mock test 2014 solutions

8/21/2019 Mock Test 2014 Solutions

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Page 1Mock Test 2014 - Solutions

Mock Test 2014

Answers and Explanations

1 2 2 1 3 4 4 4 5 * 6 3 7 1 8 2 9 4 10 1

11 5 12 1 13 4 14 2 15 3 16 2 17 3 18 5 19 5 20 3

21 2 22 4 23 2 24 2 25 1 26 1 27 2 28 3 29 4 30 3

31 3 32 3 33 3 34 3 35 3 36 1 37 1 38 2 39 4 40 3

41 4 42 1 43 3 44 4 45 3 46 3 47 1 48 5 49 2 50 *

51 3 52 3 53 4 54 4 55 4 56 5 57 5 58 1 59 3 60 5

61 5 62 2 63 4 64 5 65 4 66 3 67 3 68 2 69 3 70 3

71 2 72 1 73 1 74 3 75 3 76 4 77 2 78 2 79 3 80 2

81 5 82 1 83 1 84 2 85 5 86 4 87 2 88 3 89 2 90 1

91 1 92 4 93 3 94 2 95 3 96 4 97 4 98 1 99 2 100 3


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Page 2 Mock Test 2014 - Solutions

1. 2 We have

3f (0) 0 4(0) p p= + =

3f(1) 1 4(1) p p3= + =If p and p3 are of opposite signs, then p(p 3) < 0Hence, 0 < p < 3.

2. 1 The first strip can be of any of the four colours, The2nd can be of any colour except that of the first (i.e.3). Similarly, each subsequent strip can be of anycolour except that of the preceding strip i.e. 3.Hence, the number of ways = 4 35= 12 81.

3. 4 If p = 1! = 1, thenp + 2 = 3 when divided by 2! will give a remainder of 1.If p = 1! + 2 2! = 5, thenp + 2 = 7 when divided by 3! will give a remainder of 1.Hence, p = 1! + (2 2!) + (3 3!) + + (10 10!) whendivided by 11! leaves a remainder 1.

Alternative Method:P = 1 + 2.2! + 3.3! + + 10.10!= (21)1! + ( 31)2! + (41)3! + + (111)10!=2!1! + 3!2! + + 11!10! = 1 + 11!Hence, the remainder is 1.

4. 4 P = x yx y

log logy x

+

= x x y ylog xlog y log ylog x+ = x y2log ylog x

Let xt log y=

21 1

P 2 t tt

t

= =

Which can never be positive. Out of given options, it

cannot assume the value of +1.

5. * 3 3 3 3 3 3 3 3x 16 17 18 19 16 19 (18 17 )= + + = +

Using 3 3 2 2a b (a b)(a ab b )+ = + +We get,

3 319 16 35 oddnumberRem Rem 35

70 70

+ = =

and3 3 2 218 17 18 17 18 17Rem Rem70 70

+ + =

44 9 26Rem 9

70

+ + = =

Thus, when x is divided by 70 the remainder is 359= 26.Note 1: None of the option has 26 as their value.

Note 2: There was as similar question asked in CAT-2005which is given below.

Q. If ( )3 3 3 3x 16 17 18 19= + + + , then x dividedby 70 leaves a remainder of

(1) 0 (2) 1

(3) 69 (4) 35

Sol. 3 3 3 3x 16 17 18 19= + + + is an even numberTherefore, 2 divides x.

3 3 2 2a b (a b)(a ab b )+ = + +a + b always divides a3+ b3.Therefore, 163+ 193 is divisible by 35.183+ 173is divisible by 35.

Thus, x is divisible by 70.

Hence, option (1) is the correct choice.

6. 3 From the given equation, it is obvious that 2 < x < 3.Option (c) satisfies the condition.

Alternative Solution:

2x 4 4x x 4 4x= + = +

( )2x 4 4x=Now putting the values from options, we find onlyoption (3) satisfies the condition.

7. 1a 1 b 2

,b 3 c 1

= = a : b : c = 2 : 6 : 3

Similarly, a : b : c : d : e : f = 6 : 18 : 9 : 18 : 6 : 24

= = abc 6 18 9 3def 18 6 24 8Hence, option (1) is the correct answer.

