narayana aipmt 2008 solution

7/26/2019 Narayana Aipmt 2008 Solution

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CBSE-PMT (PRELIMS) : 2008 ANSWER KEY

1. (4) (2) (3) (4)

2. (3) (1) (3) (2)3. (4) (4) (4) (2)

4. (1) (3) (3) (4)

5. (3) (2) (4) (4)

6. (4) (4) (3) (2)

7. (2) (1) (4) (4)

8. (2) (1) (3) (4)

9. (2) (1) (2) (3)

10. (2) (3) (1) (2)

11. (3) (3) (3) (4)

12. (3) (3) (1) (1)

13. (2) (3) (3) (1)

14. (4) (3) (4) (1)15. (3) (2) (3) (1)

16. (1) (4) (4) (3)

17. (3) (1) (4) (3)

18. (4) (3) (1) (4)

19. (1) (2) (2) (1)

20. (3) (4) (3) (3)

21. (4) (3) (3) (2)

22. (1) (3) (2) (4)

23. (1) (2) (3) (2)

24. (2) (4) (1) (2)

25. (4) (1) (2) (4)

26. (3) (1) (2) (4)

27. (2) (4) (4) (1)28. (2) (3) (3) (1)

29. (3) (2) (3) (1)

30. (1) (1) (4) (3)

31. (2) (2) (4) (3)

32. (1) (4) (4) (3)

33. (4) (2) (3) (2)

34. (3) (4) (2) (2)

35. (2) (1) (2) (2)

36. (1) (1) (1) (3)

37. (2) (4) (4) (3)

38. (4) (4) (4) (3)

39. (4) (3) (3) (4)40. (4) (1) (4) (1)

41. (1) (3) (4) (2)

42. (2) (2) (3) (3)

43. (4) (1) (2) (3)

44. (4) (2) (4) (1)

45. (1) (2) (1) (4)

46. (2) (3) (2) (2)

47. (1) (1) (2) (4)

48. (1) (1) (4) (1)

49. (4) (2) (2) (2)

50. (3) (3) (4) (2)

51. (2) (2) (3) (2)

52. (4) (2) (4) (1)53. (3) (2) (2) (3)

54. (2) (4) (4) (3)

55. (4) (2) (1) (4)

56. (2) (1) (4) (2)

57. (1) (1) (2) (4)

58. (2) (4) (1) (3)

59. (4) (4) (1) (4)

60. (4) (4) (2) (3)

61. (2) (3) (3) (2)

62. (3) (4) (4) (2)

63. (4) (1) (1) (2)

64. (4) (2) (4) (2)65. (3) (3) (4) (3)

66. (1) (3) (2) (4)

67. (4) (3) (1) (2)

68. (3) (1) (3) (1)

69. (3) (2) (3) (4)

70. (3) (1) (3) (1)

71. (2) (3) (2) (3)

72. (1) (2) (4) (2)

73. (4) (4) (4) (1)

74. (4) (3) (2) (4)

75. (2) (2) (1) (1)

76. (4) (1) (3) (2)

77. (1) (3) (3) (3)78. (4) (2) (1) (2)

79. (1) (2) (1) (1)

80. (4) (4) (1) (4)

81. (1) (1) (2) (1)

82. (3) (2) (4) (4)

83. (1) (1) (1) (1)

84. (3) (4) (1) (2)

85. (3) (3) (3) (4)

86. (3) (2) (3) (4)

87. (4) (2) (2) (4)

88. (2) (1) (4) (1)

89. (2) (2) (3) (3)90. (2) (2) (4) (2)

91. (1) (1) (4) (3)

92. (3) (4) (2) (4)

93. (2) (2) (3) (2)

94. (4) (2) (1) (1)

95. (2) (2) (4) (4)

96. (1) (4) (4) (4)

97. (2) (1) (1) (1)

98. (1) (4) (4) (2)

99. (3) (1) (3) (2)

100. (2) (1) (3) (1)

101. (3) (3) (1) (4)

102. (2) (4) (1) (3)103. (3) (1) (1) (4)

104. (1) (1) (1) (4)

105. (4) (1) (3) (1)

106. (1) (4) (3) (2)

107. (2) (4) (4) (4)

108. (3) (3) (2) (3)

109. (4) (3) (3) (4)

110. (2) (2) (2) (2)

111. (3) (1) (4) (1)

112. (2) (2) (3) (2)

113. (2) (2) (1) (1)

114. (3) (1) (1) (3)115. (3) (1) (4) (4)

116. (3) (2) (4) (4)

117. (3) (1) (4) (1)

118. (4) (1) (2) (4)

119. (3) (4) (1) (2)

120. (1) (2) (2) (3)

121. (1) (3) (4) (4)

122. (2) (3) (1) (2)

123. (1) (4) (3) (4)

124. (2) (1) (1) (1)

125. (2) (1) (4) (1)

126. (3) (2) (4) (1)

127. (2) (1) (2) (4)128. (4) (1) (3) (4)

129. (2) (3) (1) (3)

130. (3) (3) (3) (1)

131. (4) (4) (4) (1)

132. (3) (3) (4) (1)

133. (3) (2) (3) (3)

134. (2) (4) (1) (3)

135. (3) (4) (1) (1)

136. (3) (1) (2) (3)

137. (3) (2) (2) (1)

138. (4) (4) (3) (1)

139. (4) (3) (4) (3)140. (2) (3) (3) (3)

141. (3) (3) (2) (4)

142. (2) (1) (1) (1)

143. (4) (2) (2) (4)

144. (3) (2) (2) (4)

145. (1) (2) (2) (1)

146. (3) (3) (2) (1)

147. (1) (1) (3) (4)

148. (4) (1) (3) (3)

149. (2) (4) (4) (1)

150. (1) (1) (3) (4)

151. (2) (4) (1) (3)

152. (4) (2) (1) (2)153. (1) (1) (4) (3)

154. (2) (4) (3) (3)

155. (1) (3) (1) (3)

156. (2) (1) (1) (2)

157. (1) (2) (4) (1)

158. (3) (4) (3) (1)

159. (4) (3) (3) (1)

160. (1) (4) (2) (3)

161. (3) (2) (4) (2)

162. (2) (1) (4) (1)

163. (2) (2) (3) (2)

164. (1) (3) (3) (1)165. (3) (2) (1) (4)

166. (1) (2) (3) (1)

167. (4) (3) (1) (2)

168. (1) (4) (2) (2)

169. (2) (3) (2) (4)

170. (2) (3) (3) (3)

171. (4) (3) (3) (4)

172. (4) (2) (1) (4)

173. (1) (1) (1) (4)

174. (3) (3) (1) (4)

175. (2) (1) (4) (4)

176. (2) (2) (2) (2)

177. (4) (1) (4) (4)178. (4) (1) (3) (1)

179. (3) (1) (2) (1)

180. (1) (4) (4) (2)

181. (2) (1) (4) (1)

182. (3) (2) (1) (1)

183. (2) (3) (3) (3)

184. (2) (4) (1) (1)

185. (3) (3) (4) (4)

186. (4) (1) (3) (2)

187. (1) (3) (2) (4)

188. (4) (4) (4) (2)

189. (3) (4) (2) (3)190. (2) (2) (4) (4)

191. (1) (1) (3) (2)

192. (3) (3) (1) (2)

193. (2) (2) (2) (1)

194. (1) (4) (2) (4)

195. (1) (1) (4) (4)

196. (4) (3) (3) (2)

197. (2) (1) (2) (4)

198. (3) (4) (1) (3)

199. (2) (3) (1) (2)

200. (4) (4) (3) (3)

Q. CODE

No. A B C D

Q. CODE

No. A B C D

Q. CODE

No. A B C D

Q. CODE

No. A B C D

Janak Puri: A-1/171 A, Janakpuri, N.D. 58,. Ph.: 41576123/24/25: South Extn.: F-38, South Extension-I, New Delhi-49, Ph.: 46052731/32;Rohini Centre : D-11/141, Sector - 8, Rohini, New Delhi - 110085, Phone : 47016398/99: Rohtak Centre : SCF-1, HUDA Complex,

Rohtak, Haryana: Tel.: 9255321118/1119: Head Office.: Vittalwadi, Narayanaguda, Hyderabad-500 029, Ph.: 23220400, 23226800

k i ih lhi h /

NARAYANAGROUP OF EDUCATIONAL INSTITUTIONS

ACODE


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[1 ] CBSE PMT - 2008 Prelims Paper (Code - A) with H in ts & Solutions

NARAYANA INSTITUTE :A-1/171 A, Janak Puri, N.D.58; Ph.: 011-41576123/24/25; F-38, South Extn.-I, N.D.-49; D-11/141, Sec.-8, Rohini, N.D.-85;

NARAYANA INSTITUTE OF CORRESPONDENCE COURSES : 63 FNS House, K.S. Market, Sarvpriya Vihar, New Delhi-110016; Ph.:011-46080617/18

Head Office.:Vittalwadi, Narayanaguda, Hyderabad-29www.narayanadelhi.com, www.narayanaicc.com, www.narayanaonline.com, e-mail : [email protected]

CBSE-PMT : 2008 (PRELIMS)

PAPER WITH HINTS & SOLUTIONSPHYSICS

1. Which two of the following five physical parametershave the same dimensions ?

(a) Energy density (b) Refractive index

(c) Dielectric constant (d) Youngs modulus

(e) magnetic field

(1) (a) and (e) (2) (b) and (d)

(3) (c) and (e) (4) (a) and (d)

Sol.(4) [Energy density] = 3 3 3[W] [F].[L] [F]

L [L ][L] [L ]= = = [P]

= [Y]

2. If the error in the measurement of radius of a sphereis 2 %, then the error in the determination of volumeof the sphere will be

