

    x

    xx

    xf

    2011 Pearson Education, Inc.

    =

    +=

    =

    +=

    1if31if2)(d.

    1if01if2)(c.

    xxxxk

    xxxxh

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    Chapter 2: Functions and Graphs2.1 Functions

    Example 1 Determining Equality of Functions

    Solution:When x = 1,

    ( ) ( )

    ( ) ( )( ) ( )11

    ,11

    ,11

    kf

    hf

    gf

    2011 Pearson Education, Inc.

    By definition, g(x) = h(x) = k(x) for all x 1.Since g(1) = 3, h(1) = 0 and k(1) = 3, we conclude

    that

    kh

    hg

    kg

    =

    ,

    ,

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    Chapter 2: Functions and Graphs2.1 Functions

    Example 3 Finding Domain and Function Values

    Let . Any real number can be usedfor x, so the domain of g is all real numbers.

    a. Find g(z).Solution:

    2( ) 3 5g x x x= +

    2( ) 3 5g z z z= +

    2011 Pearson Education, Inc.

    b. Find g(r2).Solution:

    c. Find g(x + h).Solution:

    2 2 2 2 4 2( ) 3( ) 5 3 5

    g r r r r r = + = +

    2

    2 2

    ( ) 3( ) ( ) 5

    3 6 3 5

    g x h x h x h

    x hx h x h

    + = + + +

    = + + +

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    Chapter 2: Functions and Graphs2.1 Functions

    Example 5 Demand Function

    Suppose that the equation p = 100/q describes therelationship between the price per unit p of a certain

    product and the number of units q of the product thatconsumers will buy (that is, demand) per week at thestated price. Write the demand function.

    2011 Pearson Education, Inc.

    Solution: pq

    q =100

    a

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    Chapter 2: Functions and Graphs

    2.2 Special Functions2.2 Special Functions

    Example 1 Constant Function

    We begin with constant function.

    Let h(x) = 2. The domain of h is all real numbers.

    2011 Pearson Education, Inc.

    A function of the form h(x) = c, where c = constant, isa constant function.

    x= = =

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    Chapter 2: Functions and Graphs

    2.2 Special Functions

    Example 3 Rational Functions

    a. is a rational function, since the

    numerator and denominator are both polynomials.

    b. is a rational function, since .

    2 6( )

    5

    x xf x

    x

    =

    +

    ( ) 2 3g x x= + 2 32 31

    xx ++ =

    2011 Pearson Education, Inc.

    Absolute-value function is defined as , e.g.x

    if 0

    if 0

    x xx

    x x

    =

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    Chapter 2: Functions and Graphs

    2.2 Special Functions

    Example 7 Genetics

    Two black pigs are bred and produce exactly fiveoffspring. It can be shown that the probability P that

    exactly r of the offspring will be brown and the othersblack is a function of r ,

    51 3

    5!

    r r

    2011 Pearson Education, Inc.

    On the right side, P represents the function rule. Onthe left side, P represents the dependent variable.

    The domain of P is all integers from 0 to 5, inclusive.Find the probability that exactly three guinea pigs willbe brown.

    ( )( ) 0,1,2,...,5! 5 !P r rr r= =

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    Chapter 2: Functions and Graphs

    2.2 Special Functions

    Example 7 Genetic

    Solution:

    3 21 3 1 9

    5! 120454 4 64 16

    3!2! 6(2) 512(3)P

    = ==

    2011 Pearson Education, Inc.

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    Chapter 2: Functions and Graphs

    2.3 Combinations of Functions2.3 Combinations of Functions

    We define the operations of function as:

    ( )( ) ( ) ( )

    ( )( ) ( ) ( )

    ( )( ) ( ). ( )

    ( )( ) for ( ) 0

    ( )

    f g x f x g x

    f g x f x g x

    fg x f x g x

    f f xx g x

    g g x

    + = +

    =

    =

    =

    2011 Pearson Education, Inc.

    Example 1 Combining FunctionsIf f(x) = 3x 1 and g(x) = x2 + 3x, find

    a. ( )( )

    b. ( )( )

    c. ( )( )

    d. ( )g

    1 e. ( )( )2

    f g x

    f g x

    fg x

    fx

    f x

    +

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    Chapter 2: Functions and Graphs

