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Page 1: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic

Yuxi Fu

BASICS

Yuxi Fu Presburger Arithmetic 1 / 36

Page 2: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic is seen as a test for the limit of decidability.

It is the arithmetic with only the addition operator; in other wordsit is the Peano Arithmetic without the multiplication operator.

Yuxi Fu Presburger Arithmetic 1 / 36

Page 3: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Mojzesz Presburger (A polish student, 1929).

Uber die Vollstandigkeit eines gewissen Systems der Arithmetikganzer Zahlen, in welchem die Addition als einzige Operationhervortritt. In Comptes Rendus du Premier Congres desMathematicienes des Pays Slaves, 395:92-101, WarsawMathematics Congress.

R. Stansifer (1984).

Presburger’s Article on Integer Arithmetic: Remarks andTranslation. Technical report, Computer Science Department,Cornell University.

Yuxi Fu Presburger Arithmetic 2 / 36

Page 4: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Synopsis

1. Presburger Arithmetic

2. Decidability of PA

3. Complexity of Validity Checking

Yuxi Fu Presburger Arithmetic 3 / 36

Page 5: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic

Yuxi Fu Presburger Arithmetic 4 / 36

Page 6: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

First Order Theory

1. First Order Logic: >,⊥,∧,∨,¬,⇒,∃,∀.

2. First Order Theory with Equality:

P{r1(t11 , . . . , t1k1

)/X1, . . . , rn(tn1 , . . . , tnkn

)/Xn} P a tautology

t = ts = t ⇒ t = s

r = s ∧ s = t ⇒ r = t∧1≤i≤k ti = t ′i ⇒ f(t1, . . . , tk) = f(t ′1, . . . , t

′k) f a k-ary function∧

1≤i≤k ti = t ′i ⇒ r(t1, . . . , tk)⇒ r(t ′1, . . . , t′k) r a k-ary relation

∀x .φ⇒ φ{t/x}φ⇒ ∀x .φ x not in φ

(∀x .(ϕ⇒ ψ))⇒ (∀x .ϕ⇒ ∀x .ψ)

Yuxi Fu Presburger Arithmetic 5 / 36

Page 7: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

First Order Theory

1. First Order Logic: >,⊥,∧,∨,¬,⇒,∃,∀.

2. First Order Theory with Equality:

P{r1(t11 , . . . , t1k1

)/X1, . . . , rn(tn1 , . . . , tnkn

)/Xn} P a tautology

t = ts = t ⇒ t = s

r = s ∧ s = t ⇒ r = t∧1≤i≤k ti = t ′i ⇒ f(t1, . . . , tk) = f(t ′1, . . . , t

′k) f a k-ary function∧

1≤i≤k ti = t ′i ⇒ r(t1, . . . , tk)⇒ r(t ′1, . . . , t′k) r a k-ary relation

∀x .φ⇒ φ{t/x}φ⇒ ∀x .φ x not in φ

(∀x .(ϕ⇒ ψ))⇒ (∀x .ϕ⇒ ∀x .ψ)

Yuxi Fu Presburger Arithmetic 5 / 36

Page 8: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic, PA

1. Function: nullary 0, unary s.

2. Relation: binary <. Let ≤ be the union of < and =.

3. Axiom:

PA1 ∀x .(s(x) 6= 0)PA2 ∀xy .(s(x) = s(y)⇒ x = y)PA3 ∀x .(x = 0 ∨ ∃y .s(y) = x)PA4 ∀x .(x < s(x))PA5 ∀xy .(x < y ⇒ s(x) ≤ y)PA6 ∀xy .(¬(x < y)⇔ y ≤ x)PA7 ∀xy .((x < y) ∧ (y < z)⇒ x < z)

PA8 ∀x .(x + 0 = x)PA9 ∀xy .(x + s(y)) = s(x + y)

Yuxi Fu Presburger Arithmetic 6 / 36

Page 9: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic

Fact. ∀x , y .x < y ⇔ s(x) < s(y).

Fact. ∀x , y .x < y ∨ x = y ∨ y < x .

Fact. ∀x , y .x 6< y ⇔ (x = y ∨ y < x).

