more stoichiometric calculations
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More Stoichiometric Calculations. More Stoichiometric Calculations. Moles to Mass. 2 Na + Cl 2 → 2 NaCl. 2 Na + Cl 2 → 2 NaCl If you use 1.25 mol of Cl 2 , what mass of NaCl will you get?. 2 Na + Cl 2 → 2 NaCl If you use 1.25 mol of Cl 2 , what mass of NaCl will you get? - PowerPoint PPT PresentationTRANSCRIPT
More Stoichiometric Calculations
More Stoichiometric Calculations
Moles to Mass
2 Na + Cl2 → 2 NaCl
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equation
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equation
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?
1.25 mol Cl2
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?
1.25 mol Cl2 x
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?
1.25 mol Cl2 x
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?
1.25 mol Cl2 x = mol NaCl
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratio
1.25 mol Cl2 x = mol NaCl
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratio
1.25 mol Cl2 x = mol NaCl2 mol NaCl
1 mol Cl2
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratio
1.25 mol Cl2 x = mol NaCl2 mol NaCl
1 mol Cl2
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: Multiply
1.25 mol Cl2 x = mol NaCl2 mol NaCl
1 mol Cl2
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: Multiply
1.25 mol Cl2 x = 2.50 mol NaCl2 mol NaCl
1 mol Cl2
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: MultiplyStep 6: Convert moles to grams
1.25 mol Cl2 x = 2.50 mol NaCl2 mol NaCl
1 mol Cl2
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: MultiplyStep 6: Convert moles to grams
2.50 mol NaCl
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: MultiplyStep 6: Convert moles to grams
2.50 mol NaCl x =
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: MultiplyStep 6: Convert moles to grams
2.50 mol NaCl x =g NaCl
mol NaCl
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: MultiplyStep 6: Convert moles to grams
2.50 mol NaCl x =g NaCl
mol NaCl
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: MultiplyStep 6: Convert moles to grams
2.50 mol NaCl x = 58.44 g
NaCl
1 mol NaCl
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: MultiplyStep 6: Convert moles to grams
2.50 mol NaCl x = 146.1 g 58.44 g
NaCl
1 mol NaCl
2 Na + Cl2 → 2 NaClIf you use 1.25 mol of Cl2,
what mass of NaCl will you get?
Step 1: Balance the equationStep 2: What do you know?Step 3: What do you need to know?Step 4: Find the ratioStep 5: MultiplyStep 6: Convert moles to grams
2.50 mol NaCl x = 146.1 g 58.44 g
NaCl
1 mol NaCl
What skills did we just use?
•Balance an equation•Read a question and figure out what it is asking for•Find the molar mass of a compound•Use a conversion factor.
NH4NO3 → N2O + 2 H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3
mol H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x =
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x =1
mol
80g
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x =1
mol
80g
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3 1
mol
80g
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3
1 mol
80g
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x =
1 mol
80g
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x =
1 mol
80g2 mol H2O
1 mol NH3NO3
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x =
1 mol
80g2 mol H2O
1 mol NH3NO3
mol H2O
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
1 mol
80g2 mol H2O
1 mol NH3NO3
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
.625 mol H2O
1 mol
80g2 mol H2O
1 mol NH3NO3
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
.625 mol H2O x =
1 mol
80g2 mol H2O
1 mol NH3NO3
g H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
.625 mol H2O x =
1 mol
80g2 mol H2O
1 mol NH3NO3
18 g H2O
1 mol H2Og H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
.625 mol H2O x =
1 mol
80g2 mol H2O
1 mol NH3NO3
18 g H2O
1 mol H2Og H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
.625 mol H2O x = 11.25 g H2O
1 mol
80g2 mol H2O
1 mol NH3NO3
18 g H2O
1 mol H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
.625 mol H2O x = 11.25 g H2O
1 mol
80g2 mol H2O
1 mol NH3NO3
18 g H2O
1 mol H2O
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
.625 mol H2O x = 11.25 g H2O
1 mol
80g2 mol H2O
1 mol NH3NO3
18 g H2O
1 mol H2O
Should have the same
number of significant
digits
NH4NO3 → N2O + 2 H2ODetermine the mass of water produced when
25.0 g of ammonium nitrate decomposes.
25.0g NH4NO3 x = .3125 mol NH4NO3
.3125 mol NH4NO3 x = .625 mol H2O
.625 mol H2O x = 11.3 g H2O
1 mol
80g2 mol H2O
1 mol NH3NO3
18 g H2O
1 mol H2O
Should have the same
number of significant
digits
In-class work:
Solve practice problems 11-14 on pages 360 & 362.
You will be tested tomorrow on problems just like this.
If you need help, now is the time to ask.
.