mrs. rivas. (x − 26) + x = 180 x − 26 + x = 180 2x − 26 = 180 2x = 206 x = 103 103 77...
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Homework Mrs. Rivas
Homework Mrs. Rivas
Homework Mrs. Rivas
Homework Mrs. Rivas
Homework Mrs. Rivas
(x − 26) + x = 180
x − 26 + x = 180
2x − 26 = 180 2x =
206x = 103
103
77
Same-side Interior angles
103 + 77 = 180
Homework Mrs. Rivas
Corresponding angles
(3x − 5) = (x + 55)3x − 5 = x +
552x − 5 = 55
2x = 60
x = 303(30) − 5 = 30 + 5590 − 5 = 30 +
55 85 = 85
Homework Mrs. Rivas
(x + 20) + (x + 10) = 180
Linear Pair angles = Suppl.
x + 20 + x + 10 = 180 2x + 30 =
180 2x = 150
x = 75
95 85
95 + 85 = 180
Homework Mrs. Rivas
(y − 40) + y = 180
Linear Pair angles = Suppl.
y − 40 + y = 1802y − 40 =
180 2x = 220x = 110
110
70
110 + 70 = 180
Homework Mrs. Rivas
Alternate Exterior angles(2x + 6) =
422x + 6 = 42 2x =
36x = 18
42
Homework Mrs. Rivas
(3x − 17) + 98 = 1803x − 17 + 98 =
1803x + 81 = 180 3x = 99
x = 33
Same-side Interior angles
82
98 + 82 = 180
Homework Mrs. Rivas
2x + 20 + 6x + 24 = 180 8x + 44 =
180 8x = 136x =
17
Same-side Interior angles(2x + 20) + (6x + 24) = 180
54
126
126 + 54 = 180
Homework Mrs. Rivas
Alternate Exterior angles(2x + 2) = (3x −
63) 2x + 2 = 3x − 63 2x = 3x − 65
− x = − 65
x = 65
132
132
Homework Mrs. Rivas
Linear Pair angles = Suppl.(5x − 5) + 140 =
1805x − 5 + 140 = 1805x + 135 =
180 5x = 45
x = 9
40
140 + 40 = 180
Homework Mrs. Rivas
Same-side Interior angles(4x − 8) + 112 =
1804x − 8 + 112 = 1804x + 104 =
180 4x = 76x =
19
68
112 + 68 = 180
Homework Mrs. Rivas
(7x + 14) + (2x + 4) = 1807x + 14 + 2x + 4 =
180 9x + 18 = 180 9x =
162x = 18
140
40
140 + 40 = 180
Linear Pair angles = Suppl.
Homework Mrs. Rivas
15.
(4x − 5) + (x + 20) = 180
4x − 5 + x + 20 = 180
5x + 15 = 180 5x =
165x = 33
127
53
127 + 53 = 180
Linear Pair angles = Suppl.
Homework Mrs. Rivas
16.
Homework Mrs. Rivas
Algebra Determine the value of for which . Then find and .
17.
Alternate exterior Angles are
𝟏𝟎𝟎 – 𝒙=𝟒𝟎+𝟐 𝒙𝟏𝟎𝟎=𝟒𝟎+𝟑 𝒙𝟔𝟎=𝟑 𝒙𝟐𝟎=𝒙
𝟏𝟎𝟎−𝟐𝟎=𝟖𝟎
𝟒𝟎+𝟐(𝟐𝟎)=𝟖𝟎
Homework Mrs. Rivas
Algebra Determine the value of for which . Then find and .
18.
Alternate exterior Angles are
𝟗𝟎−𝟔 𝒙=𝟏𝟎𝟎−𝟖 𝒙𝟗𝟎+𝟐𝒙=𝟏𝟎𝟎
𝟐 𝒙=𝟏𝟎𝒙=𝟓
𝟗𝟎−𝟔 (𝟓)=𝟔𝟎
𝟏𝟎𝟎−𝟖(𝟓)=𝟔𝟎
Homework Mrs. Rivas
19. Developing Proof Complete the flow proof below.
Given: 1 and 4 are supplementary.
Prove:
Given
Vertical ∠s are ≅
∠2 and ∠3 are supplementary
Converse of same-side Interior Angles
Homework Mrs. Rivas
20. Developing Proof Complete the flow proof below.
Given: and are supplementary;
Prove:
∠2 and ∠3 are supplementary
Give
∠s suppl. to the same ∠ are ≅ ∠1 ≅ ∠4 If corr. ∠s are ≅ lines are