power = pressure * pipe size area. pneumatics pushing force force = surface area * pounds per square...
TRANSCRIPT
![Page 1: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/1.jpg)
Power = Pressure * Pipe Size Area
![Page 2: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/2.jpg)
Pneumatics Pushing Force
Force = Surface Area * Pounds Per Square Inch
= Pi*R2 * 60 lbs/inch2
= 3.14*12 inch2 * 60 lbs
= 188 lbs
60 PSI
1”
![Page 3: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/3.jpg)
Pneumatics Pulling Force
Force = Surface Area * Pounds Per Square Inch
= Pi*R2 - Pi*r2 * 60 lbs/inch2
= 3.14*12 - 3.14*(.625/2)2 * 60 lbs
= 170 lbs
60 PSI
R=1”
r = ¼”
![Page 4: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/4.jpg)
Pneumatic Forces
Piston Rod Force Force
Diameter Diameter Push(pi*R2) Pull (pi*(R2-r2))
2” .625” 188 170
1.5” .44” 106 97
1.0” 3/16 47 45.5
0.75” .25” 26.49 23.55
![Page 5: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/5.jpg)
Pneumatic Forces at Different Pressures
![Page 6: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/6.jpg)
Switches, Solenoid, Remote Control
Computer
Interface Controller
12 v
![Page 7: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/7.jpg)
Switches, Solenoid, Remote Control
Computer
Interface Controller
12 v
![Page 8: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/8.jpg)
Pneumatic Mounting: Open PositionLength = co = 18 inches
Co = 90 degrees
c2 = a2 + b2 - 2a*b*Cos(Co)
182 = a2 + b2
a = sqrt(c2 - b2) b = sqrt(c2 – a2)
a
b
c
C
0
2
4
6
8
10
12
14
16
18
20
0 2 4 6 8 10 12 14 16 18 20
b
a
![Page 9: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/9.jpg)
Pneumatic Mounting: Closed PositionLength = cc = 10 inches
Cc = 40
c2 = a2 + b2 - 2a*b*Cos(Cc)
102 = a2 + b2 - 2a*b*Cos(40)
100 = a2 + b2 – 1.532a*b
0 = a2 – 1.532a*b + (b2 - c2)
a = ½ *(2bCos(Cc) +/- sqrt((-2bCos(Cc))2 – 4 (b2 - c2))
a
b
100 = (324-b2) + b2 -1.532*sqrt(324-b2)b ;from previous page1.532*sqrt(344-b2)b=224Sqrt(324-b2)b=146.2141(324-b2)b2=21378.562 ;square both sides0 = b4-324b2 + 21378.562 b2= (324 +/- sqrt(3242 – 4*21378.562))/2 ; quadratic eqb2= 92.247 or b2 = 231.7527b = 9.6 or b = 15.223a = sqrt(324 - b2)A = 15.223 or a = 9.6
-15
-10
-5
0
5
10
15
20
0 5 10 15 20
b
a
open closed (b-) closed (b+)
c
C
![Page 10: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/10.jpg)
Pneumatic Mounting: Two PositionsClosed:Length = Cc = 10 inchesCc = 10 c2 = a2 + b2 - 2a*b*Cos(Cc) 102 = a2 + b2 - 2a*b*Cos(10) 100 = a2 + b2 – 1.9696a*b100 = (324-b2) + b2 -1.9696*sqrt(324-b2)b1.9696*sqrt(344-b2)b=224Sqrt(324-b2)b=113.72778(324-b2)b2=12934.0080 = b4-324b2 + 12934.008 b2= (324 +/- sqrt(3242 – 4*12934.008))/2b2= 46.631 or b2 = 277.369b = 6.8287 or b = 16.6544a = sqrt(324 - b2)
A = 16.6544 or a = 6.8287
a
b
c
![Page 11: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/11.jpg)
Pneumatic Mounting: Two Positions
a
b
co
co2 = a2 + b2 -2a*b*Cos(Co)
cc2 = a2 + b2 -2a*b*Cos(Cc)
co2 - cc
2 = 2a*b*(Cos(Cc)-Cos(Co))
(co2 - cc
2 )/(Cos(Cc)-Cos(Co))=2ab
ab = k; where k= ½ (co2 - cc
2 )/(Cos(Cc)-Cos(Co))
a = k/b; then plug into equation(1)
co2 = (k/b)2 + b2 -2k*Cos(Co)
0 = b2 +(- 2k*Cos(Co)- co2)+k2/b2
0 = b4 +jb2+k2 where (- 2k*Cos(Co)- co2)
b2 = (-j +/- sqrt(j2 - 4k2))/2
b = sqrt(b2); a = k/b;
Co
a
b
cc
Cc
![Page 12: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/12.jpg)
Pneumatic Mounting: Two Positions
a
b’
co
co2 = a2 + b2 -2a*b*Cos(Co)
cc2 = a2 + b2 -2a*b*Cos(Cc)
co2 - cc
2 = 2a*b*(Cos(Cc)-Cos(Co))
(co2 - cc
2 )/(Cos(Cc)-Cos(Co))=2ab
ab = k; where k= ½ (co2 - cc
2 )/(Cos(Cc)-Cos(Co))
co2 = (k/b)2 + b2 -2(k/b)*b*Cos(Co)
co2 = (k/b)2 + b2 -2k*Cos(Co)
0 = b4 +(- 2k*Cos(Co)- co2)b2+k2
0 = b4 +jb2+k2 where (- 2k*Cos(Co)- co2)
b2 = (-j +/- sqrt(j2 - 4k2))/2
b = sqrt(b2); a = k/b;
Co
a’
b’
cc
Cc
CT=C+asin(b/Hb)+asin(a/Ha) b’=sqrt(b2-Hb
2)a’=sqrt(a2-Ha
2)
a’
b
![Page 13: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/13.jpg)
‘
![Page 14: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/14.jpg)
Speed?Too Fast!!!• Adjustable inlets are available for adjustable speed
to slow down the pistons.
Too Slow???• Air volume through plastic tubing limiting factor.• Larger pistons are more powerful, but need more
air, so are generally slower.• If need speed, can use parallel air tanks,
Team 39 used 3 parallel tanks and
valves with large brass 4 way + connector in 2007 to catapult large ball.
![Page 15: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/15.jpg)
Adjustable Positions• Magnetic reed switches come with the ordered
pistons.
• Can place at desired position and then turn off both input and output valves. This is rumored to work.– I believe it takes two separate festo valves– But may be able to be done with one
![Page 16: Power = Pressure * Pipe Size Area. Pneumatics Pushing Force Force = Surface Area * Pounds Per Square Inch =Pi*R 2 * 60 lbs/inch 2 = 3.14*1 2 inch 2 *](https://reader033.vdocuments.net/reader033/viewer/2022061617/5697bfc41a28abf838ca5aad/html5/thumbnails/16.jpg)
Adjustable Force• Use two different regulators to get two
different pressures.
• Add them in the T using two different valves