nguyen minh duc_chuan

8/6/2019 Nguyen Minh Duc_chuan

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Thit k cung cp in cho mt xng sn xut cngnghip

n 1

Thit k cung cp in cho mt xng sn xut cng nghip

Sinh vin: Nguyn Minh c

Lp: 4LT-H3

I. D kin:

Thit k cung cp in cho mt xng sn xut cng nghip

Xng ny c trang b 15 loi thit b tiu th in. S liu v kch thc ca phn

xng (di, rng, cao), ri yu cu ca chiu sng phn xng, khong cch l tngun in n nh xng, cng sut ca mi thit b tiu th in c cho nh sau:

Kchthc, m Eyc

l Cng sut ca cc thit b

axb h Lux m 1 2 3 4 5 6 7 8 9 10 11 12

13

14

16x

38

4,4 100 58 3,5 3,6 4,5 3 2x1,

2

2,1 0,6 0,8 6,5 2,8 3 4,

5

2,

8

6

Tn tht in p cho php t ngun in n u vo ca cc thit b tiu th in

l

UCP

= 2,5%. Cn b cng sut phn khng t n h s cng sut l cos

= 0,9. Thi gian hon vn

Ttc

= 8 nm, h s khu hao thit b

=

kkh

6%. Thi

gian s dng cng sut cc i

Tmax

= 3500 h. Cng sut ngn mch ti im u

in

=SN

2,65 MVA. Thi gian tn ti ca dng in ngn mch

=tN

2,5 s. H s

cng sut v h s s dng ca cc thit b tiu th in c cho nh sau:

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STT Tn thit b tiu th in H s s dng

ksd

cos

1 B ngm dung dch kim 0,35 12 B ngm nc nng 0,32 13 B ngm tng nhit 0,3 14 T sy 0,36 15 My qun dy 0,57 0,806 My qun dy 0,60 0,807 My khoan bn 0,51 0,788 My khoan ng 0,55 0,789 Bn th nghim 0,62 0,85

10 My mi 0,45 0,70

11 My hn 0,53 0,8212 My tin 0,45 0,7613 My mi trn 0,4 0,7214 Cn cu in 0,32 0,815 My bm nc 0,46 0.82

I. Ni dung ca bn thuyt minh

1. Tnh ton chiu sng cho phn xng

2. Tnh ton ph ti in

- Ph ti chiu sng

- Ph ti thng thong v lm mt

- Ph ti ng lc

- Ph ti tng hp

3. Vch cc s cung cp in, chn s cung cp in hp l

4. La chn v kim tra cc thit b ca s ni in

- Chn tit din dy dn ca mng in ng lc, chn tit din dy dn ca mngin chiu sng

- Chn thit b bo v

5. Tnh ton v chn t b cng sut phn khng

6. D ton

II. Bn v

1. Mt bng phn xng vi s b tr ca cc thit bTrang 3


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2. S mng in trn mt bng phn xng

3. S nguyn l ca mng in c ch r cc m hiu v cc tham s ca thit bc chn

4. Bng s liu tnh ton mng in

CHNG I: TNH TON CHIU SNG CHO PHN XNG

Trong thit k chiu sng, vn quan trng nht phi quan tm l p ng ccyu cu v ri v hiu qu ca chiu sng i vi th gic. Ngoi ri, hiu quca chiu sng cn ph thuc vo quang thng, mu sc nh sng, s la chn hp lcng s b tr chiu sng va m bo tnh kinh t v m quan hon cnh. Thit kchiu sng phi m bo cc yu cu sau:

Khng b lo mt

Khng lo do phn x

Khng c bng ti Phi c ri ng u

Phi m bo sng v n nh

Phi to ra c nh sng ging nh sng ban ngy.

Cc h thng chiu sng bao gm chiu sng chung, chiu sng cc b v chiusng kt hp ( kt hp gia cc b v chung ) . Do yu cu th gic cn phi lm vicchnh xc, ni m cc thit b cn chiu sng mt phng nghing v khng to ra cc

bng ti su thit k cho phn xng thng s dng h thng chiu sng kt hp.

Chn loi bng n chiu sng: gm 2 loi: bng n si t v bng n hunhquang. Cc phn xng thng t dung n hunh quang v n hunh quang c tn sl 50Hz thng gy ra o gic khng quay cho cc ng c khng ng b, nguy himcho ngi vn hnh my, d gy ra tai nn lao ng. Do ngi ta thng s dngn si t cho cc phn xng sa cha c kh.

Vic b tr n kh n gin, thng c b tr theo cc gc ca hnh vung hochnh ch nht .

Thit k chiu sng cho phn xng c kh sa cha c kch thc a.b.H l16.38.4,4 m ,Coi trn nh mu trng , tng mu vng , sn nh mu sm ,vi riyu cu l Eyc = 100 lux .

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Theo biu Kruithof ng vi ri 60 lux nhit mu cn thit l m=32000Kscho mi trng nh sng tin nghi .Mt khc v l xng sa cha c nhiu my inquay nn ta dng n si t vi cng sut l 200W vi quang thng l F= 3000

lumen .Chn cao treo n l : h = 0,5 m ;Chiu cao mt bng lm vic l : hlv = 0,8 m ;

Chiu cao tnh ton l : h = H h lv = 4,4 0,8 = 3,6 m ;

T s treo n:

'

'

0,5 10,122

3,6 0,5 3

hj

h h= = = tha mn yu cu.

Vi loi n dng chiu sng cho phn xng sn xut nn chn khong

cch gia cc n c xc nh l L/h =1,5 (bng 12,4) tc l:L = 1,5. h = 1,5.3,6 = 5,4 m.Cn c vo kch thc phn xng ta chn khong cch gia cc n l Ld =

3,2 mt v Ln =2,9m => p=1,6m; q=1,45m;

Kim tra iu kin:Ld3qLd2 vLn3pLn2 hay

3,2 3,21,45

3 2<

v2,9 2,9

1,63 2

<

=>tha

mn

Nh vy l b tr n l hp l.

