notes for beams bs 8110 fy 415

2
Notes For Beams x / d≯ 0.5 z≯ 0.95 d For Fy 415 d / x≯ 0.48 d x = 10.87 fy sC 0.0035 d x = 10.87415 20010 3 0.0035 =0.48 If d x >0.48 then f s c <0.87 fs c =E s sC sC = 0.0035 ( Xd ) x fs c =20010 3 0.0035∗( 1d x ) fs c =700 ( 1d x ) اب ت ك راب م ك ل ل ع ي وز ت ل ا ب س ن دول ج

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Notes for Beams Bs 8110 Fy 415

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Page 1: Notes for Beams Bs 8110 Fy 415

Notes For Beams

x /d≯� 0.5

z≯� 0.95d

For Fy 415

d ‛ /x ≯� 0.48

d ‛

x= 1−0.87 fyℇ sC∗0.0035

d ‛

x= 1−0.87∗415200∗103∗0.0035

=0.48

If d‛

x>0.48 then f sc<0.87

f sc=Es∗ℇ sC

ℇ sC=0.0035 ( X−d‛ )

x

f sc=200∗103∗0.0035∗(1−d

x)

f sc=700(1−d ‛

x)

كتاب للكمرات التوزيع نسب جدول

Manual for design reinforced concrete building structure bs8110 page 46 in pdf