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TRANSCRIPT
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o 𝑑4𝑑
o 4𝑑𝑑
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• 𝑏
𝑑 σ𝑖=1𝑑 𝑏𝑖 = Θ 𝑏𝑑
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Θ 𝑏𝑑 Θ 𝑏𝑑
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1. Θ(𝑏 ⋅ 𝑑)
2. Θ((𝑏/2)𝑑)
3. Θ(𝑏𝑑/2)
4. Θ(𝑏𝑑)
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𝑔(𝑛)
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𝑔(𝑛)
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o
o
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• 𝜖 > 0
• 𝐶∗
𝜖1 + ⌊𝐶∗/𝜖⌋
• Θ(𝑏𝑑+1)
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Θ 𝑏1+ 𝐶∗/𝜖 Θ 𝑏1+ 𝐶∗/𝜖
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Θ 𝑏𝑚 Θ 𝑏 ⋅ 𝑚
• Θ 𝑏𝑚 𝑚
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Θ 𝑏𝑚 Θ 𝑏 ⋅ 𝑚
• ℓ = 1,2,…
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𝑑 ⋅ 𝑏 + 𝑑 − 1 𝑏2 +⋯+ 1 ⋅ 𝑏𝑑 = Θ 𝑏𝑑
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Θ 𝑏𝑑 Θ 𝑏 ⋅ 𝑑
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Θ 𝑏𝑑 Θ 𝑏𝑑
Θ 𝑏1+ 𝐶∗/𝜖 Θ 𝑏1+ 𝐶∗/𝜖
Θ 𝑏𝑚 Θ 𝑏 ⋅ 𝑚
Θ 𝑏𝑑 Θ 𝑏 ⋅ 𝑑
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o ≈
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