physics 219 – fall, 2007 labnotes 6 – op amps friday...
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page 1 Last modified on 11/13/07
Physics 219 – Fall, 2007
LabNotes 6 – Op Amps Friday, November 2 ............................................................................................. 2
Differential Amplifiers ....................................................................................... 2
Introduction to Op amps ..................................................................................... 3
Open Loop Gain.............................................................................................. 4
Student Manual Section 8-1 ......................................................................... 4
Feedback ......................................................................................................... 5
Op Amp Golden Rules .................................................................................... 6
Some Op Amp Circuits....................................................................................... 7
Inverting Amplifier ......................................................................................... 7
Student Manual Section 8-2 ......................................................................... 9
Non-Inverting Amplifier ................................................................................. 9
Student Manual Section 8-3 ........................................................................10
Op Amp Follower ..........................................................................................10
Student Manual Section 8-4 ........................................................................11
Op Amp Current Source.................................................................................11
Student Manual Section 8-5 ........................................................................12
Current-to-Voltage Converter.........................................................................12
Student Manual Section 8-6 ........................................................................14
Friday, November 9 ............................................................................................14
Summing Amplifier .......................................................................................14
Summing Amplifier as a Digital to Analog Converter ....................................15
Student Manual Section 8-7 ........................................................................16
Op Amp Buffer for Push-Pull Amplifier ........................................................16
Student Manual Section 8-8 ........................................................................20
Op Amp Limitations..........................................................................................21
Student Manual Section 9-1 ........................................................................23
Op Amp Integrator .........................................................................................23
Student Manual Section 9-2 ........................................................................25
Audio Amplifier .............................................................................................26
Student Manual Section 9-4 ........................................................................27
Sound Sensor ..............................................................................................27
Comparator........................................................................................................27
Schmitt Trigger ..............................................................................................28
Student Manual Section 10-1 ......................................................................30
RC Relaxation Oscillator................................................................................30
Student Manual Section 10-2 ......................................................................33
Stabilizing the length of a laser cavity to a part in 108 with a 40 cent op amp33
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Friday, November 2
Differential Amplifiers
Amplifiers such as the common emitter have a single input terminal into which one
feeds a voltage Vin measured with respect to ground. The output voltage, Vout also
measured with respect to ground is given by
Vout = G Vin
Now, often we’d like to measure the difference between two input signals. Here’s
one important reason why:
signal
signal + 60 Hz "pick-up"
Vout=G VinVinVsource long lead
Ordinary Amplifier - subject to "pick-up" of unwanted signals
signal
signal + 60 Hz "pick-up"
Vout=Gdiff ( V+ - V-)
Vin
Vsource
long lead
-
+
"pick-up" is approximately the same for this lead
Differential Amplifier – minimizes unwanted “pick up”
Vout = Gdiff V+ V( )
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where Gdiff is the differential mode gain of the amplifier.
In the case of the differential amplifier, both the "signal lead" and the "ground
lead" are subject to the same pick up; the differential amplifier "rejects this
common mode signal."
(Section 6-4 of the Student Manual shows how to build a simple differential
amplifier using two transistors. You can build this circuit as an optional exercise.)
Introduction to Op amps
An "ideal" differential amplifier would have the following characteristics:
• very large (nearly infinite) differential mode gain
• zero common mode gain; that is if you feed identical non-zero voltages
into the two inputs, ideally you’d expect zero volts at the output
• infinite input impedance
• zero output impedance
So-called operational amplifiers (“op amps”) are a class of amplifiers that come
amazingly close to satisfying this ideal. They are available as integrated circuits
(ICs) typically consisting a 10 -20 transistors and related resistors, capacitors and
diodes, all etched into a single slice of silicon. They are cheap, selling for as little
as 20 cents.