    2.3 Combinations of Functions

    Example 1 Combining Functions

    Solution:2 2

    2 2

    2 3 2

    2

    a. ( )( ) ( ) ( ) (3 1) ( +3 ) 6 1

    b. ( )( ) ( ) ( ) (3 1) ( +3 ) 1c. ( )( ) ( ) ( ) (3 1)( 3 ) 3 8 3

    ( ) 3 1d. ( )

    f g x f x g x x x x x x

    f g x f x g x x x x xfg x f x g x x x x x x x

    f f x xx

    + = + = + = +

    = = =

    = = + = +

    = =

    2011 Pearson Education, Inc.

    1 1 1 3 1e. ( )( ) ( ( )) (3 1)

    2 2 2

    xf x f x x

    = = =

    2

    Composition Composite of f with g is defined by ( )( ) ( ( ))f g x f g x=o

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    Chapter 2: Functions and Graphs

    2.3 Combinations of Functions

    Example 3 Composition

    2If ( ) 4 3, ( ) 2 1, and ( ) ,find

    a. ( ( ))

    b. ( ( ( )))c. ( (1))

    F p p p G p p H p p

    F G p

    F G H pG F

    = + = + =

    2011 Pearson Education, Inc.

    2 2

    2 2

    2

    a. ( ( )) (2 1) (2 1) 4(2 1) 3 4 12 2 ( )( )

    b. ( ( ( ))) ( ( ))( ) (( ) )( ) ( )( ( ))

    ( )( ) 4 12 2 4 12 2

    c. ( (1)) (1 4 1 3) (2) 2 2 1 5

    F G p F p p p p p F G p

    F G H p F G H p F G H p F G H p

    F G p p p p p

    G F G G

    = + = + + + = + + =

    = = = =

    = + + = + =

    = + = = + =

    o

    o o o o o

    o

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    One-to-one function

    A function f that satisfies

    For all a and b, if f(a)=f(b) then a=b

    is called a one-to-one function

    Or

    2011 Pearson Education, Inc.

    For all a and b, if ab then f(a)f(b)

    Example

    f(x)=x2, then f(-1)=f(1)=1 and -11 show thatthe squaring function is not one-to-one.

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    Chapter 2: Functions and Graphs

    2.4 Inverse Functions2.4 Inverse Functions

    Example 1 Inverses of Linear Functions

    An inverse function is defined as 1 1( ( )) ( ( ))f f x x f f x = =

    Show that a linear function is one-to-one. Find theinverse of f(x) = ax + b and show that it is also linear.

    2011 Pearson Education, Inc.

    Assume that f(u) = f(v), thus .

    We can prove the relationship,

    au b av b+ = +

    ( )( )( ) ( ( ))

    ax b b axg f x g f x x

    a a

    + = = = =o

    ( )( ) ( ( )) ( )x bf g x f g x a b x b b xa= = + = + =o

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    Chapter 2: Functions and Graphs

    2.4 Inverse Functions

    Example 3 Inverses Used to Solve Equations

    Many equations take the form f(x) = 0, where f is afunction. If f is a one-to-one function, then the

    equation has x = f 1(0) as its unique solution.

    Solution:

    2011 Pearson Education, Inc.

    Applying f 1 to both sides gives .

    Since , is a solution.

    ( )( ) ( )1 1 0f f x f

    =

    1(0)f

    1( (0)) 0f f =

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    Chapter 2: Functions and Graphs

    2.4 Inverse Functions

    Example 5 Finding the Inverse of a Function

    To find the inverse of a one-to-one function f , solvethe equation y = f(x) for x in terms of y obtaining x =

    g(y). Then f1

    (x)=g(x). To illustrate, find f1

    (x) iff(x)=(x 1)2, for x 1.

    2011 Pearson Education, Inc.

    Solution:Let y = (x 1)2, for x 1. Then x 1 = y and hence

    x = y + 1. It follows that f1(x) = x + 1.

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    Chapter 2: Functions and Graphs

    2.5 Graphs in Rectangular Coordinates2.5 Graphs in Rectangular Coordinates

    The rectangular coordinate system provides ageometric way to graph equations in two

    variables. An x-intercept is a point where the graph

    intersects the x-axis. Y-interce t is vice versa.

    2011 Pearson Education, Inc.

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    Chapter 2: Functions and Graphs

    2.5 Graphs in Rectangular Coordinates

    Example 1 Intercepts and Graph

    Find the x- and y-intercepts of the graph of y = 2x + 3,and sketch the graph.

    Solution:

    3

    2011 Pearson Education, Inc.

    ,

    When x = 0,

    22(0) 3 3y = + =

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    Chapter 2: Functions and Graphs

    2.5 Graphs in Rectangular Coordinates

    Example 3 Intercepts and Graph

    Determine the intercepts of the graph of x = 3, andsketch the graph.