Vy s lng n ti thiu m bo ng u chiu sng l N min = 65;

H s khng gian:

. 16.383,13

( ) 3,6.(16 38)kga b

kh a b

= = =+ +

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Cn c c im ca ni tht chiu sng c th coi h s phn x catrn:tng:sn l 70:50:30 . Tra bng ph lc ng vi h s phn x nu trn v hs khng gian l kkg =4,337 ta tm c h s li dng kld = 0,6; H s d tr ly bng

kdt=1,2; h s hiu dng ca n l58,0=

. Xc nh quang thng tng

. . 100.16.38.1, 2209655,17

. 0,58.0,6

yc dt

ld

E S k F

k = = =

(lumen)

S lng n ti thiu l:

min

209655,17

65,52 653200d

F

N NF

= = = = =

Nh vy tng s n cn lp t l 65 c b tr nh sau:

Kim tra ri thc t:

. . . 3200.65.0,58.0,699,72

. . 16.38.1, 2

d ld

dt

F N k E

a b

= = =

(lux) ~ Eyc=100lux

Ngoi chiu sng chung cn trang b thm cho mi my 1 n cng sut 100 W

chiu sng cc b, cho 2 phng thay v 2 phng v sinh mi phng 1 bng 100W.Nh vy cn tt c 19 bng dng cho chiu sng cc b.

CHNG II. TNH TON PH TI

Tnh ton ph ti in l cng vic bt buc v u tin trong mi cng trnh cungcp in , gip cho vic thit k li in v sau ca ngi k s . Ph ti tnh ton cgi tr tng ng vi ph ti thc t v mt hiu ng nhit , do vic chn dy dnhay cc thit b bo v cho n s c m bo .

C nhiu phng php tnh ton ph ti in nh phng php h s nhu cu , hs tham gia cc i . i vi vic thit k cung cp in cho phn xng sa cha ckh , v c cc thng tin chnh xc v mt bng b tr thit b , bit oc cng sutv qu trnh cng ngh ca tng thit b nn ta s dng phng php h s nhu cu tng hp nhm ph ti ng lc . Ni dung chnh ca phong php nh sau :

- Thc hin phn nhm cc thit b c trong xng , mi nhm khong t 7 8thit b , mi nhm s c cung cp in t 1 t ng lc ring , ly in t 1 t

phn phi chung . Cc thit b trong nhm nn c v tr gn nhau trn mt bng phnxng . Cc thit b trong nhm nn c cng ch lm vic , s lng thit b trong 1nhm khng nn qu 8 v gy phc tp trong vn hnh , gim tin cy cung cp

in .Trang 6


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- Xc nh h s s dng tng hp ca nhm thit b theo biu thc sau :

sdk

=

i

sdii

Pk.P

- Xc nh s lng thit b hiu dng ca mi nhm nhd ( l 1 s qui i gm cnhd thit b gi nh c cng sut nh mc v ch lm vic nh nhau v tiu thcng sut ng bng cng sut tiu th ca nhm thit b thc t ) . Cc nhm yu trn 4 thit b nn ta xc nh t s k

min

max

P

P=

, sau so snh k vi kb l h s ng

vi

sdk

ca nhm . Nu k > kb , ly nhd = n , l s lng thit b thc t ca nhm .

Ngc li c th tnh nhd theo cng thc sau :

nhd =

( )2

i

2

i

P

P

- H s nhu cu ca nhm s c xc nh theo biu thc sau :

knc =

sdk

+

hd

sd

n

k1

- Cui cng ph ti tnh ton ca c nhm l :

Ptt = knc.

iP

2.1. Ph ti chiu sng .Tng cng sut chiu sng chung (coi h s ng thi kt =1).Pcs chung = kt.N .Pd = 1.65.200 = 13000 WChiu sng cc b :Pcb = (15+ 4).100 = 1900 WVy tng cng sut chiu sng l:Pcs = Pcs chung + Pcb = 13000 + 1900 = 14900 W = 14,9 kWV n dng si t nn h s cos ca nhm chiu sng l 1

2.2. Ph ti thng thong v lm mt

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Phn xng trang b 30 qut trn mi qut c cng sut l 120 W v 10 qut htmi qut 80 W, h s cng sut trung bnh ca nhm l 0,8;Tng cng sut chiu sng v lm mt l:Plm = 30.120 +10.80 = 4400 W = 4,4 kW

2.3. Ph ti ng lc.Trc khi tnh ton cn qui cc ph ti lm vic ch ngn hn lp li v ch lm vic lm vic di hn , theo cng thc :

P = Pt .

, kW .

Trong :

Pt : l cng sut ca ph ti ly theo trong bng 1.2 , tc l cng sut nh mc caph ti .

P : cng sut qui v ch lm vic di hn ca thit b .

: h s tip in ca thit b

* Nhm 1Bng 2.1 Bng ph ti nhm 1.