(1) 2 %

(2) 4 %

(3) 6 %(4) 8 %

Sol.(3) 3V R

V 3 R

V R

=

3. The distance travelled by a particle starting from restand moving with an acceleration 4/3 ms2, in the thirdsecond is

(1)

19m

3 (2) 6 m

(3) 4 m (4)10

m3

Sol.(4) rd31

S u a(2n 1)2

= +

=1 4 10

0 (6 1) m2 3 3

+ =

4. A particle moves in a straight line with a constantacceleration. It changes its velocity from 10 ms1to20 ms1while passing through a distance 135 m in tsecond. The value of t is

(1) 9

(2) 10

(3) 1.8(4) 12

Sol.(1) Using v2 u2= 2as

202 102 = 2 a 135

300 10a

270 9= =

Using v u = at

20 10 =10

9

t

t = 9 sec

5. A particle shows distance-time curve as given in thisfigure. The maximum instantaneous velocity of theparticle is around the point

Timet

Dis

tance

S

A B

C

D

(1) A (2) B

(3) C (4) D

Sol.(3) V maximum velocity point means point at which

dx

dt= slope is maximum

C

NARAYANAGROUP OF EDUCATIONAL INSTITUTIONSA

CODE


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[2 ] CBSE PMT - 2008 Prelims Paper (Code - A) with H ints & Solutions

6. A particle of mass m is projected with velocity v makingan angle of 45 with the horizontal. When the particleland on the level ground the magnitude of the changein its momentum will be

(1) Zero (2) 2 mv

(3) mv / 2 (4) mv 2

Sol.(4) p m(v u) = ! ! !

| p | |mv[cos45i sin45 j] mv(cos45i sin45 j) | = +!

= 2 mv sin 45 = 2 mv

7. Sand is being dropped on a conveyor belt at the rateof M kg/s. The force necessary to keep the beltmoving with a constant velocity of v m /s will be

(1) Zero (2) Mv newton

(3) 2 Mv newton (4) Mv / 2 newton

Sol.(2)d(mv) dm

F vdt dt

= =

as V = constant

F = Mv8. Three forces acting on a body are shown in the figure.

To have the resultant force only along the y-direction,the magnitude of the minimum additional force neededis

30

60

1N

2N

4N

y

x

(1) 3N (2) 0.5 N

(3) 1.5 N (4)3

4N

Sol.(2) Frequired= [x component of res. force]

now, res F (4 2)(cos 30 j sin 30i)=

!

1(cos60i sin60j)+ +

reqd1 1 F i i i2 2

= + =

!

9. Water falls from a height of 60 m at the rate of 15 kg/s to operate a turbine. The losses due to frictionalforces are 10 % of energy. How much power isgenerated by the turbine ? (g = 10 m/s2)

(1) 7.0 kW (2) 8.1 kW

(3) 10.2 kW (4) 12.3 kW

Sol.(2) generated input90

P P100

=

=Mgh 90

t 100

= 15 10 60 901 100

= 8.1 KW

10. A shell of mass 200 gm is ejected from a gun of mass4 kg by an explosion that generates 1.05 kJ of energy.The initial velocity of the shell is

(1) 120 ms1 (2) 100 ms1

(3) 80 ms1 (4) 40 ms1

Sol.(2) 4V + 0.2 v = 0 ..... (1)

12 4 V2+ 12 0.2 v

2= 1050 ..... (2)

Solving (1) and (2)

v = 100 m/s

11. The ratio of the radii of gyration of a circular disc tothat of a circular ring, each of same mass and radius,around their respective axes is

(1) 2 : 3 (2) 3 : 2

(3) 1 : 2 (4) 2 : 1

Sol.(3)

2ringdisc

2ring disc

IK mr1K I mr2

= =

ring

disc

K 1

K 2=

12. Thin rod of length L and mass M is bent at its midpointinto two halves so that the angle between them is90. The moment of inertia of the bent rod about anaxis passing through the bending point and

perpendicular to the plane defined by the two halvesof the rod is

(1)22ML

24(2)

2ML

24

(3)2ML

12(4)

2ML

6


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Sol.(3)2

1 M LI 2

3 2 2

=

=2ML

12

L

M

M2

L2

,

axis

M2

L2

,

13. A roller coaster is designed such that riders experienceweightlessness as they go round the top of a hillwhose radius of curvature is 20 m. The speed of thecar at the top of the hill is between

(1) 13 m/s and 14 m/s (2) 14 m/s and 15 m/s

(3) 15 m/s and 16 m/s (4) 16 m/s and 17 m/s

Sol.(2)2

MV MgR

=

V Rg=

N = 0MV /R

2

Mg

V 20 10=

= 14.14 m/s

14. If Q, E and W denote respectively the heat added,change in internal energy and the work done in a closedcycle process, then

(1) Q = 0 (2) W = 0

(3) Q = W = 0 (4) E = 0Sol.(4) For a cyclic process U 0 = or E = 0

15. On a new scale of temperature (which is linear) andcalled the W scale, the freezing and boiling points ofwater are 39W and 239W respectively. What willbe the temperature on the new scale, correspondingto a temperature of 39C on the Celsius scale ?

(1) 139W (2) 78W

(3) 117W (4) 200W

Sol.(3)true faulty

t LFP t LFP

UFP LFP UFP LFP

=

39 C 0 C t 39 W

100 C 0 239 W 39 W

=

t = 117W

16. At 10C the value of the density of a fixed mass ofan ideal gas divided by its pressure is x. At 110C thisratio is

(1)283

x383

(2) x

(3)383

x283

(4)10

x110

Sol.(1) PV = nRT0

PV 1RT

m M=

0

P RT

M=

1

P T

1 1 2

2 2 1

/ P T

/ P T

=

2 2

x 383K

( / P ) 283K =

2

2

283x

P 383

=

17. Two Simple Harmonic Motions of angular frequency100 and 1000 rad s1have the same displacement

amplitude. The ratio of their maximum accelerationis

(1) 1 : 104 (2) 1 : 10

(3) 1 : 102 (4) 1 : 103

Sol.(3) 2maxa A=

1

2

2max 1

2max 2

a( A is same)

a

=

"

=

2

2 2

(100) 1

(1000) 10=

18. The wave described by y = 0.25 sin (10 x 2 t) ,where x and y are in meters and t in seconds, is awave travelling along the

(1) Negative x direction with amplitude 0.25 m andwavelength = 0.2 m

(2) Negative x direction with frequency 1 Hz

(3) Positive x direction with frequency Hz andwavelength = 0.2 m

(4) Positive x direction with frequency 1 Hz andwavelength = 0.2 m

Sol.(4) 0.25sin(10 x 2 t)=

as t and kx have opposite sign wave travels alongpositive x.

as 2 t t =

f 1Hz= (4) is correct


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19. A point performs simple harmonic oscillation of periodT and the equation of motion is given by

x asin(wt 6)= + . After the elapse of what fractionof the time period the velocity of the point will beequal to half of its maximum velocity

(1) T/12 (2) T/8

(3) T/6 (4) T/3

Sol.(1) x a sin t6= +

dxV a cos t

dt 6

= = +

aa cos t

2 6

= +

1cos t

2 6

= +

t

6 3

+ = t

6

=

2t

T 6

= t =

T

1220. Two points are located at a distance of 10 m and 15

m from the source of oscillation. The period ofoscillation is 0.05 sec and the velocity of the wave is300 m/sec. What is the phase difference betweenthe oscillation of two points ?

(1)6

(2)

3

(3) 23 (4)

Sol.(3) X 15m 10m 5m = =

T = 0.05 sec1

20Hz0.05

= =v

v = 300 m/sv 300

15m20

= = =v

x 5 2

2 15 2 3

= = =

21. The velocity of electromagnetic radiation in a medium

of permittivity 0 and permeability 0is given by

(1)0

0

(2)

0

0

(3) 0 0 (4)0 0

1

Sol.(4)0 0

1v

=

a standard formula

22. Two periodic waves of intensities I1 and I2 passthrough a region at the same time in the same direction.The sum of the maximum and minimum intensities is

(1) 2(I1+ I2)

(2) I1+ I2

(3) ( )2

1 2I I+

(4) ( )2

1 2I I

Sol.(1) ( )2

max 1 2I I I= +

( )2

min 1 2I I I=

( ) ( )2 2

max min 1 2 1 2I I I I I I+ = + +

= 2(I1+ I2)

23. Two thin lenses of focal lengths f1and f2are in contactand coaxial. The power of the combination is

(1)1 2

1 2

f f

f f

+(2)

1

2

f

f

(3)2

1

f

f (4)1 2f f

2

+

Sol.(1)1 2

1 1 1Feq f f

= +

1 2eq

1 2

f fP

f f

+=

24. A boy is trying to start a fire by focusing sunlight on apiece of paper using an equiconvex lens of focal length10 cm. The diameter of the sun is 1.39 109m andits mean distance from the earth is 1.5 1011m. Whatis the diameter of the suns image on the paper ?

(1) 12.4 10

4

m (2) 9.2 10

4

m(3) 6.5 104m (4) 6.5 105m

Sol.(2)1 v

O u= O = 1.39 109m

v = 0.1m

u = 1.5 1011m

putting

I = 9.2 104m


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25. The energy required to charge a parallel platecondenser of plate separation d and plate area ofcross-section A such that the uniform electric fieldbetween the plates is E, is

(1)2

01

E Ad2

(2)

2

0

1

E / A.d2

(3) 20E / Ad

(4) 20E Ad

Sol.(4) Energy of charged capacitor =1

2CV2

Energy given by cell = CV2

= ( )20A Ed

d

= 20A E d

26. A Thin conducting ring of radius R is given a charge+Q. The electric field at the centre O of the ring dueto the charge on the part AKB of the ring is E. Theelectric field at the centre due to the charge on thepart ACDB of the ring is

B

A

C

D

K

O

(1) 3E along OK

(2) 3E along KO

(3) E along OK

(4) E along KO

Sol.(3)

totalE 0=!

