purdue university - homework# 9 solution · 2007. 4. 2. · at midpoint b (x = l,q) 3pl = width at...
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![Page 1: Purdue University - Homework# 9 Solution · 2007. 4. 2. · AT MIDPOINT B (X = L,Q) 3PL = width at midpoint B (x = L/2) bxh2 Therefore, 2x 2bBX — and bx = 3Px AT DISTANCE X M =](https://reader035.vdocuments.net/reader035/viewer/2022071507/61278ff891307e6cb9768f5c/html5/thumbnails/1.jpg)
AAE 204 Homework# 9
Solution
![Page 2: Purdue University - Homework# 9 Solution · 2007. 4. 2. · AT MIDPOINT B (X = L,Q) 3PL = width at midpoint B (x = L/2) bxh2 Therefore, 2x 2bBX — and bx = 3Px AT DISTANCE X M =](https://reader035.vdocuments.net/reader035/viewer/2022071507/61278ff891307e6cb9768f5c/html5/thumbnails/2.jpg)
![Page 3: Purdue University - Homework# 9 Solution · 2007. 4. 2. · AT MIDPOINT B (X = L,Q) 3PL = width at midpoint B (x = L/2) bxh2 Therefore, 2x 2bBX — and bx = 3Px AT DISTANCE X M =](https://reader035.vdocuments.net/reader035/viewer/2022071507/61278ff891307e6cb9768f5c/html5/thumbnails/3.jpg)
![Page 4: Purdue University - Homework# 9 Solution · 2007. 4. 2. · AT MIDPOINT B (X = L,Q) 3PL = width at midpoint B (x = L/2) bxh2 Therefore, 2x 2bBX — and bx = 3Px AT DISTANCE X M =](https://reader035.vdocuments.net/reader035/viewer/2022071507/61278ff891307e6cb9768f5c/html5/thumbnails/4.jpg)
3
22
22
22
2112
1
2
0.91125216
04
102
1004
122
12
4242
in
ybb
ybbQ
=
−=
⎟⎟⎠
⎞⎜⎜⎝
⎛−−⎟⎟
⎠
⎞⎜⎜⎝
⎛−=
⎟⎟⎠
⎞⎜⎜⎝
⎛−−⎟⎟
⎠
⎞⎜⎜⎝
⎛−=
ksipsi
ItVQ
42.11424
267.89491000,28
max
==
××
=
=∴ τ
NA
A A΄ MINIMUM SHEAR STRESS IN THE WEB (AT LEVEL A-A΄ )
ksipsi
ItVQ
in
tbbt
yAQ
03.11033
267.89466000,28
0.6621
212112
22
min
3
11
==
××
=
=
=
⎟⎠⎞
⎜⎝⎛ −×=
⎟⎠⎞
⎜⎝⎛ −=
=
τ