projectile motion ryan knab mat 493. definition projectile motion is defined as the motion of an...
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![Page 1: PROJECTILE MOTION Ryan Knab MAT 493. DEFINITION Projectile Motion is defined as the motion of an object near the earth’s surface. ‘Near’ Gravity](https://reader036.vdocuments.net/reader036/viewer/2022062805/5697c0251a28abf838cd5164/html5/thumbnails/1.jpg)
PROJECTILE MOTION Ryan KnabMAT 493
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DEFINITION
Projectile Motion is defined as the motion of an object near the earth’s surface. ‘Near’ Gravity extremely influential to the trajectory of an object
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HISTORY
Aristotle – projectiles pushed along by some external force that was transmitted through the air called “impetus”Moved in a straight line until object lost momentum, then fell straight to the ground
Galileo – performed experiments on uniformly accelerated motionBall rolled with uniform motion until falling off the tableNoted time was the same no matter how fast the marble was moving horizontally
Vertical and horizontal directions do not depend on each other
Newton – Three laws of motion: 1686Law 1: uniform motion until external force will change stateLaw 2: sum of forces in each direction must be equal to mass*acceleration in specific direction
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CREATING A MODEL
∑ Forces in x-direction = m
∑ Forces in y-direction = m
∑ Forces in z-direction = m
What are some possible forces?Gravity? Air resistance? Wind?
Assume air resistance proportional to velocity
m = -rx + Fx(t)m = -ry +) Fy(t)m = -rz -mg + Fz(t)
Reduce to first order differential equation with change of variables:
Vx =, V’x =
Vy = , V’y =
Vz = , V’z =
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PROJECTILE MOTION MODELS 1 AND 2 Model 1: No air resistance
m V’x = Fx(t)
m V’y = Fy(t)
m V’z = Fz(t)
Model 2: Air resistance proportional to velocity
m V’x = -rxVx + Fx(t)
m V’y = -ryVy + Fy(t)
m V’z = -rzVz + Fz(t)
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H-CP
Model 1
=
Model 2
=
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H-CP SOLUTIONS: U(T) =
Model 1
Model 2
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H-CP GRAPH
H-CP Solutions do not physically make sense, we are not taking account for gravity
Can we find a better way to model the motion?
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NON-CP
Model 1
= ,
m = mass, g = gravity(9.8m/s)
Model 2
= , m = mass, g = gravity(9.8m/s)
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NON-CP SOLUTIONS: U(T) =
Model 1
Model 2
According to theorem 5.3.1, if the forcing function is continuous in each direction for the entire time interval, we can say the Non-CP IVP has a unique solution given by the variation of parameters formula
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PROJECTILE MOTION MODEL 3
Model 3: Air resistance proportional to velocity squared
m V’x = - (c1 + c2)Vx + Fx(t)
m V’y = - (c1 + c2)Vy + Fy(t)
m V’z = - (c1 + c2)Vz + Fz(t)
Even more realistic of a model would be air resistance proportional to velocity squared
This causes some problems: Cant just square velocity always
positive No longer linear
Use some constant that can relate:c1 + c2
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NON-CP GRAPHS Non-CP Model 2
R=0.01
Non-CP Model 3
R=0.01 + .005
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PROJECTILE MOTION MODEL 4 Model 4: Air resistance proportional to square of speed
m V’x = - + Fx(t,)
m V’y = - + Fy(t,)
m V’z = -+ Fz(t,)
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SEMI-CP: MODEL 4
= +
m = mass, g = gravity (9.8m/s)
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SEMI-CP SOLUTION
Model 4
+
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THE GREEN MONSTER
Left field, Fenway Park95.4 meters away from home plate11 meters tallX-coordinate third base lineY-coordinate first base line
Launch angle? 29 degrees
Batted ball speed? 45.15 m/s
Initial height? 0.82 meters
Official baseball mass? 0.145kg
= 39.49 m/s
= 21.89 m/s
= 38.14 m/s
= 10.22 m/s
= 21.89 m/s
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HOMERUNS?
Using our realistic velocities to ensure the appropriate launch angle and direction along with a coefficient value of 0.005 will result in the ball flight we are looking for
If the resistance were to be any greater or the initial velocities any slower, may not have a homerun
In order to ensure homeruns, either raise initial velocities or lower the quadratic coefficient below 0.005
01020304050607080900
5
10
15
20
25
30
35
40o = Linear Resistance; * = Quadratic Resistance
x
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THREE DIMENSIONAL
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THE END