AKB ACDBE E 0+ =! !

ACDB AKBE E= ! !

ACDBE =!

E along OK

27. The electric potential at a point in free space due to acharge Q coulomb is Q 1011volts. The electric fieldat the point is

(1) 22012 Q 10 volt / m

(2) 2204 Q 10 volt / m

(3) 20012 Q 10 volt / m

(4) 2004 Q 10 volt / m

Sol.(2)0

1 QV

4 r=

20

1 QE

4 r=

2 2 220

04 V Q 10

E 4Q Q

= =

E = 2204 Q 10 volt / m

28. A cell can be balanced against 110 cm and 100 cm ofpotentiometer wire, respectively with and withoutbeing short circuited through a resistance of 10 ohm.Its internal resistance is

(1) Zero

(2) 1.0 ohm

(3) 0.5 ohm

(4) 2.0 ohm

Sol.(2) 1E l 2ER

r R

+l

1

2

r R

R

+=

l

l

r1 1.1

R+ =

r = 1 ohm

29. A wire of a certain material is stretched slowly by

ten per cent. Its new resistance and specificresistance become respectively

(1) 1.1 times, 1.1 times

(2) 1.2 times, 1.1 times

(3) 1.21 times, same

(4) Both remain the same

Sol.(3) Specific resistance remain same while resistancechange.


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30. In the circuit shown, the current through the 4 ohmresistor is 1 amp when the points P and M areconnected to a d.c. voltage source. The potentialdifference between the points M and N is

N

MP

!"

#"

$%&"

$%&"

'"

(1) 3.2 volt (2) 1.5 volt

(3) 1.0 volt (4) 0.5 volt

Sol.(1) VPM= 1 A 4 ohm = 4 volt

So MN 1V 4 volt1 0.25=

+ = 3.2 volt

31. An electric kettle takes 4A current at 220 V. Howmuch time will it take to boil 1 kg water fromtemperature 20C ? The temperature of boiling wateris 100C

(1) 4.2 min (2) 6.3 min

(3) 8.4 min (4) 12.6 min

Sol.(2) V I t ms t=

ms t 1 4200 80t VI 220 4 = = = 6.3 min

32. A current of 3 amp flows through the 2 ohm resistorshown in the circuit. The power dissipated in the 5ohm resistor is

!"

("

'" &"

(1) 5 watt (2) 4 watt

(3) 2 watt (4) 1 watt

Sol.(1) voltage across 2 ohm, v = 3 2 = 6 volt

So current across 5 ohm =6v

1 5 + = 1A

Power across 5 ohm = P = I2R = (1)2 5 ohm

= 5 watt

33. A particle of mass m, charge Q and kinetic energy Tenters a transverse uniform magnetic field of induction

B!

. After 3 seconds the kinetic energy of the particle

will be

(1) 4 T (2) 3 T

(3) 2 T (4) T

Sol.(4) Magnetic field can never increase the energy of

a charge particle so its kinetic energy will remainT.

34. A closed loop PQRS carrying a current is placed in auniform magnetic field. If the magnetic forces onsegments PS, SR and RQ are F1, F2 and F3respectively and are in the plane of the paper andalong the directions shown, the force on the segmentQP is

Q

RS

P

F3

F3

F1

(1) F3 F1+ F2 (2) F3 F1 F2

(3) 2 23 1 2(F F ) F + (4)2 2

3 1 2(F F ) F

Sol.(3) Force on QP will be equal and opposite to sum offorces on other 3 sides

F3

F2

F1

So 2 2QP 3 1 2F (F F ) F= +

35. A circular disc of radius 0.2 meter is placed in a

uniform magnetic field of induction 21 b

m

in such

a way that its axis makes an angle of 60 With B!

.The

magnetic flux linked with the disc is

(1) 0.01 b (2) 0.02 b

(3) 0.06 b (4) 0.08 b

Sol.(2)21BScos (0.2) cos60 0.02 b = = =


8/27





36. A galvanometer of resistance 50 is connected to abattery of 3V along with a resistance of 2950 inseries. A full scale deflection of 30 divisions is obtainedin the galvanometer. In order to reduced this deflectionto 20 divisions, the resistance in series should be

(1) 4450 (2) 5050

(3) 5550 (4) 6050

Sol.(1) Current through galvanometer

33VI 10 Amp50 2950

= = +

Current for 30 division = 103Amp

Current for 20 division =3

310 220 10 Amp30 3

=

32 310 R 44503 50 R

= = +

37. Curie temperature is the temperature above which(1) Ferromagnetic material becomes diamagnetic

material

(2) Ferromagnetic material becomes paramagneticmaterial

(3) Paramagnetic material becomes diamagneticmaterial

(4) Paramagnetic material becomes ferromagneticmaterial

Sol.(2) According to curie-weisis law, susceptisicitry of

ferromagnetic substance varies with absolute

temperature as nC

1X

(T T )

, but for

paramagnetic substance n1

XT

. So after Tc i.e.

curie temperature every ferromagnetic substancebehaves like paramagnetic.

38. A long solenoid has 500 turns. When a current of 2ampere is passed through it, the resulting magneticflux linked with each turn of the solenoid is 4 103 b .The self-inductance of the solenoid is

(1) 4.0 henry (2) 2.5 henry

(3) 2.0 henry (4) 1.0 henry

Sol.(4) Net flux through solenoid

3500 4 10 2 b = =

LI 2 b L 2Amp L 1 = = = henry

39. In an a.c. circuit the e.m.f. (e) and the current (i) atany instant are given respectively by

0e E sin t=

0i I sin( t )=

The average power in the circuit over one cycle ofa.c. is

(1) E0I0 (2) 0 0E I2

(3) 0 0E I

sin2

(4) 0 0E I

cos2

Sol.(4) av 0 01

P E I cos2

=

40. In the phenomenon of electric discharge throughgases at low pressure, the colored glow in the tube apears as a result of

(1) Collision between different electrons of the atoms

of the gas(2) Excitation of electrons in the atoms

(3) Collision between the atoms of the gas

(4) Collisions between the charged particles emittedfrom the cathode and the atoms of the gas

Sol.(4) Theoretical

41. The work function of a surface of a photosensitivematerial is 6.2 eV. The wavelength of the incidentradiation for which the stopping potential is 5 V lies inthe

(1) X-ray region

(2) Ultraviolet region

(3) Visible region

(4) Infrared region

Sol.(1) KEmax= hv

or maxhv KE= +

= 5 ev + 6.2 ev

= 11.2 ev (lies in x rays)

42. A particle of mass 1 mg has the same wavelength asan electron moving with a velocity of 3 106ms1.

The velocity of the particle is

(1) 2.7 1021ms 1 (2) 2.7 1018ms 1

(3) 9 102ms 1 (4) 3 1031ms 1

(Mass of electron = 9.1 1031kg)

Sol.(2) meve= mv

v = e em v

m


9/27





43. The ground state energy of hydrogen atom is 13.6eV. When its electron is in the first excited state, itsexcision energy is

(1) 0

(2) 3.4 eV

(3) 6.8 eV

(4) 10.2 eV

Sol.(4) E1= 13.6 eV

E2=13.6

4ev

2 1E E E =

44. Two radioactive materials X1 and X2 have decayconstants 5 and repetitively. If initially they havethe same number of nuclei, then the ratio of the numberof nuclei of X1to that X2will be 1/e after a time

(1)e

(2)

(3)1

2 (4)

1

4

Sol.(4)5 t

4 t1 t

2

N 1 ee

N e e

= = =

1 4 t=

or t =1

4

45. Two nuclei have their mass numbers in the ratio of 1 : 3.Then ratio of their nuclear densities would be

(1) 1 : 1

(2) 1 : 3

(3) 3 : 1

(4) (3)1/3: 1

Sol.(1) Density is independent of mass number.

46. If M (A; Z), Mp and Mn denote the masses of the

nucleus AZ X

, proton and neutron respectively in units

of u (1u = 931.5 MeV/C2) and BE represents itsbonding energy in MeV, then

(1) M(A, Z) = ZMp+ (A Z) Mn + BE / C2

(2) M(A, Z) = ZMp+ (A Z) Mn BE / C2

(3) M(A, Z) = ZMp+ (A Z) Mn + BE

(4) M(A, Z) = ZMp+ (A Z) Mn BE

Sol.(2) Theoretical

47. The voltage gain of an amplifier with 9 % negativefeedback is 10. The voltage gain without feedbackwill be

(1) 100 (2) 90

(3) 10 (4) 1.25

Sol.(1) Voltage gain =v

Av

1 A+

10 =v

Av

1 9 /100A+

v10

A 1000.1

= =

48. If the lattice parameter for a crystalline structure is3.6 , then the atomic radius in fcc Crystal is

(1) 1.27

(2) 1.81(3) 2.10

(4) 2.92

Sol.(1) 4 r = 2a

2a

r4

=

49. The circuit

NOR NAND NOT

is equivalent to

(1) OR gate

(2) AND gate

(3) NAND gate

(4) NOR gate

Sol.(4) Theoretical

50. A p-n photodiode is made of a material with a bandgap of 2.0 eV. The minimum frequency of the radiationthat can be absorbed by the material is nearly

(1) 20 1014Hz(2) 10 1014Hz

(3) 5 1014Hz

(4) 1 1014Hz

Sol.(3) 2 ev = hv

2ev

h =


10/27





CHEMISTRY

51. If uncertainty in position and momentum are equal,then uncertainty in velocity is :

(1)h

(2)

1 h

2m

(3)h

2 (4)1 h

m

Sol : (2)h

x p4

=

2 hp4

=

1 hp

2 =

1 hv

2m =

52. If a gas expands at constant temperature, it indicatesthat:

(1) Number of the molecules of gas increases

(2) Kinetic energy of molecules decreases(3) Pressure of the gas increases(4) Kinetic energy of molecules remains the same

