on unicyclic reflexive graphs. the spectrum of a simple graph (non-oriented, without loops and...
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ON UNICYCLIC REFLEXIVE GRAPHS
• The spectrum of a simple graph (non-oriented, without loops and multiple edges) is the spectrum of its adjacency matrix, along with the usual assumption
• The Interlacing theorem: Let be the eigenvalues of a
graph G and eigenvalues of its induced subgraph H. Then the inequalities
, , hold.• Reflexive graphs are graphs having
1 2( , ,..., )n 0,1
1 2 ... .n
1 2 ... n
1 2 ... k
n k i i i 1,2,...,i k
2 2.
• Graph G is a maximal reflexive graph inside a given class of graphs C if G is reflexive and any extension G+v that belongs to C has
• Theorem (Smith): For a simple graph G (resp. )
if and only if each component of G is an induced subgraph (resp. proper induced subgraph) of one of the graphs of Fig. 1, all of which have
2 2.
1 2G 1 2G
1 2.G
Figure 1.Connected graphs that have their largest eigenvalue (the index) equal to 2 are known as Smith graphs
1
1
3
2
n n -1
C n W n
1 2 n
• Theorem (Schwenk): Given a graph G, let ( ) denote the
set of all cycles containing a vertex and an edge of G, respectively. Then
(i)
(ii)
where Adj(v) denotes the set of neighbors of v, while G – V(C) is the graph obtained from G by removing the vertices belonging to the cycle C.
C v C uvv
uv
2 ,G G v G v u G V Cu Adj v C C v
P P P P
2 ,G G uv G v u G V CC C uv
P P P P
• Corollary 1. Let G be a graph obtained by joining a vertex of a
graph to a vertex of a graph by an edge. Let ( ) be the subgraph of ( ) obtained by deleting the vertex ( ) from (resp. ). Then
• Corollary 2. Let G be a graph with a pendant edge , being of degree 1. Then where ( ) is the graph obtained from G (resp. ) by deleting the vertex (resp. )
1v
1G 2v 2G
1G 2G
1G 2G1v 2v 1G 2G
1 2 1 2' ' .G G G G GP P P P P
1 2v v 1v
1 2
,G G GP P P
1G 2G
1v 2v1G
Theorem RS
Let G be a graph with a cut vertex u.i. If at least two components of G-u are supergraphs
of Smith graphs, and if at least one of them is a proper supergraph, then
ii. If at least two components of G-u are Smith graphs, and the rest are subgraphs of Smith graphs, then
iii. If at most one component of G-u is a Smith graph, and the rest are proper subgraphs of Smith graphs, then
2 2.G
2 2.G
2 2.G
Maximum number of loaded vertices of the cycle
in unicyclicreflexive graph
Theorem 1.
The cycle of unicyclic reflexive graph of length greater than 8 cannot have more than 7 loaded vertices.
Theorem 2.
The cycle of unicyclic reflexive graph of length greater than 10 cannot have more than 6 loaded vertices.
The length of the cycle with six loaded vertices
Theorem 3. Maximal length of the cycle of unicyclic reflexive graph with 6
loaded vertices is l = 12.
The length of the cycle with five loaded vertices
Theorem 4.
1. Maximal length of the cycle of unicyclic reflexive graph with 5 loaded vertices, if these vertices are not consecutive, is l = 14.
2. Maximal length of the cycle of unicyclic reflexive graph with 5 consecutive loaded vertices is l = 16.
The length of the cycle with four loaded vertices
Theorem 5.
1. Maximal length of the cycle of unicyclic reflexive graph with 4 loaded vertices, if there are no consecutive loaded vertices on the cycle, is l = 16.
2. Maximal length of the cycle of unicyclic reflexive graph with 4 loaded vertices, if there are are two (but not three, and not four) consecutive loaded vertices on the cycle is l = 21.
3. Maximal length of the cycle of unicyclic reflexive graph with 4 loaded vertices, if there are are three (but not four) consecutive loaded vertices on the cycle is l = 38.
