melting ice to find the value of the latent heat capacity of fusion of ice

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  • 7/30/2019 Melting ice to find the value of the latent heat capacity of fusion of ice

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    Marc Wierzbitzki Physics HL 20 January 2011

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    Melting ice to find the value of the latent heat capacity of fusion of ice

    Aim:

    With the help of this experiment, we wanted to find the value of the latent heat capacity of fusion (Lfus) of

    water.

    Construction:

    Method:

    After setting everything up as shown in the illustration above, reset the mass balance to 0 so that the mass

    of the beaker and the thermometer will be ignored, because only the mass of the ice and water matter.

    Start by filling the water into the big beaker and note down the temperature and mass. After doing that,

    also give in the ice and wait until it is completely melted. Note down the additional mass and the final

    temperature.

    Results:

    MI (g) MW(g) T1(I) (C) T2(W) (C) T2(C) MITW (gK) MWTW (gK) E (J)0.2g 0.2g 1C 1C 1C 11% 11% 30%

    21.30 150.00 0 53 40.0 0852 -1950 04597

    45.90 112.00 0 40 13.0 0597 -3024 10163

    50.00 220.00 0 56 36.0 1800 -4400 10886

    19.30 164.10 0 65 52.0 1004 -2133 04730

    30.50 189.00 0 34 23.0 0702 -2079 05768

    41.97 133.87 0 49 18.5 0776 -4083 13845

    77.21 133.38 0 44 07.5 0579 -4868 17959

    20.08 100.00 0 45 25.5 0512 -1950 06021

    07.25 100.00 0 48 40.0 0290 -0800 02135

    37.25 100.00 0 42 17.0 0633 -2500 07816

    46.16 100.00 0 52 16.0 0739 -3600 11981

    04.50 050.45 0 57 46.0 0207 -0555 01457

    15.20 050.30 0 60 35.0 0532 -1258 03038

    54.20 163.70 0 65 33.0 1785 -5238 1445868.60 163.50 0 67 29.0 1989 -6213 17684

    Error analysis:

    The smallest error can be found in the masses of water and ice, as the mass balances we used were quite

    accurate. Comparing them to each other, the biggest deviation we noticed was 0.2g. The thermometers

    all displayed the same temperature, but as they were not digital, we could only read the results with an

    error of 1C, whereas a digital thermometer would have been more accurate. Using those values, we

    calculated that the error for MITW has to be 11% and for E30%. Those two errors are quite big (as you

    can see in the graph below), which will make it harder for us to decide whether our final result is right or

    not.

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    Marc Wierzbitzki Physics HL 20 January 2011

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    Graph:

    The above graph gives a mean value of Lfus=245.15Jg-1. The minimum value is equal to 147.65 Jg-1, whereas

    the maximum value is 305.37 Jg-1. Therefore, we can compute an error to the mean value of 97.5 Jg -1.

    Looking at the result that we expected (L fus=334Jg-1), our result still fits into the error range. But on the

    other hand, the experiment is still not very conclusive, since the error is about 40% of the mean value and

    the range it gives us is simply too big.

    The problem with this experiment was probably the amount of energy that was lost to the surroundings.

    This happened at two situations throughout the experiment and therefore the total error added up to

    30%. Firstly, we assumed that the ice was constantly at 0C, which is not true. While doing the

    y = 245.15x + 19.706

    y = 305.37x - 293.13

    y = 147.65x + 1200.3

    0

    5000

    10000

    15000

    20000

    25000

    0 10 20 30 40 50 60 70 80 90

    -(CW

    (MI

    TI+MWTW)

    MI

    Lfus

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    Marc Wierzbitzki Physics HL 20 January 2011

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    experiment, you could definitely see that more and more ice melted, it was wet as we did not put it back

    into a refrigerator after we had used it. Also, since the water was very hot, it constantly loosed mass

    through evaporation, which we did not capture. This affected the value of E (shown in the last column in

    the table). Improvements to this could lower the error for this value.

    Possible ways to improve the experiment:Looking at the problems that I described above, quite many improvements can be suggested. Firstly, since

    this is the most significant error source, we have to minimize the energy loss to surroundings. To do so,

    we should not use a beaker anymore but utilize a thermos flask, which would eliminate the effect of the

    temperature surroundings. Furthermore, we should also think about closing the flask entirely so that no

    water can evaporate and disappear, but it would be trapped within the flask.

    Also, it has to be ensured that the ice stays at the same temperature throughout the whole experiment,

    otherwise no conclusion can be drawn. To make this possible, the ice should be stored in a refrigerator

    until it is needed, just like the water should be boiled for each new repetition.

    To reduce all other errors as much as possible, a digital thermometer and mass balance should be used.

    Those two devices will reduce the errors in the mass and temperature readings since they are more

    accurate and no mistakes can be made when reading off the corresponding values.

    Redoing the experiment with the improved set-up will hopefully reduce the errors that have beenmentioned above. Since we tried to eliminate the energy loss to surroundings, the results in general

    should be more accurate and closer to the actual value of 334Jg-1.