Sol : (4) Avg. K.E.3

RT2

=

At. const. temperature K.E. remains constant

53. The value of equilibrium constant of the reaction

2 21 1HI(g) H (g) I (g)2 2+##$#%### is 8.0

The equilibrium constant of the reaction

2 2H (g) I (g) 2HI(g)+ ##$#%### will be:

(1)1

8(2)

1

16

(3)1

64(4) 16

Sol : (3) 2 21 1

HI H I2 2

+##$#%###

K = 8

then,2 2H I 2HI+ ##$#%###2

1 1K

8 64

= = 54. If a stands for the edge length of the cubic systems

simple cubic, body centred cubic and face centredcubic, then the ratio of radii of the spheres in thesesystems will be respectively,

(1) 1a: 3a : 2a (2)1 3 1

a: a : a2 4 2 2

(3)1 1

a: 3a : a2 2

(4)1 3 2

a: a : a2 2 2

Sol : (2) S.C.C., ar 2=

F.C.C., r =a

2 2

B.C.C.,3a

r4

=

rSCC: rBCC: rFCC

a 3a 1: : a

2 4 2 2

55. Kohlrauschs law states that at:

(1) Infinite dilution, each ion makes definitecontribution to equivalent conductance of anelectrolyte, whatever be the nature of the otherion of the electrolyte

(2) finite dilution, each ion makes definite contributionto equivalent conductance of an electrolyte,whatever be the nature of the other ion of theelectrolyte

(3) Infinite dilution each icon makes definitecontribution to equivalent conductance of anelectrolyte depending on the nature of the other

ion of the electrolyte(4) Infinite dilution, each ion makes definite

contribution to conductance of an electrolytewhatever be the nature of the other ion of theelectrolyte

Sol : (4) According to Kohlransch law, at infinite dilution,each ion makes definite contribution toconductance of an electrolyte whatever be thenature of the other ion of the electrolyte

56. The measurement of the electron position is associatedwith an uncertainty in momentum, which is equal to 1

1018g cms1. The uncertainty in electron velocityis, (mass of an electron is 9 1028g)

(1) 1 1011cms1 (2) 1 109cms1

(3) 1 106cms1 (4) 1 105cms1

Sol : (2) P m V = 1 1018= 9 1028 V

10910V 1.1 10 cm /s

9 = =


11/27




[10] CBSE PMT - 2008 Prelims Paper (Code - A) with H ints & Solutions

57. Which of the following are not state functions ?

I. q + w II. q

III. w IV. H-TS

(1) II and III (2) I and IV

(3) II, III and IV (4) I, II and III

Sol : (1) Heat and work are not state function

58. The bromination of acetone that occurs in acid solutionis represented by this equation,

3 3 2 3 2CH COCH (aq) Br (aq) CH COCH Br(aq)+

H (aq) Br (aq)+ + +

These kinetic data were obtained for given reactionconcentrations

Initial concentrations, M

[CH3COCH3] [Br 2] [H+]

0.30 0.05 0.05

0.30 0.10 0.05

0.30 0.10 0.10

0.40 0.05 0.20

Initial Rate, disappearance of Br2, Ms1

5.7 105

5.7 105

1.2 104

3.1 104

Based on these data, the rate equation is :

(1) Rate = k[CH3COCH3][Br2][H+]

(2) Rate = k[CH3COCH3][H+]

(3) Rate = k[CH=COCH3

][Br2

]

(4) Rate = k[CH3COCH3][Br2][H+]2

Sol : (2) From Expt. (1) & (2)

b 52

52

Br 5.7 10

Br 5.7 10

=

[ ]b

0.051

0.10

= b = a

From expt. (2) & (3)

c 52

43

H 5.7 10

H 1.2 10

+

+

=

[ ]c

0.050.475

0.10

=

c1

0.4752

=

approx., c= 1

is (2)

59. What volume of oxygen gas (O2) measured at 0Cand 1 atm, is needed to burn completely 1L of propanegas (C3H8) measured under the same conditions ?

(1) 10 L (2) 7 L

(3) 6 L (4) 5 L

Sol : (4) 3 8 2 2 2C H 5O 3CO 4H O+ +

1 mol 5 22.4 ltr

22.4 ltr 5 22.4 ltr

1 ltr 5 ltr60. Bond dissociation enthalpy of H2, Cl2and HCl are

434, 242 and 431 kJ mol1respectively. Enthalpy offormation of HCl is:

(1) 245 kJ mol1 (2) 93 kJ mol1

(3) 245 kJmol1 (4) 93 kJmol1

Sol : (4) 2 2H Cl 2HCl+

[ ] [ ]434 242 2 431H

2

+ =

676 86293kJ/mol

2

= =

61. Which of the following statement is not correct ?

(1) The number of Bravais lattices in which a crystalcan be categorized is 14

(2) The fraction of the total volume occupied by theatoms in a primitive cell is 0.48

(3) Molecular solids are generally volatile

(4) The number of carbon atoms in an unit cell ofDiamond is 4

Sol : (2) The fraction of total volume occupied in primitivecell is 0.52.

62. Equal volumes of three acid solutions of pH 3, 4 and5 are mixed in a vessel. What will be the H+ ionconcentration in the mixture ?

(1) 1.11 103M (2) 1.11 104M

(3) 3.7 104M (4) 3.7 103M

Sol : (3)

3 4 5

10 1 10 1 10 1H M 3

+ + + = = 3 1 210 1 10 10

3

+ + =

[ ]310 1.11

3

=

341.11 10 3.7 10

3

= =


12/27

[11] CBSE PMT - 2008 Prelims Paper (Code - A) with H in ts & Solutions




63. The values of Kp1and Kp2for the reactions

X Y Z.........(1)+##$#%### and

A 2B.........(2)##$#%###

are in ratio of 9:1. If degree of dissociation of X andA be equal, then total pressure at equilibrium (1) and(2) are in the ratio :

(1) 1 : 1 (2) 3 : 1(3) 1 : 9 (4) 36 : 1

Sol : (4) Kp1= Kp2

X Y Z11

+

##$#%### A 2B11 2

##$#%###

ngy z 1

x 1

n n P1

n y

& ( )

( )

ng2B 2

A 2

n P9

n y

=

22P49

1 1

=

+

P1= 36P2

1

2

P

P=

36

1

64. If the concentration of OHions in the reaction

33Fe(OH) (s) Fe (aq) 3OH (aq)

+ +##$#%### is

decreased by 14

times, then equilibrium concentration

of Fe3+will increase by:

(1) 4 times (2) 8 times

(3) 16 times (4) 64 times

Sol : (4) 33 (aq.)Fe(OH) (s) Fe (aq.) 3OH+ +##$#%###

33cK Fe OH

+ =

since, kcdepends only on temperature

3 33 3

i FFe OH Fe OH+ + =

33 1 yx y x

4

=

1x x

64=

x = 64x

65. For the gas phase reaction,

5 3 2PCl (g) PCl (g) Cl (g)+##$#%###

which of the following conditions are correct ?

(1) H O > and S O

(4) H O < and S O K+> Rb+> Cs+

(2) K

+

> Na

+

> Rb

+

> Cs

+

(3) Cs+> Rb+>K+> Na+

(4) Rb+>K+> Cs+> Na+

Sol : (3) Ionic mobility increases down the group as thehydrated ionic radii decreases down the group

70. Percentage of free space in a body centred cubicunit cell is:

(1) 28% (2) 30%

(3) 32% (4) 34%

Sol : (3) Packing fraction in BCC is 68%, so free space =32%

71. The correct order of decreasing second ionisationenthalpy of Ti(22), V(23), Cr(24) and Mn(25), is:

(1) Ti > V > Cr> Mn (2) Cr > Mn > V > Ti

(3) V > Mn > Cr > Ti (4) Mn > Cr > Ti > V

Sol : (2) Cr > Mn > V > Ti

72. How many moles of lead (II) chloride will be formedfrom a reaction between 6.5g of PbO and 3.2g ofHCl ?

(1) 0.029 (2) 0.044

(3) 0.333 (4) 0.011

Sol : (1) 2 2PbO 2HCl PbCl H O+ +223 +73 278gm

Given 6.5gm 3.2gm

eq. of PbO6.5

2 0.058223

= = (limiting reagent)

eq. of HCl3.2

1 0.0876736.5

= =

Now, eq. of PbO = eq. of PbCl20.058 = n z

n =0.058

0.0292

=

73. Which of the following complexes exhibits the highestparamagnetic behaviour ?

(1) [Ti(NH3)6]3+

(2) [V(gly)2(OH)2(NH3)2]+

(3) [Fe(en)(bpy)(NH3)2]2+

(4) [Co(OX)2(OH)2]

Where gly = glycine, en = enthylenediamine andpby=bipyridyl moities)

(at. nos. Ti = 22, V = 23, Fe = 26, Co = 27)

Sol : (4) [Ti(NH3)6]3+ 3 1Ti 4s+

lonpaired e

[V(Gly)2(OH)2(NCl3)2]+ 5 6V 3p+

o unpaired e

[Fe(en)(bpy)(NH3)2]+2 2 6Fe 3d+

but pairing takes place, so no. of unpaired eiszero

[Co(OX)2(OH)2] 5 4Co 3d+

even after pairing their will be 2 unpaired e. Sthus highest paramagnetism


14/27





74. Volume occupied by one molecule of water (density= 1 g cm3) is :

(1) 5.5 1023cm3

(2) 9.0 1023cm3

(3) 6.023 1023cm3

(4) 3.0 1023cm3

Sol : (4) Volume of one water molecules is

3

23

18cm

6.023 10= 3 1023cm3

75. Number of moles of 4MnO required to oxidize one

mole of ferrous oxalate completely in acidic mediumwill be :

(1) 0.2 moles

(2) 0.6 moles

(3) 0.4 moles

(4) 7.5 moles

Sol : (2) H 3 24 2 4MnO FeC O Fe Mn

+ + ++ +

Eq. of 4MnO = Eq. of FeC2O4

n 5 = 1 3

n =3

0.65

= moles

76. On the basis of the following E values, the strongestoxidizing agent is:

4 36 6[Fe(CN) ] [Fe(CN) ] + e1; E = 0.35 V

2 3 1Fe Fe e ;+ + + E = 0.77 V

(1) [Fe(CN)6]3 (2) [Fe(CN)6]

4

(3) Fe2+ (4) Fe3+

Sol : (4) Fe+3has highest SRP & thus behaves as strongestoxidising agent.

