Part 3

The electric field can push AND pull charges Because there are two types of charges (+

and -)

The gravitational field can only pull Only positive masses

Charges cause an electrical field.Each charge creates its own electric

field in the surrounding space.

Electric Field is a vector quantity Has magnitude and direction

Use Electric Field lines(lines of force) to show the Electric Field

Electric field direction from charge that creates the field: Away from positive charge

Toward negative charges

The lines begin on positive charges and end on negative charges.

Draw lines perpendicular to charge Lines never cross

Electric field strength: The closer to the charge, the stronger the field The closer the field lines, the stronger the field The farther away, the weaker the field

Electric field strength: The number of lines are proportional to

strength The more lines the stronger the field

Electric field strength: (quantitative)

E = kq/d2

▪ Depends on Charge and distance

E = Electric field strength (Newton/Coulomb, N/C)

k = 9.0 x 109 Nm2/C q= charge causing the field (Coulomb, C) d or r = distance (meters, m)

A fly accumulates 3.0 x 10-10 C of positive charge as it flies through the air. What is the magnitude and direction of the electric field at a location 2.0 cm away from the fly?

q = 3.0 x 10-10Cd or r = 2.0 cm = _____ mE = ? equation E = kq/ r2

E = (9.0 x 109)(3.0x10-10) (0.020)2

E = 6750 N/C

0.020

Electric Field = force exerted on positive charge

If +q = force in same direction (pull) of the field If -q = force in opposite direction (push) of the field

The strength of the electric field…

E = F/qE = strength of the field

(Newton/Coulomb, N/C)F = Force exerted on charge in field

(Newton, N)q = charge (Coulomb, C) that sits in

the field; experiences the force

A charge of -2.0 xC is placed in a uniform electric field of strength 5000 N/C that points downward. What is the magnitude and direction of the force experienced by this charge?

E = F / q 5000 N/C= F / (-2.0 x 10-6C) (-2x10-6 )(5000)=F -0.01N=F magnitude of the forcedirection? - 2 charge, the force on the electron is opposite the field!

A charge of -2.0 xC is placed in a uniform electric field of strength 5000 N/C that points downward. What is the magnitude and direction of the force experienced by this charge?