TT Tn thit b Shiu k sd cos P P2 P.cos P.k sd

1 B ngm dung dch kim 1 0,35 1 3,5 12,25 3,5 1,225

2 B ngm nc nng 2 0,32 1 3,6 12,96 3,6 1,152

3 B ngm tng nhit 3 0,3 1 4,5 20,25 4,5 1,35

4 T sy 4 0,36 1 3 9 3 1,08

5 My bm nc 15 0,46 0,82 4 16 1,92 1,368

Tng 17,6 60,22 16,52 6,175

- S lng hiu dng nhm 1:

2 2

1 2

( ) 17,64,8

60,22

ihdn

i

Pn

P

= = =

K

- H s s dng nhm 1:

1

. 6,1750,36

17,6

i sdisdn

i

P kk

P

= = =

- H s nhu cu nhm 1:

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11 1

1

1 1 0,360,36 0,652

4,8

sdnncn sdn

hdn

kk k

n

= + = + =

- Tng cng sut ph ti nhm 1:

1 1. 0, 625.17 10, 62n ncn i P k P = = =

(kW)

- H s cng sut ca ph ti nhm 1:

i1

P.cos 16,52cos 0,97

17

in

iP

= = =

*Nhm 2:

Bng 2.2. Bng ph ti nhm 2.TT Tn thit b Shiu k sd cos P P2 P.cos P.k sd

1 My qun dy 6 0,6 0,8 2,1 4,41 1,68 1,26

2 My khoan bn 7 0,51 0,78 0,6 0,36 0,468 0,306

3 My khoan ng 8 0,55 0,78 0,8 0,64 0,624 0,44

4 Cn cu in 14 0,32 0,8 6 42,25 5,525 4,03

5 My mi 10 0,45 0,7 2,8 7,84 1,96 1,26

Tng12,

8 55,5 10,257 7,296

- S lng hiu dng nhm 2:2 2

2 2

( ) 12,82,95

55,5

ihdn

i

Pn

P

= = =

- H s s dng nhm 2:

2

. 7,2960,57

12,8

i sdisdn

i

P kk

P

= = =

- H s nhu cu nhm 2:

22 2

2

1 1 0,570,57 0,83

2,95

sdnncn sdn

hdn

kk k

n

= + = + =


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2 2. 0, 83.12, 8 10, 26n ncn i P k P = = =

(kW)

- H s cng sut ca ph ti nhm 2:i

2

P.cos 10,257cos 0,8

12,8

in

iP

= = =

*Nhm 3:Bng 2.3. Bng ph ti nhm 3.

TT Tn thit b Shiu k sd cos P P2 P.cos P.k sd

1 My hn 11 0,53 0,82 3 9 2,46 1,59

2 My tin 12 0,45 0,76 4,5 20,25 3,42 2,025

3 My mi trn 13 0,4 0,72 2,8 7,84 2,016 1,12

4 My qun dy 5 0,3 0,6 6 36 4,8 1,92

5 Bn th nghim 15 0,62 0,85 4 16 0,8 1,84

Tng20,

3 89,09 13,496 8,495

- S lng hiu dng nhm 3:2 2

3 2

( ) 20,34,63

89,09i

hdn

i

Pn

P

= = =

- H s s dng nhm 3:

3

. 8,4950,42

20,3

i sdisdn

i

P kk

P

= = =

- H s nhu cu nhm 3:

33 3

3

1 1 0,420,42 0,69

4,63

sdnncn sdn

hdn

kk k

n

= + = + =


3 3. 0, 69.20, 3 13, 9

n ncn i P k P = = =

(kW)

- H s cng sut ca ph ti nhm 3:Trang 10


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i3

P.cos 13,496cos 0,66

20,3

in

iP

= = =

Bng 2.6. Bng tng hp ph ti ng lc ca cc nhm:

TT Ph ti k sdni cosni Pni Pni.Pni Pni.cosni Pni.ksdni

1 Nhm 1 0,36 0,97 10,625 112,891 10,3063 3,825

2 Nhm 2 0,57 0,8 10,264 105,35 8,2112 5,85048

3 Nhm 3 0,42 0,66 13,98 195,44 9,2268 5,8716

Tng 34,869 413,68 27,74 15,54

- S lng hiu dng:2 2

2

( ) 34,8692,94

413,68

nihd

ni

Pn

P

= = =

- H s s dng ph ti ng lc:

. 15,540,445

34,869

ni sd nisd

ni

P kk

P

= = =

- H s nhu cu ph ti ng lc:

1 1 0,4450,445 0,77

2,94

sd

nc sd

hd

kk k

n

= + = + =

- Tng cng sut ph ti ng lc:

. 0, 77.34, 869 26,8dl nc ni

P k P = = =

(kW)

- H s cng sut trung bnh ca ph ti tng hp:niP .cos 27,74cos 0,8

34,869

nitb

niP

= = =

2.4. Ph ti tng hp

Bng 2.7. Kt qu tnh ton ph ti:

S th t Ph ti P ; KW cos

1 Chiu sng 14,9 1Trang 11


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2 Thng thong, lm mt 4,4 0,8

3 ng lc 26,85 0,8

Xc nh ph ti tng hp theo phng php s gia:- Tng cng sut tnh ton ca 2 nhm ph ti chiu sng v lm mt:

0,044,414,9 (( ) 0, 41).4,4 17,4735

cslmP = + =

(kW)

- Tng cng sut tc dng tnh ton ton phn xng:

0,0417,473

26,85 (( ) 0,41).17,473 38,0555P = + =

(kW)

- H s cng sut tng hp:

.cos 14,9.1 4, 4.0,8 26,85.0,8cos 0,86

14,9 4,4 26,85

i i

i

P

P

+ += = =

+ +

- Cng sut biu kin ca ph ti phn xng:=>

38,05544,25

0,86

PS

Cos

= = =

(kVA)

=>2. 44,25. 1 0,86 22,58Q S Sins = = =

(kVAr)

CHNG III.

VCH CC S V CHN S CUNG CP IN HP L

V tr ca trm bin p cn phi tha mn cc yu cu c bn sau :

- An ton v lin tc cp in

- Gn trung tm ph ti, thun tin cho ngun cung cp i ti.

- Thao tc, vn hnh, qun l d dng.

- Tit kim vn u t v chi ph vn hnh nh

- Bo m cc iu kin khc nh cnh quan mi trng, c kh nng iuchnh ci to thch hp, p ng c khi khn cp...

