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8/8/2019 Navigation Book

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  Amendment List Date  Amended by Incorporated

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CONTENTS

ii

ISSUED 2000

ACP 32NAVIGATION

Volume 1 ................. Map Reading

Volume 2 ................. Basic Navigation

Volume 3 ................ Air Navigation

Volume 4 ................. Pilot Navigation

Volume 3

Air Navigation

Chapter 1 ................ Distance speed and time

Chapter 2 ................ The triangle

Chapter 3 ................ The 1 in 60 rule

Chapter 4 ................ Compasses

Chapter 5 ................ Weather 

Instructors’ Guide

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DISTANCE/SPEED/TIME

CHAPTER 1

32.3.1-1

DISTANCE/SPEED/TIME

Introduction

1. Aircrew will always need to know how long it will take for an aircraft to fly from

 A to B, maybe just to deliver passengers or payload on time but also because

aircraft, unlike cars, cannot afford to run out of fuel. Regular checks have to be

made that the time of arrival will occur before the fuel has all been used. To do this,

it is necessary to know how far the aircraft has left to fly and how fast it is going over 

the ground.

Distance On The Earth

2. Although the Earth is not perfectly round, we users of maps can safely assume

that the Earth is a sphere. In ACP 32 Volume 1 we learned that the Latitude/Longitude

grid divides the surface of the Earth into degrees and minutes. One minute of latitude

represents one nautical mile (nm) and 1 degree of latitude (60 minutes) equals

60nm. As a complete circle is 360°, the 360 x 60 gives the circumference of the

Earth as 21600 nm (approx 25000 statute miles). Notice that on nautical maps or 

charts there are no scales on the borders, so we have to use the nm scale which is

shown along each meridian. Note also that the scale along the parallels is not used

because convergence shrinks the scale considerably in the British latitudes, and

even more near the Poles.

The nautical mile

Scales on parallels are

not used 

Fig 1-1 RAF en-route

chart 

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3. In the example above, measure the distance between Shawbury and

Birmingham, using the nm scale printed on the 02°

West Meridian. This can bedone with a ruler, a pair of dividers, or if you do not have any equipment, using the

marks on the edge of any piece of paper.

Change Of Latitude

4. If two places are on the same meridian then it is possible to calculate the

distance between them rather than having to measure it; this is much simpler if 

several map sheets are involved. For example Torrejon airfield (near Madrid in

Spain) is due south of RAF St Athan. The two latitudes are N40°29’ and N51°24’.Subtracting one latitude figure from the other gives a change of latitude of 10°55’.

Multiply 10° by 60 and add the 55’ to find that Torrejon and St Athan are 655nm

apart. However, very few air journeys are made along meridians so to find out how

far apart other airfields are, we either have to measure the distance on a suitable

small-scale chart or allow our navigational computer to do the calculation for us

using spherical trigonometry.

 Aircraft Speed

5. We measure the speed of land-based vehicles (eg cars, bicycles) in miles

per hour (mph). In aviation, as we use nm to measure distances, it follows that

speed is measured in nm per hour (known as knots from the days of the sailing

ships). The other difference from land-based vehicles is that as aircraft are not on

the ground, the speed of rotation of the wheels cannot be used to drive a

speedometer. As the aircraft flies through the air we use an instrument called an Air 

Speed Indicator (ASI) to measure the “Dynamic Pressure” which is the pressure

caused by the forward motion of the aircraft. We achieve this by measuring the

difference between the pressure of the air surrounding the aircraft (atmospheric or 

“Static Pressure”) and the pressure of the air captured in the Pitot Tube (“Pitot

Pressure”), which is made up of static and dynamic pressure.

32.3.1-2

CHAPTER 1

Find the distancebetween 2 places

Distance between

 places on the same

meridian

Units of speed 

 Air speed indicator 

Fig 1-2  A simplified Air 

Speed Indicator 

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32.3.1-3

DISTANCE/SPEED/TIME

 A simplified ASI is shown in the diagram. In forward flight the pressure above the

diaphragm will consist of dynamic and static pressure whilst the pressure below ispurely static pressure. The two static pressures cancel out and the diaphragm will

move due to the dynamic pressure, this movement is amplified and displayed on

the instrument as Indicated Air Speed (IAS), reading in knots.