The schematic symbol for an op amp looks like:
+
-
The (+) and (-) symbols on the inputs do not mean that one in put is necessarily
more positive than the other. Rather they denote the "non-inverting" and
"inverting" inputs respectively. The output voltage of the op amp is given by
Vout = Gdiff V+ V( )
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where Gdiff is the differential mode gain and V+ and V are the voltages applied
to the non-inverting and inverting inputs respectively.
The op amps we will use come packaged in 8–pin Dual In-line Packages (DIPs).
The pinout diagram for the (now obsolete) 741 and the 411 op amp is shown
below. By convention, the "notch" in the package serves to identify pin #1.
1
2
3
4 5
6
7
8offset null
inverting input
�non-inverting input
V(-) (-15 V) offset null
output
V(+) (+15 V)
no connection
-+
(The major difference between these op amps is that the input stage of the 411 uses
field effect transistors (FETs) whereas the 741 uses bipolar transistors. This results
in the 411 having a substantially high input impedance than the 741.)
Note that these op amps require both a positive and a negative power supply.
Open Loop Gain
Like all op amps, the 741 and 411 both have an extremely large differential mode
gain (also called "open loop gain", for reasons that will become clear shortly).
Student Manual Section 8-1
• Complete Lab 8–1 in the Student Manual on the Open Loop Test Circuit.
Here you’ll get a feel for what is meant by a large open loop gain by building
the following circuit:
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+
-
63
2
+15 V
-15 V
+15 V
-15 V
• Use a “potentiometer” for the variable resistor.
• Adjust the voltage divider so that the input voltage is ±1 mV.
• Due to the very large differential gain (Gdiff for the 411 is greater than
2 105!), you should see the output switch between + 15 V and -15 V just
as the input voltage changes sign.
Feedback
Feedback can roughly be defined as when one "feeds" some portion of an output
back into the input of a system. For example:
microphone
speaker
Feedback
The above is an example of positive feedback, meaning that the output is fed back
in such a manner as to add to, or reinforce the input. The result is that the sound
gets louder and louder. On the other hand, it is possible to have negative feedback,
where the output is fed back so as to partially "cancel" some of the input.
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+
-
RFBRload
Positive Feedback
Negative feedback tends to act as a "correcting" influence, stabilizing the system
at the expense of lowering the gain of the system. A good everyday example of
negative feedback is the act of driving a car on the highway. If we view the "output
signal" of this system as how far your eyes tell you that you've deviated from the
center of your lane, then the driver can be thought to be feeding this output back
into the "input" (angular position of the steering wheel) in order to achieve stable,
straight driving.
+
-
RFB
Rload
"virtualground"
Negative Feedback
Real op amp circuits (almost) always use some form of feedback:
At first we'll use mainly negative feedback (Student Manual Labs 8 and 9) and
then later (Student Manual Lab 10) we'll see some of the uses of positive feedback.
Op Amp Golden Rules
Assume negative feedback is in place as shown above. Now, suppose that V , the
voltage at the inverting (-) input, begins to drift slightly below ground. The large
differential gain of the op amp will generate a much larger positive voltage at the
input. This will cause current to flow through the feedback resistor RFB back to
the inverting input, thus raising V back toward ground. A similar argument holds
for the case where V starts drifting above ground. Thus we are lead to the first of
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two Golden Rules for op amps:
Op Amp Golden Rule I
With negative feedback in place, the output of the op amp will try to do
whatever is necessary to keep the voltage difference between the inputs equal
to zero.
The second Golden Rule follows as an immediate consequence of the very high
input impedance of op amps:
Op Amp Golden Rule II
Due to their very high input impedance, the inputs of an op amp will neither
source nor sink appreciable currents.
Some Op Amp Circuits
Inverting Amplifier
The op amp circuit shown below is an inverting amplifier.