- Tng tn tht cng sut trn cc ng dy l nh nht

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Cn c vo s b tr cc thit b trong phn xng thy rng cc ph ti cb tr vi mt cao trong nh xng nn khng th b tr my bin p trong nh . Vvy ta t my pha ngoi nh xng ngay st tng nh minh ho di y . Khi xy

dng ngoi nh th cn ch n iu kin m quan .3.1. Xc nh v tr t trm bin p phn xng:

- H s in kn th c th c xc nh theo biu thc:

Kdk =

tb M

M

S T 35000,39

S 8760 8760= = =

< 0,75

Nh vy my bin p c th lm vic qu ti 40% trong khong thi gian chophp khng qu 6 gi.

- Da vo s mt bng nh xng, v gc pha ca ra vo khng c phti, nn ta c th t trm bin p bn trong, ngay st tng nh xng, tit kimc dy dn ca mng h p.

3.2. Chn cng sut v s lng my bin p :

Ta chn cng sut v s lng my bin p 22/0,4 kV theo 3 phng n sau:

Phng n 1: dng 2 my 2.31,5 kVA.

Phng n 2: dng 2 my 2.50 kVA.

Phng n 3: dng 1 my 75 kVA.Bng 3.1. Bng s liu cc my bin p hng ABB.

SBa , kVA0

P

; kW

kP

; kWVn u t , 106

2.31,5 0,15 0,7 140,6

2.50 0,24 1,25 150,7

1.70 0,28 1,4 86,9

Di gc an ton k thut, cc phng n khng ngang nhau v tin cy cungcp in. i vi phng n 1 v phng n 2, khi c s c xy ra 1 trong 2 my binp, my cn li s phi gnh ton b ph ti loi I v II ca phn xng, i vi phngn 3 s phi ngng cung cp in cho ton phn xng. m bo tng ng v kthut ca cc phng n cn phi xt n thnh phn thit hi do mt in khi c s cxy ra trong cc my bin p.

Hm chi ph tnh ton quy i cho tng phng n:

Z = p.V + C + Yth /nm .

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C: thnh phn chi ph do tn tht. C = A.c

Vi c : gi thnh tn tht in nng.

H s tiu chun s dng vn u t:atc =

h

h

T 25

T 25

i(1 i) 0,1(1 0,1)0,11

(1 i) 1 (1 0,1) 1

+ += =

+ +

Th l tui th ca trm bin p ly bng 25 nm.

H s khu hao ca trm bin p thly bng 6,4 %

Do : pBA = atc + kkh = 0,11 + 0,064 = 0,174

Khi so snh thit hi do mt in ch cn xt n ph ti loi I v loi II, v cth coi ph ti loi III cc phng n l nh nhau:

* Phng n 1:

Ph ti trong thi gian s c 1 my bin p bao gm ph ti loi I v loi II

Ssc = Stt.

1 2m +

= 44,25.0,85 = 37,612( kVA )

H s qu ti:

37,6121,55 1,4

31,5

scqt

n

Sk

S= = = >

Nh vy my bin p c th lm vic qu ti khi xy ra s c, bi vy khi c s

c 1 trong 2 my bin p, ta ch cn ct 15% ph ti loi III m khng cn ct ph ti

loi II.

Tn tht trong my bin p c xc nh theo biu thc:

2k2

2 02 2

nBA2

2

2

P SA 2. P .8760 . .2 S

0,7 44,252.0,15.8760 . .1968,16 3987,36 kWh

2 31,5

= +

= + =

Chi ph cho thnh phn tn tht l:

C = 3987,36.103 = 3987360

Vy tng chi ph qui i ca phng n :Trang 14


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Z2 = (0,174.140,6+ 3987360 ) =3,98738.106

* Phng n 2:

Ph ti trong thi gian s c 1 my bin p bao gm ph ti loi I v loi IISsc = Stt.

1 2m +

= 44,25.0,85 = 37,612( kVA )

H s qu ti:

37,6120,752 1, 4

50

scqt

n

Sk

S= = = Hao tn cc i trong mng in h p l:

UMax = UM3= 2,8V- Hao tn in p cho php:

%. 2,5.3809,5

100 100

cp dm

cp

U UU

= = =

V

Nh vy, UMax< Ucp => mng in m bo yu cu k thut.

* Phng n 2: t t phn phi bn cnh tng phn xng.

Hnh 3.3. S t t phn phi phng n 2.

Tnh ton tng t nh phng n 1, ta c bng kt qu ca phng n 2 nh sau:



