microwave radiometry. 2outline introduction thermal radiation black body radiation –rayleigh-jeans...
TRANSCRIPT
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OutlineOutline
Introduction Thermal Radiation Black body radiation
– Rayleigh-Jeans
Power-Temperature correspondence Non-Blackbody radiation
– TB, brightness temperature
– TAP, apparent temperature
– TA, antenna temperature
More realistic Antenna– Effect of the beam shape– Effect of the losses of the antenna
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Thermal RadiationThermal Radiation
All matter (at T>0K) radiates electromagnetic energy!
Atoms radiate at discrete frequencies given by the specific transitions between atomic energy levels. (Quantum theory)– Incident energy on atom can be absorbed by it to move
an e- to a higher level, given that the frequency satisfies the Bohr’s equation.
– f = (E1 - E2) /h
where,
h = Planck’s constant = 6.63x10-34 J
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Thermal RadiationThermal Radiation
absorption => e- moves to higher levelemission => e- moves to lower level
(collisions cause emission)
Absortion Spectra = Emission SpectraAbsortion Spectra = Emission Spectra
atomic gases have (discrete) line spectra according to the allowable transition energy levels.
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Molecular Radiation SpectraMolecular Radiation Spectra
Molecules consist of several atoms. They are associated to a set of vibrational and
rotational motion modes.
Each mode is related to an allowable energy level.
Spectra is due to contributions from; vibrations, rotation and electronic transitions.
Molecular Spectra = many lines clustered together; not discrete but continuous.
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Radiation by bodies Radiation by bodies (liquids - solids)(liquids - solids)
Liquids and solids consist of many molecules which make radiation spectrum very complex, continuous; all frequencies radiate.
Radiation spectra depends on how hot is the object as given by Planck’s radiation law.
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CommonTemperature -CommonTemperature -conversionconversion
90oF = 305K = 32oC70oF = 294K = 21oC32oF = 273K=0oC0oF = 255K = -18oC -280oF = 100K = -173oC
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Properties of Planck’s LawProperties of Planck’s Law
fm = frequency at which the maximum
radiation occurs
fm = 5.87 x 1010 T [Hz]
where T is in KelvinsMaximum spectral Brightness Bf (fm)
Bf (fm) = c1 T3
where c1 = 1.37 x 10-19 [W/(m2srHzK3)]
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Stefan-Boltzmann Stefan-Boltzmann Total brightness of body at Total brightness of body at TT
Total brightness is 4
0
TdfBB f
20M W/m2 sr
13M W/m2 sr67%
where the Stefan-Boltzmannconstant is= 5.67x10-8 W/m2K4sr
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Blackbody Radiation -Blackbody Radiation -given by Planck’s Lawgiven by Planck’s Law
Measure spectral brightness Bf [Planck]
For microwaves, Rayleigh-Jeans Law,
condition hf/kT<<1 (low f ) , then ex-1 x
]Hzsr [W/m 2kT2 2
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2
c
kTfB f
At T<300K, the error < 1% for f<117GHz),and error< 3% for f<300GHz)
]Hzsr [W/m 1
12 2/2
3
kThff ec
hfB
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Rayleigh-Jeans ApproximationRayleigh-Jeans Approximation
Rayleigh-Jeansf<300Hz>2.57mm)T< 300K
TB f
Mie Theory
frequency
Bf
Wien
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Total power measured due Total power measured due to objects Brightness, to objects Brightness, BBff
dfdFfBAP n
ff
f
frbb
,,, 2
1
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B=Brightness=radiance [W/m2 sr]Bf = spectral brightness (B per unit Hz)B = spectral brightness (B per unit cm)
Fn= normalized antenna radiation pattern= solid angle [steradians]Ar=antenna aperture on receiver
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Power-Temperature correspondencePower-Temperature correspondence
fkTP
A
dFAfP
fB
dfdFAP
bb
rp
nrbb
f
n
ff
f
rbb
2
42
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is angle solidpattern but the
,2kT
2
1
overconstant ely approximat is if
,2kT
2
1
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Analogy with a resistor noise Analogy with a resistor noise
Antenna Pattern
T
fkTPbb
R
T
fkTPn
Analogous to Nyquist;noise power from R
Direct linear relationpower and temperature
*The blackbody can be at any distance from the antenna.
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Non-blackbody radiationNon-blackbody radiation
But in nature, we find variationswith direction, B()
ffBB fbb 2
2kT
Isothermal medium at physical temperature T
TB()
=>So, define a radiometric temperature (bb equivalent) TB
f
kTBeB B
bb 2
,2),(),(
For Blackbody,
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Emissivity, Emissivity, ee
The brightness temperature of a material relative to that of a blackbody at the same temperature T. (it’s always “cooler”)
10 where
,T),(),( B
e
TB
Be
bb
TB is related to the self-emitted radiation from theobserved object(s).
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Ocean colorOcean color
Pure Water is turquoise blue The ocean is blue because it absorbs all the other
colors. The only color left to reflect out of the ocean is blue.
“Sunlight shines on the ocean, and all the colors of the rainbow go into the water. Red, yellow, green, and blue all go into the sea. Then, the sea absorbs the red, yellow, and green light, leaving the blue light. Some of the blue light scatters off water molecules, and the scattered blue light comes back out of the sea. This is the blue you see.”
Robert Stewart, Professor
Department of Oceanography, Texas A&M University
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Apparent Temperature, Apparent Temperature, TTAPAP
Is the equivalent T in connection with the power incident upon the antenna
TAP()
fBinc
2AP ,2kT
),(
dFTAfP nAPr
4
2,,
2k
2
1
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Antenna Temperature, Antenna Temperature, TTAA
dFTA
T
fkTP
dFTAf
P
nAPr
rA
An
nAPr
r
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42
,,
,,2k
2
1
Noise power received at antenna terminals.
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Antenna Temperature Antenna Temperature (cont…)(cont…)
Using we can rewrite as
for discrete source such as the Sun.
dF
dFT
Tn
nAP
A
4
4
,
,,
sunp
sunA TT
prA
2
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Antenna Beam EfficiencyAntenna Beam Efficiency, , MM
Accounts for sidelobes & pattern shape
dF
dFT
dF
dFT
Tn
ml
nAP
n
ML
nAP
A
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,
,,
,
,,
dF
dF
dF
dFT
dF
dF
dF
dFT
Tn
ml
n
ml
n
ml
nAP
n
ML
n
ML
n
ML
nAP
A
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,
,
,
,,
,
,
,
,,
TA= M TML +(1- M)TSL
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Radiation Efficiency, Radiation Efficiency, ll
Heat loss on the antenna structure produces a noise power proportional to the physical temperature of the antenna, given as
TN= (1-l)To
The l accounts for losses in a real antenna
TA’= l TA +(1-l)To
TATA’