77. The alkali metals form salt-like hydrides by the directsynthesis at elevated temperature. The thermalstability of these hydrides decreases in which of the

following orders?(1) LiH > NaH > KH > RbH > CsH

(2) CsH > RbH > KH > NaH > LiH

(3) KH > NaH > LiH > CsH > RbH

(4) NaH > LiH > KH > RbH > CsH

Sol : (1) Down the group the thermal stability of hydridesdecreases because the difference in size ofincreases

78. Which one of the following arrangement does not givethe correct pictures of the trends indicated against it?

(1) F2>Cl2>Br2>I2: Electronegativity

(2) F2>Cl2>Br2>I2: Oxidizing power

(3) F2>Cl2>Br2>I2: Electron gain enthalpy

(4) F2>Cl2>Br2>I2: Bond dissociation energy

Sol : (4) The correct bond dissociation energy is

Cl2>Br2>F2> I279. With which one of the following elements silicon

should be doped so as to give p-tyupe ofsemiconductor ?

(1) Boron (2) Germanium

(3) Arsenic (4) Selenium

Sol : (1) Boron is added to form p type semiconductor

80. In which of the following coordination entities themagnitudes of 0 (CFS E in octahedral field) will bemaximum ?

(1) [Co(C2O4)3]3 (2) [Co(H2O)6]

3+

(3) [Co(NH3)6]3+ (4) [Co(CN)6]

3

(At. no.Co = 27)

Sol : (4) CN is the strongest ligand & thus CFSE ismaximum

81. The angular shape of ozone molecule (O3) consistsof:

(1) 2 sigma and 1 pi bonds

(2) 1 sigma and 2 pi bonds

(3) 2 sigma and 2 pi bonds(4) 1 sigma and 1 pi bonds

Sol : (1) OOO

+

82. The correct order of increasing bond angles in thefollowing triatomic species is:

(1) 2 2 2NO NO NO+ < (d) > (a)

(4) (d) > (b) > (c) > (a)

Sol : (2) (a) > (b) > (c) > (d)

90. The relative reactivities of acyl compounds towards

nucleophilic substitution are in the order of :(1) Acyl chloride > Ester > Acid anhydride > Amide

(2) Acyl chloride > Acid anhydride > Ester > Amide

(3) Ester > Acyl chloride > Amide > Acid anhydride

(4) Acid anhydride > Amide > Ester > Acyl chloride

Sol : (2) Weaker is basicity, better is the leaving group andmore is rate of nucleophilic substitution.

91. Base strength of:

(a) H CCH3 2

(b) H C=CH2 and

(c) HCC

is the order of :

(1) (a) > (b) > (c)

(2) (b) > (a) > (c)

(3) (c) > (b) > (a)

(4) (a) > (c) > (b)


16/27





Sol : (1) Higher the electron density on carbanion more isthe basic strength

92. 3 2

3

H C CH CH CH HBr A|

CH

= +

A (Predominantly) is:

(1) 3 3

3

CH CH CH CH

| |CH Br

(2) 3 2 2

3

CH CH CH CH Br |

CH

(3) 3 2 3

3

Br|

CH C CH CH|

CH

(4) 3 3

3

CH CH CH CH| |

Br CH

Sol : (3)3 2

3

H C CH CH CH H|

CH

= +

3 3

3

CH CH CH CH|

CH (2 carbocation)

1, 2-hydride shift

3 2 3

3

CH C CH CH|

CH 3 carbocation(more stable)

Br

3 2 3

3

Br|

CH C CH CH|

CH

93. In DNA, the complimentary bases are:

(1) Uracil and adenine; cytosine and guanine

(2) Adenine and thymine; guanine and cytosine

(3) Adenine and thymine; guanine and uracil

(4) Adenine and guanine; thymine and cytosine

Sol : (2) In DNA; the complimentary bases are

Adenine - Thymine

and Guanine - Cytosine

94. Which one of the following is most reactive towardselectrophilic attack ?

(1)

Cl

(2)

CH OH2

(3)

NO2

(4)

OH

Sol : (4)OH group behaves as +R effect therebyincreasing the electron density and increases theelectrophilic substitution.

95. An organic compound contains carbon, hydrogen andoxygen. Its elemental analysis gave C, 38.71% and

H, 9.67%. The empirical formula of the compoundwould be:

(1) CH4O (2) CH3O

(3) CH2O (4) CHO

Sol : (2) C 38.7138.71

12=3.226 1

O 51.6251.62

16= 3.226 1

H 9.679.67

1 =9.67 3

Thus empirical formula =CH3O

96. In a SN2substitution reaction of the type

DMFR Br Cl R Cl Br , + +

which one of the following has the highest relativerate?

(1) CH3CH2Br

(2) CH3CH2CH2Br

(3) 3 23

CH CH CH Br |

CH

(4)

3

3 2

3

CH|

CH C CH Br |

CH

Sol : (1) Smaller is size of alkyl group faster is rate of SN2reaction


17/27





97. Acetophenone when reacted with a base, C2H5ONa,yields a stable compound which has the structure :

(1)CHCH

OH OH

(2)C=CHC

CH3 O

(3)CHCH C2

CH3 O

(4) CH C

OH OH

CH3 CH3

Sol : (2)6 5 3

O

||C H C CH C H O Na2 5 +

C H CCH CC H6 5 2 6 5

CH3

O O

H+

C H CCH CC H6 5 2 6 5

CH3

OH O

H O2

6 5 6 5

3

O||

C H C CH C C H|

CH

=

98. In a reaction of aniline a coloured product C wasobtained

NH2NaNO2

HCl

A

BCold

C

NCH3

CH3

The structure of C would be :

(1) N=N NCH3

CH3

(2)N=NCH N2

CH3

(3) N=N

CH3 CH3

(4) NHNH N

CH3

CH3

Sol : (1)

NH2

NaNO2HCl

N Cl2+

Cold

NCH3CH3

N=N N

CH3

CH3

99. Which one of the following statements is not true ?

(1) Natural rubber is a 1, 4-polymer of isoprene

(2) In vulcanization, the formation of sulphur bridgesbetween different chains make rubber harder andstronger

(3) Natural rubber has the trans-configuration atevery double bond

(4) Buna-S is a copolymer of butadiene and styrene

Sol : (3)Natural rubber has cis configuration at everydouble

100. Which one of the following is an amine hormone ?

(1) Progesterone

(2) Thyroxine

(3) Oxypurin

(4) Insulin

Sol : (2) Thyroxine is an amine hormone


18/27





BIOLOGY

Animals Morphological feature

(1) Cockroach, Locust - Metameric

Taenia segmentation

(2) Liver fluke, - Bilateralsymmetry

Sea anemone,

Sea cucumber(3) Centipede, Prawn, - Jointed

Sea urchin appendages

(4) Scorpion, Spider, - Ventral solid

Cockroach central nervous system

Sol. (4) Taenia solium doesnt have metamericsegmentation and sea cuccumber shows radialsymmetry. Sea urchin doesnt have jointedappendages.

106. Which one of the following phyla is correctlymatchedwith its two general characteristics ?

(1) Mollusca Normally oviparous anddevelopment through atrochophore or veliger larva

(2) Arthropoda Body divided into head,thorax and abdomen andrespiration by tracheae

(3) Chordata Notochord at some stageand separate anal andurinary openings to theoutside

(4) Echinodermata Pentamerous radial

symmetry and mostlyinternal fertilization

Sol. (1) In all arthropods, respiration is not by tracheae.

107. Which one of the following in birds, indicatestheirreptilian ancestry ?

(1) Eggs with a calcareous shell

(2) Scales on their hind limbs

(3) Four-chambered heart

(4) Two special chambers crop and gizzardin theirdigestive tract

Sol. (2)

108. Ascaris is characterized by:(1) Presence of true coelom and metamerism

(metamerisation)

(2) Absence of true coelom but presence ofmetamerism

(3) Presence of neither true coelom normetamerism

(4) Presence of true coelom but absence ofmetamerism

Sol. (3) Ascarishas pseudocoelom

101. Select one of the following pairs of importantfeaturesdistinguishing Gnetum, from Cycasand Pinusandshowing affinities withangiosperms:

(1) Embryo development and apical meristem

(2) Absence of resin duct and leaf venation

(3) Presence of vessel elements and absence ofarchegonia

(4) Perianth and two integuments

Sol. (3)

102. Thermococcus, Methanococcus, an dMethanobacterium exemplify:

(1) Bacteria that contain a cytoskeleton andribosomes

(2) Archaebacteria that contain proteinhomologousto eukaryotic core histones

(3) Archaebacteria that lack any histones resemblingthose found in eukaryotes but whose DNA isnegatively supercoiled

(4) Bacteria whose DNA is relaxed or positivelysupercoiled but which have a cytoskeleton as wellas mitochondria

Sol. (2) Archaebacteria have specific histone proteinswhich are similar to eukaryotic histone proteinsinvolved in DNA coiling. This is also used as animportant evidence to show that early eucaryoticcells have evolved from archaebacteria.

