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TRANSCRIPT
Chapter 3
Mathematics of
Finance
Section 2
Compound and
Continuous Interest
2 Barnett/Ziegler/Byleen College Mathematics 12e
Learning Objectives for Section 3.2
The student will be able to compute compound and
continuous compound interest.
The student will be able to compute the growth rate of a
compound interest investment.
The student will be able to compute the annual
percentage yield of a compound interest investment.
Compound and
Continuous Compound Interest
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Table of Content
Compound Interest
Continuous Compound Interest
Growth and Time
Annual Percentage Yield
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Terms
compound interest
rate per compounding period
continuous compound interest
APY (Annual Percentages Yield)
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Compound Interest
Unlike simple interest, compound interest on an amount
accumulates at a faster rate than simple interest. The basic
idea is that after the first interest period, the amount of
interest is added to the principal amount and then the
interest is computed on this higher principal. The latest
computed interest is then added to the increased principal
and then interest is calculated again. This process is
completed over a certain number of compounding periods.
The result is a much faster growth of money than simple
interest would yield.
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Example
Suppose a principal of $1,000 was invested in an
account paying 8% annual interest compounded
quarterly. How much would be in the account after one
year?
Compounding quarterly means that the interest is paid
at the end of each 3-month period and the interest as
well as the principal earn interest for the next quarter.
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Solution
Solution: Using the simple interest formula A = P (1 + rt)
we obtain:
At the end of the first quarter will have:
A = P (1 + rt)
A = 1000[1 + 0.08(1/4)]
A = 1000(1.02) = $1.020
Now the principal is $1,020. At the end of the second
quarter will have :
A = 1020[1 + 0.08(1/4)]
A = 1020(1.02) = $1.040.40
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Solution (cont.)
At the end of the third quarter will have :
A = 1.040.40[1 + 0.08(1/4)]
A = 1.040.40(1.02) = $1.061.21
At the end of the fourth quarter will have :
A = 1.061.21[1 + 0.08(1/4)]
A = 1.061.21(1.02) = $1.082.43
• Compare with simple interest:
A = P(1 + rt) = $1,000[1 + 0.08(1)]
A = $1,000[10.08] = $1,080 $2,43 more
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Solution (cont.)
Looking over the calculations …
A = 1.000(1.02) End 1st quarter
A = [1.000(1.02)](1.02) = 1,000(1.02)2 End 2nd quarter
A = [1.000(1.02)2](1.02) = 1,000(1.02)3 End 3rd quarter
A = [1.000(1.02)3](1.02) = 1,000(1.02)4 End 4th quarter
• At the end of n quarters:
A = 1.000(1.02)n End nth quarter
or A = 1.000[1 + 0.08(1/4)]n
A = 1.000[1 + 0.08/4]n
Rate per compounding period = annual nominal rate / number of
compounding periods per year
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Solution (cont.)
In general
A = P(1 + i) End 1st period
A = [P(1 + i)](1 + i) = P(1 + i)2 End 2nd period
A = [P(1 + i)2](1 + i) = P(1 + i)3 End 3rd period
….
A = [P(1 + i)(n-1)](1 + i) = P(1 + i)n End nth period
Then it can be summarized …
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This formula can be generalized to
where A is the future amount, P is the principal, r is the interest
rate as a decimal, m is the number of compounding periods in
one year, and t is the total number of years. To simplify the
formula,
General Formula
1
mtr
A Pm
1n
A P i r
im
n mt
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Compound Interest General Formula
where i = r/m
A = amount (future amount) at the end of n periods
P = principal (present value)
r = annual nominal rate
m = number of compounding periods per year
i = rate per compounding period
t = time (years)
n = total number of compounding periods = mt
1n
A P i
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Graphical Illustration of
Compound Interest
Growth of 1.00 compounded monthly at 6% annual interest
over a 15 year period (Arrow indicates an increase in value of
almost 2.5 times the original amount.)
0
0.5
1
1.5
2
2.5
3
Growth of 1.00 compounded monthly at 6% annual interest
over a 15 year period
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Example
Find the amount to which $1500 will grow if compounded
quarterly at 6.75% interest for 10 years.
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Example
Find the amount to which $1500 will grow if compounded quarterly at 6.75% interest for 10 years.
Solution: Use
Helpful hint: Be sure to do the arithmetic using the rules for order of operations.
1n
A P i 10(4)
0.06751500 1
4
2929.50
A
A
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Same Problem Using
Simple Interest
Using the simple interest formula, the amount to which $1500
will grow at an interest of 6.75% for 10 years is given by
A = P (1 + rt)
= 1500(1+0.0675(10)) = 2512.50
which is more than $400 less than the amount earned using
the compound interest formula.
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Changing the number of
compounding periods per year
To what amount will $1500 grow if compounded daily at
6.75% interest for 10 years?