Alternate Method:

a b c d e a 1 1 1 12 3

b c d e f f 3 2 4 4 = = =

b c b 12 1

c d d 2 = = =

c d c 1 33

d e e 2 2 = = =

abc a b c 1 3 3So, 1 .

def f d e 4 2 8= = =


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8. 2 Let the number be 10x + y so when number is reversedthe number because 10y + x. So, the number increasesby 18Hence, (10y + x)(10x + y) = 9 (y x) = 18

yx = 2So, the possible pairs of (x, y) are (3, 1) (4, 2) (5, 3)(6, 4), (7, 5) (8, 6) (9, 7)But we want the number other than 13 so, there are 6possible numbers, i.e. 24, 35, 46, 57, 68, 79.

So total possible numbers are 6.

9. 4 Let number of elements in progression be n, then

( )= + 1000 1 n 1 d

( ) = = 3n 1 d 999 3 37

Possible values of d 1, 3, 9, 27, 37, 111, 333Hence, 7 progressions are possible.

10. 1 + 2 / 3 1/ 3x x 2 0

+ 2 / 3 1/ 3 1/ 3x 2x x 2 0

( )( ) + 1/ 3 1/ 3x 1 x 2 0

1/ 32 x 1 8 x 1

11. 5 f(x) = max (2x + 1, 3 - 4x)So, the two equations are y = 2x + 1 and y = 3 - 4xy2x = 1

+ =y x

11 1/ 2

Similarly, y + 4x = 3

+ =y x

13 3 / 4

Their point of intersection would be2x + 1 = 3 - 4x

6x = 2

=1

x3

(1/3,5/3)

(0,3)

(-1 /2,0) (0 ,3/4)

y=3 4x

y=2x+1

x

y

So when max1

x , then f(x) 3 4x3

=

and when max1

x , then f(x) 2x 13

= +

Hence, the minimum of this will be at x =1

3

i.e. = 5y3

Alternative Method:As f(x) = max (2x + 1, 3 - 4x)We know that f(x) would be minimum at the point ofintersection of these curvesi.e. 2x + 1 = 3 - 4x

6x = 2

1x3

=

Hence, min f(x) is

5

3

12. 1 Let f(x) = 2ax bx c+ +At x = 1, f(1) = a + b + c = 3At x = 0, f(0) = c = 1The maximum of the function f(x) is attained at

x =b

2a

= 1 =a2

2a

a =2 and b = 4

f(x) = 22x + 4x + 1Therefore, f(10) = 159

13. 41 4 1

, n 60m n 12

+ = x2+ 82 x = 8, 9, 10 , 11, 12Case (ii): x2> 152+ 82 X = 18, 19, 20, 21, 22

Hence, the number of triangles = 5 + 5 = 10.

Alternative Method:The three sides of the obtuse triangle are 8 cm, 15 cmand x cm. As 15 is greater than 8, hence either x or 15will be the largest side of this triangle. Consider twocases:

Case I:

15 cm

CB 8 cm

x

A

90

Consider the right ABC above,

2 2x 15 8 12.68 cm= =

For all values of x < 12.68, the ABC will be obtuse.But as the sum of two sides of triangle must be greaterthan the third side, hence (x + 8) > 15 or x > 7.Thus, the permissible values of x are 8, 9, 10, 11and 12.

Case II:

15 cm

CB 8 cm

x

A

90

In the right ABC above, 2 2x 15 8 17= + = .

For all values of x > 17, ABC will be obtuse. But, asthe length of third side should be less than the sum of

other two sides, hence x < (15 + 8) or x < 23. Thepermissible values of x are: 18, 19, 20, 21 and 22.From Case I and II, x can take 10 values.

18. 5 We can use the formula for the circum radius of a

triangle:

a b cR

4 (Area of the triangle)

=

ora b c a c

R1 2 AD

4 b AD2

= =

17.5 9

26.25 cm.2 3

= =

19. 5 A B

D

E

F

G

P QH L

C

Let the length of AH be xcm.By symmetry of the figure given above, we can

conclude that APD and BQC will have the samearea.

