newton’s laws continued

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Newton’s Laws Continued

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Newton’s Laws Continued. Question: For each question, make sure to draw an accurate free body diagram!. What is the net force on a 15 kg box that is sitting on a table?. What is the net force on a 15 kg box that is being pulled to the left with 40 N of force and 28 N to the right?. - PowerPoint PPT Presentation

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Page 1: Newton’s Laws Continued

Newton’s Laws Continued

Page 2: Newton’s Laws Continued

Question:For each question, make sure to draw an accurate free body diagram!

What is the net force on a 15 kg box that is sitting on a table?

What is the net force on a 15 kg box that is being pulled to the left with 40 N of force and 28 N to the right?

Page 3: Newton’s Laws Continued

Question:For each question, make sure to draw an accurate free body diagram!

What is the net force on a 15 kg box on a frictionless surface that is moving at a constant velocity of 4 m/s to the right?

What is the net force on a 15 kg box on a frictionless surface that is accelerating to the right at a rate of 3 m/s2?

Page 4: Newton’s Laws Continued

Can you do this one?What is the acceleration to the right of a 15 kg box sitting on a frictionless surface if you pull it from a rope at an angle of 30 degrees from the horizontal?

Ack! We don’t know how to do this!!!!! I know! We need…

TRIGONOMETRY!

Page 5: Newton’s Laws Continued

TrigonometryTrig is a set of useful rules for finding various parts of a triangle.

Page 6: Newton’s Laws Continued

Vector ComponentsAny vector can be broken up into two perpendicular components that lie along the x axis and along the y axis.

y c

ompo

nent

x component

-We call these the x and y components of a vector.

-You can think of an individual component of a vector as the shadow it would cast on either the x axis or the y axis.

Page 7: Newton’s Laws Continued

Components

y c

ompo

nent

x component

y c

ompo

nent

al

so

Page 8: Newton’s Laws Continued

Back to the original question:What is the acceleration to the right of a 15 kg box sitting on a frictionless surface if you pull it from a rope at an angle of 30 degrees from the horizontal?

Lets break it down into components:

Page 9: Newton’s Laws Continued

Naming right trianglesWhen using trigonometricratios, once you pick anangle, you give newnames to the legs.

• For instance, if you chose , you now will renamethe sides.

Hypotenuse

adjacent

opp

osite

• If you choose β, you willrename the sides asshown.

β a

djac

ent

opposite

Hypotenuse

Page 10: Newton’s Laws Continued

The story of Sohcahtoa

SOHSin Opposite Hypotenuse

CAHCosine Adjacent Hypotenuse

TOATangent Opposite Adjacent

Page 11: Newton’s Laws Continued

Taking the inverse

How would I find the opposite side using the sin function?

(hyp)*sin() = opp

Page 12: Newton’s Laws Continued

Back to the original question:What is the acceleration to the right of a 15 kg box sitting on a frictionless surface if you pull it from a rope at an angle of 30 degrees from the horizontal?

Now we can use trig to figure out what the components of the force are, and in tern, the answer to the question!

Page 13: Newton’s Laws Continued

What if I want to find an angle?

20 cm

12 c

m

Here we know the opposite side and the hypotenuse.

So we will use the sin function

Sin-1(opp/hyp) =

- this is called the inverse sin function

= 36.87 degrees

Page 14: Newton’s Laws Continued

Frictional ForceFriction is a force that opposes motion.

Draw a free body diagram of a 20 kg box that is being pushed to the right with a force of 50 N and there is a 30 N frictional force.

Page 15: Newton’s Laws Continued

Types of frictionStatic Friction: The frictional force that exists between two surfaces when they are stationary

Kinetic Friction: The frictional force that exists between two surfaces when the objects are moving across each other (like a book sliding on a table)

Both of these types of friction can be calculated by using the coefficient of friction (either the coefficient of static friction or the coefficient of kinetic friction.)

Page 16: Newton’s Laws Continued

Coefficient of FrictionA value that is different for any two surfaces.

- It is a constant that can be used to help calculate the force due to friction if you know the normal force of an object.

Ff = FN

Mu (like the pokemon)

is usually in between zero and one

Page 17: Newton’s Laws Continued

Coefficient of FrictionThe coefficient of static friction tends to be greater than that of kinetic friction

Another way to think about what is, is how “sticky” the interaction between two surfaces is.

- The greater the , the greater the friction.

Page 18: Newton’s Laws Continued

QuestionsIf the coefficient of friction between your tires and the road is 0.2, and the car has a mass of 1700 kg, what is the frictional force between the tires and the road?

Page 19: Newton’s Laws Continued

QuestionsA car with a mass of 700 kg is breaking hard. If the car is traveling at an initial velocity of 15 m/s, and takes 3 seconds to stop, what is the coefficient of friction between the tires and the road? (draw a free body diagram)

Page 20: Newton’s Laws Continued

Mu of the shoe

Page 21: Newton’s Laws Continued

Here’s a doozyIf this 15 kg box is sliding down the hill at a constant velocity, what is the frictional force between the box and the incline?

30o

Page 22: Newton’s Laws Continued

Thought questionWhy is it impossible to make a piece of string completely horizontal and straight if you hang a mass from the center?