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Changing the number of
compounding periods per year
To what amount will $1500 grow if compounded daily at
6.75% interest for 10 years?
Solution: = 2945.87
This is about $15.00 more than compounding $1500 quarterly
at 6.75% interest.
Since there are 365 days in year (leap years excluded), the
number of compounding periods is now 365. We divide the
annual rate of interest by 365. Notice, too, that the number of
compounding periods in 10 years is 10(365)= 3650.
10(365)0.0675
1500 1365
A
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Changing the number of
compounding periods per year
Example 1
If $1,000 is invested at 8% compound:
A. Annually
B. Semiannual
C. Quarterly
D. Monthly
What is the amount after 5 years?
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Changing the number of
compounding periods per year
Example 1 - Solution
If $1,000 is invested at 8% compound, what is the amount after
5 years?
n = 5 ; I = r = 0.08
A = P(1 + i)n
= 1,000(1 + 0.08)5
= 1,000(1.469328)
= $1,469.33
A. Annually
n = (2)5 = 10
I = r/n = 0.08/2 = 0.04
A = P(1 + i)n
= 1,000(1 + 0.04)10
= 1,000(1.480244)
= $1,480.24
B. Semiannual
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Changing the number of
compounding periods per year
Example 1 - Solution
If $1,000 is invested at 8% compound, what is the amount after
5 years?
n = (12)5 = 60
I = r/n = 0.08/12 = 0.006666
A = P(1 + i)n
= 1,000(1 + 0.00666)60
= 1,000(1.489846)
= $1,489.85
D. Monthly
n = (4)5 = 20
I = r/n = 0.08/4 = 0.02
A = P(1 + i)n
= 1,000(1 + 0.02)20
= 1,000(1.485947)
= $1,485.95
C. Quarterly
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Effect of Increasing the
Number of Compounding Periods
If the number of compounding periods per year is
increased while the principal, annual rate of interest and
total number of years remain the same, the future amount
of money will increase slightly.
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Continuous Compound Interest
Previously we indicated that increasing the number of
compounding periods while keeping the interest rate,
principal, and time constant resulted in a somewhat higher
compounded amount. What would happen to the amount if
interest were compounded daily, or every minute, or every
second?
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Answer to Continuous Compound
Interest Question
As the number m of compounding periods per year increases
without bound, the compounded amount approaches a limiting
value. This value is given by the following formula:
limm P(1
r
m)mt Pert
A Pert
Here A is the compounded amount.
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Example of
Continuously Compounded Interest
What amount will an account have after 10 years if $1,500
is invested at an annual rate of 6.75% compounded
continuously?
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Example of
Continuously Compounded Interest
What amount will an account have after 10 years if $1,500
is invested at an annual rate of 6.75% compounded
continuously?
Solution: Use the continuous compound interest formula
A = Pert with P = 1500, r = 0.0675, and t = 10:
A = 1500e(0.0675)(10) = $2,946.05
That is only 18 cents more than the amount you receive by
daily compounding.
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Changing the number of
compounding periods per year
To what amount will $1500 grow if compounded daily at
6.75% interest for 10 years?
Solution: = 2945.87
That is only 18 cents more than the amount you receive by
daily compounding.
10(365)0.0675
1500 1365
A
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Continuously Compounded Interest
Example 2
What amount will an account have after 2 years if $5,000 is
invested at an annual rate of 8% compoundly
A. daily?
A = P(1 + r/m)mt
P = 5,000; r = 0.08; m = 365
t = 2
A = 5,000(1+ 0.08/365)(365)(2)
= $5,867.55
A. continuously?
A = Pert
P = 5,000; r = 0.08; t = 2
A = 5,000e(0.08)(2)
= $5,867.55
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Growth & Time
How much at a future date?
What annual rate has been earned?
How long take to double the investment?
The formulas for the compound interest and the
continuous interest can be used to answer such
questions.
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Growth & Time
How long will it take for $5,000
to grow to $15,000 if the money
is invested at 8.5%
compounded quarterly?
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Growth & Time
Solution
How long will it take for $5,000
to grow to $15,000 if the money
is invested at 8.5%
compounded quarterly?
1. Substitute values in the
compound interest formula.
2. divide both sides by 5,000
3. Take the natural logarithm of
both sides.