Corrections

6. The reading on the ASI can be in error because of two errors, namely Pressure

Error and Instrument Pressure. Pressure Error previously known as position error 

is caused by sensing incorrect values for Pitot and Static pressure due to their position relative to the airflow around the aircraft. Instrument error is caused by

poor manufacturing tolerances when the instrument was built. Both errors can be

measured by testing the aircraft under controlled conditions and a calibration card

with the combined errors is displayed in the cockpit next to the instrument. Once

the two errors have been accounted for, we are left with Calibrated Air Speed (CAS).

IAS + Pressure Error + Instrument Error = CAS

Thus, an IAS of 118 kts with a correction on the calibration card of +2 kts would give

a CAS of 120kts.

7. A pilot flies using Calibrated Air Speed because it represents the force of the

airflow around the aircraft. The higher an aircraft flies, the less dense the air becomes

and the faster the aircraft has to fly through the air to achieve the same force and

therefore the same CAS. A navigator however, needs to know the actual speed that

the aircraft is flying through the air so that he can compare it with his speed over the

ground and hence estimate the wind.

8. Therefore to obtain True Air Speed (TAS) from CAS you need to correct for 

air density changes caused by changes in temperature and altitude. This can be

done either calculation or by a navigation computer. In additrion of you are flying at

speeds greater than 300 kts then you need to apply a correction for compressibility

error which is caused by air becoming compressed in the Pitot Tube.

CAS + Density Error + Compressibility Error = TAS

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Units of Time

9. Time is probably the only example of a scientific measurement where every

nation uses the same units. Everyone is familiar with days, hours and minutes; it is

only necessary to ensure that you use hours when working with knots as this speed

is actually nautical miles per hour. In military and commercial aviation the 24 hour 

clock is used, set to Greenwich Mean Time (GMT) or Universal Time (UT) as it is

now known. In other words, Summer time or Daylight Saving Time is always ignored.

Calculation of Time of Flight (Still Air)

10. If a car travels 120 miles at 60 mph, it will take 2 hours to complete the

 journey. This is found by the DST formula:

TIME (T) = = = 2  

SPEED = DISTANCE = SPEED X TIME  

11. This same Formula can be used for an aircraft flying in still air. For example,

a Nimrod flying at a TAS of 400 kts over an 1800 nm sector will take 41/2 hours in still

air.

SPEED =

12. The formula can also be re-arranged to find distance or speed if the other 

two quantities are known; thus:

13. This example is done for you. How fast must we go to cover 1500nm in 5

hours?

DISTANCE (D)

SPEED (S)

120 

60 

DISTANCE 

TIME 

DISTANCE 

TIME 

The DST formula

32.3.1-4

CHAPTER 1

Which time do we use? 

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1500 

Using:

s = = 300 kts

Manipulation of equations

Simple equations can be easily manipulated using cross multiplication. That is,

numbers on one side of an equation can cross the equals sign to the other side

provided that, if the number is below the line (division) when it changes side, it

comes above the line (Multiply) and visa-versa. For example:

DISTANCE = SPEED x TIME = SPEED

DISTANCE = SPEED x TIME = TIME  

32.3.1-5

DISTANCE/SPEED/TIME

DISTANCE 

TIME 

DISTANCE SPEED

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32.3.1-6

CHAPTER 1

Do not mark the paper in

any way - write your 

answers on a separate

 piece of paper.

Self Assessment Questions

1. One degree of latitude represents:

a. 1 nm

b. 6 nm

c. 60 nm

d. 360 nm

2. Glasgow is due north of Plymouth (approximately on the same meridian). If Glasgow is latitude 55°50’ and Plymouth is latitude 50°25’ what distance are the

two places apart?

a. 525 nm

b. 275 nm

c. 450 nm

d. 325 nm

3. In the RAF, aircraft speeds are generally expressed in:

a. metres per second

b. miles per hour 

c. nautical miles per second

d. knots

4. An ASI has an instrument correction factor of +3 kts and a pressure correction

factor of -1 kts. If the instrument reads 130 kts what is the RAS?

a. 130 kts

b. 132 kts

c. 133 kts

d. 134 kts

5. A Tornado is flying at a TAS of 400 kts. How far will it travel in 2 hrs?

a. 200 nm

b. 200 km

c. 800 nm

d. 800 km

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32.3.2-1

TRIANGLE OF VELOCITIES

CHAPTER 2

Representing vectors

Vectors can be added 

together 

THE TRIANGLE OF VELOCITIES

Introduction

1. So far, we have talked about flying in still air conditions. It is now necessary

to consider the wind, which is simply air that is moving.

