motor for scribd

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    y-Tarun Goel

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    Contents

    Motor Failures Thermal Protection

    Start/stall protection

    Earth Fault Protection Negative Phase sequence Protection

    Other Protections

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    Motor failures

    Motor Induced Insulation

    Bearing

    Mec anica Load Induced

    Overload

    High Inertia Environment Induced

    High ambient temperature

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    Motor failure (cont..)

    Source Induced Under voltage

    Phase failure/ reversal

    Vo tage un a ance Operation Induced

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    Thermal (overload) protection

    Thermal replica model of a motor is used. The temperature T at any instant t is given by:

    T = Tmax(1-e-t/t

    h)

    = R 1-e

    -

    hCold characteristics

    Hot characteristics

    ( ) =21ln IIt R

    ( )( )( )

    =

    22

    22

    .

    1

    lnB

    P

    IkI

    ICHI

    t

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    Start/stall protection

    A motor may fail to accelerate from rest due to : Loss of a supply phase

    Mechanical problems

    Low supp y vo tage Excessive load torque

    Start time < safe stall time

    Definite time overcurrent protection Start time >= safe stall time

    Definite time overcurrent protection + Speed sensing.

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    Time

    Stalled motor

    Running motor

    thermal withstand

    characteristic

    Current

    Motor

    starting

    characteristi

    c

    characteristic

    start time less than withstand time

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    Time

    Running motor

    thermal withstand

    characteristic

    Current

    Motor

    starting

    characteristi

    c

    Stalled motor

    thermal withstand

    characteristic

    start time greater than withstand time

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    Earth fault protection

    Current is measured with a Residual CT connection andMotor is tripped when this current exceeds the setting.

    A lower limit is imposed by

    System capacitive currents

    Stabilizing Resistor: to prevent operation from the spillcurrent resulting from the unequal CT saturation

    ( )rlctst

    stab RkRRI

    IR ++=0

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    Negative phase sequenceprotection

    Negative phase sequence current is generated due to Unbalanced loading

    Loss of a single phase

    ng e-p ase au s I2 Z2/Z1 = Rated current/Starting Current = 1/6 (usually)

    Also, negative sequence current is at twice supplyfrequency. Hence, heating due to negative sequence is

    much larger than that due to positive sequence. Operating time is generally, inversely proportional tosquare of unbalance.

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    Other protections

    RTDs temperature detection: A rise in temperaturemay denote:

    Hot spot

    ver oa ng

    Beginning of a fault in the affected part.

    Undervoltage protection

    Loss of load Protection

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    Protection of a Sample motor

    A pump using a HV induction motor. Details of the motor :

    Rated O/P : 580 kW

    a e o age : .

    Rated frequency : 50 Hz

    Rated p.f. : 0.91

    Rated efficieny : 95.8%

    Stall withstand time (hot) : 12 secStall withstand time (cold) : 18 sec

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    Details(cont..)Starting Current : 560%

    CT Ratio : 60:1

    tart t me @ 100 vo tage : 2 secStart time @ 80% voltage : 4 sec

    Heating time constant : 4 mins

    Control Device : VC

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    Thermal Protection

    Hot operating characteristics:

    AefficiencypfV

    PIFLC 58

    958.0*91.0*3*6.6

    580

    **3*===

    ( ) 22 1 ICHI

    where, I = relay current

    IB = basic current = full load current = 1pu

    Ip = steady state current prior to load = 1puk = 1.05

    H/C = 18/12

    { } =

    22 ).(og

    B

    e

    IkI

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    Locked Rotor Protection

    Starting Current = 5.6*IN Hence Current Setting = 2*IN

    Start time = 4 sec and safe stall time = 12 sec

    Hence Time Setting = 10 sec

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    Earth Fault Protection

    Current setting = 20% of motor rated Instantaneous protection with a relay inherent time of

    60ms.-

    maloperation due to CT spill current during starting. Calculation of Stabilizing Resistor:

    RCT= 3 Ohm, Rl= 1 Ohm, Rr= 0.2 Ohm

    Hence, Rstab = 140 Ohms.

    ( )2.0*60

    2.01*23*58*6.5 ++=stabR

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    Negative Phase sequence Protection

    The setting current is limited by the followingconsiderations:

    Unbalance in CT secondary currents due to saturation.

    External unbalanced faults which may permit the motorto act as a generator and feed negative sequence currentinto the faults.

    Hence a setting of 20% with a TMS = 1.0 can be used.

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    RTD Protection

    The motor has class F insulation Six resistance thermometers (Pt100) are provided

    within the motor.

    = e . temperature + a owa e temp. r se +allowance for hot spot winding

    = 40C + 105C + 10C

    = 155C

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    THANK YOU