mth55_lec-48_sec_8-1a_sqrt_property.ppt 1 bruce mayer, pe chabot college mathematics bruce mayer, pe...
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MTH55_Lec-48_sec_8-1a_SqRt_Property.ppt 3 Bruce Mayer, PE Chabot College Mathematics The Square Root Property Let’s consider x 2 = 25. We know that the number 25 has two real-number square roots, 5 and −5, which are the solutions to this equation. Thus we see that square roots can provide quick solutions for equations of the type x 2 = k.TRANSCRIPT
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Bruce Mayer, PE Chabot College Mathematics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
Chabot Mathematics
§8.1 Complete§8.1 CompleteThe SquareThe Square
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Bruce Mayer, PE Chabot College Mathematics
Review §Review §
Any QUESTIONS About• §7.7 → Complex Numbers
Any QUESTIONS About HomeWork• §7.7 → HW-30
7.7 MTH 55
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Bruce Mayer, PE Chabot College Mathematics
The Square Root PropertyThe Square Root Property Let’s consider x2 = 25. We know that the number 25 has
two real-number square roots, 5 and −5, which are the solutions to this equation.
Thus we see that square roots can provide quick solutions for equations of the type x2 = k.
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Bruce Mayer, PE Chabot College Mathematics
SQUARE ROOT PROPERTYSQUARE ROOT PROPERTY For any nonzero real number d, and
any algebraic expression u, then the Equation u2 = d has exactly two solutions:
dududu orthen If 2
Alternatively in a ShortHand Notation:
dudu then If 2
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Bruce Mayer, PE Chabot College Mathematics
Example Example Use SqRt Property Use SqRt Property Solve 5x2 = 15. Give exact solutions and
approximations to three decimal places. SOLUTION 25 15x
2 3x
3 or 3.x x
Isolating x2
Using the Property of square roots
The solutions are which round to 1.732 and −1.732.
3Or x ShortHand Notation
3,
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Bruce Mayer, PE Chabot College Mathematics
Example Example Use SqRt Property Use SqRt Property Solve x2 = 108 SOLN
Check
Use the square root principle.
Simplify by factoring out a perfect square.
2 108x 108x
6 3x
Check
6 3 : 26 3 108
Note: Remember the ± means that the two solutions are and .
6 3 6 3
6 3 : 26 3 108
336x
108336 108336
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Bruce Mayer, PE Chabot College Mathematics
Example Example Use SqRt Property Use SqRt Property Solve x2 +14 = 32
SOLN 2 14 32x 2 18x
18x
3 2x
29x
Subtract 14 from both sides to isolate x2
Use the square root property
Simplify by factoring out a perfect square
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Bruce Mayer, PE Chabot College Mathematics
Example Example Use SqRt Property Use SqRt Property Solve (x + 3)2 = 7 SOLN
Using the Property of square roots
The solutions are The check is left for us to do Later
Solving for x
2( 3) 7x
3 7 or 3 7x x
3 7 or 3 7.x x
73Or x ShortHand Notation
3 7.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Use SqRt Property Use SqRt Property Solve 16x2 + 9 = 0 SOLN
The solutions are The check is left for Later
216 9 0x
2 9/16x
Recall that 1 .i
169or169 xx
ixix43or
43
i43
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Bruce Mayer, PE Chabot College Mathematics
Solving Quadratic EquationsSolving Quadratic Equations To solve equations in the form ax2 = b, first
isolate x2 by dividing both sides of the equation by a.
Solve an equation in the form ax2 + b = c by using both the addition and multiplication principles of equality to isolate x2 before using the square root principle
In an equation in the form (ax + b)2 = c, notice the expression ax + b is squared. Use the square root principle to eliminate the square.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Use SqRt Property Use SqRt Property Solve (5x − 3)2 = 4 SOLN
Add 3 to both sides and divide each side by 5, to isolate x.