Fact. ∀x , y .x = y ⇔ (x < s(y) ∧ y < s(x)).

Fact. ∀x , y .x 6= y ⇔ (x < y ∨ y < x).

So the relations 6<,=, 6= can be dispensed with in favour of ’<’.

Yuxi Fu Presburger Arithmetic 7 / 36

Page 10: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic

Fact. ∀x , y .x < y ⇔ s(x) < s(y).

Fact. ∀x , y .x < y ∨ x = y ∨ y < x .

Fact. ∀x , y .x 6< y ⇔ (x = y ∨ y < x).

Fact. ∀x , y .x = y ⇔ (x < s(y) ∧ y < s(x)).

Fact. ∀x , y .x 6= y ⇔ (x < y ∨ y < x).

So the relations 6<,=, 6= can be dispensed with in favour of ’<’.

Yuxi Fu Presburger Arithmetic 7 / 36

Page 11: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Numeral

For a natural number i , the closed term

s(s(. . . s︸ ︷︷ ︸i times

(0) . . .))

is called a numeral and is denoted by i (by abusing notation).

Yuxi Fu Presburger Arithmetic 8 / 36

Page 12: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Term

Multiplication by constant

ixdef= x + x + . . .+ x︸ ︷︷ ︸

i times

.

Yuxi Fu Presburger Arithmetic 9 / 36

Page 13: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Term

The terms(s(. . . s︸ ︷︷ ︸i times

(t) . . .))

is equal to t + i .

A term containing variable x1, . . . , xk is equal to a term of the form

n0 + n1x1 + n2x2 + nkxk .

When we write kx + t, we always mean that x does not appear in t.

Yuxi Fu Presburger Arithmetic 10 / 36

Page 14: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Term

The terms(s(. . . s︸ ︷︷ ︸i times

(t) . . .))

is equal to t + i .

A term containing variable x1, . . . , xk is equal to a term of the form

n0 + n1x1 + n2x2 + nkxk .

When we write kx + t, we always mean that x does not appear in t.

Yuxi Fu Presburger Arithmetic 10 / 36

Page 15: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Term

The terms(s(. . . s︸ ︷︷ ︸i times

(t) . . .))

is equal to t + i .

A term containing variable x1, . . . , xk is equal to a term of the form

n0 + n1x1 + n2x2 + nkxk .

When we write kx + t, we always mean that x does not appear in t.

Yuxi Fu Presburger Arithmetic 10 / 36

Page 16: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Formula

In this talk a term in Z is seen as an abbreviation for a term in N.

For example x ← 3 stands for x + 3 < 0 and −y + 3 < x for3 < x + y .

Yuxi Fu Presburger Arithmetic 11 / 36

Page 17: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Expressiveness

Finite quantification

∃x ∈ S .ϕ(x)def=

∨i∈S

ϕ(i).

Unique existence

∃!x .ϕ(x)def= ∃x .ϕ(x) ∧ ∀y .ϕ(y)⇒ y = x .

Yuxi Fu Presburger Arithmetic 12 / 36

Page 18: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Expressiveness

The predicate m = µx .ϕ(x) can be defined by

ϕ(m) ∧ ∀z .ϕ(z)⇒ m ≤ z .

Similarly m = max(S) and m = min(S) are definable.

Yuxi Fu Presburger Arithmetic 13 / 36

Page 19: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Expressiveness

The predicate m = µx .ϕ(x) can be defined by

ϕ(m) ∧ ∀z .ϕ(z)⇒ m ≤ z .

Similarly m = max(S) and m = min(S) are definable.

Yuxi Fu Presburger Arithmetic 13 / 36

Page 20: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Congruence

A useful predicate is the congruence predicate defined by

s ≡k tdef= ∃z .kz+s=t ∨ kz+t=s.

The divide predicate i |x can be defined by x ≡i 0.

Fact. The congruence ≡k is decidable.

Yuxi Fu Presburger Arithmetic 14 / 36

Page 21: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Congruence

A useful predicate is the congruence predicate defined by

s ≡k tdef= ∃z .kz+s=t ∨ kz+t=s.

The divide predicate i |x can be defined by x ≡i 0.

Fact. The congruence ≡k is decidable.