Vectors and Velocity

2. Whenever we talk about aircraft or wind movement, we must always give

both the direction and speed of the movement. Direction and speed together are

called a velocity. A velocity can be represented on a piece of paper by a line called

a vector. The bearing of the line (usually relative to true north) represents the direction

of the movement, and the length of the line represents the speed.

The Vector Triangle

3. Let us begin with a situation in everyday life which we can easily relate to the

vector triangle. Imagine two children, one either side of a river, with a toy boat

driven by an electric motor. The boat has a rudder to keep it on a straight course

and has a speed of 2 knots. Child A stands on the southern bank and points the

boat at her friend on the other side of the river. If the river is not flowing the boat willcross the river at right angles and reach child B on the other side.

Fig 2-1 Representation of 

vectors

Fig 2-2 When the water in the river is not moving 

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4. However, rivers flow downstream towards the sea, so let us look at a river 

where the speed of the current is 2 knots. Picture child B putting the boat in thewater pointing at his friend. Where will the boat reach the other bank?

5. The vector triangle solves this problem for us. In Fig 2-3, the velocity of the

boat is shown as the line with the single arrow crossing the river, and the water 

velocity is the line with three arrowheads pointing downstream. The two lines are

the same length as they are both representing speeds of 2 knots. By joining the two

ends to make a triangle, the third side of the vector triangle (called the resultant and

indicated with two arrowheads) represents the actual movement of the boat as it

crabs across the river. By use of Pythagoras’s theorem it can be shown that thespeed of the boat over the riverbed is 2.83 knots. So, child A has to walk downstream

to point C to collect the boat. If she now wishes to send the boat back to B, without

making child B walk along the bank, she must walk upstream twice as far (to a point

D - see below) before launching the boat again on a heading at right angles to the

stream. Another solution is possible if child A can alter the speed of the boat, she

can go to point A, set the speed to 2.83 knots and launch the boat pointing at E,

because it will then travel directly from A to B as required.

Fig 2-3 When the water in the river is moving 

Vector Triangle

Fig 2-4

32.3.2-2

CHAPTER 2

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The Air Triangle

6. Exactly the same triangle can be used to show the motion of an aircraft through

the air which itself is moving. There are two differences. The first is that we label the

triangle with new names (eg wind instead of current).

The second is that as the aircraft speed is normally a lot more than the wind speed,

the triangle will be much longer and thinner than the squat triangle which represents

the movement of the toy boat. There are 6 components of the air triangle, and they

are described in the next 3 paragraphs.

Heading and TAS

7. The heading of the aircraft is the direction that the aircraft is pointing (ie what

is on the compass). The TAS is the speed of the aircraft through the air, taking into

account all the corrections mentioned in Chapter 1. This vector, shown by a line of 

scale length, carries one arrow. Remember, the vector represents 2 components,

HDG and TAS.

Wind Velocity

8. This is a scale line with three arrows; it represents 2 more components, the

wind strength and the direction FROM which it is blowing (northerly in the diagram).

Track and Groundspeed

9. The remaining 2 components in the air triangle are the direction and speed

that the aircraft is actually moving over the ground. This vector has two arrows, and

it is the resultant of the other two vectors. note that the number of arrows put on

each vector is simply a convention that is used, to avoid confusing one with another.

Fig 2-5  Air triangle of 

velocities

The air triangle of velocities

Some definitions

32.3.2-3

TRIANGLE OF VELOCITIES

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Drift

10. Drift is the angle between the heading and track vectors and represents the

angle at which the aircraft is being blown sideways. It is labelled Port or Starboard,

depending on which way the aircraft is blown. Of course, if you fly directly into wind

or directly downwind, heading will be the same as track and there will be no drift.

The TAS and GS will in this case differ by exactly the value of the wind speed.

The Real World

11. All this theory is very well but what happens in the real world? There are

three possible occasions when we have to solve the vector triangle. One is at the

planning stage of a flight, when we know where we want to go, in which case we

know what the track and distance is to the destination. We also know the performance

of the aircraft (TAS) and the Met Office can forecast the W/V for us. Given 4 of the

6 elements in the triangle (TAS, TK, W/V) it is now possible to solve for the other 

two quantities (GS & HDG) and then use the DST formula to calculate how long the

flight will take. The second occasion on which we solve the triangle is in the air 

when we know the TAS and HDG, and we can measure our TK and GS by watchingour changing position over the ground. From these 4 items, the W/V can be

calculated. Finally, when you know your heading and TAS and have a reliable W/V

but are over a featureless area such as the sea and are unable to take any form of 

fix, then by applying the W/V to your Heading and TAS you can calculate your Track

and Groundspeed. Once you have your G/S and TK you can produce a deduced

reckoning position (DR position) by applying the time from your last known position

to the G/S to give you a distance along the TK.

