mean, median, and mode

Find the average of 502, 477, 593, 481, 735, and 614.

Mean, Median, and ModeMean, Median, and ModeCOURSE 2 LESSON 1-10COURSE 2 LESSON 1-10

502 + 477 + 593 + 481 + 735 + 6146

Divide the sum by the number of terms.

Simplify. The mean is 5673,402

6 = 567

1-10

Find the outlier of the data below. Describe how the outlier

affects the mean.


40 37 53 42 45 12 39 48

The outlier is 12, which is much lower than the other data items.

The outlier lowers the mean of the data.

1-10

Find the average of the

data in the chart.


18 Responses to “How many pizzas did you order?”

2 0 1 2 4 21 0 3 2 0 80 1 2 3 0 1

First write the data in order from least to greatest.

0 0 0 0 0 1 1 1 1 2 2 2 2 2 3 3 4 8

The median is 1.5 pizzas.

The two middle values are 1 and 2.

Find the mean of the two middle values.1 + 2

2 = 1.5

1-10

Find the average of

the data in the chart.


peppers onions mushrooms

onions sausage peppers

onions peppers mushrooms

onions sausage onions

Favorite Pizza Topping of Twelve People Surveyed

Make a table to organize the data.

Peppers Onions Mushrooms Sausage

The mode is onions.

1-10

Suppose a teen jogs an average of 2.5 mi per day on

weekdays and 4 mi per day on weekends. How many miles does this

teen jog each week?


Multiply the weekday average by the number of weekdays. Multiply the weekend average by the number of weekend days.

2.5 • 5 + 4 • 2 = 20.5

The teen jogs a total of 20.5 mi each week.

1-10


Find the mean, median, and mode of each set of data.

1. 25 27 21 27 20

2. –8 –4 2 10 –10

3. 7.5 3.6 15.4 3.6 15.4

mean, 24; median, 25; mode, 27

mean, –2; median, –4; mode, no mode

mean, 9.1; median, 7.5; mode, 3.6 and 15.4

1-10

mean, median, and mode

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