Vin R1
+
-
R2
Vout
IR1
IR2
virtual�ground
The analysis of this circuit is simplicity itself:
1) Op Amp Golden Rule I implies:
V = 0
2) Ohm's Law implies:
IR1=VinR1
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3) Op Amp Golden Rule II implies:
IR1= IR2
4) Ohm's Law implies:
Vout = 0 IR2R2 =
VinR1
R2
That is,
Vout =R2R1
Vin
This is closely analogous to the result we obtained for the common emitter
amplifier. The gain in this case is given by:
G =R2R1
independent of the differential gain of the amp.
A few notes:
1) The minus sign appearing in the gain indicates that the output is inverted
(180o out of phase) relative to the input. This is why this circuit is called an
inverting amplifier.
2) As is always the case with amplifiers, the "output swing" is limited by the
supply voltages. The maximum output voltage will ~ 1volt less than the
positive supply voltage and the minimum output voltage will ~ 1volt greater
than the negative supply voltage.
3) The input impedance of this configuration is given by:
ZinVinIin
= R1
Note that even though the op amp itself has a very high input impedance, the input
impedance of the inverting amplifier configuration is not particularly high. This is
a drawback of this design, but in most other ways the amplifier performs
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wonderfully, so if you don't need a very high input impedance this circuit is highly
recommended.
The output impedance can be found experimentally to be very low (fractions of an
ohm!!) for small signals. This is a big advantage in using this op amp-based design
as opposed to a common emitter amplifier. However, op amps are usually limited
in the amount of load current they can supply, so the output impedance effectively
increases for larger signals.
Student Manual Section 8-2
• Complete Lab 8–2 in the Student Manual on the Inverting Amplifier.
Non-Inverting Amplifier
The op amp circuit shown below is a non–inverting amplifier.
Vin
R1
+
-
R2
Vout
IR1IR2
V-
V+
The analysis is once again pretty simple:
1) Op Amp Golden Rule I implies:
Vin = V+ = V
2) Ohm’s Law implies:
IR1=V
R1=VinR1
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3) Op Amp Golden Rule II implies:
IR1= IR2
4) Ohm's Law implies:
Vout = V + IR2( )R2 = Vin +VinR1
R2
or
Vout = 1 +R2R1
Vin
Thus the gain of this configuration is given by:
G = 1 +R2R1
Here the output signal is in phase with the input signal. (Hence the name “non–
inverting amplifier”.) Like the inverting amplifier this configuration has a very low
output impedance (for small signals). Also, since the input signal is connected
directly to the input of the op amp, the input impedance of this configuration is
very high, which is a very attractive feature of this design. However, this
configuration tends not to be quite a stable as the inverting amplifier when
operated at high gain.
Student Manual Section 8-3
• Complete Lab 8–3 in the Student Manual on the Non–Inverting Amplifier.
Op Amp Follower
If we consider the non-inverting amplifier in the limit that R2 0 and R1
we see that we now have an amplifier with a gain of one, very high input
impedance, and very low output impedance. It is a nearly ideal follower, save for
its inability to supply large currents. (This is not an insignificant drawback, since
often the main point of a follower is to supply large currents.)
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Vin+
-
VoutV-
V+
Student Manual Section 8-4
• Complete Lab 8–4 in the Student Manual on the Op Amp Follower.
Op Amp Current Source
Let’s calculate the current in the variable resistor R2 for the configuration shown
below:
Vin
R1
+
-
R2
Vout
IR1IR2
V-
V+
A
1) Op Amp Golden Rule I implies:
V = V+ = Vin
which remains constant in this case.
2) Ohm’s Law implies:
IR1=V
R1=VinR1
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3) Op Amp Golden Rule II implies:
IR2 = IR1 =VinR1
Thus the current flowing through R2 is independent of the value of R2 over a wide
range of resistances. Thus we have an excellent current source, noticeably better
than the one–transistor–based current source that you built in Lab #4.
Student Manual Section 8-5
• Complete the first part of Lab 8–5 in the Student Manual on the Op Amp
Current Source. You can skip the part that involves adding a transistor.
