notes and homework assistance inkster high school resource: chemistry textbook, chapter 11 mrs....
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![Page 1: Notes and Homework Assistance Inkster High School Resource: Chemistry Textbook, chapter 11 Mrs. Nicole Gall](https://reader033.vdocuments.net/reader033/viewer/2022061305/5514246e550346dd488b5991/html5/thumbnails/1.jpg)
Notes and Homework AssistanceInkster High School
Resource: Chemistry Textbook, chapter 11Mrs. Nicole Gall
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DO NOW: Use Double Bubble to compare: product and reactant
HOMEWORK: Continue from Chapter 11 AIMS: (c5.2) TLW Balance 8 – 12 equations.
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DO NOW: Use Double Bubble to compare: product and reactant
HOMEWORK: Continue from Chapter 11
AIMS: (c5.2) TLW Balance 8 – 12 equations.
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Label your paper please. Name April 4, 2011 Fourth hour Chemistry Chapter 11 homework- due April 12 #3, 5, 7, 8, 9, 12, 22, 23, 24, 45, 52
PS: Chemistry observations: 5 physical properties, 5 chemical properties, due today: at least one full page. 20 points. Accepted tomorrow for 18 pts.
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CHAPTER 11 TOPIC: CHEMICAL REACTIONS
PAGE 327 #3. BALANCE EACH EQUATION.A.__AgNO3 + __H2S __Ag2S + __HNO3
B.__Zn(OH)2 + __H3PO4 __Zn3(PO4)2 + __H2O
Clue: without changing molecular formulas, change coefficients so that the reactants and products contain the same numbers of each atom
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Ag N O H S Ag N O H S 1 1 3 2 1 2 1 3 1
1
Step one: count the total number of each element listed on the reactant side of the chemical equation.
Repeat for the product side of the equation. If these are the same, the equation is
balanced. This chemical equation is NOT balanced.
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Zn O H P Zn O H P 1 6 5 1 3 8 2 2
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Zn O H P Zn O H P 1 6 5 1 3 8 2 2
3 10 9 1 3 8 2 2
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Zn O H P Zn O H P 1 6 5 1 3 8 2 2
3 10 9 1 3 8 2 2
3 14 12 2 3 8 2 2
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Zn O H P Zn O H P 1 6 5 1 3 8 2 2
3 10 9 1 3 8 2 2
3 14 12 2 3 8 2 2
3 14 12 2 3 14 12 2
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Zn O H P Zn O H P X x x x x x x x
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#5a.◦ _FeCl3 + _NaOH _Fe(OH)3 + _NaCl
#5b.◦ _CS2 + _Cl2 _CCl4 + _ S2Cl2
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Fe Cl Na O H --- Fe Cl Na O H1 3 1 1 1 1 1 1 3 3
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Fe Cl Na O H --- Fe Cl Na O H1 3 1 1 1 1 1 1 3 31 3 1 1 1 1 3 3 3 3
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Fe Cl Na O H --- Fe Cl Na O H1 3 1 1 1 1 1 1 3 31 3 1 1 1 1 3 3 3 31 3 3 3 3 1 3 3 3 3
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C CS Cl I I2 C CS Cl I I2 CL4 2 2 2 2 1 1 0 4 4 1 1 It’s balanced! No changes needed. Just kidding Try this one on your own before you switch
to the next screen to check your answer (Thanks Catherine and Anthony )
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C S Cl C S Cl1 2 2 1 2 6
1 2 6 1 2 6
The balanced equation is written: CS2 + 3Cl2 CCl4 + S2Cl2
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Please read the textbook for these answers (previous section only)
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#12a◦ _SO2 + _O2 _SO3
#12b◦ _Fe2O3 + _H2 _Fe + _H2O
#12c◦ _P + O2 P4O10
#12d◦ _Al + N2 _AlN
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2SO2 + O2 2SO3
Fe2O3 + 3H2 2Fe + 3H2O
4P + 5O2 P4O10
2Al + N2 2AlN
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Mg is in the second column (2 valence electrons)
O is in the 16th column (6 valence electrons) One Mg and one O combine to form a stable
magnesium oxide, MgO molecule