4. Use the exponent property of
logarithms
5. Solve for t.
Solution:
40.08515000 5000(1 )
4
t
3 = 1.021254t
ln(3) = ln1.021254t
ln(3) = 4t*ln1.02125
ln(3)13.0617
4ln(1.02125)t
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Growth & Time
Example 3
Finding Present Value
How much will you invest now at 10% to have $8,000 toward
the purchase of a car in 5 years if interest is
A. compounded quarterly?
P = ? A = 8,000 i = 0.10/4
n = 4(5) = 20
A = P(1 + i)n
8,000 = P(1 + 0.025)20
P = 8,000 / (1 + 0.025)20
P = 8,000 / (1.638616)
= $4,882.17
B. compounded continuously?
P = ? A = 8,000 r = 0.10
t = 5
A = Pert
8,000 = Pe(0.10)(5)
P = 8,000 /e(0.10)(5)
P = $4,852.25
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Growth & Time
Example 4
Computing Growth Rate
An investment of $10,000 in a growth-oriented fund over a 10-
years period would have grown in $126,000. What annual
nominal rate would produce the same growth if interest was:
C. compounded quarterly?
A = P(1 + i)n
126,000 = 10,000 (1+ r)10
12.6 = (1+ r)10
Raiz10(12.6) = 1+ r
r = Raiz10(12.6) – 1
r = 0.28836 ó 28.836%
D. compounded continuously?
A = Pert
126,000 = 10,000e10r
12.6 = e10r
ln 12.6 = 10r
r = ln 12.6/10
r = 0.25337 ó 25.337%
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Growth & Time
Example 5
Computing Growth Time
How long will it take $10,000 to grow to $12,000 if it is invested
at 9% compounded monthly?
Using logarithms & calculator:
A = P(1 + i)n
12,000 = 10,000 (1+ 0.09/12)n
1.2 = 1.0075n
Solve for n by taking logarithms
of both sides:
ln 1.2 = ln 1.0075n
ln 1.2 = nln 1.0075
n = ln 1.2 / ln 1.0075
n = 24.40 ó 25 months
or 2yr 1mth
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Annual Percentage Yield
The simple interest rate that will produce the same amount as a
given compound interest rate in 1 year is called the annual
percentage yield (APY). To find the APY, proceed as follows:
(1 ) 1
1 1
1 1
m
m
m
rP APY P
m
rAPY
m
rAPY
m
This is also called
the effective rate, as
well as APR.
Amount at simple interest APY after one year
= Amount at compound interest after one year
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Annual Percentage Yield
Example
What is the annual percentage yield for money that is
invested at 6% compounded monthly?
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Annual Percentage Yield
Example
What is the annual percentage yield for money that is
invested at 6% compounded monthly?
General formula:
Substitute values:
Effective rate is 0.06168 = 6.168
1 1
mr
APYm
120.06
1 1 0.0616812
APY
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Computing the Annual Nominal
Rate Given the APY
What is the annual nominal rate
compounded monthly for a CD
that has an annual percentage
yield of 5.9%?
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Computing the Annual Nominal
Rate Given the APY
What is the annual nominal rate compounded monthly for a CD that has an annual percentage yield of 5.9%?
1. Use the general formula for APY.
2. Substitute value of APY and 12 for m (number of compounding periods per year).
3. Add one to both sides
4. Take the twelfth root of both sides of equation.
5. Isolate r (subtract 1 and then multiply both sides of equation by 12.
1 1
mr
APYm
12
12
12
12
12
0.059 1 112
1.059 112
1.059 112
1.059 112
12 1.059 1
0.057
r
r
r
r
r
r
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Annual Percentage Yield
EXAMPLE 6 - Using APY to Compare Investments.
Find the APY for each of the bank in the table and compare
these CD’s.
Certificates of Deposits (CDs)
Bank Rate Compounded
Advanta 4.93% monthly
DeepGreen 4.95% daily
Charter One 4.97% quarterly
Liberty 4.94% continuously
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Annual Percentage Yield
EXAMPLE 6 - Using APY to Compare Investments (contd.)
Find the APY for each of the bank in the table and compare these
CD’s.
Bank Calculations [APY = (1 + r/m)m – 1] APY
Advanta
= (1 + 0.0493/12)^12 – 1 = 0.05043 5.043%
DeepGreen
= (1 + 0.0495/365)^365 – 1 = 0.05074 5.074%
Charter One
= (1 + 0.0497/4)^4 – 1 = 0.05063 5.063%
Liberty
= e^(0.0494) – 1 = 0.05064 5.064%
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Example of
Annual Percentage Yield
EXAMPLE 7 - Computing the Annual Nominal Rate given
the APY
A savings & loans wants to offer a CD with a monthly
compounding rate that has an APY of 7.5%. What annual
nominal rate compounded monthly should they use?.
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Example of
Annual Percentage Yield
EXAMPLE 7 - Computing the Annual Nominal Rate given the
APY (continued)
APY = (1 + r/m)m - 1
0.075 = (1+ r/12)12 - 1
1.075 = (1+ r/12)12
Raiz12(1.075) = 1+ r/12
Raiz12(1.075) – 1 = r/12
r = 12(Raiz12(1.075) – 1)
Using the calculator:
r = 0.072539
r = 7.254%
Chapter 3
Mathematics of
Finance
Section 2
Compound and
Continuous Interest
END Last Update: Marzo 19/2013