APD is 120and line Ldivides the squareABCD in 2 equal halves, therefore

APH HPD 60 = =


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InAH x

AHP : tan60 3 HP cmHP 3

= = =

Area of

APD 2 area( AHP) = 21 x x

2 x cm2 3 3

= =

Area of ABQCDP = area (ABCD)2 area ( APD)

( )22

2 2x 2 3 12x4x3 3

= =

Required ratio

( )2

2

2x 2 3 1

3 2 3 12x

3

= =

Alternate Method: Concepts used:

A

B C

a b

c

a b c

sinA sinB sinC = =

Also, area of ABC =1

2ab sin C =

1

2bc sin A =

1

2ac

sin BIn the given figure

A B

CD

E

G

H L

FP Q

a

a

x x

x x

120 120

For APD, Let AP = PD = x cm

a x xsin120 sin30 sin30

= =

sin120 = sin (90+ 30) = cos 30=3

,2

sin 30=

1

2

a x

1322

= a

x cm3

=

Thus, area of APD is1

AP PD sin1202

1 a a 3

2 23 3= =

22a cm

4 3

by symmetry, Area of APD = Area of BQC

Area of ABQCDPThus, ratio of

[Removing area inside square ABCD

Area of square ABCD 2 (Area of APD)

2 (Areaof APD)

=

2 3 1=

20. 3

P Q

B

A

If P and Q lie on the intersections of the circles asshown in the figure given below.

P Q

B

A

In this case triangle APQ is equilateral. So the maximumpossible measure of the angle AQP is 60. The answeris between 0 and 60.

21. 2

A C B

D

6

2

ADB = 90 (Angle in semicircle)CD2= AC CB (6)2= 2 CB 36 = 2 CB CB = 18 cm AB = AC + CB = 20 cm

Hence, area of semicircle = = 21 (10) 502

sq. cm.


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22. 4 Let r be the radius of the two circular tracks.

The rectangle has dimensions 4r 2r.

B

r rr r

r

r

A

A covers a distance of 2r + 2r + 4r + 4r = 12 r

B covers a distance of 2 r 2 r 4 r + = Time taken by both of them is same.

B AB A

4 r 12rS S

S S 3

= =

Required percentageB A

A

S S100

S=

3

100 4.72%.3

= =

23. 2

2

x/2

x

In original rectangle ratio =x

2

In smaller rectangle ratio =2

x

2

Givenx 2

x 2 2x2

2

= =

Area of smaller rectangle x 2 x 2 2 sq. units.2

= = =

24. 2

A

2 2

8

B C

DFE

1 1AB BD AD BE

2 2 =

2 22 8 2 8 BE =

60 15BE

4 2 = =

22 15 15 1AE 2 4

2 4 2 = = =

1 1BC EF 8 7

2 2

= = + =

25. 1 DF, AG and CE are body diagonals of cube.Let the side of cube is a.

Therefore, body diagonal is a 3

a 3

a 3

a 3

Circum radius for equilateral triangle =Side

3

Therefore,a 3

a3

=


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26. 1

100 l

M

80

W

20

I II

75 l

M

60

W

15

M

60

W

15

75 l + 25 lW

The diagram is self explanatory. Removal of 25 litresat stage I will result in volume of milk being reduced by80% of 25 lit i.e. 20 lit and volume of water beingreduced by the remaining 5 lit. So M = 60 lit and W = 15lit. Addition of 25 lit water will finally given M = 60 lit andW = 40 M. Hence the ratio of W and M = 40 : 60 = 2 : 3.

27. 2 Let d be the distance to be travelled and t be the timetaken to reach at 1 p.m.

If the man cycles at 10 km/hr, thend

10t

= (i)

If the man cycles at 15 km/hr, then d 15t 2

= (ii)

Solving (i) and (ii), we get t = 6 hours and d = 60 km

To reach the place by noon, he needs to cycle at

=d 60

12 km/hrt 1 6 1

= =

28. 3 The boats will be colliding after a time which is givenby

20 4t hours 80 minutes5 10 3

= = =+ .

