number system 3 of 7
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Mathematic KFP00105
Topic 1 : Number System
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TOPIC : 1.0 NUMBER SYSTEM
SUBTOPIC : 1.3 Surd
LEARNING : At the end of the lesson, student should be able to
OUTCOMES
(a) Explain the meaning of surd and its conjugate and to carry outalgebraic operations on surds.
(b) Solve equation involving surds.
CONTENT
A number expressed in terms of root sign is radical or a surd. For example, 24 = and 3273 =
are called radical expression. However, radical expressions in the form of 7 or 3 71 whichequal to irrational numbers are known as surds.
Some examples of surds are 2 , 5 and 7 . They cannot be evaluated exactly, i.e. no
approximation is precise. For example 414213562.12 = to ten significant figures. This is not
the exact value because 2 is irrational, it can never be represented exactly as a fraction or as
terminating decimals.
RULES OF SURDS
ab = a b a, b 0 PROPERTY 1
b
a=
b
aa, 0 , b 0 PROPERTY 2
a b + c b = (a + c) b PROPERTY 3
a b - c b = (a - c) b PROPERTY 4
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Mathematic KFP00105
Topic 1 : Number System
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Additional rules
1) aaa =
2) a + a = 2 a Remark: ba+ ( a + b )
3) a b =b
a
4) ( a + b ) 2 = a + b+ 2 ab
5) ( a + b ) ( a - b ) = a2 b2
Example
Simplify:
a) 45 b) 24 c) 6 727 + d) 5 273
Solution
a) 45 = 59
= 59
= 3 5
b) 24 = 64
= 64
= 2 6
c) 6 727 + = (6 + 2) 7
= 8 7
d) 5 273 = 5 3 39
= 5 3 ( 39 )
= 5 3 3 3 = 2 3
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Mathematic KFP00105
Topic 1 : Number System
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Multiplying Radicals
There are 2 types.
1) a x b = ab
2) ba x dc = bdac
Example
Multiply:
1. 3 6 x 5 7
2. 7 8 x 10 6
3. 3 (4 7 - 3 )
4. 8 2 (5 6 + 2 )
5. (2 3 +4 2 )(6 3 +2 2 )
Solution
1. 3 6 x 5 7 = 15 42
2. 7 8 x 10 6 = 70 48
= 70 316x
= 70(4 3 )
= 280 3
3. 3 (4 7 - 3 ) = 4 21 - 9
= 4 21 -3
4. 8 2 (5 6 + 2 ) = 40 12 + 8 4
= 40 34x + 8(2)
= 80 3 +16
5. (2 3 +4 2 )(6 3 +2 2 ) =12(3) + 4 6 + 24 6 + 8(2)
= 36 + 4 6 + 24 6 +16
= 52 + 28 6
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Mathematic KFP00105
Topic 1 : Number System
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Example
Expand and simplify ( )38 ( )38 + .
Solution
( )38 ( )38 + = 8 ( )38 + - 3 ( )38 +
= 2)8( + 38 - 83 - (2)3
= 2)8( - ( 2)3
= 8 3 = 5
The conjugate of a + b is a b where ( a + b)( a b) = a b is a rational
number.
For example, ( 8 + 3 )( 8 - 3 ) = ( 8 ) 2 - ( 3 ) 2 = 8 3 = 5
Rationalising the denominator
When the denominator of a fraction contains a square root, we generally simplify the expression
by rationalising the denominator.
To rationalize a denominator, multiply the numerator and the denominator of the fraction thatwill result in the denominator to become a rational number.
If Denominator To Obtain Denominator
Contains the Factor Multiply by Free from surds
3 3 ( ) 33 2 =13 + 13 ( ) 21313 22 ==32 32 + ( ) 79232 22 ==
35 35 +
( ) ( ) 2353522
==
In rationalizing the denominator of a quotient, be sure to multiply both the numerator and the
denominator by the same expression.
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Mathematic KFP00105
Topic 1 : Number System
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Example
Rationalise:
(a)3
5(b)
32
3(c)
27
1
(d)35
32
Solution
a)3
5=
3
5
3
3
=3
35.
(b)
32
3
3
3
32
3x=
)3(2
33=
2
3=
(c)27
1
= (
27
1
)
)27(
)27(
+
+
= 22 )2()7(
)27(
+
=249
27
+
=47
27 +.
(d)35
32
= (35
32
)(35
35
+
+)
= 2
2
)3(353525
)3(2310
+
+
=22
6310 +
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Mathematic KFP00105
Topic 1 : Number System
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Example
Rationalise the denominator and simplify.
(a) 517
517
+
(b) 21
31
21
21
+
+
+
(c) 223
23+
+
Solution
(a)517
517
+
=517
517
+
)517(
)517(
=( )( )
22 )5()17(
517517
= 517
)5(175517)17( 22
+
=12
1752517 +
=12
85222
=12
)8511(2
=6
8511.
(b)21
21
21
21
+
+
+=
)21)(21(
)21)(21()21)(21(
+
+++
=[ ] ]
2
22
)2(221
)2(221)2(221
+
++++
=1
6
= -6
(c) 223
23+
+= 2
23
23
23
23+
+
+
+x
= 2)2(66)3(
)2(66)3(22
22
+
+
+++
= 21
625+
+
= 2625 ++
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Mathematic KFP00105
Topic 1 : Number System
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Surd Equation
Example
Solve each of the following equation :(a) 0512 =x
(b) 13 +x + 1 =x
(c) x + 2+x = 2
Solution
(a) 0512 =x
512 =x
22 )5()12( =x
2x 1 = 252x = 26
x = 13
(b) 13 +x + 1 =x
13 +x =x 1
( 13 +x )2 = (x 1)2
3x + 1 =x2 2x + 1
x2 5x = 0
x(x 5) = 0
x = 0 orx = 5 but x 0
x = 5
(c) x + 2+x = 2
( x + 2+x )2 = 22
x + 2 x 2+x +x + 2 = 4
2 )2( +xx = 2 2x
xx 22 + = 1 x
(xx 2
2+ )
2 = (1 x)2
x2 + 2x = 1 2x +x2
4x = 1
x =4
1
26