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25/43


Trang 25

Nguyn Minh c Lp D4LT-H3

n

Cng sut Dng Tit din in tr Hao tn

P Q S I F Fc L r0 x0 DAV00

kW kVAr kVA A mm2 mm2 kmW/km

W/km V

kWh/nm /k

MBA 38,055 22,58

44,250 1,161 1,056

AC-35

0,058 0,92 0,414

0,12 0,921 21

A-TPP38,05

5 22,5844,25

067,23

124,90

0 250,01

5 0,210 0,060,37 182,299 20

PP-L1

10,625 2,66 10,95

16,642 6,164 10

0,006 2 0,08

0,34 42,554 72

PP-L2

10,264 7,70 12,83

19,493 7,220 10

0,022 2 0,08

1,22 214,069 57

PP-L3

13,980 15,91 21,18

32,182

11,919 16

0,032 1,25 0,07

1,57 530,437 89

L1-1 3,500 0,00 3,50 5,318 1,970 2,50,00

5 8 0,090,37 14,482 40

L1-2 3,600 0,00 3,60 5,470 2,026 2,50,01

5 8 0,091,14 45,966 40

L1-3 4,500 0,00 4,50 6,837 2,532 2,50,00

5 8 0,090,47 23,940 40

L1-4 3,000 0,00 3,00 4,558 1,688 2,5

0,01

0 8 0,09

0,6

3 21,280 17

L1-15 2,400 1,68 2,93 4,447 1,647 2,50,00

9 8 0,090,46 18,229 26

L2-6 2,100 1,58 2,63 3,988 1,477 2,50,00

6 8 0,090,27 9,776 35

L2-7 0,600 0,48 0,77 1,169 0,433 1,50,00

6 9 0,090,09 0,944 48

L2-8 0,800 0,64 1,03 1,558 0,577 1,50,01

8 9 0,090,34 5,037 17

L2-10 6,500 6,63 9,2914,10

8 5,225 60,01

6 3,33 0,090,94 135,782 35

L2-14 2,800 2,10 3,50 5,318 1,970 2,5 0,014 8 0,09 0,83 40,551 17

L3-11 3,000 2,09 3,66 5,559 2,059 2,50,01

5 8 0,090,95 47,473 17

L3-12 4,500 3,85 5,92 8,996 3,332 40,00

9 5 0,090,54 46,629 26

L3-13 2,800 2,70 3,89 5,909 2,188 2,50,01

7 8 0,091,01 60,791 48

L3-5 6,000 4,50 7,50

11,39

5 4,220 6

0,00

7 3,33 0,09

0,3

8 38,754 35

L3-9 4,000 2,48 4,71 7,150 2,648 4

0,00

8 5 0,09

0,4

3 26,181 40

161,079

100,16

193,87

0,293

1506,10


26/43


Bng 3.4. Bng kt qu tnh ton phng n 2.

Trang 26


27/43


- Tnh ton hao tn in p cc i trong mng in h p

+ Hao tn cc i t TBA TPP TL 1 cc my thuc TL 1:

UM1 = UTBA-TPP + UTPP-L1 + UL1-4= 0,37 + 0,41 + 0,63 = 1,41V+ Hao tn cc i t TBA TPP TL 2 cc my thuc TL 2:

UM2 = UTBA-TPP + UTPP-L2 + UL2-10= 0,37 + 1,57 + 0,94= 2,88V

+ Hao tn cc i t TBA TPP TL 3 cc my thuc TL 3:

UM3 = UTBA-TPP + UTPP-L3 + UL3-13= 0,37 + 2,1 + 1,01 = 3,48V

=> Hao tn cc i trong mng in h p l:

UMax = UM3 = 3,48V

- Hao tn in p cho php:

%. 2,5.3809,5

100 100

cp dm

cp

U UU

= = =

V

Nh vy, UMax = 3,48 V < Ucp= 9,5 V => mng in m bo yu cu k thut.

* Kt lun:

So snh kt qu tnh ton ca 2 phng n, nhn thy phng n 1 c tng chi ph

quy i nh hn phng n 2:

S chnh lch chi ph c xc nh:

2 1

2

24,54 24,47% .100 .100 0,29

24,54

Z ZZ

Z

= = =

%

C 2 phng n u m bo ch tiu k thut, cn v kinh t th phng n 1

chim u th hn. Vy chn phng n 1 tnh ton thit k.

Trang27Nguyn Minh c Lp D4LT-H3


28/43


CHNG IV

LA CHN V KIM TRA CC THIT B CA S NI IN.

Cc tit din dy chn c phi m bo cung cp in an ton, lin tc, khng b qu

nhit. Phng thc i dy trong mng cn hp l, tin cho vic vn hnh, sa cha.

4.1. Chn tit din dy dn ca mng ng lc, dy dn mng chiu sng:

4.1.1. Dy dn mng ng lc.

+ Dng in chy trong dy dn cao p:

44,251,16

3. 3.22

SI

U= = =

A

+ Tit din dy dn cn thit:

1,161,054

1,1kt

IF

j= = =

mm2

+ i vi ng dy cao p, tit din ti thiu khng nh hn 35mm2 nn chn

loi dy AC - 35 ni t ngun vo trm bin p.

Tit din ca dy dn t trm bin p ti t phn phi v t t phn phi n cc t

ng lc c chn s b trn (bng 3.3). By gi tin hnh kim tra theo iu kin

dng in cho php:

Theo phng thc mc trong ho cp, tra trong bng 15pl 17pl [ 1 ], xc nh

c cc h s hiu chnh : k1 = 0,95, k2 = 1, k3 = 0,96.Ta tin hnh kim tra cho dy t trm bin p ti t phn phi: theo trn dng dy

XLPE.25, c dng in cho php iu kin chun l: I cp = 280 A. Dng in hiu chnh

cho php:



29/43


Ilv = 206,008> k1.k2 .k3.Icp = 0,95.1.0,96.280 = 255,36 A. Nn tit din dy ny l

tho mn.

Ta kim tra tng t cho cc on cn li, kt qu ghi trong bng 4.1:ng vi k1 = 0,95; k2 = 1 v k3 = 0,96

Bng 4.1 Kim tra iu kin cho dy dn.

TT Icp K1.K2.K3.Ic

pIlv Kt lunon

dy

F

mm2

1 Ng-MBA AC-35

17

5 159,600

1,16126

13

Tha

mn

2 MBA-TPP 25

11

9 108,528

67,2309

2

Tha

mn

3

TPP-

TL1 10 70 63,840

16,6422

86

Tha

mn

4

TPP-

TL2 10 70 63,840

19,4931

68

Tha

mn

5

TPP-

TL3 16 94 85,728

32,1824

43

Tha

mn

6 TL1-1 2,5 30 27,360

5,31769

98

Tha

mn

7 TL1-2 2,5 30 27,360

5,46963

41

Tha

mn

8 TL1-3 2,5 30 27,360

6,83704

27

Tha

mn

9 TL1-4 2,5 30 27,3604,55802

84Thamn

10 TL1-15 2,5 30 27,360

4,44685

7

Tha

mn

11 TL2-6 2,5 30 27,360

3,98827

49

Tha

mnTrang29Nguyn Minh c Lp D4LT-H3


30/43


12 TL2-7 1,5 27 24,624

1,16872

52

Tha

mn

13 TL2-8 1,5 27 24,624

1,55830

03

Tha

mn

14 TL2-10 6 51 46,512

14,1081

83

Tha

mn

15 TL2-14 2,5 30 27,360

5,31769

98

Tha

mn

16 TL3-11 2,5 30 27,360

5,55857

13

Tha

mn

17 TL3-12 4 40 36,480

8,99610

88

Tha

mn

18 TL3-13 2,5 30 27,3605,90855

54Thamn

19 TL3-5 6 51 46,512

11,3950

71

Tha

mn

20 TL3-9 4 40 36,480

7,14984

85

Tha

mn

Nh vy tt c cc dy dn ca mng ng lc u c thit din tho mn iu

kin dng in cho php.