After this time of 80 minutes, boat (1) has covered

5 2080 kms kms

60 3 = , whereas boat (2) has

covered10

80 kms60

=40

kms.3

After 79 minutes, distance covered by the first boat

= d1=20 5

kms3 60

After 79 minutes, distance covered by the second

boat = d2=40 10

kms3 60

So the separation between the two boats

= 20 ( )1 2d d+ =1

kms4

Alternative Method:Relative speed of two boats = 5 + 10 = 15 km/hri.e. in 60 min they cover (together) = 15 km

in 1 min they will cover (together) =15 1

km60 4

29. 4 Race 1:In whatever time Karan covers a distance of 100 m,Arjun covers 90 m in the same time.

Ratio of their speeds = 10 : 9Race 2:Now Karan is 10 m behind the starting point. Onceagain to cover 100 m from this new point Karan willbe taking the same time as before. In this time, Arjunwill be covering 90 meters only. This means that nowboth of them will be at the same point, which will be 10meters away from the finish point. Since both of themare required to cover the same distance of 10 m andKaran has a higher speed, he will beat Arjun. No needfor calculations as option (4) is the only such option.

30. 3 Machine I:

Number of nuts produced in one minute = 100To produce 1000 nuts time required = 10 minCleaning time for nuts = 5 minEffective time to produce 1000 nuts = 15 minEffective time to produce 9000 nuts = 15 9 5= 130 minMachine II:To produce 75 bolts time required = 1 minTo produce 1500 bolts time required = 20 minCleaning time for bolts = 10 minEffective time to produce 1500 bolts = 30 minEffective time to, produce 9000 bolts = 30 6 10= 170 min (ii)From (i) and (ii),Minimum time to produce 900 pairs of nuts and bolts= 170 minutes

31. 3 As options are independent of n, let us assume n = 2.

Circumference of the track 2 r= Time taken for first round =

11 2 4 7.5 minutes

2+ + + =

and time taken for second round = 8 + 16 + 32 + 64= 120 minutes

Hence,120

ratio 16 : 1 16

7.5

= = =


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32. 3 A B C D

20 20

90 90

10 10

50 50

100 100

110 110Total +60 30 40 50

D gets emptied first, it gets emptied in 20 minutes.Hence, option (3) is the correct answer.

33. 3 Frenchmen : F1, F2, F3Englishmen: E1, E2, E3Let E1 knows FrenchI round of calls:

F 1 F 2 F 3 E 2E 3

1 23

E 14

5

Persons Secrets know after I-roundF1 F1, F2F2 F1, F2, F3F3 F1, F2, F3, F4E1 F1, F2, F3, E2E2 F1, F2, F3, E1, E2, E3) all knownE3 F1, F2, F3, E1, E2, E3) All know

II round calls

F1 F 2 F 3

E or2

E3

9

E1

87 6

In the 6th call, E1knows all the secrets. Similarly, after9th call, everybody know all the secrets.

34. 3 Let us assume that Arun started running at 10 a.m.and Barun started at 12 noon. So, in these two hoursdistance traveled by Arun is 60 km and the relativespeed of Barun w.r.t Arun is 10 km/hr. So Barun will

overtake Arun after =60

10 = 6 hours

So, Barun reaches there at 6 p.m.

So, Kiranmala also overtakes Arun at 6 p.m.Let us assume Kiranmala takes 't' time to overtake

Arun and the relative speed of Kiranmala w.r.t Arun is30 km/hr and Arun ran for 8 hrs.So, distance travelled by Arun is = 30 8 = 240 kmwhile distance travelled by Kiranmala = 60t

240 = 6t t = 4Hence, Kiranmala start running 4 hours after Arun hadst off.

For questions 35 to 38:On day 3, there were 2 visitors from UK and 1 from USA. Onthe same day, the site was visited by 2 persons from Univer-sity 4 and 1 from University 6. So University 4 is located in UKand University 6 is in USA.Similar reasoning for day 2 gives us the conclusion that Uni-versity 3 is located in Netherlands and University 8 is in India.On day 1, the number of visitors from USA is 1 and that fromUniversity 6 is 1. University 6 is in USA (derived above), which

implies no other university is in USA.The number of visitors from India on day 1 is 1. Also, no visitorfrom University 8, which is in India has visited the site on day1. This implies that one of University 1 and University 5 is inIndia and the other in Netherlands. A similar logic gives us thatone of University 2 and University 6 is in UK and the other inCanada.