Yuxi Fu Presburger Arithmetic 14 / 36

Page 22: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Let gcd(S) be the greatest common divisor of S .

Let lcm(S) be the least common multiple of S .

Yuxi Fu Presburger Arithmetic 15 / 36

Page 23: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Decidability of PA

Yuxi Fu Presburger Arithmetic 16 / 36

Page 24: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic is Decidable

Theorem. (Presburger, 1929)

The validity of a closed Presburger formula is decidable.

Proof. The basic idea is quantifier elimination.

Yuxi Fu Presburger Arithmetic 17 / 36

Page 25: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic is Decidable

Theorem. (Presburger, 1929)

The validity of a closed Presburger formula is decidable.

Proof. The basic idea is quantifier elimination.

Yuxi Fu Presburger Arithmetic 17 / 36

Page 26: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic is Decidable

All decidability proofs make use of quantifier elimination.

The purpose of quantifier elimination is to replace in a Presburgerformula all the explicit occurrences of the quantifiers by the implicitoccurrences in the form of the congruence relations ≡1,≡2,≡3, . . ..

Fact. The validity of a closed Presburger formula without anyexplicit occurrences of the quantifiers is decidable.

Yuxi Fu Presburger Arithmetic 18 / 36

Page 27: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic is Decidable

All decidability proofs make use of quantifier elimination.

The purpose of quantifier elimination is to replace in a Presburgerformula all the explicit occurrences of the quantifiers by the implicitoccurrences in the form of the congruence relations ≡1,≡2,≡3, . . ..

Fact. The validity of a closed Presburger formula without anyexplicit occurrences of the quantifiers is decidable.

Yuxi Fu Presburger Arithmetic 18 / 36

Page 28: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Presburger Arithmetic is Decidable

All decidability proofs make use of quantifier elimination.

The purpose of quantifier elimination is to replace in a Presburgerformula all the explicit occurrences of the quantifiers by the implicitoccurrences in the form of the congruence relations ≡1,≡2,≡3, . . ..

Fact. The validity of a closed Presburger formula without anyexplicit occurrences of the quantifiers is decidable.

Yuxi Fu Presburger Arithmetic 18 / 36

Page 29: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

H. Enderton (First Edition, 1972; Second Edition, 2001).

A Mathematical Introduction to Logic. Harcourt/Academic Press.

J. Monk (1976).

Mathematical Logic. Springer-Verlag, New York.

Yuxi Fu Presburger Arithmetic 19 / 36

Page 30: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

Suppose (. . . (Qx .ϕ) . . .) is a Presburger formula in which Q is aquantifier and ϕ is quantifier free.

We will turn Qx .ϕ into an equivalent quantifier free formulacomposed of the atomic formulae (of the forms s < t, s ≡i t) andthe logical operators ∧,∨.

Yuxi Fu Presburger Arithmetic 20 / 36

Page 31: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

Suppose (. . . (Qx .ϕ) . . .) is a Presburger formula in which Q is aquantifier and ϕ is quantifier free.

We will turn Qx .ϕ into an equivalent quantifier free formulacomposed of the atomic formulae (of the forms s < t, s ≡i t) andthe logical operators ∧,∨.

Yuxi Fu Presburger Arithmetic 20 / 36

Page 32: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

1. Universal Quantifier Elimination

I If Q = ∀, then apply the De Morgan law

∀x .ϕ(x)⇔ ¬∃.¬ϕ(x)

to get rid of ∀.

2. Negation Elimination

I A negation operator is pushed down all the way to the front ofatomic formulae.

I s 6< t is replaced by t < s ∨ s < t + 1 ∧ t < s + 1.

I s 6≡i t is replaced by (s ≡i t + 1) ∨ . . . ∨ (s ≡i t + i − 1).

Yuxi Fu Presburger Arithmetic 21 / 36

Page 33: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

1. Universal Quantifier Elimination

I If Q = ∀, then apply the De Morgan law

∀x .ϕ(x)⇔ ¬∃.¬ϕ(x)

to get rid of ∀.

2. Negation Elimination

I A negation operator is pushed down all the way to the front ofatomic formulae.

I s 6< t is replaced by t < s ∨ s < t + 1 ∧ t < s + 1.

