ordered containers cmput 115 - lecture 19 department of computing science university of alberta...

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Ordered Containers Ordered Containers CMPUT 115 - Lecture 19 Department of Computing Science University of Alberta ©Duane Szafron 2003 Some code in this lecture is based on code from the book: Java Structures by Duane A. Bailey or the companion structure package

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Ordered ContainersOrdered Containers

CMPUT 115 - Lecture 19

Department of Computing Science

University of Alberta

©Duane Szafron 2003Some code in this lecture is based on code from the book:

Java Structures by Duane A. Bailey or the companion structure package

©Duane Szafron 2003

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About This LectureAbout This Lecture

In this lecture we will learn about Ordered containers.

An ordered container is a container where the order of the elements depends not on the order they are added, but rather on comparisons of the elements that are added.

©Duane Szafron 2003

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OutlineOutline

Ordered Containers OrderedStructure Interface OrderedStructure Example OrderedVector class OrderedList class

©Duane Szafron 2003

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Ordered ContainersOrdered Containers

An ordered container is a container whose elements are ordered by comparing them with each other.

This requires a binary operation to be defined that applies to any pair of elements that can be added to the container.

In Java, we use the compareTo(Object) method from the Comparable Interface.

As each element is added to the container it immediately goes to the proper location in the container based on comparing it with all other elements that are in the container.

©Duane Szafron 2003

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OrderedStructure HierarchyOrderedStructure Hierarchy

The structure package adds the OrderedStructure interface below the Collection interface.

Store

Collection

List OrderedStructure

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Structure Interface - StoreStructure Interface - Store

public interface Store {public int size();//post: returns the number of elements contained in // the store.

public boolean isEmpty();// post: returns the true iff store is empty.

public void clear();// post: clears the store so that it contains no // elements.

}

code based on Bailey pg. 18

©Duane Szafron 2003

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Structure Interface - CollectionStructure Interface - Collection

public interface Collection extends Store {public boolean contains(Object anObject);// pre: anObject is non-null// post: returns true iff the collection contains the object

public void add(Object anObject);// pre: anObject is non-null// post: the object is added to the collection. The // replacement policy is not specified

public Object remove(Object anObject);// pre: anObject is non-null// post: removes object “equal” to anObject and returns it,// otherwise returns null

public Iterator elements();// post: return an iterator for traversing the collection

}

code based on Bailey pg. 19

©Duane Szafron 2003

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Structure Interface - OrderedStructureStructure Interface - OrderedStructure

public interface OrderedStructure extends Collection {}

code based on Bailey pg. 173

The unusual thing about the OrderedStructure interface is that it does not add any new methods to those provided by Collection.

However, any class that implements this interface must ensure that when elements are added, they go to the correct location.

In essence, it changes the postcondition of the add method in Collection:// post: the object is added to the collection. The // replacement policy is not specified

©Duane Szafron 2003

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OrderedStructure ExampleOrderedStructure Example

public static void main(String[] args) {

OrderedStructure container;RandomInt generator;int index;Iterator iterator;

container = new OrderedVector();generator = new RandomInt(1);for (index = 0; index < 100; index++) {

container.add(new Integer(generator.next(100)));iterator = container.elements();while(iterator.hasMoreElements())

System.out.print(iterator.nextElement() + ' ');}

code based on Bailey pg. 158

1 1 1 2 2 3 3 3 44 5 7 7 7 8 9 9 1013 13 14 14 15 17...

©Duane Szafron 2003

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OrderedVectorOrderedVector

One implementation of OrderedStructure uses a Vector.

As each element is added, a binary search is used to put the element in the appropriate location in the Vector.