35. 3

36. 1

37. 1

38. 2

39. 4 The average expenditures (approximately) for the fami-lies:

Ahuja =700 1700 2700

1733;3

+ +

Bose =800 1750 2300

1617;3

+ +

Coomar =500 1100 1900

11673

+ + and

Dubey = 1200 2800 2000.2+ =

Hence, Dubey family has the highest averageexpenditure.

40. 3 Average incomes of Ahuja family

=3200 3000 2800 9000

3000;3 3

+ += =

Bose family=2300 2100 2800 7200

2400;3 3

+ += =

Coomar family =

1200 2200 1600 5000 16673 3

+ + = and Dubey family

= 1200 3200 4400 2200.2 2

+= =

Hence, Coomar family has the lowest average income.


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41. 4 The average savings (approximately) for the families:

Ahuja =2500 1300 100

1300;3

+ +=

Bose =1500 350 500

783;3

+ +

Coomar =700 1100 300

7003

+ += and

Dubey =0 400

200.2

+=

Hence, Dubey family has the lowest averagesavings.

42. 1 The savings of a person is maximum if he/she hashigh income but less expenditure. From the graph, amember of Ahuja family has Rs.3200 as income andRs.700 as expenditure. Hence, he/she will have themaximum savings among all.

For questions 43 to 46:

In any department in any given year, the average ageranges between 42-53 years.(i) When a 25 year old will join, the average age will dip

by a minimum of 3 years.(ii) When a 60 year old will retire, the dip will be less

compared to (i).

43. 3 In the bar graph, one dip corresponds to the new 25year old joinee. However, two dips in the trend impliesjoining of a 25 year old and the retirement of a 60 yearold employee. This trait is observed only in Financedepartment. Hence, the faculty member who retiredbelonged to Finance.

44. 4 From the graph of Marketing, it is clear that the newfaculty joined in 2001.On April 1, 2000, completed age of Professor Nareshand Devesh were 52 years and 49 years, in noparticular order.

Age of the third Professor on April 1, 2000= 49.33 3(52 + 49) = 47 yearsHence, his age on April 1, 2005 was 52 years.

45. 3 As the dip will be less in case a faculty retiredcompared to that when a new faculty joined in, so thenew faculty member joined the Finance area in 2002.

46. 3 For the OM area, the only dip comes in the year 2001.So the new 25 year old faculty joined in 2001. Hence,on April 1, 2003, his age will be 27 years old.

For questions 47 to 50:From the given information the following table can be formed:

M F V NV Total

Class 12 48 32 32 48 80

Class 11 44 36 40 40 80

SecondarySection

288 352 352 288 640

Total 380 420 424 800

47. 1 Percentage of vegetarian students in Class 12

=32

100 40%80

=

48. 5 From the above table

Male vegetarians25

32 8100

= =

Female vegetarians = 328 = 24Male non-vegetarians = 488 = 40So, their difference is 4024 = 16.

49. 2 From the above tablePercentage of male students in the secondary section

=288

100 45%640

=

50.* From the main table

M F V MaleVeg

FemaleVeg

Total

Class 12 48 32 32 80

Class 11 44 36 40 80

Secondary

Section288 352 352 320 320 640

Total 380 420 424 800

*This question is wrong because the number ofMale vegetarian cannot be greater than 288.

Note: The same question was asked in CAT-2007 as questionnumber 41 with the same error.


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For questions 51 to 54:For solving these questions make atable like this:

Africa America Australasia Europe

L 0 1 1 1 3

H 1 1 6

P 2 1 6

R 1 1 64 8 5 4 21

(i) As the labour expert is half of each of the other, so theonly possible combination is:

H

L 3

PR

6 each

(ii) Statement (d): If the number of Australasia expert is 1less, i.e. total export are 20 American be twice aseach of other. The only combined possible is Americas

= 8.Australasia = 4 + 1 = 5Europe = 4Africa = 4Now, we need to workout the various options possiblein the blank cells.