4.1.2. Chn dy dn cho mng in chiu sng:

- Ta ch chn dy dn cho mng chiu sng chung, cn chiu sng cc b c ly

in ti ch qua mng ng lc.

Mng in chiu sng c ly in t t phn phi ch khng ly in t cc t

ng lc v khi cc ng c m my s gy ra st p ln, nh hng n cht lng chiu

sng. Dy dn cung cp in t t phn phi n t chiu sng l cp ng 3 pha, cn

dy n cc bng n l cc dy 2 pha c trung tnh. T in chiu sng c t ngay

ca vo ca phn xng (cnh vn phng xng) tin cho vic bt tt.



31/43


Hnh 4.1- S mch in chiu sng

- V t phn phi c t trung tm ti nn mng in chiu sng c xy

dng vi 6 mch r, mi mch r gm 13 bng. Nh vy cng sut mi mch nhnh phi

chu l: 13x0,2 = 2,6 kW.

Ta tnh cc m men ti nh sau:

M0=P0.l0 = 14,9.20,5= 305,45kWm

M1 = P1.l1 = 2,6.48,5 = 126,1kWm

M2 = P2.l2 = 2,6.44,5 = 115,7kWm

M3 = P3.l3 = 2,6.40,5 = 105,3kWm

M4 = P4.l4 = 2,6.44,5 = 115,7kWm

M5 = P5.l5 = 2,6.48,5 = 126,1kWm

- M men qui i:

Mqd = M0+

.(M1+M2+M3+M4+M5)

=305,45 + 1,33.(126,1+115,7+105,3+115,7+126,1)

= 1088,687kWm



32/43


H s ph thuc cu trc mng in

xc nh theo bng 5.pl [ 2 ] ng vi mch

2 pha c trung tnh :

= 1,33

Ta phn b

cpU

% . C

cpU

% ca mng chiu sng s l :

Ucpcs = Ucp% - UTBA-TPP %= 2,5% - 0,0815% =2,418%

on OA :

cpU

= 2 %

Vy tit din ca on dy dn OA l:

21088,687 6,55. 83.2

qd

OA

cpOA

M F mm

C U= = =

C =83 tra bng 4.pl [ 2 ], ng vi dy ng ca mng 3 pha c trung tnh.

Ta chn dy c tit din 10mm2.

Tnh ton tng t cho cc nhnh r cn li ta c kt qu chn tit din dy dn ca

mng chiu sng ghi trong bng sau:

Bng 4.2: Tit din dy chiu sng .

on OA AB AC AD AE AFF mm2 10 2,5 2,5 2,5 2,5 2,5

Nhn xt: do cc dy mch nhnh c chn vi tit din vt cp nn khng cn kim

tra iu kin tn tht in p cho php.

Ngoi ra cn cn chn dy dn cho cc bng n ca nh v sinh v phng thay .

C 4 bng tt c, v v cng sut ca chng khng ln, nn n gin ch cn chn dy

2 pha (ng ), tit din 1,5mm2, v khng cn kim tra iu kin hao tn in p.

4.3. Chn thit b bo v:



33/43


Cc thit b ny phc v cho vic bo v mch in, h tr cho mch in lm vic tin

cy, an ton, v gip cho vic o lng c chnh xc.

4.1.2. Tnh ton ngn mchNgn mch l tnh trng s c nghim trng v thng xuyn xy ra trong h thng

cung cp in. Cc s liu trong tnh ton ngn mch l cn c quan trng la chnthit b in, thit k h thng bo v r le v.v V vy vic tnh ton ngn mch l mt

phn khng th thiu c trong h thng cung cp in.

Cc dng ngn mch thng xuyn xy ra trong h thng cung cp in l ngn mch N 3,N(1,1), N1. Trong ngn mch 3 pha l s c nghim trng nht v vy thng cn c vongn mch 3 pha la chn thit b in.

Cc im cn tnh ngn mch l :

N1: Ngn mch ngay ti thanh ci trm bin p kim tra iu kin n nh nhit can .

N2: thanh ci t phn phi h p kim tra aptmat tng .

Ta tin hnh xc nh dng in ngn mch t v 2 v tr c trng l trn thanh ci ca tphn phi v ta mt im xa nht ca mch l im s1.

0

E X Z ZN NHT d-0 1 0-1 2

1

Hnh 6: S tnh ton ngn mch.

Xc nh in tr ca cc phn t , tnh trong h n v c tn . Chn Ucb = 0,38 kV.

2 23cb

HTK

U 0,38X = 54,5.10 54

S 2,65= = = m

X-0 = x0.L-0 = 0,41. 58 = 23,78m



34/43


R-0 = r0.L-0 = 0,92.58 = 53,36 m

X0-1 = x0.L0-1= 0,06. 15 = 0,9m

R0-1= r0.L0-1= 0,21.15 = 3,15 mZk1 =

2 2 2 2

D 0 HT D 0R (X X ) 53,36 (54 23,78) 94,32m + + = + + =

Zk2 =

2 2 2 2

D 0 0 1 HT D 0 0 1(R R ) (X X X ) (53,36 3,15) (54 23,78 0,9) 96,87m + + + + = + + + + =

*Dng ngn mch 3 pha ti N1:

1

(3) 3k1

k1

U 380I = = .10 = 2,32 kA

3.Z 3.94, 32k

E

Z=

Vi t s

k

k

X1

R>

nn h s xung kch kxk = 1,15 Bng 6.1.pl Bi tp cung cp in - TS.