4. The length of the cycle of unicyclic reflexive graph with 4 consecutive loaded vertices, has no upper bound.
Let m, p, n, q be the lengths of the paths (a; b), (c; d), (a; d), (b; c), respectivelyThe length of the cycle of graph G is l = m + p + q + n
PG(2) = mpqn-4mpn-4mnq-4pqm- 4pqn+12mn+12mq+12pq+12np+16nq+16mp-32m - 32n - 32p - 32q
m = 1: PG(2) = -3pqn + 8pn + 12nq + 8pq - 20n - 20q - 16p - 32 n
m n q PG(2) λ2≤2 λ2>2 l1. 1 2 2 4p-64 p≤16 p≥17 212. 1 2 3 6p-60 p≤10 p≥11 163. 1 2 4 8p-56 p≤7 p≥8 144. 1 2 5 10p-52 p≤5 p≥6 135. 1 2 6 12p-48 p≤4 p≥5 136. 1 2 7 14p-44 p≤3 p≥4 137. 1 2 8 16p-40 p≤2 p≥3 138. 1 2 9 18p-36 p≤2 p≥3 149. 1 2 10 20p-32 p≤1 p≥2 14
10. 1 2 11 22p-28 p≤1 p≥2 1511. 1 2 12 24p-24 p≤1 p≥2 1612. 1 3 3 5p-44 p≤8 p≥9 1513. 1 3 4 4p-28 p≤7 p≥8 1514. 1 3 5 3p-12 p≤4 p≥5 1315. 1 3 6 2p+4 / p≥1 /16. 1 3 7 p+20 / p≥1 /17. 1 3 8 36 / p≥1 /
m = n = 1: PG(2) = 5pq - 8p - 8q – 52
p≥35: PG(2)= 167q - 332 > 0
p≥11 and q≥3: PG(2)= 47q - 140 > 0
p PG(2) λ2≤2 λ2>2 l
1. 2 2q-68 q≤34 q≥35 38
2. 3 7q-76 q≤10 q≥11 15
3. 4 12q-84 q≤7 q≥8 13
4. 5 17q-92 q≤5 q≥6 12
5. 6 22q-100 q≤4 q≥5 12
6. 7 27q-108 q≤4 q≥5 13
7. 8 32q-116 q≤3 q≥4 13
8. 9 37q-124 q≤3 q≥4 14
9. 10 42q-132 q≤3 q≥4 15
m=n=p=1: PG(2) = -3q - 60 < 0
The length of the cycle with three loaded vertices
Theorem 6. Let G be the unicyclic reflexive graph with exactly three
loaded vertices of the cycle, and let m, n and k be the lengths of the paths between its loaded vertices, p= min (m,n,k).
1. If p≥3 then the maximal length of the cycle is 18. 2. If p=2: 2.1. m=n=2, the length of the cycle is not bounded. 2.2. m=2, n≥3, k≥3, maximal length of the cycle is 23. 3. If p=1: 3.1. m=n=1, or m=1, n=2, the length of the cycle is not bounded. 3.2 m=1, n≥3, k≥3, maximal length of the cycle is 40.
Let m, n, k be the lengths of the paths (a; b), (b; c), (c; a), respectively
The length of the cycle of graph G is l = m + n + k
p = min (m,n,k)
PG(2) = -mnk + 4mn + 4mk + 4nk - 12m - 12n - 12k
p=1: p=3:
p=2: p=4:
m n k l1 3 k≤36 7≤l≤401 4 k≤11 8≤l≤161 5 k≤7 9≤l≤131 6 k≤6 10≤l≤13
m n k l2 3 k≤18 8≤l≤232 4 k≤10 9≤l≤162 5 k≤7 10≤l≤142 6 k≤6 11≤l≤14
m n k l
3 3 k≤12 9≤l≤18
3 4 k≤9 10≤l≤16
3 5 k≤7 11≤l≤15
3 6 k≤6 12≤l≤15
m n k l
4 4 k≤8 12≤l≤16
4 5 k≤7 13≤l≤16
4 6 k≤6 14≤l≤16
p=5:1. m=n=k=5, l=152. m=n=5, k=6, l=163. m=5, n=k=6, l=17
p=6:m=n=k=6, l=18