random walks and surfaces generated by random permutations of natural series
DESCRIPTION
Random Walks and Surfaces Generated by Random Permutations of Natural Series. Gleb OSHANIN Theoretical Condensed Matter Physics University Paris 6/CNRS France. Isaac Newton Institute Workshop, June 2006. Outlook. Northern face of Peak Oshanin, 6320 m Pamir. - PowerPoint PPT PresentationTRANSCRIPT
Random Walks and Surfaces Generated by Random Permutations
of Natural Series
Gleb OSHANINTheoretical Condensed Matter Physics
University Paris 6/CNRSFrance
Isaac Newton Institute Workshop, June 2006
Outlook
RaphaelMyself
I. Random Walk Generated by Permutations of 1,2,3, …, n+1
(with R. Voituriez)
Northern face of Peak Oshanin, 6320 m Pamir
II. Statistics of Peaks in Surfaces Generated by Random
Permutations of Natural Series
(with F.Hivert, S.Nechaev and O.Vasilyev)
♠ Spades < ♣ Clubs < ♦ Diamonds < ♥ Hearts Convention:
2 < 3 < 4 < 5 < 6 < 7 < 8 < 9 < 10 < J < Q < K < A
Who won and how much when the game is over?
(52! =80658175170943878571660636856403766975289505440883277824000000000000answers (not necessarily different) on this question)
Random Walk Generated by Random Permutations of Natural Series
(with R. Voituriez)
= {1,2,3, …, n+1} – random unconstrained permutation of [n+1]
In two line notation
( )1 2 3 … n+1
1, 2, 3, …, n+1
time l, (l = 1,2,3, …., n+1)
random number
X
- at l=0 - the walker is at the origin- at l=1 – the walker is moved to the right if 1 < 2 (permutation rise, ↑) to the left if 1 > 2 (permutation descent, ↓)- at l=2 – the walker is moved to the right if 2 < 3 (permutation rise, ↑) to the left if 2 > 3 (permutation descent, ↓)
and etc up to time l=n+1
where is the walker at time l=n+1 ?
Trajectory:
1
1)(, 1
1
)(kkk
l
kk
nl signssX
I. Probability Distribution Function of the end-point P(Xn=X)?
Let N↑ (N↓) denote the number of “rises” (“descents”) in a given permutation i.e. number of k-s at whichk < k+1 (k > k+1).
Evidently, Xn = N↑ - N↓, and since N↑ + N↓= n
Xn = 2N↑ - n
Eulerian number:
N
r
nnr
r rNCN
n
0
12 )1()1(1
determines a total number of permutations of [n+1] having exactly N↑ rises
The PDF of the end-point:
2
1
)!1(2
)1(1)( nX
n
nXXP
nX
n
)cos()
)sin((
)1(1)(
0
2 Xkk
kdkXXP n
nX
n
n
X
nXXP n 2
3exp
2
3)(
22/1
Integral representation of the PDF:
Looks almost like the PDF of standard n-n 1D RW except for the integration limits and the kernel
Asymptotic limit n → ∞:
Lattice Green Function:
00 ))sin(sin(
)cos())sin(sin(1)(),(
kzk
Xkkz
zXXPzzXG n
n
n
0 )cos(1
)cos(1
kz
Xkstandard n-n 1D RW result
Hence, using permutations as the generator of RW leads to conventional diffusive behabior at long times! <Xn
2> → n/3 - two-thirds of the diffusion coefficient disappear somewhere (walker steps at each tick of the clock, stops nowhere and rises and descents are equiprobable).Hence, there should be something non-trivial with the transition probabilities – correlations in the “rise-and-descent” sequences.