103. Which one of the following is hetcrosporous ?

(1) Equisetum

(2) Dryopteris

(3) Salvinia

(4) Adiantum

Sol. (3)

104. In which one of the following, male and femalegametophytes do not have free living independentexistence ?

(1) Cedrus(2) Pteris

(3) Funaria

(4) Polytrichum

Sol. (3)

105. Which one of the following groups of threeanimalseach is correctly matched with their onecharacteristic morphological feature ?


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115. In the light of recent classification of livingorganismsinto three domains of life (bacteria, archaea andeukarya), which one of the followingstatements istrue about archaea ?

(1) Archaea completely differ from prokaryotes

(2) Archaea resemble eukarya in all respects

(3) Archaea have some novel features that areabsent in other prokaryotes and eukaryotes

(4) Archaea completely differ from both prokaryotesand eukaryotes

Sol. (3)

(i) The nucleoticle sequence of rRNA of archae isdifferent from both procaryotes and eucaryotes

(ii) The cell membrane of archae have single layeredbranched lipid layer.

116. Keeping in view the fluid mosaic model for thestructure of cell membrane, which one of thefollowing statements is correct with respect to themovement of lipids and proteins from one lipidmonolayer to the other (described as flip-flopmovement) ?

(1) Neither lipids, nor proteins can flip-flop

(2) Both lipids and proteins can flip-flop

(3) While lipids can rarely flip-flop, proteinscan not

(4) While proteins can flip-flop, lipids can not

Sol. (3)

117. In germinating seeds fatty acids are degradedexclusively in the:

(1) Mitochondria

(2) Proplastids

(3) Glyoxysomes

(4) Peroxisomes

Sol. (3)

118. The two sub-units of ribosome remain united atacritical ion level of:

(1) Calcium (2) Copper

(3) Manganese (4) Magnesium

Sol. (4)

119. Thorn ofBougainvillea and tendril of cucurbitaareexamples of:

(1) Retrogressive evolution

(2) Analogous organs

(3) Homologous organs

(4) Vestigial organs

Sol. (3) Homologous organs have similar origin or basicfundamental structure and perform different orsimilar function

109. Which one of the following isNOT acharacteristicof phylum Annelida ?

(1) Ventral nerve cord

(2) Closed circulatory system

(3) Segmentation

(4) Pseudocoelom

Sol. (4) Annelids have true coelom

110. Cellulose is the major component of cell walls of:(1) Saccharomyces (2) Pythium

(3) Xanthomonas (4) Pseudomonas

Sol. (2)

111. Vacuole in a plant cell :

(1) Lacks membrane and contains water andexcretory substances

(2) Is membrane-bound and contains storageproteinsand lipids

(3) Is membrane-bound and contains water andexcretory substances

(4) Lacks membrane and contains air

Sol. (3)

112. A competitive inhibitor of succinicdehydrogenase is:

(1) Malate

(2) Malonate

(3) Oxaloacetate

(4) -ketoglutarateSol. (2)

113. Polysome is formed by:

(1) Ribosomes attached to each other in a lineararrangement

(2) Several ribosomes attached to a singlemRNA

(3) Many ribosomes attached to a strand ofendoplasmic reticulum

(4) A ribosome with several subunits

Sol. (2)

114. Carbohydrates are commonly found as starch inplantstorage organs. Which of the followingfive propertiesof starch (a - e) make it useful as astorage material?

(a) Easily translocated

(b) Chemically non-reactive

(c) Easily digested by animals

(d) Osmotically inactive

(e) Synthesized during photosynthesis

The useful properties are:

(1) (a) and (e) (2) (b) and (c)

(3) (b) and(d) (4) (a),(c) and(e)

Sol. (3)


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(3) Hereditary diseases like colour blindnessdo notspread in the isolated population

(4) Wrestlers who develop strong bodymuscles intheir life time pass this character on to theirprogeny

Sol. (2) In the small tribal population, there will beconsangious marriages which will lead toincreased expression of recessive traits. The traits

which are recessive and lethal will thereforeexpress in homozygous condition leading to moredeaths, therefore decline in population.

125. Which one of the following scientists name iscorrectly matched with the theory put forth byhim?

(1) Mendel Theory of Pangenesis

(2) Weismann Theory of conti nui ty of Germplasm

(3) Pasteur Inheritance of acquiredcharacters

(4) de Vries Natural selection

Sol. (2)126. Which one of the following is incorrect about the

characteristics of protobionts (coacervates andmicrospheres) as envisaged in the abiogenicorigin oflife ?

(1) They could maintain an internal environment

(2) They were able to reproduce

(3) They could separate combinations of moleculesfrom the surroundings

(4) They were partially isolated from the surroundings

Sol. (3)

127. Darwins Finches are an excellent example of:(1) Connecting links (2) Adaptive radiation

(3) Seasonal migration (4) Brood parasitism

Sol. (2)

128. Which one of the following pairs of itemscorrectlybelongs to the category of organsmentioned againstit ?

(1) Wings of honey bee Homologous

and wings of crow organs

(2) Thorn ofBougainvillea Analogous

and tendrils of Cucurbita organs

(3) Nictitating membrane and Vestigialblind spot in human eye organs

(4) Nephridia of earthworm Excretory

and malpighian tubules organs

of Cockroach

Sol. (4) Wings of honeybee & wings of crow areanalogous organs. Thorn of Bougainvilleaandtendrils of Cucurbita are homologous organs.Blind spot is not vestigeal in humans

120. Haploids are more suitable for mutation studiesthanthe diploids. This is because:

(1)All mutations, whether dominant or recessive areexpressed in haploids

(2) Haploids are reproductively more stable thandiploids

(3) Mutagens penetrate in haploids moreeffectivelythan is diploids

(4) Haploids are more abundant in nature thandiploids

Sol. (1) Haploids contain only one set of alleles thereforeall alleles whether dominant or recessive expressin the organism.

121. Which one of the following pairs of nitrogenousbasesof nucleic acids, is wrongly matched with thecategory mentioned against it ?

(1) Adenine, Thymine Purines

(2) Thymine, Uracil Pyrimidines

(3) Uracil, Cytosine Pyrimidines

(4) Guanine, Adenine Purines

Sol. (1) Adenine and Guanine are purines where asThymine & Cytosine are pyrimidines

122. Which one of the following conditions inhumans iscorrectly matched with itschromosomal abnormality/linkage ?

(1) Down syndrome 44 autosomes + XO

(2) Klinefelters syndrome 44 autosomes +XXY

(3) Colourblindness Y-linked

(4) Erythroblastosis foetalis X-linked

Sol. (2) Downs syndrome is due to trisomy ofchromosome no. 21. Colourblindess is x-lined andexythroblastosis foetalis is due to Rh-factorincompatibility.

123. In the DNA molecule:

(1) There are two strands which run antiparallel-one

in 5 3 direction and other in 3 5(2) The total amount of purine nucleotides and

pyrimidine nucleotides is not alwaysequal

(3) There are two strands which run parallelin the

5 3 direction(4) The proportion of Adenine in relation tothymine

varies with the organism

Sol. (1)

124. What is true about the isolated small tribalpopulations?

(1) There is no change in population size as they havea large gene pool

(2) There is a decline in population as boys marrygirls only from their own tribe


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(2) Vessels and tracheid differentiation

(3) Leaf abscission

(4) Annual plants

Sol. (2) Vessels and tracheids are dead cells(components) of xylem, which is necessary forthe conduction of water

135. Vascular tissues in flowering plants developfrom:

(1) Dermatogen (2) Phellogen

(3) Plerome (4) Periblem

Sol. (3)

136. In leaves of C4plants malic acid synthesis duringCO2fixation occurs in:

(1) Guard cells (2) Epidermal cells

(3) Mesophyll cells (4) Bundle sheath

Sol. (3)

137. Importance of day length in flowering of plantswasfirst shown in:

(1) Petunia (2) Letting

(3) Tobacco (4) Cotton

Sol. (3)

138. Endosperm is consumed by developing embryoin theseed of:

(1) Maize (2) Coconut

(3) Castor (4) Pea

Sol. (4) Pea is an example of non-endospermic seeds

139. Nitrogen fixation in root nodules ofAlnus isbroughtabout by:

(1) Azorhizobium (2) Bradyrhizobium

(3) Clostridium (4) Frankia

Sol. (4)

140. The energy-releasing process in which thesubstrateis oxidised without an external electronacceptor iscalled:

(1) Glycolysis (2) Fermentation

(3) Photorespiration (4) Aerobic respiration

Sol. (2) External electron accepter is oxygen which is notused in fermentation

141. Replum is present in the ovary of flower of:

(1) Pea (2) Lemon(3) Mustard (4) Sun flower

Sol. (3)

142. The fleshy receptacle of syconus of fig encloses anumber of:

(1) Mericarps (2) Achenes

(3) Samaras (4) Berries

Sol. (2)

129. The fruit is chambered, developed from inferiorovaryand has seeds with succulent testa in:

(1) Cucumber (2) Pomegranate

(3) Orange (4) Guava

Sol. (2)

130. The C4plants are photosynthetically moreefficientthan C3plants because:

(1) They have more chloroplasts(2) The CO2compensation point is more

(3) CO2generated during photorespiration is trappedand recycled through PEP carboxylase

(4) The CO2efflux is not prevented

Sol. (3) Since in C4 cycle the second carboxylationreaction occurs in bundle sheath cells, so CO2generated during photorespiration can be used forCO2fixation in the mesophyll cells.