Computers

12. So far we have only talked about drawing vectors on paper. This is fine in the

office or classroom but impossible in the cramped confines of a small aircraft. For 

many years, navigators have been using the Dalton hand held computer and these

are still used in the private flying world. The fast jet navigator in the RAF solves the

triangle using a simplified mental calculation which is beyond the scope of this

course. In civil airliners an onboard electronic computer continually solves the triangle

and many other things besides.

32.3.2-4

CHAPTER 2

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32.3.2-5

TRIANGLE OF VELOCITIES

Magic Number 

13. All aviators, no matter how much help they have from electronics, have to do

a lot of mental arithmetic. This can be made much easier if magic numbers are

used. The number in question is the ground speed in nautical miles per minutes;

some examples are shown in the table below. It does not matter if you are flying in

a Bulldog or a Tornado, the method works equally well.

GS nm/min GS nm/min

60 1 210 31/2

80 11/3 240 4

90 11/2 300 5

100 12/3 360 6

120 2 420 7

150 21/2 480 8

180 3 540 9

Examples

14. Your are in a Tornado at low level over Wales, doing 420 knots GS and you

have 49 miles to run to the next turning point. Divide 49 by 7 and the answer is 7

minutes to go.

15. You are on a cross country exercise in a Bulldog, heading into wind at 80

knots GS. How long will a 20 mile leg take? To divide 20 by 11/3, is the same as

dividing by 4/3 or multiplying by 3/4. However, there is a much easier method in thisexample. As the distance is 1/4 of the speed, it must take one quarter of an hour.

Magic numbers

Fig 2-6 The RAF’s Dalton computer 

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Six Minute Magic

16. With the slower speeds it is often easier to think in terms of how far do we go

in 6 minutes (1 tenth of an hour). This simply is the ground speed with the last zero

removed. So the Bulldog above doing 80 knots, will travel 8 miles in 6 minutes. For 

short legs this is a much more useful calculation.

Time Of Arrival

17. A by-product of solving the triangle is that by making the DST calculation

using GS and Distance To Go, we can calculate the time that it will take to reachthe next turning point or the destination. This time is called Estimated Time of 

 Arrival (ETA) and is important both for fuel calculations and for Air Traffic Control

purposes. A particular application of this is the ETA for the destination. If you do not

arrive on time, Air Traffic will have to take overdue action; very similar to the way a

search party goes out to find a group of walkers who have not returned from a

mountain trek.

Conclusion

18. Hopefully this chapter will have convinced you that despite all the computers,

some mental arithmetic is essential, whether you plan to join the RAF as aircrew,

become an airline pilot, obtain a PPL, or simply make the most of the available air 

experience and passenger flying opportunities. The starting point is the 6 times

table; no one in their right mind would dream of aviating without this knowledge.

32.3.2-6

CHAPTER 2

Six minute magic 

ETA

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TRIANGLE OF VELOCITIES

Do not mark the paper in

any way - write your 

answers on a separate

 piece of paper.

Self Assessment Questions

1. What do the initials TAS stand for?

a. True Air Speed

b. Track Air Space

c. Track Aviation Speed

d. True Air Space

2. The 4 vectors shown represent the movement of 4 aircraft. Which aircraft istravelling due south?

a. W

b. X

c. Y

d. Z

3. In the diagram above which aircraft is travelling the fastest?

a. W

b. X

c. Y

d. Z

4. In an Air Triangle vector diagram the 3 vectors are:

a. Heading and TAS - Drift angle - Wind speed and direction

b. Track and ground speed - Wind speed and direction - Drift velocity

c. Wind speed and direction - Track and ground speed - Heading and TAS

d. Wind speed and direction - TAS and heading - Drift speed and direction

5. A Bulldog when travelling at a GS of 90 kts will cover 11/2 nm in one minute. How

long will it take to cover 30 nm?

a. 20 mins

b. 30 mins

c. 45 mins

d. 60 mins

32.3.2-7

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32.3.3-1

CHAPTER 3

CHAPTER 3

THE 1 IN 60 RULE

Introduction

1. In modern aircraft it is often necessary to do quick mental calculations to

check that the navigational computer is still making sense and that we have not

fallen into the “garbage in, garbage out” trap. The previous chapter looked at progress

along track (DST and ETA); we now need to consider our position across track.

First though, a couple of definitions.

