maths ppt on quadratic equation

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Page 1: Maths Ppt on QUADRATIC EQUATION

ADVANCE BUSINESS MATH’S

PRESENTED TO SIR RIZWAN YAZDANI

PRESENTED BY:MEHWISH ALI AKBER

ALMAS AMIR ALIMARINA KHAN

ALINA SHAH

Page 2: Maths Ppt on QUADRATIC EQUATION

TOPIC

QUADRATIC EQUATION

Page 3: Maths Ppt on QUADRATIC EQUATION

QUADRATIC EQUATION

A Quadratic Equation in Standard Form(a, b, and c can have any value, except that a

can't be 0.)

The letters a, b and c are coefficients (you know those values) The letter "x" is the variable or

unknown (you don't know it yet)

Page 4: Maths Ppt on QUADRATIC EQUATION

EXAMPLE

•The name Quadratic comes from "quad" meaning square, because of x2 (in other words x squared).

•It can also be called an equation of degree 2

Page 5: Maths Ppt on QUADRATIC EQUATION

SOME MORE EXAMPLES

In this one a=2, b=5 and c=3

Page 6: Maths Ppt on QUADRATIC EQUATION

EXAMPLES CONTINUED

This one is a little more tricky: Where is a? In fact a=1, because we don't usually write "1x2" b=-3 And where is c? Well, c=0, so is not shown.

Page 7: Maths Ppt on QUADRATIC EQUATION

EXAMPLES CONTINUED

Oops! This one is not a quadratic equation, because it is missing x2 (in other words a=0, and that means it can't be quadratic)

Page 8: Maths Ppt on QUADRATIC EQUATION

QUADRATIC FORMULA

If b²–4ac>0 there will be two real roots. If b²–4ac=0 there will be one real roots. If b²–4ac<0 there will be no real roots.

Page 9: Maths Ppt on QUADRATIC EQUATION

QUADRATIC FORMULA CONT.. Discriminant: The part (b2 - 4ac) is called the discriminant,

because it can "discriminate" between the possible types of answer:

when b2 - 4ac is positive, you will get two solutions when it is zero you get just ONE solution, and when it is negative you get two Complex solutions

Page 10: Maths Ppt on QUADRATIC EQUATION

SOLVING EXAMPLE: 5x² + 6x + 1 = 0

Example: Solve 5x² + 6x + 1 = 0

Coefficients are:   a = 5, b = 6, c = 1      

Quadratic Formula:   x = [ -b ± √(b2-4ac) ] / 2a    

Substitute a,b,c:  x = [ -6 ± √(62-4×5×1) ] / (2×5)      

Solve:

  x = [ -6 ± √(36-20) ]/10    

x = [ -6 ± √(16) ]/10  

  x = ( -6 ± 4 )/10    

x = -0.2 and -1

Page 11: Maths Ppt on QUADRATIC EQUATION

THANK YOU