I s 6≡i t is replaced by (s ≡i t + 1) ∨ . . . ∨ (s ≡i t + i − 1).

Yuxi Fu Presburger Arithmetic 21 / 36

Page 34: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

3. Normalization

I The propositional subformula is converted to a dnf.

I The formula

∃x .((α0 ∧ . . . ∧ αi ) ∨ . . . ∨ (γ0 ∧ . . . ∧ γk))

is then converted to

∃x .(α0 ∧ . . . ∧ αi ) ∨ . . . ∨ ∃x .(γ0 ∧ . . . ∧ γk).

Yuxi Fu Presburger Arithmetic 22 / 36

Page 35: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

4. Coefficient Uniformization

I So we only have to consider formulae of the following form

∃x .

(∧i

nix < ti

)∧

∧j

tj < njx

∧(∧k

nkx ≡ck tk

).

I Let n = lcm({ni , nj , nk}i ,j ,k). We get the equivalent formula

∃x .

(∧i

x < si

)∧

∧j

sj < x

∧(∧k

x ≡dk sk

)∧ x ≡n 0.

Yuxi Fu Presburger Arithmetic 23 / 36

Page 36: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

I The formula∧

i x < si is equivalent to

∨i

x < si ∧∧i ′ 6=i

si ≤ si ′

.

Similarly the formula∧

j sj < x is equivalent to

∨j

sj < x ∧∧j ′ 6=j

sj ′ ≤ sj

.

Yuxi Fu Presburger Arithmetic 24 / 36

Page 37: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Quantifier Elimination

5. Substitution

I So we have reduced the original problem to that of decidingthe validity of formulas of the form

∃x .t ′ < x < t ′′ ∧∧l

x ≡dl tl .

I Let ddef= lcm({dl}l). The above formula is equivalent to

∨0<m≤d

(t ′+m < t ′′ ∧

∧l

t ′+m ≡dl tl

).

Yuxi Fu Presburger Arithmetic 25 / 36

Page 38: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Theorem (Presburger, 1929).

Presburger Arithmetic admits quantifier elimination.

Corollary.

Presburger Arithmetic is consistent, complete and decidable.

Yuxi Fu Presburger Arithmetic 26 / 36

Page 39: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Theorem (Presburger, 1929).

Presburger Arithmetic admits quantifier elimination.

Corollary.

Presburger Arithmetic is consistent, complete and decidable.

Yuxi Fu Presburger Arithmetic 26 / 36

Page 40: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

D. Cooper (1972).

Theorem Proving in Arithmetic without Multiplication. In B.Meltzer and D. Michie, eds., Machine Intelligence. EdinburghUniversity Press: 91-100.

Yuxi Fu Presburger Arithmetic 27 / 36

Page 41: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

Cooper’s algorithm is a decision procedure for integer PresburgerArithmetic Z.

It works for N by imposing the condition: all variables ≥ 0.

Yuxi Fu Presburger Arithmetic 28 / 36

Page 42: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

Cooper’s algorithm is a decision procedure for integer PresburgerArithmetic Z.

It works for N by imposing the condition: all variables ≥ 0.

Yuxi Fu Presburger Arithmetic 28 / 36

Page 43: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

The basic idea of Cooper’s algorithm is to do as less formulaconversion as possible.

∀-elimination, ¬-elimination (but keep 6≡i ), coefficientuniformization are all that is necessary.

The trade-off is that it must test a lot of instantiation cases.

Yuxi Fu Presburger Arithmetic 29 / 36

Page 44: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

The basic idea of Cooper’s algorithm is to do as less formulaconversion as possible.

∀-elimination, ¬-elimination (but keep 6≡i ), coefficientuniformization are all that is necessary.

The trade-off is that it must test a lot of instantiation cases.

Yuxi Fu Presburger Arithmetic 29 / 36

Page 45: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

Let ϕ be a negation-free propositional formula whose atomicformulae are

{x < si}i ∪ {sj < x}j ∪ {x ≡dk 0}k ∪ {x 6≡dl 0}l .

Let ϕ−∞(x) be obtained from ϕ by replacing

I all x < si by >, and

I all sj < x by ⊥.