Track Required

2. The track required is normally the line drawn on the map between the

departure airfield and the destination, or from one turning point to another on the

route.

Track Made Good

3. If for some reason the aircraft drifts off track and we can establish our position

overhead some unique feature (a pinpoint), then the line joining the departure airfield

and the pinpoint is known as Track Made Good (TMG).

Revised Track

4. From a pinpoint which is off the track required we have 2 options. One would

be to regain the required track, but more normally we would draw a line from the

pinpoint to the next turning point. This is called the revised track.

1 In 60 Rule

5. The 1 in 60 rule states that if an aircraft flies a TMG 1° in error from the

required track, then after 60 miles of flying the aircraft will be one mile off the required

track. This can be proved with trigonometry but all you need to know is how to use

the triangle. The example in the diagram shows that with a 10° track error, after 60

nm the aircraft would be 10nm off track.

The 1 in 60 rule

Some definitions

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THE 1 IN 60 RULE

32.3.3-2

6. The 1 in 60 rule holds good for track errors up to 23°

beyond that the differencein the length of the two tracks (TMG and Track required) becomes too great and the

approximation will not work.

 Application Of 1 In 60 Rule

7. The simplest application of the 1 in 60 rule is when a pinpoint is taken exactly

halfway along track. From the diagram below you can see that the triangle formed

as the aircraft drifts off track is exactly mirrored by the triangle showing the aircraft

regaining track.

8. As the triangles are the same size and shape, it is only necessary to alter 

heading to the right by twice the track error to ensure that the aircraft reaches point

B (assuming that the wind remains constant). As the pinpoint is taken halfway along

track, the actual distances do not affect the results, but in the next example the only

pinpoint available is one third of the way along track so some sums are needed.

Fig 3-1 After 60 nm the

error is 1 nm for every 1°  

off track 

Fig 3-2  A pinpoint is

taken exactly halfway along the track 

Pinpoint 1 / 2 way along 

track 

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THE 1 IN 60 RULE

32.3.3-4

11. Once you understand the method and can do the mental arithmetic, you can

then omit the drawing of the triangles in Figs 3-4 and 3-5. Putting these figuresback into the original problem from Fig 3-3, you can see that the track error angle

and the closing angle are added together to give 18°, this is the amount that you

need to turn right in order to regain track at point B.

Practical Application

12. The 1 in 60 rule is used a great deal in both military and civil flying. Because

pinpoints are not always available when we want them, we are often left with awkward

numbers that do not lend themselves to mental arithmetic. The solution is to use

approximate numbers that are easily handled, either round numbers like 20, 30, 40

or those divisible by 6. Bear in mind that the answer is only needed to whole degrees

so ultimate accuracy is unnecessary. Remember also, that once a pinpoint is found,

it takes you a measurable time to do the calculations, during which time you are

drifting further off track so if you have any rounding up to do, ensure that you turn

more than the precise calculation rather than less.

Keep it simple

Fig 3-6  Adding the TE 

and CA gives the amount 

of turn required 

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COMPASSES

32.3.4-1

CHAPTER 4

COMPASSES

Introduction

1. Earlier in your Navigation training, you will have learned about the difference

between True North and Magnetic North and how to use a simple hand held compass

such as the Silva. To understand aircraft compasses, their strengths and weaknesses

we need to look into the subject a little deeper. The first thing you need to understand

is the shape of the magnetic field around a magnet. An experiment at school with

a magnet and iron filings, will produce a pattern similar to that shown in Fig 4-1

below.

I have included a circle round the magnet in Fig 4-1 to signify the Earth and you will

note that the lines of force are only parallel to the surface of the Earth at the Equator.

Indeed, at the poles the lines of force are vertical! A compass needle will try to

follow the lines of force but is restrained by the construction of the compass and is

forced to stay horizontal. The end result of this is that the directional force that

makes the compass needle point North gets weaker the closer you get to the Earth’s

Magnetic Poles. At our latitude, the lines of force point down at an angle (known as

the angle of Dip) of 65°; once the angle exceeds 75° (which occurs about 1200

miles from the Poles) the driving force becomes so weak as to render magnetic

compasses virtually useless.

Fig 4-1 Magnetic Lines of force round a bar magnet 

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32.3.4-2

CHAPTER 4

2. In an aircraft, the simplest form of compass is the direct indicating compass,

which looks very similar to the car compass, which can be bought from accessory

shops.

The Direct Indicating Compass

3. The Direct Indicating Compass (DIC), like the hand held Silva compass, has

a magnet suspended in a thick liquid, which helps to dampen the movements.