The following method will be used in the implementation of the add method and in many other methods as well.

protected int indexOf(Comparable anObject) {// pre: anObject is non-null// post: returns index of object in the collection or where// it should be placed if it is not in the collection

©Duane Szafron 2003

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OrderedVector - OrderedVector - State and ConstructorState and Constructor

class OrderedVector implements OrderedStructure {

protected Vector data;

public OrderedVector(){// post: initializes the OrderedVector to have 0 elements

this.data = new Vector();}

code based on Bailey pg. 173

©Duane Szafron 2003

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OrderedVector - OrderedVector - Store InterfaceStore Interface

/* Interface Store Methods */public int size() {//post: returns the number of elements contained in // the store.

return this.data.size();}

public boolean isEmpty() {// post: returns the true iff store is empty.

return this.size() == 0;}

public void clear(){// post: clears the store so that it contains no // elements.

this.data.clear();}

code based on Bailey pg. 178

©Duane Szafron 2003

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OrderedVector - OrderedVector - contains(Object)contains(Object)

/* Interface Collection Methods */ public boolean contains(Object anObject) {

// pre: anObject is non-null// post: returns true iff the collection contains the object

int index;

index = this.indexOf((Comparable) anObject);return (index < this.size()) &&

(this.data.elementAt(index).equals(anObject));}

code based on Bailey pg. 176

©Duane Szafron 2003

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OrderedVector - OrderedVector - add(Object)add(Object)

public void add(Object anObject){// pre: anObject is non-null// post: the object is added to the collection at the// appropriate position based on comparing it to the other// elements.

int index;

index = this.indexOf((Comparable) anObject);this.data.insertElementAt(anObject, index);

}

code based on Bailey pg. 176

©Duane Szafron 2003

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OrderedVector - OrderedVector - remove(Object)remove(Object)

public Object remove(Object anObject){// pre: anObject is non-null// post: removes object “equal” to anObject and returns it,// otherwise returns nil

int index;Object result;

index = this.indexOf((Comparable) anObject));if (index < this.size()) && (this.data.elementAt(index).equals(anObject)) { result = this.data.elementAt(index); this.data.removeElementAt(index); return result;}return null;

}

code based on Bailey pg. 177

©Duane Szafron 2003

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OrderedVector - OrderedVector - elements()elements()

public Iterator elements(){// post: return an iterator for traversing the collection

return this.data.elements();}

code based on Bailey pg. 177

©Duane Szafron 2003

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The Search ProblemThe Search Problem

To complete this class, we need to solve the search problem for a sorted container.

Given a container, find the index of a particular element, called the key.

If it is not there, find the index where it should be. We use a modified version of a Binary search:

– start with one extra space since the index we are looking for may be one past the end.

– stop when there is only one element left - it is either the element we are looking for or the element should be inserted before it.

30 10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

©Duane Szafron 2003

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Modified Binary Search - foundModified Binary Search - found

30 middle = (low + high) / 2

high = middle - 1

HML

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

low = middle + 1

L HM

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

HH H H HL HM

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

©Duane Szafron 2003

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Element not found - 1Element not found - 1

35

middle = (low + high) / 2

high = middle - 1

HML

L HM

low = middle + 1

L HM

middle = (low + high) / 2

middle = (low + high) / 2

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

©Duane Szafron 2003

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Element not found - 2Element not found - 2

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H

low = middle + 1

L HM

low < high

middle = (low + high) / 2LM

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

Notice that if we were looking for 50, the same steps would be taken so when (low < high) becomes false, it is either because we found the key or because the key should be inserted before the stopping index.

©Duane Szafron 2003

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Element past end -1Element past end -1

90

middle = (low + high) / 2

HML

L HM

low = middle + 1

L HM

middle = (low + high) / 2

middle = (low + high) / 2

10 25 30 50 55 60 70 75 80

0 1 2 3 4 5 6 7 8 9

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

low = middle + 1

©Duane Szafron 2003

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Element past end - 2Element past end - 2

90

H

low = middle + 1

L HM

low < high

middle = (low + high) / 2 LM

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

10 25 30 50 55 60 70 75 800 1 2 3 4 5 6 7 8 9

©Duane Szafron 2003

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OrderedVector - OrderedVector - indexOf(Object) 1indexOf(Object) 1

/* Protected Methods */ protected int indexOf(Comparable anObject) {

// pre: anObject is non-null// post: returns index of object in the collection or where// it should be placed if it is not in the collection

Comparable midObject;int low;int high;int middle;int comparison;

low = 0;high = this.data.size();middle = (low + high) / 2;

code based on Bailey pg. 174

©Duane Szafron 2003

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OrderedVector - OrderedVector - indexOf(Object) 2indexOf(Object) 2

while (low < high) { midObject = (Comparable)

this.data.elementAt(middle); comparison = midObject.compareTo(anObject); if (comparison) < 0)

low = middle + 1; else if (comparison > 0)

high = middle - 1; else

return middle; middle = (low + high) / 2;}return low; //low is either the index of the key or

} // the key should be inserted at this index.

code based on Bailey pg. 174

©Duane Szafron 2003

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©Duane Szafron 2003

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Time Complexity of OrderedVectorTime Complexity of OrderedVector

The indexOf(Object) method does O(log(n)) comparisons to find the index.

