practice midterm 1
DESCRIPTION
practice midterm 1TRANSCRIPT
7/17/2019 Practice Midterm 1
http://slidepdf.com/reader/full/practice-midterm-1-568e473c4cf02 1/8
Math 442 Fall 2015
Sample problems for Exam 1
Name:
No calculators or other electronic devices may be used. Show
all work, have fun, and good luck! (50 points possible)
Problem 1. Use the Maximum principle to show that if ut = k uxx, x ∈ R, t > 0
u(x, 0) = 1
then the function v(x, t) = ux(x, t) = 0. Conclude that u(x, t) = 1.
7/17/2019 Practice Midterm 1
http://slidepdf.com/reader/full/practice-midterm-1-568e473c4cf02 2/8
2
Problem 2. Solve problem 1 above using the Heat kernel.
7/17/2019 Practice Midterm 1
http://slidepdf.com/reader/full/practice-midterm-1-568e473c4cf02 3/8
3
Problem 3. Let:
φ(x) =
e−x, x > 0
ex, x < 0
and solve: ut = k uxx, x ∈ R, t > 0
u(x, 0) = φ(x)
7/17/2019 Practice Midterm 1
http://slidepdf.com/reader/full/practice-midterm-1-568e473c4cf02 4/8
4
Problem 4.
Find the regions in the (x, y)-plane where the equation:
yuxx + xuyy = 0
is respectively elliptic, parabolic or hyperbolic.
7/17/2019 Practice Midterm 1
http://slidepdf.com/reader/full/practice-midterm-1-568e473c4cf02 5/8
5
Problem 5. Solve the equation:utt = c2 uxx, x ,t ∈ Ru(x, 0) = x2, ut(x, 0) = x
7/17/2019 Practice Midterm 1
http://slidepdf.com/reader/full/practice-midterm-1-568e473c4cf02 6/8
6
Problem 6. Use the substitution v = r u to transform the equation:
utt = c2
urr +
2
rur
into:vtt = c2vrr
and use this to solve:
utt = c2
urr + 2
rur
u(r, 0) = r, ut(r, 0) = 1
7/17/2019 Practice Midterm 1
http://slidepdf.com/reader/full/practice-midterm-1-568e473c4cf02 7/8
7
Problem 7. Let u(r, t) be the n-dimensional spherical wave:
utt = c2
urr + n − 1
r ur
Show that a solution of the special from u(r, t) = α(r)f (t− β (r)) exists onlyif n = 3
7/17/2019 Practice Midterm 1
http://slidepdf.com/reader/full/practice-midterm-1-568e473c4cf02 8/8
8
Problem 8. Prove that
+∞
−∞
e−(x−y)2
4kt√ 4πkt
x2dx = y2 + 2t
Hint: Regard the L.H.S. as a solution to the diffusion equation with assignedinitial condition and then make use of the Maximum Principle.