mcq on practical application of trigonometry prepared by: ramil t. francisco ismael mathay sr. high...

MCQ on Practical Application of Trigonometry

Prepared by:RAMIL T. FRANCISCO

Ismael Mathay Sr. High School

Question 1: The angle of elevation of the top a tower 40 meters high is 37 degrees when seen from a point on level ground. Find the distance of the point from the foot of the tower

A. 53.08 meters

B. 45.08 meters

C. 63. 08 meters

D. 35.08 meters

Question 2: From the window of a building 45 meters above the ground level, the angle of depression of a car on level ground is 42 degrees, How far is the car from the building?

A. 53.08 meters

B. 49.98 meters

C. 63. 98 meters

D. 94.08 meters

Question 3: A lighthouse is 72 meters high. Find the angle of elevation of its top from a ship 125 meters away on ground level

A. 53.08 degrees

B. 49.98 degrees

C. 29.90 degrees

D. 94.08 degrees

Question 4: A tower stands at the top of a cliff. At a distance of 60 m from the foot of the cliff which is at ground level, the angle of elevation of the top of the tower as well as the cliff are 65 and 53 degrees respectively, Find the height of the tower.

A. 53.08 meters

B. 49.98 meters

C. 29.90 meters

D. 49.05 meters

Question 5: From the top of a cliff 52 m high, the angles of depression of two ships due east of it are 36 and 24 degrees respectively. Find the distance between the ships.

A. 54.68 meters

B. 49.22 meters

C. 45.22 meters

D. 71.57 meters

Congratulations, good job!

You are

CORRECT!

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Try again !

SORRY!

C

BA37 degrees

40 m

x m

The diagram shows the tower from a point A

Let AB = x m

Tan 37 = BC / AB

= 40 / x

x = 40 / tan 37

= 53.08 to 4 significant digit

Solution for Question 1

C

45 m

B A

D

X m

42 degreesIn the diagram, A represents the car, BC represents the height of the building where C is the point of observation and angle ACD is the angle of depression

Let AB = x m

/_ACB = 90-42 = 48 degrees

Tan 48 = x /45 x = 45 tan 48 = 49.98 meters



You are

CORRECT!


72 m

125 m

C

B A

The diagram shows the lighthouse BC of height 72 m at a distance of 125 m away on level ground

Let the angle of elevation be X

Tan X = 72 / 125 = 0.576 X= 29.9 degrees



You are

CORRECT!

Click for solution

Solution for Question 4R

Q

PS

60 m

53 degrees60

In the diagram, PQ represents the cliff and QR the tower, S is 60 m from P

In SPQ, tan 53 = PQ /SP = PQ /60 PQ = 60 tan 53 = 79.62

In SPR, tan 65 = PR /SP = PR /60 PR = 60 tan 65 = 128.67

QR = PR – PQ = 49.05


You are

CORRECT!


Question 5: From the top of a cliff 52 m high, the angles of depression of two ships due east of it are 36 and 24 degrees respectively. Find the distance between the ships.

A. 54.68 meters

B. 77.56 meters

C. 70.68 meters

D. 45.22 meters


P A B

Q

36 degrees 24 degrees

36 degrees

24 degrees

52 m

In the figure PQ represents the cliff, A and B the shipsPBQ = 24 and PAQ = 36

PAQ = tan 36 = PQ/PA = 71.57PBQ = tan 24 = PQ/PB = 116.79

The distance between the 2 ships is 116.79 – 71.57 = 45.22 m

Congratulatio

nsYOU ARE SMART

mcq on practical application of trigonometry prepared by: ramil t. francisco ismael mathay sr. high...

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