pg 586-587: 1 - 21 all; pg 582-584: 1 - 24 all. chapter 9 review

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Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all

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Page 1: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all

Page 2: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Chapter 9 Review

Page 3: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Theorem 9.1: If the altitude is drawn to the hypotenuse of a right triangle, then the two triangles formed are similar to the original triangle and to each other.

CNB~ANC~ACB:Then

CN altitude ACB; rt with ABC :Given

A

C

BN

Page 4: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Theorem 9.2 (Geo mean altitude): When the altitude is drawn to the hypotenuse of a right triangle, the length of the altitude is the geometric mean between the segments of the hypotenuse.

CN altitude ACB; rt with ABC :Given

A

C

BN

AN CNCN BN

=

Page 5: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Theorem 9.3 (Geo mean legs): When the altitude is drawn to the hypotenuse of a right triangle, each leg is the geometric mean between the hypotenuse and the segment of the hypotenuse that is adjacent to that leg.

CN altitude ACB; rt with ABC :Given

A

C

BN

AB ACAC AN

=

Page 6: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Theorem 9.3 (Geo mean legs): When the altitude is drawn to the hypotenuse of a right triangle, each leg is the geometric mean between the hypotenuse and the segment of the hypotenuse that is adjacent to that leg.

CN altitude ACB; rt with ABC :Given

A

C

BN

AB ACAC AN

=AB BCBC BN

=

One way to help remember is thinking of it as a car and you draw the wheels.

Another way is hypotenuse to hypotenuse, leg to leg

Page 7: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

A

C

BN6 3

xy

w

z

6 + 3 = 9

w = 9

altGeo

x

x

x

x

23

18

3

6

2

legsGeo

y

y

y

y

63

54

6

9

2

legsGeo

z

z

z

z

33

27

3

9

2

Page 8: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

A

C

B

K

x

9

y z

w

15

16

259

x

x

legsGeo

z

z

z

z

20

400

16

25

2

altGeo

y

y

y

y

12

144

9

16

2

legsGeo

w

w

w

25

22599

15

15

Page 9: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

The Pythagorean Theorem: In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the legs.

222 cba :Then

ACB rt with ABC :Given

a

c

b

Page 10: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

8 in

Find Area

Page 11: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Converse of Pythagorean Theorem: If the square of the hypotenuse is equal to the sum of the squares of the legs, then the triangle is a right triangle.

ert triangl a is ABC :Then

cba with ABC :Given 222

a

c

b

B A

Cacute is ABC ;90CmThen

bac If 222

obtuse is ABC ;90CmThen

bac If 222

Page 12: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

12 6, 5, 2 ,1 ,3 9 8, 6, 8 11, 4,

neither)?(or obtuseor right, acute,it Is

16 64121 36 64 81 3 1 4 5 + 6 < 12

Neither

+ < + > + =

Obtuse Acute Right

Watch out, if the sides are not in order, or are on a picture, c is ALWAYS the longest side and should be by itself

Page 13: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

leg a as long as times2 is

hypotenuse the triangle,904545 aIn

904545

Theorem

legshort the times3 is leglonger

theand leg,short theas long as times2 is

hypotenuse the triangle,906030 aIn

906030

Theorem

45

45

x

x 2x

60

30

x2x

3xRemember, small side with small angle.

Common Sense: Small to big, you multiply (make bigger)

Big to small, you divide (make smaller)

For 30 – 60 – 90, find the smallest side first (Draw arrow to locate)

Page 14: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Lots of examples

Page 15: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

sine sin

cosine cos

Tangent tan

These are trig ratios that describe the ratio between the side lengths given an angle.

ADJACENT

OP

PO

SIT

E

HYPOTENUSE

adjacent

OppositeA

Hypotenuse

adjacentA

Hypotenuse

OppositeA

tan

cos

sin

A

B

C

A device that helps is:

SOHCAHTOAin pp yp os dj yp an pp dj

Page 16: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

A

B

C14

539

B

B

B

A

A

A

tan

cos

sin

tan

cos

sin39

5

39

14

14

5

39

14

39

5

5

14

Page 17: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

x

y

20

3434sin

Find xHypotenuse

Look at what they want and what they give you, then use the correct trig ratio.

Opposite

opposite, hypotenuse

USE SIN!

hypotenuse

opposite x

20

Pg 845

Angle sin cos tan

34o .5592 .8290 .6745

Or use the calculator

205592.

x

x184.11

Page 18: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

x

y

20

3434cos

Find yHypotenuse

Look at what they want and what they give you, then use the correct trig ratio.

Adjacent

adjacent, hypotenuse

USE COS!

hypotenuse

adjacent y

20

Pg 845

Angle sin cos tan

34o .5592 .8290 .6745

Or use the calculator

208290.

y

y58.16

Page 19: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

4

30

x

Find x

Look at what they want and what they give you, then use the correct trig ratio.

AdjacentOpposite

Adjacent, Opposite, use TANGENT!

adjacent

oppositex tan

30

4

5.7tan x

Pg 845

Angle sin cos tan

81o .9877 .1564 6.3138 82o .9903 .1392 7.1154 83o .9925 .1219 8.1443

82x

If you use the calculator, you would put tan-1(7.5) and it will give you an angle back.

Page 20: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

Word Problems

• Hills, Buildings, Trees

Page 21: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

• Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all

Page 22: Pg 586-587: 1 - 21 all; Pg 582-584: 1 - 24 all. Chapter 9 Review

• 14-23

• Geo mean legs, alt, pythag

• Pythag area of triangle

• 45-45-90, 30-60-90

• State trig ratios

• Trig word prob

• VECTORS!!