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    19-Apr-13

    IESO

    Observational Astronomy

    Part 5

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    19-Apr-13

    A stars color, temperature, size,

    brightness and distance are all

    related!

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    The Beginnings

    Late 1800s, early 1900s how light is produced by

    atoms is being intenselystudied by Gustav Kirchoff & Robert Bunsen

    Max PlanckJosef Stefan...

    Ludwig BoltzmannAlbert Einstein

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    Black Bodies

    In 1862, Kirchoff coins the phrase black body to

    describe an imaginary object that would perfectly

    absorb any light (ofany wavelength) that hit it.

    No light transmitted through, no light reflected off,just totally absorbed.

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    a perfect absorber of light would also be a perfectemitter

    amount of light energy given off each second (itsbrightness or luminosity) and the color of its light are

    related to the objects temperature.

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    Molten lava and hot iron are two good examples ofblack bodies, but

    a star is an excellent black body emitter.

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    Max Planck, a German physicist, was able to maketheoretical predictions of how much light of each color

    or wavelength would be given off by a perfect black

    body at any given temperature.

    These predictions or models are today called Planck

    Curves.

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    Ohio University - Lancaster Campus

    Spring 2009 PSC 100 slide 7 of 47

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    What 2 characteristics of the curves change as thetemperature increases?

    (1) The size of the curve increases.

    (2) The peak of the curves shift to the

    left, to shorter wavelengths & higher

    energies.

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    Can we draw some conclusions?

    Hotter stars should be brighter than cooler stars.

    Hotter stars should emit more of their light at shorter

    wavelengths (bluer light)

    Cooler stars should emit more of their light at longer

    wavelengths (redder light).

    All stars emit some energy at allwavelengths!

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    In 1879, Josef Stefan discovered that the luminosity of astar was proportional to the temperature raised to the

    4th power.

    In 1884, Stefans observations were confirmed whenLudwig Boltzmann derived Stefans equation from

    simpler thermodynamic equations.

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    Stefan-Boltzmann Law Today, we honor both scientists by naming the

    equation after themthe Stefan-Boltzmann Law:

    At the surface of the star, the energy thats given offper square meter (Watts / m2) called the luminous

    flux is...

    W / m2 = 5.67 x 10-8 T4

    Ohio University - Lancaster Campus slide 11 of 47

    Spring 2009 PSC 100

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    At 100 K (cold enough to freeze you solid in justseconds), a black body would emit only 5.67 W/m2.

    At 10x hotter, 1000 K, the same black body would emit104 times as much light energy, or 56,700 W/m2.

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    If the temperature of a star were to suddenly double,how much brighter would the star become?

    If the temperature of a star somehow fell to 1/3 of what

    it was, how much fainter would the star become?

    24 = 16 times brighter

    (1/3)4 = 1/81, or 81 times dimmer

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    In 1893, Wilhelm Wien (pronounce vine) discoveredby experiment the relationship between the main

    color of light given off by a hot object and its

    temperature.

    This main color is the peak wavelength, called max ,

    at the top of the Planck Curve.

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    For each curve, the

    top of the curve is the

    peak wavelength.

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    Wiens Law Wiens Law says that the peak wavelength is

    proportional to the inverse of the temperature:

    max = 2.9 x 106 T = 2.9 x 106

    T max

    T must be in Kelvin, and max in nanometers.

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    What is the peak wavelength of our sun, with a T =5750 K?

    What is the peak wavelength of a star with a surface

    temperature of 3500 K?

    2.9 x 106 = 504 nm (yellowish-green)

    5750 K

    2.9 x 106 = 829 nm (this star emits the

    3500 K majority of its light as

    infrared, IR).

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    A reddish star has a peak wavelength of 650 nm. Whatis the stars temperature?

    A star has a peak wavelength in the ultra-violet of 300 nm.

    What is the stars temperature?

    2.9 x 10

    6

    = 4462 K (cooler than the sun)650 nm

    2.9 x 106 = 9667 K

    300 nm

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    We now have a color thermometer that we can use

    to determine the temperature of any astronomical

    object, just by examining the light the object gives

    off.

    We know that different classes of objects are at

    different temperatures and give off different peak

    wavelengths.

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    What kinds of objects?