Current-to-Voltage Converter
Photodiodes - You are already very familiar with light emitting diodes (LEDs):
When current flows through a light emitting diode, one photon of light is emitted
for every electron of current. The reverse process is also possible: When light is
absorbed at the p-n junction of a diode, a “photo-current” is generated. Since the
size of the photo-current is approximately linearly proportional to the intensity of
the illuminating light, a diode can serve as a light detector. In this case it is called a
photodiode. (The infra-red beam emitted by your remote control unit is detected
by a silicon photodiode located inside your TV set.) Surprisingly, the direction of
the photo-current is in the direction opposite to the normal direction of current flow
in a diode. Why this is so requires a reasonable amount of solid state physics to
explain. I’ll resist the temptation and ask you to simply accept this for now as a
rule handed down in the spirit of our other golden rules. (The phototransistor that
you encountered previously can be thought of as a “photodiode with gain”.)
In order to “detect” the induced photo-current we would like to “convert” the
photocurrent into a voltage. The simplest I-to-V converter is the humble resistor.
However in this case it has two major disadvantages: 1) the photodiode is not a
very compliant current source, the biggest output voltage it can sustain is about 0.5
V and 2) As a voltage is allowed to develop across the photodiode, the "response"
varies, thus diminishing the linearity of the device.
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I
Rhν
The following op amp circuit makes for a simple, but vastly improved I-to-V
converter.
Ihν
Vout
1MΩ
An ordinary light emitting diode can be used as a photodiode (The light detection
process described above is exactly the inverse of the way light is generated in an
LED, where an “injected” current of electrons and holes meet up at the p-n
junction and “recombine”, resulting in the emission of photons.) (If you want the
best performance you wouldn’t use an LED as a light detector, the materials used
to make efficient LEDs, such as gallium arsenide, don’t work as well as silicon-
based photodiodes.)
If the photodiode is replaced by a phototransistor, the current gain of the
phototransistor makes for a much more sensitive light detector. (We need to now
use a smaller feedback resistor; otherwise the circuit is too sensitive.)
I
hν
Vout
10 kΩ +15 V
The figure above shows how to wire an npn phototransistor with an op amp
configured as a current to voltage converter. Note that in this case, in contrast to
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the situation with a photodiode, the current flow is in the direction of the arrow.
When you get this working, make sure to check out the suggestion on page 182 of
the Student Manual where you make an oscilloscope “part of the feedback loop”.
(But you’ll have to use an old–style analog oscilloscope.) By simply aiming the
phototransistor at an oscilloscope trace that is monitoring the output of the above
circuit you should see the trace move to “avoid”, or deflect around, the
phototransistor. This trick, which shows off some of the power (and magic) of the
feedback principle, will work best in a darkened room.
Student Manual Section 8-6
• Complete Lab 8–6 in the Student Manual on the Current to Voltage
Converter.
Friday, November 9
Summing Amplifier
The name “op amp”, short for “operational amplifier”, derives from the ability of
these amplifiers to be configured to perform various mathematical operations. The
simplest of these, addition, can be performed by the circuit below.
Vout
Rfb
summing�junction
Ifb
R1
R2
V1
V2
I1
I2
The currents through the input resistor add at the summing junction and flow
through the feedback resistor:
I fb = I1 + I2
The summing junction is a virtual ground so
Vout = 0V I fbRfb = I1 + I2( )Rfb
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Vout =V1R1
+V2R2
Rfb
If R1 = R2 = R then
Vout =RfbR
V1 + V2( )
so the output voltage is proportional to the sum of the input voltages.
• Question: Can you design a circuit using op amps that subtracts two
voltages?
