maths equations
TRANSCRIPT
-
7/24/2019 Maths Equations
1/3
The points that I choose to input into the cubic polynomial function were the
coordinates for 12, 15, 16 and 17 year olds. I chose 12 and 17 year olds because
these were the oldest and youngest of the experiment. raph 1 shows that there is
a possible in!exion between ages 15 and 16.
The points are listed as below"
#12, 2$%& 'aximum (alue
#15, 1)*& +ossible in!exion point
#16, 127& +ossible in!exion point
#17, 12*& 'inimum (alue
The formula for a cubic polynomial function is gi(en as"
y=a x3
+b x2
+cx+d
xwill be dened as the age of the sub-ect ranging from 12 to 17 years old
ywill be dened as the a(erage fundamental freuency for non/spontaneous speech
in 0ert #0&
sing the points that I chose for non/spontaneous speech, I substituted the x and y
(alues into the formula"
122
+c (12 )+d12
3
+b
248=a
152
+c (15 )+d15
3
+b
130=a
162
+c (16 )+d16
3+b
127=a
17
2
+c (17 )+d17
3
+b
120=a
sing the simultaneous euation sol(er in the 34"
-
7/24/2019 Maths Equations
2/3
a=113
60
b=522
5
c=98471
60
d=8739
This is the resulting function for non/spontaneous speech
y=113
60x
3+522
5x
298471
60x+8739
The points I chose for the non/spontaneous speech model were"
#12, 21*, 12&
#16, 121&
#17, 11$&
sing the coordinates from abo(e, I substituted the x and y (alues into the formula"
122
+c (12 )+d12
3
+b
210=a
152
+c (15 )+d15
3
+b
129=a
162
+c (16 )+d16
3
+b
121=a
172
+c (17 )+d173+b
114=a
sing the simultaneous euation sol(er in the 34"
a=17
20
-
7/24/2019 Maths Equations
3/3
b=413
10
c=13509
20
d=3837
This is the resulting function for spontaneous speech
y=17
20x
3
+413
10x
2
13509
20x+3837