131. The chemiosmotic coupling hypothesis ofoxidativephosphorylation proposes thatadenosine triphosphate

(ATP) is formedbecause:(1) There is a change in the permeability of theinner

mitochondrial membrane toward adenosinediphosphate (ADP)

(2) High energy bonds are formed inmitochondrialproteins

(3) ADP is pumped out of the matrix into theintermembrane space

(4) A proton gradient forms across the innermembrane

Sol. (4)132. Dry indehiscent single-seeded fruit formed from

bicarpellary syncarpous inferior ovary is:

(1) Cremocarp (2) Caryopsis

(3) Cypsela (4) Berry

Sol. (3)

133. The rupture and fractionation do not usually occurin the water column in vessel/ tracheids duringtheascent of sap because of:

(1) Transpiration pull

(2) Lignified thick walls(3) Cohesion and adhesion

(4) Weak gravitational pull

Sol. (3) Cobesive and adhesive forces maintain thecontinuity of water column in xylem vessles.

134. Senescence as an active developmental cellularprocess in the growth and functioning of afloweringplant, is indicated in:

(1) Floral parts


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148. Which one of the following is thecorrectdifferencebetweenRod Cells and Cone Cells ofour retina ?

Rod Cel ls Cone Cel ls

(1) Distribution More Evenly

concentrated distributed all

in centre of over retina

retina

(2) Visual acuity High Low(3) Visual Iodopsin Rhodopsin

pigment

contained

(4) Overall Vision in poor Colour vision

function light and detailed

vision in bright light

Sol. (4)

149. Which one of the following items gives its correct

total number?(1) Cervical vertebrae in humans - 8

(2) Floating ribs in humans - 4

(3) Amino acids found in proteins - 16

(4) Types of diabetes - 3

Sol. (2) Cervical vertebrae are 7 in humans. 20 aminoacids are protein amino acids. Diabetes is of 2types, type I & type II Last 2 pair of ribs arefloating ribs

150. Given below is a diagrammatic cross section of asingleloop of human cochlea:

Which one of the following options correctlyrepresents the names of three different parts ?

(1) A: Perilymph, B: Tectorial membrane C:Endolymph

(2) B: Tectorial membrane, C: Perilymph, D:Secretory cells

(3) C: Endolymph, D : Sensory hair cells,A: Serum

(4) D: Sensory hair cells, A: EndolymphB: Tectorialmembrane

Sol. (1)

143. Electrons from excited chlorophyll molecule ofphotosystem II are accepted first by:

(1) Ferredoxin (2) Cytochrome-b

(3) Cytochrome-f (4) Quinone

Sol. (4)

144. Which type of white blood cells are concernedwiththe release of histamine and the natural anticoagulantheparin ?

(1) Monocytes (2) Neutrophils

(3) Basophils (4) Eosinophils

Sol. (3)

145. Which one of the following is the true descriptionabout an animal concerned ?

(1) Cockroach 10 pairs of spiracles (2 pairs onthorax and 8 pairs on abdomen)

(2) Earthworm The alimentary canal consistsof a sequence of pharynx,oesophagus, stomach, gizzard

and intestine

(3) Frog Body divisible into three regions- head, neck and trunk

(4) Rat Left kidney is slightly higher inposition than the right one

Sol. (1)

146. Which one of the following is the correctmatchingof the site of action on the given substrate, theenzyme acting upon it and the end product ?

(1) Stomach : Fats Lipase

micelles

(2) Duodenum : Triglycerides Trypsinmonoglycerides

(3) Small intestine : Starch AmylaseDisaccharide (Maltose)

(4) Small intestine: Proteins Pepsin Amino

acids

Sol. (3) In stomach protein digestion begins by pepsin.

Micelles are formed in small intestine.147. What is vital capacity of our lungs ?

(1) Total lung capacityminus residual volume

(2) Inspiratory reserve volumeplus tidal volume

(3) Total lung capacity minus expiratory reservevolume

(4) Inspiratory reserve volume plus expiratoryreserve volume

Sol. (1)


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Sol. (2) Parathormone increases plasma Ca2+ level bymobilising Ca2+from bones to blood. Deficiencyof this hormone will decrease blood Ca2+level.

155. The most active phagocytic white blood cellsare:

(1) Neutrophils and monocytes

(2) Neutrophils and eosinophils

(3) Lymphocytes and macrophages

(4) Eosinophils and lymphocytes

Sol. (1)

156. Earthworms have no skeleton but duringburrowing,the anterior end becomes turgid and acts as ahydraulic skeleton. It is due to:

(1) Setae (2) Coelomic fluid

(3) Blood (4) Gut peristalsis

Sol. (2)

157. In humans,, blood passes from the post caval tothediastolic right atrium of heart due to:

(1) Pressure difference between the post cavaland

atrium(2) Pushing open of the venous valves

(3) Suction pull

(4) Stimulation of the sino auricular node

Sol. (1)

158. In humans, at the end of the first meiotic division,themale germ cells differentiate into the:

(1) Spermatozonia

(2) Primary spermatocytes

(3) Secondary spermatocytes

(4) Spermatids

Sol. (3)

159. Which one of the following is resistant to enzymeaction ?

(1) Leaf cuticle

(2) Cork

(3) Wood fibre

(4) Pollen exine

Sol. (4) Exine is composed of sporopollenin. So far thereis known enzyme to degreade sporopollenin

160. The length of different internodes in a culm ofsugarcane is variable because of:

(1) Intercalary meristem

(2) Shoot apical meristem

(3) Position of axillary buds

(4) Size of leaf lamina at the node below eachinternode

Sol. (1)

151. Given below are four methods (A - D) and theirmodesof action (a - d) in achieving contraception.Selecttheir correct matching from the fouroptions thatfollow:

Method Mode of Action

A. The pill (a) Prevents sperms

reaching cervix

B. Condom (b) Prevents implantationC. Vasectomy (c) Prevents ovulation

D. Copper T (d) Semen contains no

sperms

(1) A-(b), B-(c), C-(a), D-(d)

(2) A-(c), B-(a), C-(d), D-(b)

(3) A-(d), B-(a), C-(b), D-(c)

(4) A-(c), B-(d), C-(a), D-(b)

Sol. (2)152. What will happen if the secretion of parietal cellsof

gastric glands is blocked with an inhibitor ?

(1) Enterokinase will not be released from theduodenal mucosa and so trypsinogen is notconverted to trypsin

(2) Gastric juice will be deficient in chymosin

(3) Gastric juice will be deficient inpepsinogen

(4) In the absence of HCl secretion, inactivepepsinogen is not converted into the act iveenzyme pepsin.

Sol. (4) Parietal cells or oxyntic cells secrete HCl whichconverts pepsinogen to pepsin

153. During the propagation of a nerve impulse, theactionpotential results from the movement of:

(1) Na+ions from extracellular fluid to intracellularfluid

(2) K +ions from extracellular fluid tointracellularfluid

(3) Na+ions from intracellular fluid toextracellularfluid

(4) K

+

ions from intracellular fluid toextracellularfluid

Sol. (1) Action potentail is due to influx of Na+.

154. The blood calcium level is lowered by thedeficiencyof:

(1) Calcitonin

(2) Parathormone

(3) Thyroxine

(4) Both Calcitonin and Parathormone


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167. Consider the statements given below regardingcontraception and answer as directedthereafter:

(a) Medical Termination of Pregnancy (MTP)duringfirst trimester is generally safe

(b) Generally chances of conception are nil untilmother breast-feeds the infant uptotwo years

(c) Intrauterine devices like copper-T are effectivecontraceptives

(d) Contraception pills may be taken upto one weekafter coitus to prevent conception

Which two of the above statements are correct ?

(1) a, b

(2) b, c

(3) c, d

(4) a, c

Sol. (4) Oral contraceptive pills are to be taken dailystarting from 5th day of menstrual cycle.

168. In human adult females oxytocin:

(1) Causes strong uterine contractions duringparturition

(2) Is secreted by anterior pituitary

(3) Stimulates growth of mammary glands

(4) Stimulates pituitary to secrete vasopressin

Sol. (1) Oxytocin or pitocin is synthesized by hypothalamicneurons & stored in posterior pituitary. It isreleased from posterior pituitary. It is also calledbi rt h hormon e because it causes ut er in econtractions & results in parturition.

169. Which one of the following is thecorrectpercentageof the two (out of the total of 4) greenhouse gasesthat contribute to the total globalwarming ?

(1) Methane 20%, N2O 18%

(2) CFCs 14%, Methane 20%

(3) CO2 40%,CFCs 30%

(4) N2O 6%, CO2 86%

Sol. (2)

170. Quercus species are the dominant componentin:

(1) Tropical rain forests

(2) Temperate deciduous forests(3) Alpine forests

(4) Scrub forests

Sol. (2)

171. About 70% of total global carbon is found in:

(1) Forests (2) Grasslands

(3) Agroecosystems (4) Oceans

Sol. (4)

161. Which one of the following pairs of plantstructureshas haploid number ofchromosomes ?

(1) Egg nucleus and secondary nucleus

(2) Megaspore mother cell and antipodalcells

(3) Egg cell and antipodal cells

(4) Nucellus and antipodal cells

Sol. (3)

162. What does the filiform apparatus do at the entranceinto ovule ?

(1) It guides pollen tube from a synergid to egg

(2) It helps in the entry of pollen tube into asynergid

(3) It prevents entry of more than one pollen tubeinto the embryo sac

(4) It brings about opening of the pollen tube

Sol. (2)

163. Unisexuality of flowers prevents:

(1) Autogamy and geitonogamy

(2) Autogamy, but not geitonogamy(3) Both geitonogamy and xenogamy

(4) Geitonogamy, but not xenogamy

Sol. (2)

164. Which extraembryonic membrane in humanspreventsdesiccation of the embryo inside theuterus ?

(1) Amnion (2) Chorion

(3) Allantois (4) Yolk sac

Sol. (1)

165. Which one of the following statements isincorrect

about menstruation ?(1) The beginning of the cycle ofmenstruation is

called menarche

(2) During normal menstruation about 40 mlblood islost

(3) The menstrual fluid can easily clot

(4) At menopause in the female, there is especiallyabrupt increase in gonadotropic hormones

Sol. (3) Menstrual fluid doesnt clot

166. The haemoglobin of a human foetus:

(1) Has a higher affinity for oxygen than that of anadult

(2) Has a lower affinity for oxygen than thatof theadult

(3) Its affinity for oxygen is the same as thatof anadult

(4) Has only 2 protein subunits instead of 4

Sol. (1) Foetal haemoglobin has very high affinity foroxygen


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177. The table below gives the populations (inthousands)of ten species (A - J) in four areas(a - d) consistingof the number of habitats givenwithin brackets againsteach. Study the tableand answer the question whichfollows:

Which area out of a to d shows maximum speciesdiversity ?