Trn Quang Khnh.

Dng in xung kch :ixk1 = kxk.

2

.(3)

k1I

= 1,15.

2

.2,32 = 3,787 kA

*Dng ngn mch 3 pha ti N2:

2

(3) 3k2

k2

U 380I = = .10 = 2,267 kA

3.Z 3.96,87k

E

Z=

Dng in xung kch :ixk2 = kxk.

2

.(3)

k2I

= 1,15.

2

.2,267 = 3,687 kA

4.3.1. Chn thit b phn phi pha cao p:



35/43


Theo s liu cho trong bi ta c thi gian ct l tk= 2,5s

4.3.1.1. Cu chy cao p:

Cu chy cao p gip ngt in khi xy ra s c pha cao. Cu chy ny ri khi c s cgip d pht hin.

Dng in lm vic bnh thng pha cao p:

44,25

3. 3.22

ttlv

C

SI

U= =

= 1,16A

Ta chn cu chy cao p do hng SIEMENS ch to ( hoc cu chy tng ng

loai KT do Lin Bang Nga ch to ) c Un = 22kV, dng nh mcIn = 5A ( Tra bng 20.d.pl ) [ 2 ] .

4.3.1.2. Dao cch ly:

Cn c vo dng in lm vic ta chn dao cch ly plh22/630(hoc loi 3DC do

SIEMENS ch to)

4.3.1.3.Chng st

Chn chng st van loi PBC-22T1 do Nga sn xut (hoc loi C24 do Php sn

xut,hoc loi AZLP501B24 do hng Cp M ch to)4.3.2.5. Chn ptmt:

a. Chn aptmt cho mch chiu sng:

T chiu sng c bo v bng aptmt khi mt in c th ng li nhanh, khng

mt thi gian phi thay dy ch nu dng cu chy, m bo chiu sng lin tc.

V cng sut chiu sng chung l 14,9 kW nn dng in lm vic ca mch chiu sng

chung l:

14,9

3. 3.0,38

cscs

H

SI

U= =

=22,66A

Tra bng 20.e.pl [ 2 ] ta chn aptmt loi A50 3MT c dng nh mc l In =

25A .



36/43


b. Chn aptmat bo v cc ng c :

Chn aptmt co cc ng c nh sau:

Tnh ton tiu biu cho 1 ng c l my tin c s hiu trn s l thit b 10.Dng in lm vic trn dy dn t t ng lc n ng c l 14,19 A ( xc nh

mc 4.1).

Coi cc ng c c bi s m my l kmm = 4. V ng c khi ng iu kin khi

ng nh nn

mm

= 2,5. Do dng m my ca ng c l:

Imm = 4.14,19 = 56,43A.

Dng khi ng ca phn t nhit ca aptmat nm trong gii hn (c chn ging

nh ca cu ch ):

cpkd

mm

mm I.45,1II

56,4322, 573 1, 45.51 73, 95 A

2,5k dA I= =

Icp l dng cho php hiu chnh ca dy dn, tnh c phn chn tit din (bng

4.1) l 51 A.

Bng 4.3 Chn p tmt

ng

c Ilv Imm Icp Ik In

Loi

Aptomat

TL1-1 5,318

21,27

1 30

8,5083

2 10 EA52G

TL1-2 5,470

21,87

9 30

8,7514

1 10 EA52G

TL1-3 6,83727,34

8 3010,939

3 15 AII50-3MT

TL1-4 4,558

18,23

2 30

7,2928

5 10 EA52GTL1-

15 4,447

17,78

7 30

7,1149

7 10 EA52G



37/43


TL2-6 3,988

15,95

3 30

6,3812

4 10 EA52G

TL2-7 1,169 4,675 27

1,8699

6 10 EA52G

TL2-8 1,558 6,233 27

2,4932

8 10 EA52GTL2-

10 14,108

56,43

3 51

22,573

1 25 AII50-3MTTL2-

14 5,318

21,27

1 30

8,5083

2 10 EA52GTL3-

11 5,559

22,23

4 30

8,8937

1 10 EA52GTL3-

12 8,996

35,98

4 40

14,393

8 15 EA52GTL3-

13 5,909

23,63

4 30

9,4536

9 10 EA52G

TL3-5 11,395

45,58

0 51

18,232

1 20 AII50-3MT

TL3-9 7,150

28,59

9 40

11,439

8 15 AII50-3MT

Nh vy theo bng trn cn dng tt c 10 aptomat loi EA52G;4 aptomat loi A50-

3MT.

c. Chn aptomat bo v cc t ng lc:

Chn cho 1 t tiu biu l t 1:

Dng khi ng ca aptmat c xc nh theo biu thc:

Ikd =

+

1n

1nit

mm

maxmm IkI

Immmax : dng m my ca 1 ng c c dng lm vic ln nht trong nhm .



38/43


Dng m my ca ng c ln nht l ng c 10 c Ilvmax = 14,108A (y l dng

hiu chnh theo h s tip in ).

Nn :Immmax = 4.14,108= 56,43 A. Trong 4 l bi s m my ca cc ng c

kt: l h s ng thi ca nhm. V khng cho qui trnh cng ngh ca nhm nn ta

coi cc my lm vic ng thi, tc kt = 1.

Ini l dng lm vic ca cc ng c lc bnh thng, c xc nh trong bng 4.1.

mm: h s ph thuc ch m my ca ng c. Nh trn coi cc ng c c ch

m my nh nn ly bng 2,5.