Summing Amplifier as a Digital to Analog Converter
You can use an op amp to build an “digital to analog converter”, along the same
lines as the one you previously built to control the brightness of an LED. Suppose
we let 6 V represent a binary "1" and 0 V represent a binary "0". The following
"weighted summing amplifier" produces an analog output voltage that is
proportional to a 4-bit input number:
Vout
Rfb = 1.6 kΩ
�
summing�junction
R3 = 1 kΩ
R2 = 2 kΩ
R1 = 4 kΩ
R0 = 8 kΩ
+5V
0 V
+5V
+5V
D3
D2
D1
D0
1
0
1
1
MSB
LSB
I3
Ifb
I2
I0
I1
I fb = I3 + I2 + I1 + I0
Vout = 0V I fbRfb = I3 + I2 + I1 + I0( )Rfb
Vout = I3 + I2 + I1 + I0( )Rfb
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Vout =V3R3
+V2R2
+V1R1
+V0R0
Rfb
Note that:
R3 =R08
, R2 =R04, R1 =
R02
so that
Vout = 8V3R0
+ 4V2R0
+ 2V1R0
+ 1V0R0
Rfb
Vout =RfbR0
8 5V + 4 0 V + 2 5 V + 1 5V( )
Vout =RfbR0
5 V 10112( )
Thus the circuit acts as a digital to analog converter.
Student Manual Section 8-7
• Complete Lab 8–7 in the Student Manual on the Summing Amplifier.
Op Amp Buffer for Push-Pull Amplifier
Recall the push-pull amplifier:
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+15 V
-15 V
Vin Vout
Rload
Advantages:
useful for supplying large currents to low impedance loads
can follow both positive and negative input voltages
no large quiescent currents
Disadvantages:
crossover distortion
provides no gain; must rely on another "stage" to provide gain
Goal: Use relatively high impedance small signal source (e.g. a microphone) to
provide a lot of current to a low impedance load (e.g. a loud speaker). Specifically,
suppose we try to design a circuit that can take a 50 mV signal produced by
microphone (source impedance = 2.2 k ) and produce an 2 volt signal into a 8
load. Obviously we need a circuit with an overall gain of 40.
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First try:
Vin
+
-
+15 V
-15 V
Vout
Rload
Vint
�
400 k
20 k
+5V
2.2μF
mic.
ac coupled�microphone
2.2k8Ω
This works except you can see (and hear?) the crossover distortion:
t
V(t)Vin(t)
Vout(t)�
0.6V
crossover distortion
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Second try:
Vin
+
-
+15 V
-15 V
Vout
Rload
Vint
�
400 k
20 k
+5V
2.2μF
mic.
ac coupled�microphone
2.2k8Ω
If you were to look at Vout with your oscilloscope you would find that the
crossover distortion gas disappeared! What happened!?
Analysis:
1) From Golden Rule I:
V = 0
2) From Ohm's Law and Golden Rule II:
IR1=VinR1
=Vin20 k
= IR2
3) From Ohm's Law:
Vout = IR2R2 =
Vin20 k
400 k
or
Vout = 20 Vin
We see from this analysis that the output voltage should always equal -20 times the
input voltage, whatever the input voltage is! Thus this result confirms that there
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should be no crossover distortion, yet one can't help feeling that a swindle has just
taken place. We still haven't really answered the question "Where did the crossover
distortion go?"
The answer is that, according to Golden Rule I, the output of the op amp (labeled
Vint in the drawing above) will try to do whatever it takes to keep the inputs at the
same voltage. In the present case this apparently includes compensating for the
crossover distortion:
t
V(t)
Vout(t)Vint(t)
�
0.6V
0.6V
Whenever Vout > 0 the circuit is "sourcing" current into the load resistor.
(Note that very little current flows into the load via the 400 k resistor.)
This means the npn transistor in the push-pull amplifier in "on" and
Vint = Vout + 0.6 V .
Whenever Vout < 0 the circuit is "sinking" current from the load resistor.
This means the pnp transistor in the push-pull amplifier in "on" and
Vint = Vout 0.6 V .