(1) a (2) b

(3) c (4) d

Sol. (4)

178. A lake near a village suffered heavy mortality offisheswithin a few days. Consider the followingreasons

for this ?(a) Lots of urea and phosphate fertilizer were used

in the crops in the vicinity

(b) The area was sprayed with DDT by an aircraft

(c) The lake water turned green and stinky

(d) Phytoplankton populations in the lake declinedinitially thereby greatly reducing photosynthesis.

Which two of the above were the main causes offish mortality in the lake ?

(1) a, b (2) b, c

(3) c, d (4) a, cSol. (4)

179. Consider the following four statements (a - d)aboutcertain desert animals such as kangaroorat.

(a) They have dark colour and high rate ofreproduction and excrete solid urine

(b) They do not drink water, breathe at a slowrateto conserve water and have their bodycoveredwith thick hairs

(c) They feed on dry seeds and do not require

drinking water(d) They excrete very concentrated urine anddo not

use water to regulate bodytemperature.

Which two of the above statements for such animalsare true ?

(1) a and b (2) c and d

(3) b and c (4) c and a

Sol. (3)

172. Which one of the following is not observed inbiodiversity hotspots ?

(1) Species richness (2) Endemism

(3) Accelerated species loss

(4) Lesser inter-specific competition

Sol. (4)

173. World Summit on Sustainable Development(2002)was held in :

(1) South Africa (2) Brazil

(3) Sweden (4) Argentina

Sol. (1)

174. The slow rate of decomposition of fallen logs innatureis due to their:

(1) Low cellulose content

(2) Low moisture content

(3) Poor nitrogen content

(4) Anaerobic environment around them

Sol. (3) Condtions for high rate of decomposition

A Climatic factors

(i) Temperature

(ii) soil mositure

(B) Chemical quality of detritus

(i) Slow rate of decomposition if detritus is rich insubstances such as lignin and chitin.

(ii) Nirogen rich detritus, decomposesrapidly.

175. Consider the following statements concerningfoodchains:

(a) Removal of 80% tigers from an arearesulted ingreatly increased growth ofvegetation

(b) Removal of most of the carnivores resultedin anincreased population of deers

(c) The length of food chains is generallylimited to3 - 4 trophic levels due to energyloss.

(d) The length of food chains may vary from 2to 8trophic levels.


(1) a, b (2) b, c

(3) c, d (4) a, d

Sol. (2)

176. According to Central Pollution Control Board(CPCB), which particulate size in diameter (inmicrometers) of the air pollutants is responsibleforgreatest harm to human health ?

(1) 5.2 - 2.5 (2) 2.5 or less

(3) 1.5 or less (4) 1.0 or less

Sol. (2)


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180. A transgenic food crap which may help in solvingtheproblem of night blindness in developingcountries is:

(1) Golden rice (2) Flavr Savr tomatoes

(3) Starlink maize (4) Bt Soybean

Sol. (1)

181. Bacterial leaf blight of rice is caused by a speciesof:

(1) Envinia (2) Xanthomonas

(3) Pseudomonas (4) Alternaria

Sol. (2)

182. Which one of the following is linked to thediscoveryof Bordeaux mixture as a popularfungicide ?

(1) Black rust of wheat

(2) Bacterial leaf blight of rice

(3) Downy mildew of grapes

(4) Loose smut of wheat

Sol. (3)

183. Which one of the following is being tried in Indiaas abiofuel substitute for fossil fuels ?

(1) Aegilops (2) Jatropha

(3) Azadirachta (4) Musa

Sol. (2)

184. Trichoderma harzianum has proved a usefulmicroorganism for:

(1) Biological control of soil-borne plantpathogens

(2) Bioremediation of contaminated soils

(3) Reclamation of wastelands

(4) Gene transfer in higher plantsSol. (2) Bioremediation can be defined as a process that

uses microrganisms, fungi, green plants or theirenzymes to retum the natural envioronmentaltered by contaminants to its original condition.

185. Gel electrophoresis is used for:

(1) Isolation of DNA molecule

(2) Cutting of DNA into fragments

(3) Separation of DNA fragments according to theirsize

(4) Construction of recombinant DNA by joining withcloning vectors

Sol. (3)

186. To which type of barriers under innate immunity,dothe saliva in the mouth and the tears from theeyes,belong ?

(1) Physical barriers (2) Cytokine barriers

(3) Cellular barriers (4) Physiological barriers

Sol. (4)

187. Match the disease in Column I with theappropriateitems (pathogen/prevention/treatment) in Column II.

Column I Column I I

(a) Amoebiasis (i) Treponemapallidum

(b) Diphtheria (ii) Use only sterilized food andwater

(c) Cholera (iii) DPT Vaccine

(d) Syphilis (iv) Use oval rehydration therapy

(1) a-(ii), b-(iii), c-(iv), d-(i)(2) a-(i), b-(ii), c-(iii), d-(iv)

(3) a-(ii), b-(iv), c-(i), d-(iii)

(4) a-(ii), b-(i), c-(iii), d-(iv)

Sol. (1)

188. Consider the following statements aboutbiomedicaltechnologies:

(a) During open heart surgery blood iscirculated inthe heart-lung machine

(b) Blockage in coronary arteries is removedby

angiography(c) Computerised Axial Tomography (CAT) shows

detailed internal structure as seen in a section ofbody

(d) X-ray provides clear and detailed images oforgans like prostate glands and lungs


(1) a and b (2) b and d

(3) c and d (4) a and c

Sol. (4) Blockage in coronary artery is removed byangioplasty.

189. Which one of the following pairs of codons iscorrectly matched with their function or thesignalfor the particular amino acid ?

(1) UUA, UCA - Leucine

(2) GUU, GCU - Alanine

(3) UAG, UGA - Stop

(4) AUG, ACG - Start/Methionine

Sol. (3)

190. Which one of the following is thecorrectstatementregarding the particular psychotropicdrug specified?

(1) Barbiturates cause relaxation and temporaryeuphoria

(2) Hashish causes after thought perceptions andhallucinations

(3) Opium stimulates nervous system and causeshallucinations

(4) Morphine leads to delusions and disturbedemotions

Sol. (2) Barbiturates induce sleep and morphine is ananalygesic


27/27


191. Cry1 endotoxins obtained from Baci llusThuringiensis are effective against:

(1) Boll worms (2) Mosquitoes

(3) Flies (4) Nematodes

Sol. (1)

192. Modern detergents contain enzyme preparationsof:

(1) Thermophiles (2) Acidophiles

(3) Alkaliphiles (4) ThermoacidophilesSol. (3)

193. The linking of antibiotic resistance gene with theplasmid vector became possible with:

(1) Exonucleases (2) DNA ligase

(3) Endonucleases (4) DNA polymerase

Sol. (2)

194. Which one of the following proved effective forbiological control of nematodal diseases inplants ?

(1) Paecilomyces lilacinus

(2) Pisolithus tinctorius(3) Pseudomonas cepacia

(4) Gliocladium virens

Sol. (1) Paecilonyces lilacinusinfects nematodal larvaethereby helping in biocontrol of nematodaldiseases.

195. Main objective of production/use of herbicideresistantGM crops is to:

(1) Reduce herbicide accumulation in food articlesfor health safety

(2) Eliminate weeds from the field without theuseof manual labour

(3) Eliminate weeds from the field without theuseof herbicides

(4) Encourage eco-friendly herbicides

Sol. (1)

196. Consider the following four measures (a - d) thatcouldbe taken to successfully grow chickpea in an areawhere bacterial blight disease iscommon:

(a) Spray with Bordeaux mixture

(b) Control of the insect vector of the disease

pathogen(c) Use of only disease-free seeds

(d) Use of varieties resistant to the disease

Which two of the above measures can control thedisease ?

(1) a and d (2) b and c

(3) a and b (4) c and d

Sol. (2)

197. Human insulin is being commercially producedfroma transgenic species of:

(1) Saccharomyces(2) Escherichia

(3) Mycobacterium

(4) Rhizobium

Sol. (2)

198. Cornea transplant in humans is almost neverrejected.This is because:

(1) It is a non-living layer

(2) Its cells are least penetrable by bacteria

(3) It has no blood supply

(4) It is composed of enucleated cells

Sol. (3) Cornea is avascular so there is no problem ofimmunological rejection.

199. Which one of the following pairs of organsincludesonly the endocrine glands ?

(1) Adrenal and Ovary

(2) Parathyroid and Adrenal

(3) Pancreas and Parathyroid

(4) Thymus and Testes

Sol. (2) Ovaries & pancreas are mixed tissues. Theseperform endocrine function as well as otherfunctions also. Ovaries produce ova, testesproduces sperm. Pancreas secrete enzymes aswell as hormones.

200. What is antisense technology ?

(1) RNA polymerase producing DNA

(2) A cell displaying a foreign antigen used forsynthesis of antigens

(3) Production of somaclonal variants in tissuecultures

(4) When a piece of RNA that is complementary insequence is used to stop expression of a specificgene

Sol. (4)

narayana aipmt 2008 solution

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