However, it looks very different, having the appearance of a squash ball inside a

very small goldfish bowl. The points of the compass are printed around the equator 

of the ball and the heading is shown against the index mark on the bowl. The

magnet is hidden inside the ball.

Limitations of the DIC

4. The DIC has several serious limitations, so in most aircraft it is only used asa standby. These limitations are:

a. The suspended magnet will only give a correct reading in straight and

level un-accelerated flight. During turns and accelerations the magnet is

swung to one side and thus gives false readings.

b. The DIC is located in the cockpit, and there it is affected by the magnetic

fields emanating from the metal the aircraft is made from and from the various

electrical circuits in the aircraft. These other magnetic fields badly affect the

accuracy of the DIC.

Fig 4-2 The direct indicating compass (DIC)

in a Viking 

DIC 

Limitations and advantages

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accurate than the DIC because being situated on the wing tip it is less affected by

extraneous magnetic fields). During a turn however, when the detector unit isunreliable, the turn/acceleration cut out switch allows the gyro to operate on its own

until the turn is complete. The amount of error caused by the uncorrected gyro in

the turn is insignificant and is in any case removed once the detector unit is

reconnected.

8. A gyro magnetic system has considerably more torque than a DIC and can

therefore provide outputs to repeater units in other parts of the aircraft or to computer 

systems. The output to these repeaters can be easily modified so that they can

display True heading if required.

Gyro Errors

9. A gyro suffers from both real and apparent errors. Real errors are caused by

inaccuracies during manufacturing but in a modern compass gyro these are usually

less than one degree an hour. Apparent errors called as such because the gyro

appears to be in error are caused because we fly around a rotating Earth. Imagine

aligning a gyro so that it points at the rising sun, ignoring any real errors the gyrowill continue to point at the sun until it sets in the evening. Now to an observer on

Earth, the gyro will appear to have slowly changed direction from East through

South to West, yet someone watching from space will have seen that the gyro

continued to point in the same direction and it was in fact the Earth that rotated.

 Apparent errors caused by the Earth’s rotation or by flying round the Earth follow

simple mathematical formulae and are easily corrected, in many cases they are

compensated for automatically using a correction box built into the compass system.

Inertial Navigation

10. The fundamental problem with any system that relies on Magnetic North to

find True North is that our knowledge of variation (the difference between True and

Magnetic) is seldom better than one degree. This can cause hourly position errors

of up to 6 nautical miles per hour. The Inertial Navigation System (INS) eliminates

this problem and provides True Heading without the need of a magnetic detection

system. An INS uses accelerometers to detect rate of change of position and by

using a mathematical process called integration it can obtain speed from acceleration

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and distance from speed. Therefore providing you accurately know your start point

you can ascertain your position at any moment in time. It is essential that theplatform to which the accelerometers are attached is accurately aligned and

absolutely level to achieve this high quality gyros are employed. When an INS is

set up prior to flight, it automatically aligns the platform to True North by detecting

the Earth’s rotation; the platform will then provide an output of True Heading. An

accurate INS will provide positional information to an accuracy of less than one

nautical mile per hour.

The Future

11. Older Inertial navigation Systems used mechanical accelerometers, Gyros

and integrators and a complicated system of gimbals to keep the platform level and

aligned. These systems though accurate were prone to break down and took an

enormous amount of time to service. Modern advances have cured most of this

and a modern INS uses solid-state integrators and accelerometers, and Ring Laser 

Gyros. Even the platform can be dispensed with now and instead a fast modern

digital computer carries all the details of the aircraft’s direction and attitude. These

changes do not have a dramatic effect on the accuracy of the system; however,

they greatly enhance the reliability and reduce the servicing overheads. Combining

the INS with a modern satellite navigation system will provide a very powerful and

accurate navigation/attack system, which can be used world-wide and which is

very resistant to jamming.

COMPASSES

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Self Assessment Questions

1. The initials DIC stand for:

a. Dual Identification Compass.

b. Direct Identification Compass.

c. Direct Indicating Compass.

d. Dual Indicating Compass.

2. Having a simple magnetic compass in the cockpit of an aircraft has both

advantages and disadvantages. One such advantage may be:

a. Reads only magnetic headings.

b. Simple in operation but reliable.

c. May be affected by other instruments close by.

d. Swings about during aircraft manoeuvres.

3. The flux valve of a GMC is situated:

a. In the wing tip.

b. In the cockpit.

c. Inside the compass housing.

d. On the outside of the fuselage.

