penny for your thoughts 1. take a sample of size 5 from the population 2. calculate p = the...
TRANSCRIPT
Ch 7 - Sampling Distribution
Vocabulary
•Population (review)
•Sample (review)
•Parameter
•Statistic
*Hint: the p’s and the s’s go together!
NotationVERY IMPORTANT! and you will loose points on the exam if you use the wrong notation (as well as if you use the wrong word)
•Population mean:
•Sample mean: x
•Population Proportion: p
•Sample Proportion: p
_
^
Identify the population, the parameter, the sample, and the statistic in each of the following settings.
a) A pediatrician wants to know the 75th percentile for the distribution of heights of 10-year-old boys, so she takes a sample of 50 patients and calculates Q3 = 56 inches.
b) A Pew Research Center Poll asked 1102 12- to 17-year-olds in the United States if they have a cell phone. Of the respondents, 71% said Yes.
Randomly select 5 cards from a shuffled deck (of only cards 2 - 10) and note the median value. Then replace your cards. We will repeat this “many, many” times
Create a table of sample medians
Create a dotplot of sample medians
Describe what you see.
Sampling Distribution
The sampling distribution of a statistic is the distribution of values taken by the statistic in all possible samples of the same size from a population.
For example, in our card activity if we were able to take every possible sample of size 5 of cards 2 through 10 and record the outcomes, that would be the sampling distribution of the median of a deck of cards when selecting 5 cards.
That would be 36 nCr 5 = 376,992 different samples!
It’s very time consuming to take all possible samples, instead simulations are done to imitate the process we just did. (FATHOM)
Using Fathom to simulate choosing 500 SRSs of size 5 from
the deck of cards 2 though 10 and finding the sample medians produced the following dotplot.
Describe it!What is the population median?Is there any connection to the
population and the sampling distribution?
Distribution, Distribution, Distribution...
There are 3 different types of distributions:
1. Population Distribution
2. Distributions of Sample Data
3. Sampling Distributions
What’s the difference between the 3 distributions?
A population distribution is one graph of everything possible as a whole.
What would it have been for out card activity?
A distribution of sample data is an individual graph depicting each outcome from the sample you drew from the population.
What would it have been for out card activity?
Sampling distribution describes how a statistic varies in many, many samples of the population. You are no longer looking at the individual elements in the sample/population.
What would it have been for out card activity?
Helpful HintPopulation & Sample Distributions describe individuals
Sampling Distribution describes a statistic.
Let’s look at page 420 for a diagram to help
More questions about our card simulation:
Was that a sampling distribution?
If someone claims to set up the same activity and they select a sample of size 5 and get a median of 4, is that convincing evidence that they set their deck up wrong?
According to the National Center for Health Statistics, the distribution of heights for 16-year-old females is modeled well
by a Normal density curve with mean of 64 inches and standard deviation of 2.5 inches.
A. Make a graph of the population distribution.
B. Sketch a graph of at the distribution of sample data for an SRS of size 20.
Exit Slip - you must complete
p420 CYU #1 - 3 ON YOUR OWN
BEFORE OU LEAVE!
Biased or Unbiased?So which sample statistics are biased and which are unbiased? To find
out, let’s collect some quantitative data:1. On the piece of paper given to you write how many hours of sleep you got last night.2. Each of you will randomly select a sample of 4 cards.3. You will need to record the following information: the four numbers, the sample mean, and the sample range.4. Replace the cards.5. Pass the bag to the next person then record your sample mean and sample range on the corresponding dotplots on the board.6. Once everyone plots their data, we will analyze it and compare it to the population mean and population range.
Definitions
•Biased Estimator - the mean of a sampling distribution is not close to the population’s parameter being estimated
•Unbiased Estimator - the mean of a sampling distribution is equal to the value of the parameter being estimated
Biased and Unbiased
Estimators•This is different than the sampling
process being biased. When using an estimator (i.e. a measure of center or spread) we are assuming the sampling process is not biased.
•The actual statistic we are finding can be biased or unbiased as well.
Variability of a Statistic
“the spread of the sampling distribution”
•What will help decrease the variability?
•Will it decrease bias?To answer these questions,
let’s read p424 - 426
7.2 - Sample Proportions
Remember your notation:
population parameter is p
sample proportion is p^
More NotationsWe have a population, we take a sample, and find some proportion.
If we want to investigate those sample proportions we can find the mean and standard deviation of the sampling distribution of the sample proportions.
mean of sample proportions:
standard deviation of sample proportions:
^
^
Describe the Sampling Distribution of p
SHAPE: sometimes it can be approximated by the Normal curve. It depends on the sample size n and the population proportion p.
CENTER: = p because p is an unbiased estimator of p.
SPREAD: gets smaller as n gets larger. The value of depends on both n and p.
^^
^
^
p. 436 shows a good, small proof of why these are true
^
Sampling Distribution of a Sample Proportion
Choose an SRS of size n from a population of size N with proportion p of successes. Let p be the sample proportion of successes. Then:
➡ the mean of the sampling distribution of p is = p
➡ the standard deviation of the sampling distribution of p is
➡ AS LONG AS THE 10% CONDITION IS SATISFIED:
➡ if and , the Normal conditions are satisfied and the sampling distribution of p is approximately Normal.