Nh vy:

Ikd =

56,431.(5,318 5, 470 6,837 4,558 4, 447)

2,5+ + + + +

= 49,201A

Dng khi ng ct nhanh ca aptmat phi tha mn iu kin:

Ikdcn

1,25Immmax = 1,25. 49,201 = 61,5sA

Ta chn aptmat loi EA103G ( tra bng 31.pl )[ 2 ] c dng nh mc l:

In= 75A

Tng t ta chn aptmat bo v cho cc t phn phi cn li, kt qu ghi trong bng

sau :

Bng 4.4 Bng chn aptmt cho cc t ng lc:

T

Ik In

Loi aptmtA A

L1 61,5 75 EA103-G

L2 60,89 75 EA103-G



39/43


L3 76,97 100 EA103-G

Nh vy theo bng trn cn dng 3 aptomat loi EA103-G

4.3.2.5. Chn aptomat tng bo v t phn phi chnh:

Aptmt tng c dng in ph ti chy qua l : I = 108,528 A (xc nh theo

bng4.1), cn c vo chn loi aptmat SA403-H do Nht Bn ch to c dng nh

mc l : In = 125 A c dng ct l Ik= 85kA .

Kim tra kh nng lm vic ca aptmt:

Ict> Isc suy ra : 85 kA >2,923 kA

Isc : dng ngn mch 3 pha ti im N2 tnh c mc 4.2, bng 2,923 kA.Vy

aptmt chn tha mn iu kin k thut .



40/43


CHNG V

TNH CHN T B NNG CAO H S CNG SUT.

Vic t b c li v mt gim tn tht in p, in nng, cho i tng dng in l

t phn tn cc b t b cho tng ng c. Tuy nhin nu t phn tn qu s khng c

li v vn u t, v qun l vn hnh. Cho nn vic b tr t t b u l 1 bi ton

cn xem xt k.

5.1. Xc nh dung lng b cn thit:

Yu cu h s cng sut cn nng ln l cos2 = 0,9. Nn tg 2 = 0,48.

C: cos = 0,86. Nn tg = 0,593.Do dung lng b cn thit l

Qb = P.(tg - tg 2 ) = 38,055.( 0,593 0,48 ) = 4,3kVA

Chn t b loi KM1 - 0,38 c cng sut Q = 13kVAr

5.2. nh gi hiu qu b cng sut phn khng:

Cng sut biu kin ca phn xng sau khi b s l:

Ssaub = Ptt + j( QN Qbn ) = 38,055 + j( 22,58 4,3 ) = 38,055 + j18,28kVA

Gi tr mun ca n l :



41/43


Ssaub =2 2

38,055 18,28 42,22+ =

kVA, nhn thy nh i rt nhiu so vi gi tr

tnh ton ban u. Nh vy cc tit din ta chn ban u s c m bo iu kin pht

nng.

CHNG 6

D TON CNG TRNH.

6.1 Danh mc cc thit b.Trong hch ton cng trnh ta ch xt n cc thit b chnh c nu trong bng di y.

Bng 8.1 Danh mc cc thit b cung cp cho phn xng.

STT Tn thit b Quy cchn

vS lng

n gi

106

V

106

1 Trm bin p 31,5kAV Ci 2 140,6 140,72 Dy dn 22KV AC -35 km 0.58 218 126.446 Cp h p XPLE.25 km 0.019 576 10.947 Cp h p XPLE.16 km 0.02 485 9.708 Cp h p XPLE.10 km 0.05 405 20.259 Cp h p XPLE.6 km 0.023 355 8.17



42/43


10 Cp h p XPLE.4 km 0.017 265 4.5111 Cp h p XPLE.2,5 km 0.319 179 57.1013 Cp h p XPLE.1,5 km 24 115 2,760.00

19 Cu chy cao p KT B 1 17 17.0020 Chng st van PBC-22T1 B 1 1.5 1.5021 V t in Ci 4 1 4.0022 Aptomat t phn phi SA403-H Ci 1 2.3 2.3024 Aptomat t ng lc EA130G Ci 3 0.6 1.8025 Aptomat ng c EA52G Ci 11 1.25 13.7526 Aptomat ng c A50-3MT Ci 4 1.37 5.4827 Aptomat mch chiu sng A50-3MT Ci 1 0.37 0.3728 Cng t 3 pha Ci 1 0.6 0.60

29 My bin dng TKM-0,5 B 1 0.9 0.9030 ng thanh ci h p M,50.6 Kg 10 0.06 0.6031 Cc tip a 5,6 Cc 12 0.1 1.2032 Thanh ni tip a 50.6 Mt 22 0.015 0.3333 T b KM2-0,38-36.Y B 1 7 7.0034 Thanh ci MBA CU 50x5mm Mt 4 0.05 0.20 Tng 3054,14

6.2 Xc nh cc tham s kinh t .

Tng gi thnh ca cng trnh lV = 3,054.106 Tng gi thnh c tnh cho cng sut lp t:

6 6. 1,1.3054,14.10 3359,5510lV k V = = =

Trong :

kl : h s lp t, ly bng 1,1

Gi thnh mt n v cng sut lp t:

663359,55.10 69,02.10 /

44,25

V g kVA

S

= = =

Chi ph vn hnh hng nm

Cvh = k0&M. V = 0,02. 3359,55.106 = 73,91.106 ng.Trang42Nguyn Minh c Lp D4LT-H3


43/43


Tng chi ph quy i

Z = pV + C = (0,185. 3359,55+ 73,91).106 = 695,43.106 /nm

Tng in nng tiu th:A = P.TM = 38,55.3500 = 134925 kWh.

Tng chi ph trn mt n v in nng

6695,43 / kWh134,925

Zg = = .10 = 5,154

A

/kWh.

nguyen minh duc_chuan

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