Therefore, whenever Vout crosses through 0 V, the op amp must abruptly change
Vint between +0.6 V and - 0.6 V. Real op amps cannot change their output voltages
instantly; they have a limited "slew rate", as we shall soon see. This limits the
ability of a real op amp to fully compensate for the crossover distortion.
Student Manual Section 8-8
• Complete Lab 8–8 in the Student Manual on the Push Pull Buffer.
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• Save your circuit. Shortly you’ll construct a microphone circuit that you can
use with this circuit to amplify your voice.
Op Amp Limitations
Real op amps do not quite behave in the idealized manner that we have assumed.
For example, there are mild violations of the two Golden Rules. Corrected
versions of the Golden Rules would look like:
Modified Golden Rule I
With negative feedback in place, the output of the op amp will try to do whatever is
necessary to keep the voltage difference between the inputs equal to a very small
voltage difference, called the offset voltage Vos .
Typical offset voltages for the op amps that we use in the lab are ~ a few mV.
Modified Op Amp Golden Rule II
Due to their very high input impedance, the inputs of an op amp will sink a very
small current, called the input bias current Ibias.
Because of their FET input stage, the typical input bias currents for a 411 op amp
are extremely low, ~ 3 pA (That's picoamps. 1 pA =10-12 A.) The 741 op amps
have input bias currents of a few nanoamps.
Another op amp limitation is relatively small amount of output current that they
can supply. The 411 can supply at most 25 mA to a load.
(There exist specialized op amps for delivering more substantial currents. We have
for example in our parts shelf the “386” op amp which is designed for audio
applications and is capable of directly driving a small 8 ohm speaker.)
Perhaps the most noteworthy op amp limitation is the fact that the open loop gain
of the op amp "rolls off" at high frequencies. The gain curve for a 411 op amp is
shown below:
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Gain�(dB)
Frequency (Hz)1 10 1k 10k 100k 1M
20
40
60
80
100
This drop in gain limits the op amps ability to respond to high frequency signals,
resulting in a limited slew rate for the op amp. The slew rate is defined as the
maximum rate at which the output of the op amp's output can change. The 411 has
a slew rate of about 15 V/_s while the 741 has a slew rate of about 0.5 V/_s.
(This roll off in gain is actually intentional. In effect the output of the op amp is fed
through a low pass filter with a f3dB of about 100 Hz. The reason for doing this
has to do with op amp stability. Without this roll-off the op amp would be subject
to spontaneous high frequency oscillations. These high frequency oscillations
result when stray capacitance causes phase shifts in the feedback loop, so that the
feedback unintentionally becomes positive for high frequency signals. See
Horowitz and Hill section 4.33 for more on this.)
The effect of the slew rate can easily be seen by observing how an op amp follower
responds to a square wave input:
Vout
10k �
Vin = ?
(The 10 k resistor serves to limit the input current in the event that a clumsy user
allows Vin to exceed the supply voltages.)
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Note that as the amplitude of the square wave increases, the distortion will become
more apparent. As noted previously, the slew rate limits the ability of the op amp
to compensate for the crossover distortion in the push-pull buffer circuit.
Student Manual Section 9-1
• Complete Lab 9-1 in the Student Manual on the Op Amp Limitations.
Op Amp Integrator
We’ve already seen how an op amp can sum two voltages. Integration is another
mathematical operation that an op amp can perform with aplomb.
Recall the simple RC integrator. It worked well only when Vout << Vin For low
frequency signals ( << (RC)-1), where the capacitor has time to charge, problems
arise:
The op amp integrator shown below removes the restriction Vout << Vin .
Vout
�
Vin
R
CI(t)
It's operation is simple to analyze:
From Golden Rule I we see that V = 0 so that
I t( ) =Vin t( )
R
independent of Vout t( ) . Also we have
Vout t( ) =q t( )C
the negative sign arising because for the currents we have defined as positive,
negative charge will build up on the output side of the capacitor.