II. Correlations in rise-and-descent sequences.
1
1 121
)2(22
1 12
),(2)(n
j
n
jjn jjCnNNX
)(,),()(11121 121
)2(21
)2(jjjjj signsssjjCjjmC
Inverse problem: Given the PDF and hence, the moments, to determine correlations in the rise-and-descent sequences
Second moment of the PDF
Pair correlations in the r&d sequence
Their generating functions:
0
2)2( )(n
nn zXzX
1
21)2()2( )()(
m
mzjjmCzC
)()1(
2
)1()( )2(
22)2( zC
z
z
z
zzX
Relation between them:
20
2)2(
)1(3
)23()(
z
zzzXzX
n
nn
From the PDF we get:
3)()(
1
)2()2( zzmCzC
m
m
Hence:
0
3/1)()2( mCand
m = 1
m > 1
4/1
6/1
4
)(1)()(
)2(
,,
mCmpmp
4/1
3/1
4
)(1)()(
)2(
,,
mCmpmp
Probability of having two rises (descents) at distance m:
Probability of having a rises and a descents at distance m:
Pair correlations extend to nn only!
rises “repel” each other
rises “attract” descents
squared mean density
squared mean density
m > 1
m = 1
m = 1
m > 1
Fourth moment of the PDF
)2()1()1(16)2()1(3 )2(4 nmCnnnnnX n
3
1
)4()2( )4()()2(!4)3()1()2)3((12n
m
nmCmnnmCnn
where C(4)(m) is the fourth-order correlation function of the form (all other vanish):
211)4(
1111)( mjmjjj ssssmC
)()1(
!4
)1(15
803515)( )4(
2
3
3
32)4( zC
z
z
z
zzzzX
Relation between the generating functions:
3
432)4(
)1(15
)848803515()(
z
zzzzzzX
...)(9
1
15
2
)1(45
)6()( 432)4(
zzzzz
zzzC
9/1
15/2)()4( mC
if m = 1
if m > 1
III. Probabilities of rise-and-descent sequences of length 3 and 4.
2/16/1
8/1)(, mp
2/16/1
24/1)(, mp
6/16/1
120/1)(, mp
6/16/1
20/1)(, mp
3/16/1
30/1)()( ,, mpmp
2, 3/1
120/11)( mp
2, 3/1
15/2)( mp
m = 1
m = 1
m = 1
m = 1
m = 1
m = 1
m = 1
m > 1 m > 1
m > 1
m > 1
m > 1
m > 1
m > 1
All configurations have different weights
3/16/1
40/3)()( ,, mpmp
IV. Reconstructing the PGRW trajectories of length 4.
A set of all possible PGRW trajectories for n=4. Numbers above the solid arcs with arrows indicate the corresponding transition probabilities. Dashed lines with arrows connect the trajectories for different l.Transition probabilities clearly depend not only on the number of previous turns to the left (right) but also on their order.
A Non-Markovian Random Walk!
Theorems:
-The probability P(Yl=X) that the trajectory Yl of an auxiliary process appears at site X at time l is exactly the same as the probability P(Xl
(l)=X) that random walk generated by permutations of [l+1] has its end-point at site X (Eulerian).
-The probability P(Xl(n)=X) that at any intermediate step l, l=1,2,3, …, n-1, the PGRW trajectory
appears at the site X obeys
V. A deeper look on the PGRW trajectories.
The idea is to build recursively an auxiliary Markovian stochastic process Y l which is distributed exact-ly as Xl
(n) (similarly to Hammersley’s analysis of the longest increasing subsequence problem).
Yl is a random walk on a line of integers defined as follows:- At each time step l we define a real-valued random variable xl+1, uniformly distributed in [0,1].- At each moment l compare xl+1 and xl; if xl+1 > xl, a walker is moved one step to the right; otherwise, to the left.
Trajectory Yl:
l
kkkl xxsignY
11 )(
- The joint process (xl+1,Yl) and therefore Yl, are Markovian, since they depend only on (xl,Yl-1).
- Yl is a sum of correlated random variables - one has to be cautious with central limit theorems
)()()( )()( XXPXYPXXP lll
nl
VI. Even more deeper look on the PGRW : Measure of different trajectories
},...,,,,{)( nlX
1
1
)(lx
ll dxI
Each given PGRW trajectory is uniquely defined by the sequence of rises and descent of the corresponding permutation π of [n+1]. And vice versa!