Use the square root property
25 3 4x
5 3 4x
or
5 3 2x 2 35
x
2 35
x
2 35
x
1x 15
x or
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Bruce Mayer, PE Chabot College Mathematics
Completing the SquareCompleting the Square Not all quadratic equations can be
solved as in the previous examples. By using a method called
completing the square, we can use the principle of square roots to solve any quadratic equation
To Complete-the-Sq we Add ZERO to an expression or equation
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Bruce Mayer, PE Chabot College Mathematics
Example Example Complete the Sq Complete the Sq Solve x2 + 10x + 4 = 0 SOLN:
2( 5) 21x
2 10 4 0x x 2 10 4x x
x2 + 10x + 25 = –4 + 25
5 21 or 5 21x x
5 21.
Using the property of square roots
Factoring
Adding 25 to both sides.
The solutions are The check is left for Later
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Bruce Mayer, PE Chabot College Mathematics
Solving Quadratic Equations Solving Quadratic Equations by Completing the Squareby Completing the Square Write the equation in the form 11·x2 + bx = c. Complete the square by adding (b/2)2 to both
sides.• (b/2)2 is called the “Quadratic Supplement”
Write the completed square in factored form. Use the square root property to eliminate the
square. Isolate the variable. Simplify as needed.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Complete the Sq Complete the Sq Solve by Completing the Square:
2x2 − 10x = 9 SOLN:
Divide both sides by 2.
2 952
x x Simplify.
Add to both sides to complete the square.
22 10 9x x 22 10 9
2 2x x
2 25 9 2554 2 4
x x 254
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Bruce Mayer, PE Chabot College Mathematics
Example Example Complete the Sq Complete the Sq Solve 2x2 − 10x = 9 SOLN:
Combine the fractions.
Factor.
Add to both sides and simplify the square root.
52
Use the square root principle.
443
425
418
25 2
x
443
25
x
243
25
x
2435
x
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Bruce Mayer, PE Chabot College Mathematics
Example Example Complete the Sq Complete the Sq Solve by Completing the Square:
3x2 + 7x +1 = 0 SOLUTION: The coefficient of the x2
term must be 11. When it is not, multiply or divide on both sides to find an equivalent eqn with an x2 coefficient of 1.
23 7 1 0x x
1 13 3
23 7 1 0 x x Divide Eqn by 3
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Bruce Mayer, PE Chabot College Mathematics
Example Example Complete the Sq Complete the Sq Solve: 3x2 + 7x +1 = 0 SOLN: 2 7 1 0
3 3x x
2 7 1 3 3
x x
2 49 4936
7 13 3 36
x x
27 12 496 36 36
x
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Bruce Mayer, PE Chabot College Mathematics
Example Example Complete the Sq Complete the Sq Solve: 3x2 + 7x +1 = 0 SOLN:
7 37 7 37 or 6 6 6 6
x x
27 376 36
x
7 37 7 37 or 6 6 6 6
x x
27 376 36
x
Square Root Property
Isolatex
Taking the Square Root of Both Sides
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Bruce Mayer, PE Chabot College Mathematics
Example Example Taipei 101 Tower Taipei 101 Tower The Taipei 101 tower in Taiwan is 1670
feet tall. How long would it take an object to fall to the ground from the top?
Familiarize: A formula for Gravity-Driven FreeFall with negligible air-drag is s = 16t2 • where
– s is the FreeFall Distance in feet – t is the FreeFall Time in seconds
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Bruce Mayer, PE Chabot College Mathematics
Example Example Taipei 101 Tower Taipei 101 Tower Translate: We know the distance is
1670 feet and that we need to solve for tSub 1670 for s → 1670 = 16t2
CarryOut: 1670 = 16t2
2167016
t
1670 1670 or 16 16
t t
10.2 or 10.2 t t
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Bruce Mayer, PE Chabot College Mathematics
Example Example Taipei 101 Tower Taipei 101 Tower Check: The number −10.2 cannot be a
solution because time cannot be negative.• Check t = 10.2 in formula:
s = 16(10.2)2 = 16(104.04) = 1664.64– This result is very close to the 1670 value.