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Golden Rule II implies that this current flows entirely onto the capacitor so that
I t( ) =dq t( )dt
and also
Vout t( ) =I t( ) dt
C
Vout t( ) =
Vin t( )
Rdt
C
Vout t( ) =1RC
Vin t( ) dt
One problem is that because that op amp works so well, if the input signal has even
a small dc offset component, over time this will integrate to give a very large
result, causing the op amp to slowly "drift to one of the supply rails":
V(t)
t
Vout(t)
� Vin(t)
A solution is to roll off the integrating action for the dc component by putting a
large by-pass resistor into the feedback loop:
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Vout
�
Vin
RC
10M
The dc current will flow through the resistor; it will not accumulate on the
capacitor.
Student Manual Section 9-2
• Complete Lab 9-2 in the Student Manual on the Op Amp Integrator.
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Audio Amplifier
The circuit below is an audio amplifier than can takes a signal from a microphone
and amplify it by a variable amount. (That is, it’s got a “volume” knob!)
+
–
+4.7µF
0.1µF
0.1µF
1M1k
10k to100k
3.3M
1M
2.2k
Voutmic
case
+6V +6V
+6V
+6V
LM3582
3
1
4
8
The circuit uses a LM358 op amp, wired in a non-inverting configuration and
powered by a single 6 V battery pack. The LM358 can produce output voltages
from just above ground (the voltage on pin 4) and about 1.5 V below the positive
power supply voltage on pin 8 (6V 1.5V = 4.5V in this case). A voltage divider is
used to position the dc offset near the middle of these two limits and the audio
signal from the microphone is capacitively coupled to the amplifier.
The gain for ac signals is
G = 1 +1 M
1 k + Rvar
where Rvar is determined by the setting on a potentiometer. The dc gain is 1,
owing to the presence of the 4.7 μF capacitor.
Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 27 Last modified on 11/13/07 12:27 PM
Student Manual Section 9-4
• Complete Lab 9-4 in the Student Manual on the Microphone Amplifier. By
using battery power you should avoid the oscillations described in this section.
Sound Sensor
• Connect the output of your amplifier circuit to a LogoChip’s analog input.
Can you get your LogoChip to flash (or do something else that’s interesting)
whenever it hears a loud enough sound?
• Try connecting your microphone to the input of Push Pull Amplifier you built
previously. Connect the output of the Push Pull Amplifier to a speaker. Can you
hear your voice?
Comparator
A comparator is a device which, as the name implies, compares two different
voltages and indicates which of the two voltages is larger. A simple op amp
without any feedback can serve as a comparator:
Vout
�
input #1 �
input #2
The output of the op amp will swing to one of the two supply voltages, depending
on which of the inputs is larger. (In other words, the output "changes state",
depending on which of the two input voltages is larger.)
While any garden variety op amp (e.g., the 411) can serve as a comparator, chips
that are especially designed to act as comparators (e.g., the 311) offer improved
performance. For example, for the above application, as well as many others, it is
desirable for the comparator to have as fast a slew rate as possible. To achieve a
fast slew rate, comparators such as the 311 make use of an open collector output,
as shown below. With an external, user-supplied pull-up resistor connected to +5
V, the comparator output will switch between near ground and 5 V, depending on
whether the output transistor is "on" or "off":
Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 28 Last modified on 11/13/07 12:27 PM
Vin
Vout
+5V
4.7k
When Vin > 0, the output transistor is "off" and Vout = +5 V.
When Vin < 0 , the output transistor is "on", the transistor saturates, and
Vout +0.3V .
Thus the two output states of the comparator correspond to digital "1" and "0"
states.