    Solution:

    There is no -interce t because x cannot be 0.

    2011 Pearson Education, Inc.

    Ch 2 F i d G h

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    Chapter 2: Functions and Graphs

    2.5 Graphs in Rectangular Coordinates

    Example 7 Graph of a Case-Defined Function

    Graph the case-defined function

    if 0 < 3

    ( ) 1 if 3 54 if 5 < 7

    x x

    f x x xx

    =

    2011 Pearson Education, Inc.

    Ch t 2 F ti d G h

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    Use the preceding definition to show that the graphof = x2 is s mmetric about the -axis.

    Chapter 2: Functions and Graphs

    2.6 Symmetry2.6 Symmetry

    Example 1 y-Axis Symmetry

    A graph is symmetric about the y-axis when (-a,b) lies on the graph when (a, b) does.

    2011 Pearson Education, Inc.

    Solution:

    When (a, b) is any point on the graph, .

    When (-a, b) is any point on the graph, .

    The graph is symmetric about the y-axis.

    2b a=

    2 2( )a a b = =

    Chapter 2: Functions and Graphs

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    Chapter 2: Functions and Graphs

    2.6 Symmetry

    Graph is symmetric about the x-axis when (x, -y)lies on the graph when (x, y) does.

    Graph is symmetric about the origin when (x,y)

    lies on the graph when (x, y) does.

    Summary:

    2011 Pearson Education, Inc.

    Chapter 2: Functions and Graphs

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    Chapter 2: Functions and Graphs

    2.6 Symmetry

    Example 3 Graphing with Intercepts and Symmetry

    Test y = f (x) = 1 x4 for symmetry about the x-axis,the y-axis, and the origin. Then find the intercepts

    and sketch the graph.

    2011 Pearson Education, Inc.

    Chapter 2: Functions and Graphs

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    Chapter 2: Functions and Graphs

    2.6 Symmetry

    Example 3 Graphing with Intercepts and Symmetry

    Solution:

    Replace y with y, not equivalent to equation.

    Replace x with x, equivalent to equation.Replace x with x and y with y, not equivalent toequation.

    2011 Pearson Education, Inc.

    Thus, it is only symmetric about the y-axis.

    Intercept at 41 0

    1 or 1

    x

    x x

    =

    = =

    Chapter 2: Functions and Graphs

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    Chapter 2: Functions and Graphs

    2.6 Symmetry

    Example 5 Symmetry about the Line y = x

    A graph is symmetric about the y= xwhen (b, a)and (a, b).

    Show that x2 + y2 = 1 is symmetric about the liney = x.

    2011 Pearson Education, Inc.

    Solution:Interchanging the roles of x and y produces

    y2 + x2 = 1 (equivalent to x2 + y2 = 1).

    It is symmetric about y = x.

    Chapter 2: Functions and Graphs

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    Chapter 2: Functions and Graphs

    2.7 Translations and Reflections2.7 Translations and Reflections

    6 frequently used functions:

    2011 Pearson Education, Inc.

    Chapter 2: Functions and Graphs

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    p p

    2.7 Translations and Reflections

    Basic types of transformation:

    2011 Pearson Education, Inc.

    Chapter 2: Functions and Graphs

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    p p

    2.7 Translations and Reflections

    Example 1 Horizontal Translation

    Sketch the graph of y = (x 1)3.

    Solution:

    2011 Pearson Education, Inc.

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    2.8 Functions of Several Variables

    For any three sets X, Y and Z, the notation ofa function f: XYZ

    fis simply a rule which assign is assigns toeach element (x,y) in XY at most one

    2011 Pearson Education, Inc.

    , , .

    Example

    f(x,y)=x+y is a function of two variables.

    f(1,1)=1+1=2f(2,3)=2+3=5

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    Graphing a Plane

    In space, the graph of an equation of theform

    Ax+By+Cz+D=0

    where D is a constant and A, B, and C areconstants that are not all zero, is a plane.

    2011 Pearson Education, Inc.

    same line) determine a plane, a convenientway to sketch a plane is to first determinethe points, if any, where the plane intercept

    the x-, y-, and x-axes. These points arecalled intercepts.

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    Example 1Sketch the plane 2x+3y+z=6.

    The plane intersects the x-axis when y=0 and

    z=0. Thus 2x=6 which gives x=3.

    Similarly, if x=z=0, then y=2;

    2011 Pearson Education, Inc.

    if x=y=0, then z=0.

    Therefore, the intercepts are (3,0,0), (0,2,0)

    and (0,0,6). After these points are plotted, aplane is passed through them.