nov 13, 2014 worksheet 18: inde nite and de nite integrals …€¦ · nov 13, 2014 worksheet 18:...

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Nov 13, 2014 Worksheet 18: indefinite and definite integrals SOLUTIONS 1. Find each of the following indefinite integrals. Check your answers by differentiation. (a) Z 4 x dx = 4 x ln(4) + C (b) Z (5 x + x 5 +5 5 ) dx = 5 x ln(5) + x 6 6 +5 5 x + C 1

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Page 1: Nov 13, 2014 Worksheet 18: inde nite and de nite integrals …€¦ · Nov 13, 2014 Worksheet 18: inde nite and de nite integrals SOLUTIONS 2.Find each of the following de nite integrals:

Nov 13, 2014 Worksheet 18: indefinite and definite integrals SOLUTIONS

1. Find each of the following indefinite integrals. Check your answers by differentiation.

(a)

∫4x dx =

4x

ln(4)+ C

(b)

∫(5x + x5 + 55) dx =

5x

ln(5)+x6

6+ 55x+ C

1

Page 2: Nov 13, 2014 Worksheet 18: inde nite and de nite integrals …€¦ · Nov 13, 2014 Worksheet 18: inde nite and de nite integrals SOLUTIONS 2.Find each of the following de nite integrals:

Nov 13, 2014 Worksheet 18: indefinite and definite integrals SOLUTIONS

(c)

∫ (3y2 +

3

y2+ 3√y +

3√y

)dy = y3 − 3

y+ 2y3/2 + 6y1/2 + C

(d)

∫(12 sin(x) + sin(12x) + x sin(12)) dx

= −12 cos(x)− cos(12x)

12− x2 sin(12)

2+ C

2

Page 3: Nov 13, 2014 Worksheet 18: inde nite and de nite integrals …€¦ · Nov 13, 2014 Worksheet 18: inde nite and de nite integrals SOLUTIONS 2.Find each of the following de nite integrals:

Nov 13, 2014 Worksheet 18: indefinite and definite integrals SOLUTIONS

2. Find each of the following definite integrals:

(a)

∫ 1

0

(eu/3 + 2) du = 3e1/3 − 1

(b)

∫ 1

−1

1

1 + x2dx =

π

2(Here, you may wish to recall that tan(−π/4) = −1 and

tan(π/4) = 1.)

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Page 4: Nov 13, 2014 Worksheet 18: inde nite and de nite integrals …€¦ · Nov 13, 2014 Worksheet 18: inde nite and de nite integrals SOLUTIONS 2.Find each of the following de nite integrals:

Nov 13, 2014 Worksheet 18: indefinite and definite integrals SOLUTIONS

3. Solve the initial value problem

F ′(x) = 2− x+ cos(x), F (0) = −2.

F (x) = 2x− x2

2+ sin(x)− 2.

4. Find the area under the graph of f(x) = 2− x+ cos(x) from x = 0 to x = π/2.

Π

2

Π

4

x

1

2

3y

∫ π/2

0

f(x) dx = 1 + π − π2

8

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