L 0 1 1 1 3

H 2 2 1 1 6

P 1 2 2 1 6

R 1 3 1 1 6

4 8 5 4 21


L 0 1 1 1 3

H 1 3 1 1 6

P 1 2 2 1 6

R 2 2 1 1 6

4 8 5 4 21


L 0 1 1 1 3

H 1 3 1 1 6

P 2 1 2 1 6

R 1 3 1 1 6

4 8 5 4 21

51. 3

52. 3

53. 4

54. 4

For questions 55 to 59:

From statement one, team would include exactly one amongP, R, SP (or) R (or) S.

From statement two, team would include either M, or QM but not Q(or) Q but not M

From statement three, if a team includes K, it will include L orvice versa.K, L always accompany each other.

From statement four, if one of S, U, W is included, then theother two also have to be included.

S, U, W are always together.

From statement five, L and N cannot be included togetherL, N are never together.

From statement six, L and U cannot be included together.L, U are never together.

55. 4 From statements one and twoTwo members are to be selected.Of the remaining seven;To maximize the size of the team.We would chose S,U and W are included in the team (statement four)We cannot include K (or) L because we would thenhave to leave out N and U (from statementsfive and six)

56. 5 If 'K' is included, 'L' has to be included (statement (3))If 'L' is chosen, neither N nor U can be chosen(statements (5) and (6))S, W are also not included because S, U, W have tobe always together. (Statement (4))Hence one of P (or) R would be selected(statement (1)) and one of M (or) Q would be selected(statement (2))(K, L) and two of the above five have to be included.


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57. 5 If a team includes N, it cannot include 'L',and therefore, not even 'K'. (from statement five andthree)According to statement (1), one of P or R or S has tobe included.According to statement (2), one of M or Q has to beselected.So the following cases are possibleP Q N,

R Q NP M N,R M NIf 'S' is selected, then S U W M N and S U W Q N are theonly possible cases.Hence, in all 4 + 2 = 6 teams can be constituted.

58. 1 From statements one and two;one of P, R, S andone of M, Q are to be selected. We require one moremember.But from statement three; (K, L) are always together.Hence 'L' cannot be included in a team of 3 members.

59. 3 Again, from statement one;one of P, R, S has to be selected.

To make a team of '5''S' will be chosen (which leaves out P and R) If 'S' is chosen 'U' and W have to be chosen(statement four) If 'U' is chosen 'L' cannot be chosen (statementfive)K cannot be chosen (statement three)And from statement two; one of M (or) Q has to bechosen.

For questions 60 to 63:The given basic information can be collated as below:(i) Six teamsA, B, C, D, E, F.(ii) Matches scheduled in two stagesI & II.(ii) No team plays against the same team more than once.(iv) No ties permitted.

As per the instructions given for stage I, we canreach the following conclusions:

(a) As B lost at least one match, A won all the 3 matches.(b) The two teams who lost all the matches cannot be A

(as explained above), cannot be B (E lost to B), cannotbe D (D won against C & F). Hence, the two teamsmust be C and F.

(c) F did not play against the top team (i.e. A).

We get the following table for stage I.

(To be read from rows)

A B C D E F

A X W W W

B L X W W

C L X L L

D L W X W

E L W X W

F L L L X

As per the instructions given for Stage-II, we can reach thefollowing conclusions.(d) A lost both its matches against E and F.(e) F won against A, hence is the bottom team

(out of C & F) which won both the matchesF won against C as well.This also means that C lost both its matches againstB and F.

(f) Apart from A and C, one more team lost both thematches in Stage-II.That team can neither be E (A lost to E), nor B(as C lost to B), nor F (as F won both its matches).Hence, the team must be D.

We get the following table for Stage-II.

(To be read from rows)

A B C D E F

A X L L

B X W W

C L X L

D L X L

E W W X

F W W X

60. 5 D and F won exactly two matches in the event.

61. 5 B and E have most wins, 4 each.

62. 2 E and F defeated A.

63. 4 B, E and F won both the matches in Stage-II.