    Clouds of coldhydrogen gas

    (nebulae) emit

    radio waves

    http://www.narrowbandimaging.com/images/vdb142_small.jpg

    l d f l l h f

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    Warmer clouds of molecules where stars form

    emit microwaves and IR.

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    Protostars emit IR.

    http://www.antonine-education.co.uk/Physics_GCSE/Unit_3/Topic_10/protostar.jpg

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    Sun-like stars emit mostly visible light, while

    hotter stars peak in the UV.

    http://www.nasa.gov/images/content/138952main_whywe16full.jpg

    N d bl k h l k i h X

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    Neutron stars and black holes peak in the X-

    ray.

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    Star cores emit gamma rays.

    http://aspire.cosmic-ray.org/labs/star_life/images/star_pic.jpg

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    Where would the peak wavelength be for

    your body

    a lightning bolt

    the coals from a campfire

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    A stars spectrum is also influenced byits temperature.

    In 1872, Henry Draper obtained the firstspectrum of a star, Vega, in the

    constellation Lyra.

    photojournal.jpl.nasa.gov/jpeg/PIA04204.jpgCredit: Lick Observatory Archives

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    In 1885, Edward Pickering began a project

    at Harvard University to determine the

    spectra of many stars. Drapers widow

    funded the work.

    The first 10,000 spectra obtained were

    classified by Williamnia Fleming, using theletters A through Q.

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    From 1901 to 1919, Pickering & his assistant

    Annie Jump Cannon classified and publishedthe spectra of 225,000 stars (at the rate of

    about 5000 per month!)

    When Pickering died in 1919, Cannon

    continued the work, eventually classifying

    and publishing the spectra of 275,000 stars.

    Credit: amazing-space.stsci.edu

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    Hotter stars have

    simpler spectra.

    Cooler stars have

    more complexspectra, since most

    atoms are not ionized.

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    Class O >30,000 K bluish

    He lines in spectrum.(These stars are so hot that H is mostly ionized &

    doesnt shows lines.) Pleiades

    Class B 11,000-30,000 K bluish

    He lines, weaker H lines

    Rigel, Regulus, Spica

    Class A 8,000-11,000 K blue-

    white H lines (Balmer Series)

    Sirius, Vega

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    Class F 6,000-8,000 K white

    H, Ca lines, weaker H lines Procyon

    Class G 5,000-6,000 K yellow

    Ca, Na lines, + other metalsSun, Capella, -Centauri

    Class K 3,500-5,000 K orangeCa & other metals

    Arcturus, Aldebaran

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    Class M

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    The stellar classes (OBAFGKM) are further

    subdivided with a number 0 to 9 following the

    letter.

    Our sun, a G2 star, is slightly cooler than the

    F range. A G9 star would be just a bit warmer

    than the K range.

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    1910-1913, Henry Russell, a professor atPrinceton, and Ejnar Hertzsprung, an

    astronomer at Leiden Observatory in the

    Netherlands, used the data from the Draper

    catalog to plot the temperature of the stars

    vs. their brightness or luminosity.

    What kind of result would you expect, arandom scatter, or a pattern?

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    universe-review.ca/I08-01-HRdiagram.jpg

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    Betelgeuse and Antares show on the diagram

    as being red stars, and red stars should be

    faint.

    Both stars are also hundreds of light

    years distant, so why do they appear so

    bright in our sky?

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    Red Dwarfs

    Red

    Red

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    The H-R Diagram makes a lot moresense when you realize that the

    different regions dont show different

    kinds of stars

    but stars at different stages

    of their lives.

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    Determining distance using the HR Diagram

    From a stars color-temperature, determine

    its absolute magnitude (M).

    Observe the stars apparent magnitude (m)

    through a telescope.

    Use the distance modulus equation to

    calculate the distance.

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    How far away is an F1 star that has a surface

    temperature of 8000 K, if its apparent

    magnitude is +9.6?

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    distance in parsecs =

    10^[(9.6 - 3.0 +5) 5] =

    10^[11.6 5] =

    10^2.32 =

    209 parsecs (or 681 light years)

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    Where might this method run into trouble?

    Red & Orange star come in 2 varieties:

    giants & dwarfs.

    The spectrum of the star must be used todetermine if the star is large or small.

    The presence of what element(s) in higherthan normal percentages might indicate

    that the star is a giant, not a dwarf?