Lemma. ϕ(x)⇔ ϕ−∞(x) for sufficiently small x .

Yuxi Fu Presburger Arithmetic 30 / 36

Page 46: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

Let ϕ be a negation-free propositional formula whose atomicformulae are

{x < si}i ∪ {sj < x}j ∪ {x ≡dk 0}k ∪ {x 6≡dl 0}l .

Let ϕ−∞(x) be obtained from ϕ by replacing

I all x < si by >, and

I all sj < x by ⊥.

Lemma. ϕ(x)⇔ ϕ−∞(x) for sufficiently small x .

Yuxi Fu Presburger Arithmetic 30 / 36

Page 47: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

Let ϕ be a negation-free propositional formula whose atomicformulae are

{x < si}i ∪ {sj < x}j ∪ {x ≡dk 0}k ∪ {x 6≡dl 0}l .

Let ϕ−∞(x) be obtained from ϕ by replacing

I all x < si by >, and

I all sj < x by ⊥.

Lemma. ϕ(x)⇔ ϕ−∞(x) for sufficiently small x .

Yuxi Fu Presburger Arithmetic 30 / 36

Page 48: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

Theorem. Suppose d = lcm{dk , dl}k,l . Then

∃x .ϕ(x) ⇔d∨

m=1

ϕ−∞(m) ∨d∨

m=1

∨j

ϕ(sj + m).

Proof. Stare at

{x < si}i ∪ {sj < x}j ∪ {x ≡dk 0}k ∪ {x 6≡dl 0}l ;

and think . . .

Yuxi Fu Presburger Arithmetic 31 / 36

Page 49: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

Theorem. Suppose d = lcm{dk , dl}k,l . Then

∃x .ϕ(x) ⇔d∨

m=1

ϕ−∞(m) ∨d∨

m=1

∨j

ϕ(sj + m).

Proof. Stare at

{x < si}i ∪ {sj < x}j ∪ {x ≡dk 0}k ∪ {x 6≡dl 0}l ;

and think . . .

Yuxi Fu Presburger Arithmetic 31 / 36

Page 50: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Cooper’s Algorithm

Let ϕ+∞(x) be obtained from ϕ by replacing

I all x < si by ⊥, and

I all sj < x by >.

Lemma. ϕ(x)⇔ ϕ+∞(x) for sufficiently large x .

Theorem. Suppose d = lcm{dk , dl}k,l . Then

∃x .ϕ(x) ⇔d∨

m=1

ϕ+∞(−m) ∨d∨

m=1

∨i

ϕ(si −m).

Yuxi Fu Presburger Arithmetic 32 / 36

Page 51: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

FMVE, Fourier-Motzkin Variable Elimination

FMVE decides the validity of a Presburger formula in Q.

After ∀-elimination and ¬-elimination, ∃-elimination is achieved byapplying the following equivalence:

∃x .

(∧h

chah≤ x

)∧

(∧i

ciai< x

)∧

∧j

x ≤djbj

∧(∧k

x <dkbk

)

if and only if∧h,j

chah≤

djbj∧∧h,k

chah

<dkbk∧∧i ,j

ciai<

djbj∧∧i ,k

ciai<

dkbk.

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Complexity of Validity Checking

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Page 53: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

M. Fischer and M. Rabin (1974).

Super-Exponential Complexity of Presburger Arithmetic. InComplexity of Computation edited by Richard M. Karp, AmericanMathematical Society, Providence, Rhode Island, 27-41.

D. Oppen (1978).

A 222pn

Upper Bound on the Complexity of Presburger Arithmetic.Journal of Computer and System Sciences, 16:323-332.

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Page 54: Presburger Arithmetic - SJTUyuxi/teaching/lectures... · It is the arithmetic with only the addition operator; in other words it is the Peano Arithmetic without the multiplication

Mojzesz Presburger (1904-1943) was a Polish Jewishmathematician, logician, and philosopher. As a student of AlfredTarski, he invented Presburger Arithmetic in 1929. He died in aconcentration camp in 1943.

In 2010, the European Association for Theoretical ComputerScience began conferring the annual Presburger Award to youngtheoretical computer scientists for outstanding contributions.

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