4. An Inertial Navigation System (INS) works by:

a. Frequent checks on position from satellites.

b. Using computers to keep a record of the aircraft’s movement from a known

starting point.

c. Using computers to continually work out the error in the magnetic readings

and compensate accordingly.

d. Frequent checks on position using ground based radar stations.

Do not mark the paper in

any way - write your answers on a separate

 piece of paper.

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WEATHER

32.3.5-1

CHAPTER 5

VMC and IMC 

Conditions affecting 

flying 

WEATHER

Introduction

1. You will have previously studied the weather as it relates to walking in the

hills. It is the same weather that affects aircraft operations but with one major 

difference; icing is a far more serious problem for an aircraft than it is for a walker.

Meteorological Conditions

2. Simple aircraft such as basic trainers are not equipped with instruments to

enable them to safely fly in cloud or fog, nor do their student pilots have sufficient

experience. Consequently, it is necessary to define the weather conditions in which

beginners may fly. These are called Visual Met Conditions (VMC) and a simplified

version of the rules are set out in the table below.

ABOVE 3000’ BELOW 3000’

Visibility - 8km or better Visibility - 5km or better  

Distance from cloud: Distance from cloud:

1000’ vertically 1000é vertically

1500m horizontally 1500m horizontally

NB Aircraft flying below 140 kts and in sight of the ground

may use 2 km visibility and merely have to keep clear of 

the cloud.

3. It follows that if an aircraft flies in weather worse than shown in the table, it

must have the necessary instruments to fly in or near to cloud or in poor visibility.

This weather is known as Instrument Met Conditions (IMC). Only aircraft with suitable

equipment and pilots with suitable instrument ratings may fly in IMC.

The Visual Circuit

4. In the early stages of flying, a trainee pilot will not want to lose sight of the

runway when flying circuits in order to practice take-offs and landings. To achieve

this, VMC is needed and normally the aerodrome controller will decide if the weather 

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is good enough. If the circuit height is 1000’ then the lowest cloudbase will need to

be above this (usually 1500’) and the visibility will need to be good enough to beable to see the runway from anywhere in the circuit (usually 5 km).

Surface Wind

5. In earlier chapters on navigation you will have learned how we deal with wind

and drift when transitting from A to B. At the aerodrome we still have to take account

of drift but the surface wind is of greater concern. If the conditions are not completely

calm, we need to take note of the wind direction and arrange to take-off and land as

closely as possible, directly into wind. This is because the airspeed of the aircraftdetermines when it can safely lift off the runway. In strong winds this can make a

big difference to the time and distance it takes to get airborne. Into a strong wind an

aircraft reaches flying speed very quickly and can therefore use a shorter runway. If 

we make the mistake of trying to take-off downwind we could well reach the end of 

the runway before reaching flying speed and this could be disastrous.

Wind Component

6. It is very rare to find the wind blowing exactly along the runway, even though

runway directions are chosen to take account of the prevailing wind. Normally the

wind will blow partly across the runway and we need to be able to calculate how

much crosswind and how much headwind there is. This can be done by drawing

vectors (see below) but it is more normal to consult a table (Fig 5-2) or alternatively

use a simple mental method which gives approximately the right answer (Fig 5-3).

Take off into wind 

Headwinds and 

crosswinds

Fig 5-1 Wind vector 

calculation on an east/ 

west runway 

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How to use the table

From Fig 5-1 the angle between the runway heading and the wind direction = 40°

(angle off). To obtain the crosswind component use the top row of angles and find

the 40° colum - follow it down until you meet the correct windspeed row, in this case

20 kts. This gives the cross wind component as 13 kts. For the headwind use the

angles at the bottom of the table.

Fig 5-2 Table showing headwind and crosswind components

Fig 5-3 The quick approximate method 

WEATHER

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Do not mark the paper in

any way - write your 

answers on a separate

 piece of paper.