Schmitt Trigger
A weakness in the above comparator circuit is that noise in the input signal can
lead to multiple transitions at the output. If you think about an application like the
clap sensor you can see why this might be a problem:
V(t)
V-(t)
V+(t)
t
t
Vout(t)5V
0V
An elegant solution is the Schmitt trigger, which makes use of positive feedback
Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 29 Last modified on 11/13/07 12:27 PM
to largely eliminate the multiple transitions:
Vin
Vout
+5V
4.7k
100k10k
The voltage at the non-inverting input, V+, determines the "threshold" voltage. The
key point is that because of the positive feedback provided by the 100 k resistor in the above circuit, the value of the threshold voltage V+ will depend on the output
state Vout .
When Vout = +5 V then V+ 0.5V
When Vout = 0 V then V+ 0 V .
Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 30 Last modified on 11/13/07 12:27 PM
V(t)
V+(t)
t
t
Vout(t)5V
0V
lower threshold (0V)
upper threshold (+5V)
This means that there are two different thresholds in the circuit, the one which
determines when the output will switch from "high" to "low" is equal to +0.5 V
while the one which determines when the output will switch from "low" to "high"
is equal to 0 V.
As you can see from the drawing above, this scheme avoids the multiple transitions
problem.
Student Manual Section 10-1
• Complete Lab 10-1 in the Student Manual on the Comparator.
RC Relaxation Oscillator
Ever wonder how your function generators can “generate” a periodically varying
voltage signal? Here is a simple way to generate a square wave with a user-
determined frequency:
Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 31 Last modified on 11/13/07 12:27 PM
Vout
+15V
4.7k
100k10k
-15V
100k
0.01uF
V+
V-
Note that in this RC relaxation oscillator circuit both positive and negative
feedback are used and there is no input signal. Assume that when the power to the
circuit is first turned on the op amp output goes into positive saturation (it's
actually a toss-up which way it will go, but as you'll see, it doesn't matter.) The
voltage at the non-inverting input V+ will thus be at about +1.3 volts due to the
voltage divider formed by the 100k and 10 k series resistors.
Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 32 Last modified on 11/13/07 12:27 PM
V-(t)
t
t
Vout(t)+15V
-15V
+1.3V
-1.3V
The capacitor (and hence V ) begins charging up toward +15 V, through the 100k
feedback resistor with time constant
RC =105 10 8s =10 3s
When the voltage on the capacitor reaches the threshold voltage of about +1.3 V,
the op amp's output will quickly swing towards the negative power supply voltage
(-15 V in this case), changing the voltage at the non-inverting input V+ to about
+1.3 volts. The capacitor (and hence V ) begins discharging down toward -15 V,
again with a time constant RC. Switching will now occur at the new threshold
voltage of -1.3 V. By varying the RC time constant the frequency of the square
wave can be adjusted.
Oscillators based on this principle are known as relaxation oscillators. They are
inexpensive and simple, and with careful design they can be made quite stable in
frequency. They can be used for example to provide a simple very tiny “clock” for
a microcontroller. Microcontrollers these days are becoming quite small and
inexpensive (much smaller than a single 3904 transistor and costing about 80 cents,
which is great if you want to start building computation into everyday objects.) A
“crystal-based clock” circuit can end up being larger (and more expensive) than the
microcontroller itself, so simple RC based relaxation oscillators, which can be
microscopic in both size and cost when built directly into the microcontroller IC,
can be quite useful at times.
Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 33 Last modified on 11/13/07 12:27 PM
Student Manual Section 10-2
• Complete Lab 10-2 in the Student Manual on the Relaxation Oscillator.
Stabilizing the length of a laser cavity to a part in 108 with a 40 cent op amp
The next page shows the circuit used to stabilize the length of a diode laser cavity
to a part in 108 as part of the laser cooling experiment that we are working on
down in the laser lab. It features 3 garden variety op amps housed inside a 40 cent
op amp package. You should be able to recognize a lot of familiar features in this
circuit.
Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 34 Last modified on 11/13/07 12:27 PM
+6.95 V
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Physics 219 - Fall, 2007 LabNotes 6 - Op Amps
page 35 Last modified on 11/13/07 12:27 PM
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