Since the contains(Object) method makes a single call to indexOf(Object), the contains(Object) method is O(log(n).

The add(Object) and remove(Object) methods also call indexOf(Object).

However, they also requires O(n) assignments to move elements in methods add(Object) and remove(Object).

Therefore, add(Object) and remove(Object) are O(n) in OrderedVector.

©Duane Szafron 2003

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OrderedListOrderedList

We can also implement the OrderedStructure Interface using a linked list in a class called OrderedList.

However, we do not simply bind an instance variable to a linked list object like a SinglyLinkedList since we require access to the middle of the list to put added elements in the correct location.

Therefore we use SinglyLinkedListElements and link them together manually.

©Duane Szafron 2003

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OrderedList - OrderedList - difference from OrderedVectordifference from OrderedVector

The important difference between OrderedList and OrderedVector is that the internal implementation of OrderedVector has access to the indexes of the underlying Vector elements.– This allows us to find the index of a particular element so

that it can be found, added, or removed.– It also allows us to do a binary search since we can divide

the search list in half using the indexes.

©Duane Szafron 2003

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OrderedList - Sequential SearchOrderedList - Sequential Search

In OrderedList, we create an analog of the indexOf(Object) method called previousOf(Object) which returns the node before the node containing the object, or the node before the node where the object should be inserted.

Unfortunately, we must do a sequential search instead of a binary search.

However, we can stop early if we encounter an element that is larger than the one we are looking for.

©Duane Szafron 2003

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OrderedList - OrderedList - State and ConstructorState and Constructor

public class OrderedList implements OrderedStructure {

protected SinglyLinkedListElement head;protected int count;

public OrderedList(){// post: initializes the OrderedList to have 0 elements

this.clear();}

code based on Bailey pg. 180

©Duane Szafron 2003

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OrderedList - OrderedList - Store InterfaceStore Interface

/* Interface Store Methods */public int size() {//post: returns the number of elements in the store.

return this.count;}

public boolean isEmpty() {// post: returns the true iff store is empty.

return this.size() == 0;}

public void clear(){// post: clears the store so that it contains no // elements.

this.head = null;this.count = 0;

}

code based on Bailey pg. 180

©Duane Szafron 2003

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OrderedList - OrderedList - elements()elements()

public Iterator elements(){// post: return an iterator for traversing the collection

return new SinglyLinkedListIterator(this.head);}

code based on Bailey pg. 182

©Duane Szafron 2003

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OrderedList - OrderedList - previousOf(Object) 1previousOf(Object) 1

/* Protected Methods */ protected SinglyLinkedListElement previousOf(Object anObject)

{// pre: anObject is non-null// post: returns the node before the node that contains the// given object, if the object is in the collection or the// node before where it should be placed if it is not in the // collection

SinglyLinkedListElement cursor;SinglyLinkedListElement previous;Comparable key;

cursor = this.head;previous = null;key = (Comparable) anObject;

code based on Bailey pg. 181

©Duane Szafron 2003

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OrderedList - OrderedList - previousOf(Object) 2previousOf(Object) 2

while ((cursor != null) && (((Comparable) cursor.value()).compareTo(key) < 0)) { previous = cursor; cursor = cursor.next();}return previous;

}

code based on Bailey pg. 181

©Duane Szafron 2003

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OrderedList - OrderedList - contains(Object)contains(Object)

/* Interface Collection Methods */ public boolean contains(Object anObject) {

// pre: anObject is non-null// post: returns true iff the collection contains the object

SinglyLinkedListElement previous;SinglyLinkedListElement current;

previous = this.previousOf((Comparable) anObject);if (previous == null) // no previous element, first node current = this.head;else current = previous.next();if (current == null) return false;else return current.value().equals(anObject);

}

code based on Bailey pg. 180