mel345-7
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mel345-7TRANSCRIPT
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Resistance Forces on A Vehicle P M V SubbaraoProfessorMechanical Engineering DepartmentEstimation of Vehicle Demands.
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Resistance Forces on A VehicleThe major components of the resisting forces to motion are comprised of :Acceleration forces (Faccel = ma & I forces)Aerodynamic loads (Faero) Gradeability requirements (Fgrade)Chassis losses (Froll resist ).
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Force System Due to Rolling Resistance*
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Road Conditions *
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Rolling ResistanceComposed primarily of Resistance from tire deformation (90%)Tire penetration and surface compression ( 4%)Tire slippage and air circulation around wheel ( 6%)Wide range of factors affect total rolling resistanceThe magnitude of this force is Approximated as:Rolling resistance of a vehicle is proportional to the component of weight normal to the surface of travel
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Standard Formula for Rolling Resistancewhere:P= power (kW) Crr= coefficient of rolling resistanceM= mass (kg)V= velocity (KpH)
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Typical Values of Coefficient of Rolling Resistance
Contact TypeCrrSteel wheel on rail 0.0002...0.0010Car tire on road 0.010...0.035Car tire energy safe 0.006...0.009Tube 22mm, 8 bar 0.002Race tyre 23 mm, 7 bar 0.003Touring 32 mm, 5 bar 0.005Tyre with leak protection 37 mm, 5 bar / 3 bar0.007 / 0.01
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Effect of Road Condition on Crr*
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Rolling Resistance And Drag Forces Versus Velocity
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Grade ResistanceComposed of Gravitational force acting on the vehicleFor small angles, gmggFg
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Total Vehicular Resistance at Constant Velocity AR = air resistance [N] RR = rolling resistance [N] GR = gradient resistance [N]TR = total resistance [N]
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ResistanceVehicle SpeedSteady State Demand Curve
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Vehicle Speed vs. Engine Speed
V=velocity , km/hrr=wheel radius, m Ncrank=crankshaft rpmi=driveline slippageGO=Overall gear reduction ratio
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Typical Engine Torque-Power Curves @ SS
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Steady State Demand Vs Available Effort*
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Inertial or Transient ForcesTransient forces are primarily comprised of acceleration related forces where a change in velocity is required. These include:The rotational inertia requirements (FI ) and the translational mass (Fma). If rotational mass is added to a translating vehicle, it adds not only rotational inertia but also translational inertia.
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Inertial Resistance*where:FIR = inertia resistance [N] meff-vehicle = Vehicle mass + Equivalent mass of rotating parts [kg]a = car acceleration [m/s2], (from 0 to 100 km/h in: 6 s (4.63 m/s2), 18 s (1.543 m/s2))mvehicle = Vehicle mass [kg]meq = Equivalent mass of rotating parts [kg]
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*
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= angular accelerationk = radius of gyrationEquivalent Mass of Rotating Parts Torque due to any rotating part (ex. Wheel)wheels and axles = 78% of total polar inertia propeller shaft = 1.5%Engine = 6%Flywheel and clutch =14.5%
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Therefore the equivalent mass of all rotational parts including losses is represented as:
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Required Torque & Power at WheelsTractive Effort demanded by a vehicle):
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Available Vehicle Tractive Effort (TE):The minimum of:Force generated by the engine, FeMaximum value that is a function of the vehicles weight distribution and road-tire interaction, Fmax
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Tractive Effort Relationships*
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MATLAB for Vehicle Torque Requirement
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MATLAB Model for Transmission System
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Requirements of Vehicle on Road & Engine Power
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Urban Driving Cycle
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Engine RPM during Urban Driving Cycle
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Engine Fuel Consumption During Urban Driving Cycle
*Torque and HP always cross at 5252 RPM. Why? Look at the equation for HP