We introduce two integral operators, and
and a polynomial Q defined as
, 1, )()(n
1l)(
lXIxQ n
l
The probability measure of a given trajectory Xl(n) obeys
1
0
)( )(}{)(
dxxXP Q nlX
nl
Example: },,,,{)5( lX
1202412840
311)(
5431
5
1 1
0
1
4321
41
2
3
)5(
xxxxdxdxdxdxdxx
xx x
x
xX IIIIIQ
l
720
19}{ )5( lXP
l = 1, 2, 3, 4, …,n
1
0
)(lx
ll dxI
VII. Distribution of the number of U-turns of the PGRW trajectories.
Left U-turn: ↑↓ - permutation peak (πj < πj+1 > πj+2)
Right U-turn: ↓↑ - permutation through (πj > πj+1 < πj+2)
Number of U-turns:(both left and right)
(shows how scrambled the trajectories are)
1
1)(,)1(
2
11
1
11 jjj
n
jjj signsssN
We calculate the characteristic function of N (funny 1d Ising model):
1
11]
2exp[)
2
)1(exp(]exp[)(
n
jjjn ss
iknikikNkZ
]2/[
0,
1 )2
tanh()1()2
1()(
n
l
lnl
lnik
n
ikW
ekZ
l
j
mjjj
l
l
jj
llmmmm
l
jj
nlj
lj
B
mmmm
m
m
ln
W1
2211
321
1
...321
, ))!22(
)14(4(
!!...!!
)!(12
321
12/12
2/1
22
]12
1coth1
1[
)1(
4)(),(
z
ee
e
ezkZzzkZ ik
ik
ik
iknn
n
Generating function of the characteristic function
3
)1(2
nN
Moments of the PDF
)4(36
)127()3(
15
)3()1(
12
)275( 222
n
nnn
nn
nnN
Asymptotic n → ∞ behavior of the PDF of the number of U-turns
n
nN
nnNP
163
245
exp5
4
3),(
2
2/1
VIII. Distribution of the distance between nearest right U-turns.
decays with l much faster than for Polya RW
IX. Diffusion limit
Using the equivalence between the processes Yl and Xl(n) , we derive the following master equation
)1()1(2
)()1(
)1(2
)4()( 1
YYPl
YlYYP
l
YlYYP lll
Introducing spatial variable y=aY (“a” has a dimension of length) and t=τ n (“τ” has a dimension of time) we turn to the limit a, τ → 0 keeping the ratio D=a2/2 τ fixed. We find a Fokker-Planck-type equation for diffusion with a negative drift term (which similarly to the Ornstein-Uhlenbeck process is proportional to “y” but decreases as 1/t) – random walk in a well
)()()(2
2
YPt
y
yYP
yDYP
t
Solution of this equation is
Dt
y
DtYP
4
3exp
4
3)(
22/1
and coincides with our previous result obtained for the discrete time and space PGRW for D=1/2.
Local Extrema (peaks) of Surfaces Generated by Random Permutations
(with F.Hivert, O.Vasilyev and S.Nechaev)
I. One-Dimensional Systems
The probability P(M,L) of having M peaks in on a chain of length L can be determined exactly
Lk
r
rM
k
kMML
rMr
L
kM
kMLkL
MLLMP )(
1)1(
)1(
)1()12()1(
)2(
2),(
00
12
First three central moments of P(M,L):
LM3
1 LMM
45
222 LMM945
2)( 3
In the asymptotic limit L → ∞ the PDF P(M,L) converges to a Gaussian distribution
L
LM
LLMP
4
)31
(45exp
5
2
3),(
22/1
II. Two-Dimensional Systems
First three central moments of P(M,L):
LM5
1 LMM
225
13222 LMM32175
512)( 3
Expanding P(M,L) into the Edgeworth series (cumulant expansion) we show that in L → ∞ limit the normalized PDF converges to a Gaussian distribution
)1
()(1
12
exp2
1),(
2/12/1
22/1
2/12 Lxf
L
xL
M
MMxP
)3(6
1)( 3
2/32
32/1 xx
M
MLxf
is independent of L
L=NxN
III. Instead of conclusions – current work
Partition function of a 2D model:
MzZ z – activity, M – number of peaks in a given permutation
B.Derrida (personal communication, unpublished) observed numericaly that for a very similar model (not integers but numbers uniformly distributed in [0,1]) there is a sign of something which looks like a phase transition at z ≈ 5.9.
Why it may happen?
Peaks can not occupy nn sites – on a square lattice they are hard-squares – nn peaks have an infinite “repulsion”
nnn peaks “attract” each other
p=(1/5)2 p=2/45 p=1/20
Liquid of peaks → Solid of peaks transition
Common number (less than the least, depletion force)
Two common numbersSquared probability of having an isolated peak