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Math 104 Yu Math 104 – Calculus 8.4 Trigonometric Subs=tu=ons

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Page 1: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Math  104  –  Calculus  8.4  Trigonometric  Subs=tu=ons  

Page 2: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Trigonometric  subs=tu=on    •  Some=mes  it  is  very  helpful  to  use  trigonometric  iden==es  to  simplify  involving  radical  expressions.  

•  It  can  be  used  to  evaluate  integrals  containing  the  following  expressions:  

•  Don’t  forget  to  change  the  limits  of  the  definite  integrals!        

1.

pa

2 � x

2

2.

pa

2+ x

2or

1

a

2+ x

2

3.

px

2 � a

2

Page 3: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Square  root  of  a2  -­‐  x2      

Nicolas Fraiman Math 104

Integrals with square root of a2-x2 Let

Then

pa

2 � x

2=

pa

2 � a

2sin

2✓

=

qa

2(1� sin

2✓)

=

pa

2cos

2✓

= a| cos ✓|

x = a sin ✓

Nicolas Fraiman Math 104

Integrals with square root of a2-x2 Let

Then

We haveSince Then Thus

pa

2 � x

2=

pa

2 � a

2sin

2✓

=

qa

2(1� sin

2✓)

=

pa

2cos

2✓

= a| cos ✓|

x = a sin ✓

✓ = arcsinx

a

�a x a

pa

2 � x

2= a cos ✓

�⇡2 ✓ ⇡

2 and cos ✓ > 0

We have ✓ = arcsin

x

a

Since �a x a,

Then �⇡

2

✓ ⇡

2

and cos ✓ � 0.

Thus

pa

2 � x

2= a cos ✓.

Page 4: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Example        

Nicolas Fraiman Math 104

Examples1. Evaluate

Z p2

1

dx

x

2p4� x

2

Page 5: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Example  2.  Find  the  area  of  the  unit  disk.  

Page 6: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Tips        

Nicolas Fraiman Math 104

Remark

To evaluate a definite integral we either undo the change of variable, or find the limits in the new variable θ.

To undo the change of variable we use the reference triangle to find formulas for functions of θ.

To find the new limits we use inverse trig. functions.

Page 7: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Square  root  of  a2  +  x2          

Nicolas Fraiman Math 104

Integrals with square root of a2+x2 Let

Then

pa

2 + x

2 =p

a

2 + a

2 tan2 ✓

=q

a

2(1 + tan2 ✓)

=pa

2 sec2 ✓

= a| sec ✓|

x = a tan ✓

Nicolas Fraiman Math 104

Integrals with square root of a2+x2 Let

Then

We haveThen Thus

pa

2 + x

2 =p

a

2 + a

2 tan2 ✓

=q

a

2(1 + tan2 ✓)

=pa

2 sec2 ✓

= a| sec ✓|

x = a tan ✓

✓ = arctanx

a

�⇡2 ✓ ⇡

2 and sec ✓ > 0

pa

2 + x

2 = a sec ✓

We have ✓ = arctanx

a

Since x can be any real number,

Then �⇡

2< ✓ <

2and sec ✓ � 1.

Thuspa

2 + x

2 = a sec ✓.

Page 8: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Example        

Nicolas Fraiman Math 104

Examples3. Find

!

!

!

4. Evaluate Z 1

0

dx

(x2 + 4)3/2

Z1

1 + x

2dx

Page 9: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Square  root  of  x2  -­‐  a2      

Nicolas Fraiman Math 104

Integrals with square root of x2-a2 Let

Then

We haveIf then soIf then so

px

2 � a

2 =pa

2 sec2 ✓ � a

2

=pa

2(sec2 ✓ � 1)

=pa

2 tan2 ✓

= a| tan ✓|

x = a sec ✓

x � a

✓ = arcsecx

a

x �a

⇡2 ✓ ⇡

0 ✓ ⇡2

px

2 � a

2 = a tan ✓

px

2 � a

2 = �a tan ✓Nicolas Fraiman Math 104

Integrals with square root of x2-a2 Let

Then

We haveIf then soIf then so

px

2 � a

2 =pa

2 sec2 ✓ � a

2

=pa

2(sec2 ✓ � 1)

=pa

2 tan2 ✓

= a| tan ✓|

x = a sec ✓

x � a

✓ = arcsecx

a

x �a

⇡2 ✓ ⇡

0 ✓ ⇡2

px

2 � a

2 = a tan ✓

px

2 � a

2 = �a tan ✓

We have ✓ = sec

�1 x

a

, note that |x| � a

1. If x � a then 0 ✓ <

⇡2 ,p

x

2 � a

2= a tan ✓.

2. If x �a then

⇡2 < ✓ ⇡,p

x

2 � a

2= �a tan ✓.

Page 10: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Example      5. Evaluate

Zdxp

9x2 � 4.

Page 11: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Summary      

2/19/2014

2

Math 104 – Rimmer8.3 Trig. Substitution

2 23. x a!

L ct se ex a "= sec arcsecx

x aa

" "

= ⇒ =

0 or 2 2

# #" " #$ < < $

or x a x a< ! >

Assume 0.a >

2 2 tan for x a a x a"! = >

Quadrant 1 Quadrant 2.

0 but t for 0 and for 2 2

so we c

tan 0 ta

an't drop the absolute value gn

n 0

si

a# #

" " #" "> $ <% $ < $

( )22 2 2secx a a a"! = !

2 2 2seca a"= !

( )2 2sec 1a "= !

2 2tana "=

tana "=

sec secx ax

a" "= ⇒ =

"

x

a

2 2x a!

2 2 tan for x a a x a"= !! < !

Math 104 – Rimmer8.3 Trig. Substitution

2 21. a x! L nt se ix a "=

( )22 2 2 sina x a a "! = !

2 2 2sina a "= !

( )2 21 sina "= !

2 2cosa "=

2 2 cosa x a "! =

sin sinx ax

a" "= ⇒ =

"

xa

2 2a x!

2 23. x a! L ct se ex a "=

( )22 2 2secx a a a"! = !

2 2 2seca a"= !

( )2 2sec 1a "= !

2 2tana "=

2 2 tanx a a "! =

sec secx ax

a" "= ⇒ =

"

x

a

2 2x a!

2 22. a x+ L nt te ax a "=

( )22 2 2 tana x a a "+ = +

2 2 2tana a "= +

( )2 21 tana "= +

2 2seca "=

2 2 seca x a "+ =

tan tanx ax

a" "= ⇒ =

"

x

a

2 2a x+

2 2

# #"

!$ $ 2 2

# #"

!$ $

02

#"$ <

2

#" #< $

2 2 tanx a a "!! =

for x a>

for x a< !

�⇡

2< ✓ <

2

x � a

x �a

Page 12: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Comple=ng  squares        

Nicolas Fraiman Math 104

Completing squares6. Evaluate

!

!

Hint: Write

Z 2

1

dxp4x� x

2

4x� x

2 = (�4 + 4x� x

2) + 4

= 4� (x� 2)2

Page 13: Math%104%–Calculus % 8.4%Trigonometric%Subs=tu=ons%shilinyu/teaching/Math104Sp15/slides/trigsub.pdfMath%104%)%Yu% Square%rootof%x 2 a 2% Nicolas Fraiman Math 104 Integrals with square

Math  104  -­‐  Yu  

Remember  u-­‐subsitu=on        

Nicolas Fraiman Math 104

Remember u-substitution!

!

• Evaluate

!

!

• Don’t use a trig. substitution if a u-substitution is easier.

Zxp

x

2 + 4dx