paku sarawak 2013 m2(a)

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  • 8/13/2019 PAKU SARAWAK 2013 M2(A)

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    CONFIDENTIAL*/SULIT

    STPM 950/2CONFIDENTIAL*

    *This question paper is CONFIDENTIAL until the examination is over.

    2

    67

    12

    )24(2

    1Median

    th

    th

    5.57

    2

    5857

    6

    )24(4

    1Q1

    th

    th

    74

    18

    )24(4

    3Q3

    th

    th

    1M

    c.

    75.32

    )5.5774(2

    35.57

    )(2

    3QboundaryLower 131

    QQ

    75.106

    )5.5774(2

    374

    )(2

    3QboundaryUpper 131

    QQ

    Outlier = 1081 M

    2M

    4a)

    Interquartile range = 13 QQ

    = 74 -57.5 = 16.5

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    CONFIDENTIAL*/SULIT

    STPM 950/2CONFIDENTIAL*

    *This question paper is CONFIDENTIAL until the examination is over.

    3

    5. 2M

    6 a) GraphYear Quarter Unemployed 4-quarter Centred 4-quarter Deviation

    3M

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    STPM 950/2CONFIDENTIAL*

    *This question paper is CONFIDENTIAL until the examination is over.

    4

    school

    leavers

    moving

    average

    moving average

    (t)

    (y-t)

    2010 1 22

    2 12

    43.75

    3 110 43.625 66.375

    43.504 31 45.25 -14.250

    47.00

    2011 1 21 52.00 -31.000

    57.00

    2 26 61.875 -35.875

    66.75

    3 150 70.375 79.625

    74.00

    4 70 75.250 -5.250

    76.50

    2012 1 50 76.000 -26.000

    75.50

    2 36 80.500 -44.50085.50

    3 146

    4 110

    b) seasonal variation

    Year Quarter 1 Quarter 2 Quarter 3 Quarter 4

    2010 66.375 -14.250

    2011 -31.000 -35.875 79.625 -5.250

    2012 -26.000 -44.500

    Unadjusted

    seasonal

    variation

    -28.500 -40.188 73.000 -9.750

    Correctionfactor

    -1.3595 -1.3595 -1.3595 -1.3595

    Seasonal

    Variation

    -27.14 -38.83 74.36 -8.39

    C)The least square method

    4822 x 66x 794182 y 784y 4627xy

    12

    )66(482

    12)784)(66(4629

    2

    = 2.664 1M

    [1M]

    [2M]

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    CONFIDENTIAL*/SULIT

    STPM 950/2CONFIDENTIAL*

    *This question paper is CONFIDENTIAL until the examination is over.

    5

    12

    66664.2

    12

    784a =50.68

    Regression line, y= 50.68+2.664x

    For the first quarter of the year 2013,e

    T = 50.68+2.664(13) = 85.312

    Unemployed school leavers for the first quarter of the year 2013=85.312+ (-27.14) = 58.172 59

    Or

    Average quarterly increment =7

    625.435.80 =5.2679

    For the first quarter of the year 2013,e

    T = 80.5 + 3 x 5.2679 = 96.304

    Unemployed school leavers for the first quarter of the year 2013

    = 96.304 + (-27.14)= 69.164 69

    1M

    1M

    1M

    1M

    2M

    1M

    7a Histogram

    b) 5.62)125(21

    21 N

    minutes58.30)1(30

    45)125(2

    1

    30

    2

    1

    Median,

    cf

    FN

    LMm

    2M

    x f fx 2fx Cumulative

    frequency,F26.5 6 6

    28.5 12 18

    29.5 27 45

    30.5 30 75

    31.5 18 93

    32.5 14 107

    33.5 9 116

    34.5 4 120

    37.5 5 125

    5.3861fx 25.1199052 fx

    89.30125

    5.3861

    ,Mean

    f

    fx

    x

    220.2)89.30(125

    25.119905,DeviationStandard 2

    2

    f

    fx

    f

    fx

    1M

    2M

    c. Pearson coefficient of skewness 1M

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    CONFIDENTIAL*/SULIT

    STPM 950/2CONFIDENTIAL*

    *This question paper is CONFIDENTIAL until the examination is over.

    6

    =deviationstandard

    median)3(mean= 4189.0

    2.220

    )58.303(30.89

    The distribution is positively skewed or skewing to the right.

    1M

    7d)

    .The number of times a bus arrives at town B between 0830 hours and 0836

    hours = 122-45 = 77 2M

    8a) Let X be the number of books read by an adult

    Then, )5(0PX

    a)

    1404.0!3

    )5()3(

    35

    e

    XP

    b) In 5 years, 2555 1M1M

    1M

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    STPM 950/2CONFIDENTIAL*

    *This question paper is CONFIDENTIAL until the examination is over.

    7

    0.1

    !2

    )25(

    !1

    )25(

    !0

    )25(-1

    )]2()1()0([1)2(

    225125025

    eee

    XPXPXPXP

    1M

    b)(i)

    0.0228

    0.9772-1

    2)P(z-1

    2)P(z

    10

    5070)70(

    zPXP

    Hence, percentage of candidates = 0.0228 x 100% = 2.28%(ii)

    76.44

    524.010

    50

    0.524z

    0.70z)P(Z

    70.010

    50

    70.0)(

    x

    x

    xZP

    xXP

    Hence, minimum marks required = 45

    2M

    1M

    2M

    1M

    8c) Expected number, 8)(E npx

    Variance, Var (x) = npq = 1.6

    8

    6.1

    np

    npq

    q = 0.2 p = 0.8 n = 10 )8.0,10(X (i) P( a teacher chosen at random owns a proton car) = 0.8(ii) P( exactly 4 teachers from the group own Proton cars)

    = P(X = 4)

    = 4104410 )2.0()8.0( C = 0.005505

    2M

    1M

    2M