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For questions 64 to 66: The given information can bedepicted as follows.(i)

3 houses on eac h side of the roadRoad

(ii) Six housesP, Q, R, S, T, U(iii) ColoursRed, Blue, Green, Orange, Yellow, White(iv) Different heights(v) T = tallest and opposite to Red(vi) Shortest opposite to Green(vii) U = Orange is between P and S, i.e. PUS or SUP.(viii) R = yellow and opposite to P(ix) Q = Green and opposite to U(x) P = White and (S, Q) > P > R (in height)

From (iv), (v), (vi), (ix) & (x), T > (S, Q) > P > R > Uin terms of heightFrom (iv), (vii), (viii), (ix) & (x), we get the following

two cases.

R

5 2/3 1

4 6 3/2

1 2/3 5

3/2 6 4

T

P S

Q Q

U

(Tallest)

U

T R

S P

Yellow Blue

Whi te Red

Green Green

ROA D ROA DO R

Orange Orange

Blue Ye llow

Red White

(Shortest) (Shortest)

64. 5 Second tallest house is either Q or S. So, we can notdetermine the answer.

65. 4 The colour of the house diagonally opposite to yellowhouse is Red.

66. 3 The tallest house, T is of Blue colour.

67. 3 Option (3) is the most logical explanation. Refer tolines those include correlations between variables

68. 2 Historical outcomes dependeach

case.Refer to the 1stpara where it says Prediction inhistory became averaged out. This is furthersupported by the example.

69. 3 Note the tone with which the third paragraph starts itemphasizes that students can do much more!

70. 3 The first paragraph details the "two developments" -agreater freedom in choosing subjects and theconcurrent abandoning of the subject by artists. Thesecond paragraph explores the connection betweenthese two developments.

71. 2 According to the passage, when "a culture is in astate of disintegration or transition he, himself hasto choose for society." So (2) is the correct option.

72. 1 The third paragraph, second line says a subject doesnot start or with something which the painter has toremember.

73. 1 According to the passage-"When a culture is in astate of disintegration or transition the freedom of theartist increases "

74. 3 The second sentence of the fifth paragraph says thesubject may have a personal meaning ; but there general meaning. This is quite the opposite of whatanswer choice (3) states, and so it becomes theanswer.

75. 3 Refer to the 4thparagraph of the passage. The elderswere of the opinion that turning of the eyes by thechild while having the ice-creams in both hands couldmake the child fall down or trip over stones, steps inthe pavement. The phrase rightly suggestedchangesthe meaning of the given sentence and hence it cannotbe inferred from the passage.

76. 4 Parvenus refer to persons who have suddenly risento a higher social and economic class but have not yetreceived social acceptance by others in that class.Hence, the phrase little parvenuswould appropriatelyrefer to young upstarts.

77. 2 Refer to the 5th paragraph of the passage. Thesentence two two-cent .suggested excessclearlytell us that it was intemperance on part of the authorwhich made him pine for two two-cent ice-creamcones instead of one four-cent pie.

78. 2 In the lines Nowadays the moralist .......spoiled. Theauthor is talking about morality in the context of thepresent day world. The rest of the options are out ofthe scope of the passage.

79. 3 We refer to the tenth line of the third paragraph. Here

Mr. Goran Lindblad admits that communism did commitbrutalities but it also had positive consequences likerapid industrialization. Hence option (3) is the bestanswer.


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80. 2 Option (4) is very blatant, but is not the 'real' reasonfor the attack. The reason that the West repeatedlyattacks communism (as stated by the author in the lastpara) is that they want to establish the current capitalistorder as supreme i.e. they idealise 'global capitalism'.Option (5) is close, but wrongly states that communistnations might overtake the capitalists. This is not givenin the passage.

81. 5 The answer can be found in the first line of the lastparagraph, which in essence implies that it is importantto go beyond and look at the motives of atrocitiesperpetrated by different regimes. The motive is globalcapitalism as described in the last paragraph.Therefore, Option (5) is correct.

82. 1 (1) is the correct answer. In the fourth paragraph theauthor explains the 'intimate link' between colonialismand Nazism. A peripheral view of this relationshipsuggests that the answer should be (3) which explainsthe terms and ideas that were imported and used bythe Nazi party. But the next few lines explain the deeperrelationship that exists between the two. These lines

refer to the atrocities that one race has committedupon the other. The British imposed their rule on theIndian people. Similarly, the Belgian forced labour andmass murder led to the death of 10 million Congolese.These references are clearly race centric. Therefore,(1) is correct.