State. It takes about 10.2 seconds for an object to fall to the ground from the top of the Taipei 101 tower.
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Bruce Mayer, PE Chabot College Mathematics
Compound InterestCompound Interest After one year, an amount of money P,
invested at 4% per year, is worth 104% of P, or P(1.04). If that amount continues to earn 4% interest per year, after the second year the investment will be worth 104% of P(1.04), or P(1.04)2. This is called compounding interest since after the first period, interest is earned on both the initial investment and the interest from the first period. Generalizing, we have the following.
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Bruce Mayer, PE Chabot College Mathematics
Compound Interest FormulaCompound Interest Formula If an amount of money P is
invested at interest rate r, compounded annually, then in t years, it will grow to the amount A as given by the Formula
• Note that r is expressed as a DECIMAL
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Bruce Mayer, PE Chabot College Mathematics
Example Example Compound Interest Compound Interest Tariq invested $5800 at an interest rate
of r, compounded annually. In two years, it grew to $6765.
What was the interest rate? Familiarize: This is a compound
interest calculation and we are already familiar with the compound-interest formula.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Compound Interest Compound Interest Translate The translation consists of
substituting into the Interest formula
(1 )tA P r 6765 = 5800(1 + r)2
CarryOut: Solve for r6765/5800 = (1 + r)2
6765/5800 1 r
1 6765/5800 r
.08 or 2.08r r
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Bruce Mayer, PE Chabot College Mathematics
Example Example Compound Interest Compound Interest Check: Since the interest rate can NOT
negative, we need only to check 0.08 or 8%.
If $5800 were invested at 8% compounded annually, then in 2 yrs it would grow to 5800·(1.08)2, or $6765. • The number 8% checks.
State: Tariq’s interest rate was 8%.
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Bruce Mayer, PE Chabot College Mathematics
Solving FormulasSolving Formulas Recall that to solve a formula for a
certain letter-variable, we use the principles for solving equations to isolate that letter-variable alone on one side of the Equals-Sign• The Bernoulli
Equation for an InCompressibleFluid:
CgPz
gV
2
2
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Bruce Mayer, PE Chabot College Mathematics
Example Example Solve Solve 21 5 for .2
D n n n
SOLN 21 52
D n n
22 5D n n Multiplying both sides by 2
Complete the Square
Express LHS as Perfect Square
222
252
255
Dnn
4258
4252
25 2
DDn
Solve Using Square Root Principle2
2585
Dn
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Bruce Mayer, PE Chabot College Mathematics
Solve a Formula for a Letter – Say, Solve a Formula for a Letter – Say, bb1. Clear fractions and use the principle of powers,
as needed. Perform these steps until radicals containing b are gone and b is not in any denominator.
2. Combine all like terms.3. If the only power of b is b1, the equation can be
solved without using exponent rules.4. If b2 appears but b does not, solve for b2 and
use the principle of square roots to solve for b.5. If there are terms containing both b and b2,
put the equation in standard form and Complete the Square.
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WhiteBoard WorkWhiteBoard Work
Problems From §8.1 Exercise Set• 22, 44, 56, 78, 88
Solve ax2 + bx + c = 0 by completing the square:
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Bruce Mayer, PE Chabot College Mathematics
All Done for TodayAll Done for Today
Taipei 101Tower
Taipei, R.o.C.
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Bruce Mayer, PE Chabot College Mathematics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
Chabot Mathematics
AppendiAppendixx
–
srsrsr 22
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Bruce Mayer, PE Chabot College Mathematics
Graph Graph yy = | = |xx|| Make T-table
x y = |x |-6 6-5 5-4 4-3 3-2 2-1 10 01 12 23 34 45 56 6
x
y
-6
-5
-4
-3
-2
-1
0
1
2
3
4
5
6
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file =XY_Plot_0211.xls
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Bruce Mayer, PE Chabot College Mathematics
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