Mole Scavenger Hunt!

By Emily Bowman & Kelsey Latimer

While having fun in Chemistry class, you get thirsty. You go down to the “good drinking

fountain” (think BB Basement) to have a drink. You drink for a full minute. How many molecules of water did you just drink? What was the mass of

this water?Experiment Process

Step one: Take two 100 mL beakers and weigh both on a scale. Record the weight of both beakers.

Step two: Take both 100 mL beakers and a timer to the water fountain at the bottom of Bishop Brown.

Step three: Place one beaker underneath the water fountain and fill it up with water for exactly ten seconds.

Step four: Then place the second beaker underneath someone drinking from the fountain and let the person drink for 10 seconds and let the beaker catch the excess water that the person did not drink.

Step five: Go back to the classroom and weigh each beaker separately. Record the weight of the beaker with water for a full 10 seconds and then record the weight , then record the weight of the beaker with the excess water not drunk.

Step five: Calculate the weight of the water that was recorded for a full 10 seconds without the beaker. Subtract the weight of the 100mL beaker by the weight of the total weight of the beaker and water beaker and that will give you just the weight of the water. Then calculate the weight of the excess water not drunk with out the beaker. Subtract the weight of the 100 mL by the total weight of the beaker and the excess water. That will give you the weight of just the excess not drunk water.

Step six: Calculate weight of water for One minute. Take the weight of the water for a constant 10 seconds with out the beaker and multiply it by six. Calculate the weight of the excess water for a whole minute. Take the weight of the excess water not drunk and multiply by six.

Step Seven: Calculate how much water was actually drunk for a full minute. Take the calculation of the excess water not for a full minute and subtract it by water for a full minute.

Step eight: Calculate how many molecules are in the how ever many grams you have. To calculate you must go from Grams to moles then to molecules.

Our Calculations!Weights!

Weight of two 100 mL beakers separately: 16 g & 162g

Beaker with water for full 10 seconds= 346.7g

Beaker with excess water not drunk in 10 seconds= 193.7g

• Calculations!

• Water without beaker for 10 seconds= 346.7g – 162g = 184.7 grams

• Excess water not drunk without beaker for 10 seconds= 193.7g -162g = 31.7 grams

• Water without beaker for One minute= 184.7g x 6 = 1108.2 grams

• Excess water not drunk without beaker for One minute = 31.7g x 6 =190.2 grams

• Water drunk= 1108.2g -190.2g = 918 grams

More Calculations!

Constant water for One minute

918 grams H20

1 mol H2o

6.022 x 10^23

Mlc H2O

18.02 Grams H2O

1 Mol H2O

= 3.067 x 10^25 Mlc H2O

If you drank at the Bishop Brown water fountain for a full minute you would drink 3.067 x 10^25 molecules of water

As you are strolling around the campus, you trip and fall on a sweet gum ball. You decide that since you tripped

that no one else should go away unharmed. You are going to cover each square of the side walk with these balls touching side by side, leaving no part uncovered.

How many squares of sidewalk could you cover with one mole of sweet gum balls?

Experiment Process

• Find a sweet gumball and find the area (length x width) of the gumball.

• Take a yard stick and find the area (length x width) of one square on the sidewalk.

• Divide the area of the gumball by the area of the square to give you how many gumballs can fit into one square.

• To find how many squares a mole of gumballs would take up create a ratio how many gumballs over one square times a mole of gumballs over blank and cross multiply.

Our Calculations!Area of One square of side walk next to the glass door to the gym = 176cm wide x 150cm long = 26,400 cm2

Area of Gumball= 3cm x 3cm= 9cm2

How many gumballs in one square= 26,400cm2 /9cm2= 2,933.3 cm2

One mole of gumballs would cover 2.696 x 10^20 squares

2,933.3 gumballs

1 square

6.022 x 10^23 gumballs2.696 x 10^20

squares

x

After all this work you are thirsty. You decide that you should have a can of Coca Cola. How many moles of

sodium did you just consume? How many moles of sugar did you consume? How many molecules of sugar did you

just consume?

Experiment procedure

• Find a can of Coca Cola look on the back to find out how much sodium and how much sugar

• Convert sodium from grams to moles

• Convert sugar from grams to moles then to molecules

Our Calculations!35mg of sodium in 8 fl oz

27g of sugar in 8 fl oz

35 mg sodium 1 grams sodium

1 Mol sodium

1000 Mg sodium

342.22 Grams sodium

27g of sugar 1 moles 6.022 x 10^23 mlc

342.22 grams 1 moles

0.000102 Mol sodium

4.75 x 10^22 Mlc

sugar

27g sugar 1 Mol sugar

342.22 G sugar

0.0789 Mol

sugar

Near the depot there are a few holly trees. How many bushes would the school have to plant to

have a total of one mole of berries?

Experiment Process

• Count on average how many berries are on branch of the holy tree.

• Count on average how many branches are on a holy tree.

• Calculate on average how many berries are on one tree.

• Make a ratio how ever many berries over one tree and one mole of berries over x number of trees and cross multiply

Our Calculations!How many berries per branch? 98 berries

How many branches per tree? 21 Branches

How many berries on a tree? 98 berries x 21 branches = 2,058 berries per tree

The school would have to plant 2.93 x 10^20 trees to have a mole of berries

2,058 berries

1 tree

6.022 x 10 23 berries2.93 x 10^20 trees

x

The school district is insisting on planting a mole of blades of grass. How much space will this take?

Experiment Procedure

• Measure out a 6cm^2 area of ground and count how many blades of grass

• Divide how many blades of grass by 6cm to get how many blades per square inch

• Set a ratio how many blades of grass per square centimeter to a mole of grass over 3^2 square centimeter.

Our Calculations!36 blades of grass in 3 cm^2

36 blades of grass3 cm^2

x6.022 x 10^235.01833 x

10^22

It will take up 5.01833 x 10^22 cm^2

Again you are thirsty, so you buy a bottle of water from the machine. How much did each molecule of

water just cost you? How many water bottles would you have to purchase to consume one mole of water? How much would it cost you to consume

One mole of water?

Experimental Process:

Step one: First get cash and go get a water bottle from the vending machine.Step two: Take a 1000 mL beaker and weigh it in grams. Pour the contents of the water bottle into the beaker and weigh it in grams.Step three: Convert the grams to moles to molecules

Our Calculations!

17.065 oz water

1 grams water

1 mol water

0.03527 oz water

6.022 x 10^23 grams water

17.065 Oz water

1 grams 1 mol 6.022 x 10^23 Mlc

0.03527 oz

18.02 grams

1 mol

= 8.03452 x 10^24 mol

water

= 1.61691 x 10^25

mlc water

Calculations Continued

One bottle of water: $1.00

Weight of water from the bottle 17.065 oz

You would only need to buy one water bottle to have one mole of molecules of water

6.022 x 10^23/ 1.61691 x 10^25 = 0.037

It would cost you 4 cents for one mole of mlc of water

1.00/ 1.61691 x 10^25= 6.18 x 10^ -26

You paid 6.18 x 10^-26 for one molecule!