Percent Composition AKA “Mass Percent” AKA “Mass Percent” AKA “Percent by Mass” AKA “Percent by Mass” Component Mass Component Mass Total Mass Example:

Download Percent Composition AKA “Mass Percent” AKA “Mass Percent” AKA “Percent by Mass” AKA “Percent by Mass” Component Mass Component Mass Total Mass Example:

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Practice: What is the percent composition for each component in sodium carbonate, Na2CO3? 2(22.99 g/mol) = g/molNa g/mol = g/molC + 3(16.00 g/mol) = g/molO g/mol Na2CO3

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<p>Percent Composition AKA Mass Percent AKA Mass Percent AKA Percent by Mass AKA Percent by Mass Component Mass Component Mass Total Mass Example: C2H4O2C2H4O2C2H4O2C2H4O2 2(12.01 g/mol) = g/molMass C 4( 1.01 g/mol) = 4.04 g/mol Mass H +2(16.00 g/mol) = g/molMass O g/molMass C 2 H 4 O g/molMass C 2 H 4 O 2 X 100% % Composition % C % C % H % H % O % O Total = % 39.99% C 53.28% O 6.73% H Practice: What is the percent composition for each component in sodium carbonate, Na2CO3? 2(22.99 g/mol) = g/molNa g/mol = g/molC + 3(16.00 g/mol) = g/molO g/mol Na2CO3 Na: Na: C: C: O: O: Total = % 43.38% Na 45.29% O 11.33% C Converting Mass Percent to an Empirical Formula (Mole Ratio) Determine Determine the empirical formula of a compound that contains 58.84% Barium, 13.74% Sulfur and 27.43% Oxygen. Assume 100 g 58.84% Ba58.84 g Ba 13.74% S13.74 g S 27.43% O27.43 g O Did somebody ask for a mole? Ba : S : O mol : mol : mol mol mol mol mol mol mol : : BaSO 4 Barium Sulfate</p>

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