83. 1 Statement 1 is a judgement because it expresses anapproval/disapproval. It is a subjective opinion- anadvice given to HIV affected patients. So, options (3)& (4) can be eliminated. Statement 2 is clearly factual.This eliminates option (2). Statement 3 is a conclusionabout the future scenario which is based on the"recent initiatives". Hence, this statement is aninference. In statement 4, "But how ironic " showsthe author's disapproval. So statement 4 is a

judgement. Thus, option (1) is the correct answer.

84. 2 Looking at the statement A, if you mark the keywords

'is certainly' then it gives us a clear idea that it is a pointof view expressed by the author. Therefore, it is ajudgement. Statement B is an inference as it arrives ata conclusion from a stated premise. The statement C,where the author mentions 'is the only insurance'(although there may be other insurances, that theauthor negates) qualifies it as a judgement. Thestatement D is a pure fact. So, option (2) is correct.

85. 5 Statement 3 is a judgement because it expresses apersonal viewpoint regarding the consequences ofred tape. This eliminates option (1). Statement 2 is afact because the latter half of the sentence is givenby way of an example and not by way of a conclusion.This eliminates option (3). Statement 1 describes what"we should." do. This statement explains thespeaker's disapproval regarding the consequences

of red tape. Therefore, it is a judgement. This eliminatesoption (4). Statement 4 is an inference. It is known tous that a red tape procedure is a point of contact withan official. That this point of contact offers a potentialopportunity is a conclusion based on this information.This makes option (5) correct.

86. 4 Statement 1 is a judgement as it is based on the author'sopinion. This eliminates option (1) & (2). Statement 2

uses the general term "we ". This makes it a judgement.If it had been about "I" or "us" then it would have beena fact. Statements 3 and 4 are personal opinions.

Hence, the correct answer is option (4).

87. 2 The second sentence does not use the article. It shouldbe As a/the project progressesin sentence C thereshould be the indefinite article abefore single-mindedwhich leaves us with option (2) as the correct answer.

88. 3 Sentence B should have making them break apart.Sentence C should have many offending chemicals.

89. 2 B should be rarely has C should begin with The.

90. 1 Option B should be since the Enlightenment.Option C should be in the 1820s

91. 1 Sentence A is incorrect as the spelling of imigrantisnot correct , should be immigrant. Sentence D isincorrect because of a missing article and should be the owner of a dry goods .. Sentence E is incorrectand should be .. would later be known as...Sentence C is incorrect. We require a comma betweenbrother-in-law and David Stern.

92. 4 Sentence B should be.its labour policy becausethe subject is Nike and we cant substitute it with theplural pronoun their. Sentence C should be Perhapssensing that the rising tide as without that thesentence structure is incomplete. Sentence E shouldbe .an industry..as the word industry begins witha vowel so the appropriate article is an.

93. 3 Sentence B should be few millions. Sentence Dshould be reach the hundreds who are marooned..Sentence E is incorrect as per subject verb agreementand should be death count has begun.

94. 2 Statement (3) is factually wrong as we dont know if

further research can happen only in Germany. Option(4) wrongly brings out a contest between researchand debate. Between options (1) and (2), choice (1)

is inappropriate because we dont know if researchwill help find a definitive answer.


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95. 3 Statements (2) and (4) are partially true, as they donot cover all the examples of preferential treatment.Statement a is incomplete, as it does not mention directprotest.

96. 4 Option (2) is factually wrong. Option (3) is wrongbecause Nietzsche does not criticize intellectuals.Option (1) is wrong because it is focussing only oncreative instincts, which are only a subset of overall

human instincts. Only option (4) captures the essenceof the paragraph. Hence, option (4) is correct.

97. 4 CDBA is a mandatory sequence. Bush was notfighting just the democrats in statement D,relates directly with At times he was fighting instatement B.

98. 1 AC is a mandatory pair and DAC is a mandatorysequence.

99. 2 B is the opening statement as it introduces the subjectand the date. EDA is a sequence that describes thesituation from the east to the west. Statement C is astand-alone statement.

100. 3 Both statements C and B (papyri is the plural for

Egyptian papers and documents) are talking aboutsources of information, making CB a mandatory pair.

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