^
^
^
^
^
^
Formulas are on your formula sheet
In a Gallop Poll of 1785 random adults, 44% said that attend a religious service last week. Suppose the actual adult population that attends a religious service is 40%.
a) What is the mean of the sampling distribution of p-hat?
b) Find the standard deviation & check the 10% condition
c) Is the sampling distribution of p-hat approximately Normal?
d) Find probability of obtaining a sample of 1785 adults with 44% or more attended a service? Do you have doubts in this poll?
e) What would the sample size need to be to reduce the standard deviation of the sampling distribution by 1/3?
The superintendent of a large school district wants to know what proportion of middle school students in her district are planning on attending a four-year college or university. Suppose that 80% of all middle school students in her district are planning on attending a four-year college or university. What is the probability that an SRS of size 125 will give a result within 7 percentage points of the true value?
We will use the 4-step method to solve this problem.
State
We want to find the probability that the percentage of middle school students that plan to attend a 4-year college or university falls between 73% and 87%
or in symbols: P(0.73 < < 0.87)
Plan= 0.80.
Since the school district is large, we’ll assume the 10% condition is satisfied and there are more than 1250 students. (10*125 = 1250). So, = 0.036^
^
We can consider the distribution of p to be approximately Normal since the following are true:np = 125(.8) = 100 > 10 n(1-p)= 125(.2) = 25 > 10
DoP(0.73 0.87) = normalcdf(0.73, 0.87, 0.80, 0.036) = 0.948
If you want full credit on the exam, you must have clearly said everything in the “Plan” step and these calculations will receive full credit.
^
Sketching a Normal curve will help.You can also use Table A to find the answer. Remember to standardize (z-score) first!
Conclude
About 95% of all SRSs of size 125 will give a sample proportion within 7 percentage points of the true proportion of middle school students who want to attend a four-year college or university.
7.3 - Sample Means
More Notation!
Mean of the sampling distribution:
Standard deviation of the sampling distribution of the sample means:
All of the notations in this chapter are very important and very similar. You will loose credit for using the wrong notations on the exam. So if you can’t remember it’s always best to write out what you are finding rather than try to use a notation.
__
The mean of the sampling distribution of is
Suppose that x-bar is the mean of an SRS of size n drawn from a large population with mean and standard deviation , it does not matter what shape the population has.
The standard deviation of the sampling distribution of is
as long as the 10% condition is satisfied!
These formulas are on your formula
sheet
𝜇𝑥=𝜇 𝜎 𝑥=𝜎√𝑛
If you are asked to find the sampling distribution of x, these means to state if it is Normal and find the mean and standard deviation.
Hint: if the population itself is approximately Normal, then so is the sampling distribution of x.
Hint: Please read carefully! Make sure you know if you are using the population standard deviation or the sample means standard deviation before you standardize or use your normalcdf on your calculator.
_
_
A grinding machine in an auto parts plant prepares axels with a target diameter mu = 40.125 mm. The machine has some variability, so the standard deviation of the diameters is sigma = 0.002 mm. The machine operator inspects a random sample of 4 axles each hour for quality control purposes and records the sample mean diameter x.
a) Assuming the process is working properly, what are the mean and standard deviation of the sampling distribution of x?
b) Can you find the probability that x is within +.05 mm if you are choosing an SRS of 100 axels? Explain
c) In order for you to pass this inspection the standard deviation of the sampling distribution of x needs to be 0.0005 mm. How many axels would you have to sample?
_
-_
_
The composite scores of individual students on the ACT in 2009 followed a Normal
distribution with mean 21.1 and standard deviation 5.1.a) What is the probability that a single
student randomly chosen from all those taking the test scores 23 or higher? Show your work.
b) Now take an SRS of 50 students who took the test. What is the probability that the mean score x of these students is 23 or higher?
What if the population shape is not Normal?
http://onlinestatbook.com/stat_sim/sampling_dist/index.html
Central Limit Theorem
Draw an SRS of size n from any population with mean and finite standard deviation
CLT - when n is large, the sampling distribution of the sample means x is
approximately Normal.
_
NOTE: this is of the
sample means, not
just any sample!!!
How large is large?In order for the Normal conditions to apply for the sample means, and the population is not Normal the CLT will apply in most cases if
The number of flaws per square yard in a type of carpet material varies with the mean 1.6 flaws per square yard and standard deviation 1.2 flaws per square yard. The population distribution cannot be Normal, because a count takes only whole-number values. An inspector studies 200 square yards of material, records the number of flaws found in each square yard, and calculates x, the mean number of flaws per square yard inspected. Find the probability that the mean number of flaws exceeds 2 per square yard.
_
State
What’s the probability that the mean number of flaws per square yard of carpet is more than 2?
Plan•The mean of the sampling
distribution of the sample means is
•10% condition is met since there’s more than 2000 square yards of carpet, so
•Since the sample size is large, 200 > 30, we can safely use the Normal distribution as an approximation for the sampling distribution of x
_
_
_
DoDraw the curve,
find P(x > 2) = normalcdf(2, 100, 1.6, 0.085) = 0
**identify what these numbers are or:
z = (2 - 1.6)/.085 = 4.705
P(z > 4.705) = 0
Conclude
There is virtually no chance that the average number of flaws per yard in the sample will be greater than 2.