Matlab simulation: the program [3]

Matlab simulation: the program [3]

clear;

clc;

N=5000;

%Number of pathst=0.0001:10/N:10;

%Time rangefc=900*10.^6;

%Carrier frequencywc=2*pi*fc;

v=30/3600;

%Receiver speed[km/h]c=300*10^3;

%Light speedwm=wc*(v/c);

%Maximum shift

fm=wm/(2*pi);

%Doppler shiftfor i=1:N

A(i)=(2*pi/N)*i;

%Azimuthal angles wn(i)=wm*cos(A(i));

O(i)=(pi*i)/(N+1);

xc(i)=2*cos(wn(i)*t(i)).*cos(O(i))+cos(wm*t(i));

xs(i)=2*cos(wn(i)*t(i)).*sin(O(i));

T(i)=(1/(2*N+1)^0.5).*(xc(i)+j*xs(i));%Complex envelope end M=mean(abs(T));

%Mean MdB=20*log10(M);

TdB=floor(20*log10(abs(T)));

%Field [dB] z1=hist(abs(T));

z=hist(TdB,9);

n=0;

for k=1:9

n=n+z(k);

end for j=1:9

P(j)=z(j)/n;

end f(1)=P(1);

for x=2:9

f(x)=f(x-1)+P(x);

F(10-x)=f(x);

endplot(z1)

%Distribution charttitle('Rayleighs distribution');

pause

semilogy(t,abs(T)/max(abs(T)),'r') %Fading graphictitle('Received field');

ylabel('Received field intensity');

xlabel('time');

grid on

pause

loglog(100*F,'m');%Indicates the probability of exceed a given attenuationtitle('Probability of exceed a given attenuation (%)');Bosch, F 220976 Rev.:0002 Lang=Eng -2001