Self Assessment Questions

1. What do the initials VMC stand for?

a. Visual Meteorological Conditions

b. Verbal Meteorological Conditions

c. Visual Metric Conditions

d. Verbal Metric Conditions

2. An aircraft should always take off into wind to:

a. Increase the length of take off run

b. Decrease the length of take off run

c. Increase ground speed at take off 

d. Reduce air speed at take off 

3. While attempting to land on runway 09 (heading of 90°) a pilot is informed of a

surface wind blowing at 25 kts on a heading of 140°. Using the table in Fig 5-2 find

the strength of the cross wind.

a. 16 kts

b. 19 kts

c. 22 kts

d. 23 kts

4. Why is icing such a problem for aircraft?

a. De-icing is expensive and time consuming

b. The aerofoil shape of wings is spoiled - decreasing lift

c. The aircraft has to fly slower due to poor visibility

d. More power is required to keep the inside of the aircraft warm

4. Rain, sleet, snow and hail are collectively known as:

a. Participation

b. IMC

c. Precipitation

d. VMC

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 Aircraft speed is normally measured in the maritime tradition using the knot, although at speeds

approaching, or beyond, the speed of sound another important units needs to be added. This unit

is the “Mach” number.

9. The mach number relates the aircraft’s speed to the local speed of sound. It may be more

precisely defined as the ratio of the speed of the aircraft through the air, to the speed of sound in

the aircraft’s vicinity.

This is shown in the following formula:

Mach Number = True Air Speed

Speed of Sound

10. Simply, if an aircraft is flying at half the speed of sound, then it will have a mach number of 

0.5.

11. The speed of sound varies according to the temperature surrounding the aircraft. At high

level, where temperature is low, the speed of sound is less than at sea level, so that the mach

meter is designed to take care of two variables - the variation of aircraft speed, and the variation of 

the speed of sound.

1° = 60 nm

therefore

10° x 60 = 600 nm

1’ = 1 nm

so 55’ = 55 nm

TOTAL = 655 nm

 AERONAUTICAL CHARTS

 A map, or chart, is primarily intended to portray sections of the Earth’s surface on a flat sheet of 

paper. The manner in which meridians and parallels are drawn, and the information overprinted on

the surface depends on the purpose of the map. An atlas for example may need to portray largeareas with the locality of certain features clearly indicated. Its purpose is usually to give geographical

information, and to do this, the cartographer may show parallels and meridians as straight parallel

lines which lie at right angles to one another, or, he may show meridians as converging straight

lines and parallels as arcs of concentric circles centred on the nearer pole. If the atlas fails to

accurately represent angles correctly over the whole area, then, quite apart from the small scale

being used, it would not form a suitable projection of the Earth’s surface to be useful for navigational

purposes. The requirements of navigational charts vary however according to their particular 

application.

It is important now to distinguish clearly between the words “projection”, “chart”, and “map”, since

these words are frequently used in this chapter and elsewhere.

 A projection is an arrangement on a flat sheet of paper, of a graticule of meridians and parallelswhich are assumed to be on the Earth’s surface. All maps and charts are therefore projections of 

one sort or another.

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 A chart is a projection which carries very little topographical detail and which is mainly used for 

navigational plotting.

 A map is a projection over which are printed details of topography, culture and other geographical

information.

THE KNOT

The unit of measurement of a vessel’s speed, corresponding to one nautical mile per hour. The

knot originated from sailing ships who measured their speed by attaching a float to the end of a

rope which had knots tied every 7 fathoms (12.8m) along its length. The float was then lowered into

the water and the number of knots paid out in 30 seconds was the speed of the ship.

INSTRUCTOR’S GUIDE

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 Answer: Track made good is 251(T), and ground speed 264 knots.

The navigation computer 

In the previous chapters the graphical construction of the triangle of velocities was described in

order to solve some of the fundamental problems presented in air navigation. In practice however,

a navigator should avoid wherever possible carrying out time wasting calculations, and in order to

do this he is helped by a purpose-built mechanical aid known as a Navigation Computer. The

navigation computer is virtually standardized in design, and is used to solve more than simply the

triangle of velocities. On the reverse of the computer there is a circular slide rule capable of solving

general arithmetical problems, and in particular those which are directly concerned with the general

business of navigation. There are a variety of different navigation computers on the market, but

they all fall fundamentally into the same physical appearance with minor modifications or additions

to suit particular aircraft requirements.

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32.3.2c NOTES

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 ANSWER SHEET

Self Assessment Questions - Answer Sheet

Chapter 1 Page 32.3.1-6

1. c

2. d

3. d

4. b

5. c

Chapter 2 Page 32.3.2-7

1. a

2. c

3. b

4. c

5. a

Chapter 3 Page 32.3.3-5

1. c

2. c

3. b

4. c

32.3.4b ANSWER SHEET

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Self Assessment Questions - Answer Sheet cont....

Chapter 4 Page 32.3.4-6

1. c

2. b3. a

4. b

Chapter 5 Page 32.3.5-6

1. a

2. b

3. b

4. b

5. c

 ANSWER SHEET