redox presentation 11 july 2011

46
REDOX 1.A.DEFINATION Transfer of electrons Oxidation is reduction is PROCESS WHERE ELECTRON IS RELEASED PROCESS WHERE ELECTRON IS GAINED

Upload: mrsmpc

Post on 07-Nov-2014

2.273 views

Category:

Business


0 download

DESCRIPTION

basic concept in chemistry

TRANSCRIPT

Page 1: Redox presentation 11 july 2011

REDOX1.A.DEFINATION

Transfer of electrons Oxidation is

reduction is

PROCESS WHERE ELECTRON IS RELEASED

PROCESS WHERE ELECTRON IS GAINED

Page 2: Redox presentation 11 july 2011

change in oxidation numberOxidation is

reduction is

PROCESS WHERE OXIDATION NUMBER INCREASE

PROCESS WHERE OXIDATION NUMBER DECREASE

Page 3: Redox presentation 11 july 2011

b.Calculate the oxidation number of i.Chromium in K2Cr2O7

ii. Chlorine in ClO4-

iii.Oxygen in H3O+.

2(+1) + 2x +7(-2) =0. , Cr = +6

x +4(-2) =-1. , Cl= +7

3(+1) +x =+1. , O= -2

Page 4: Redox presentation 11 july 2011

c.IUPAC nomenclature

i.K2CrO4

ii.MgSO4

Potasium Chromate (VI)

Magnesium sulphate(VI)

Page 5: Redox presentation 11 july 2011

iii.HNO3

iv.HNO2

nitric acid (V)

Nitric acid (III)

Page 6: Redox presentation 11 july 2011

d. Redox & non redox reaction. reasonsi. Zn + CuSO4 Cu + ZnSO4

ii. ZnCO3 ZnO + CO2

Redox reaction because the oxidation number of Zn Change from 0 to +2

Non Redox reaction because the oxidation number of Zn no change,( from +2 to +2)

Page 7: Redox presentation 11 july 2011

B) Br2 + 2KI I2 + 2KBr i.name of this reaction

ii.change in oxidation number of bromine

iii. change in oxidation number of iodine

Displacement of halogen

From 0 to -1

From -1 to 0

Page 8: Redox presentation 11 july 2011

iv.half equation for• Oxidation reaction.

• Reduction reaction

• Write the overall equation

2I- I2 + 2e

Br2 + 2e 2Br-

Br2 + 2I- 2Br- + I2

Page 9: Redox presentation 11 july 2011
Page 10: Redox presentation 11 july 2011

Question 2

Iron(II) chloride reacts with chlorine in a redox reaction

Page 11: Redox presentation 11 july 2011

Name the reaction above

• CHANGE OF IRON(II) ION TO IRON(III) ION

• REDOX (TYPE OF REACTION)

Page 12: Redox presentation 11 july 2011

Write out the rough equation first to show the products and the

reactants

2FeCl2 + Cl2 2FeCl3

Page 13: Redox presentation 11 july 2011

Place arrows to show oxidation reaction and reduction reaction on your answer on your answer in b)

above

2FeCl2 + Cl2 2FeCl3

reduction

oxidation

Page 14: Redox presentation 11 july 2011

What substance is oxidized and why?

• Iron (II) ions, oxidation number of iron

increase from +2 to +3

Page 15: Redox presentation 11 july 2011

What substance is reduced and why?

• Chlorine, because oxidation number of chlorine decrease from

0 to -1

Page 16: Redox presentation 11 july 2011

Write the half equation for oxidation

Fe2+ Fe3+ + e

Page 17: Redox presentation 11 july 2011

Write the half equation for reduction

Cl2 + 2e 2Cl-

Page 18: Redox presentation 11 july 2011

Write the overall reaction

2Fe2+ + Cl2 2Fe3+ +

2Cl-

Page 19: Redox presentation 11 july 2011

What is the oxidizing agent? And why

Chlorine water,

because it oxidised iron(II) ions to iron(III) ions

Page 20: Redox presentation 11 july 2011

What is the reducing agent? And why

Iron(II) ions,

because it reduced chlorine

to chloride ions

Page 21: Redox presentation 11 july 2011

State 2 observations in this experiment

• Green solution turns brown

Page 22: Redox presentation 11 july 2011

Describe how you would confirm the presence of the product, that is

iron(III) ion

• Add a few drops of NaOH solution, brown precipitate is formed

Page 23: Redox presentation 11 july 2011

State another substance that can replace chlorine in the above

experiment

Any oxidising agent

Bromine water //

acidified KMnO4 //

acidified K2Cr2O7

Page 24: Redox presentation 11 july 2011
Page 25: Redox presentation 11 july 2011

a) Which electrode behave as negative electrode? Why?

- +

3.

Page 26: Redox presentation 11 july 2011

a) Which electrode behave as negative electrode? Why?

A because iodide ions undergoes oxidation where it lose electrons,

the electrons are negatively charged causing it to be negative electrode

Page 27: Redox presentation 11 july 2011

b) Draw direction for electron flow in the outer circuit

Page 28: Redox presentation 11 july 2011

c) Write out the rough equation first to show reactants and the products

d) Put arrows on your equation above to show oxidation reaction and reduction reaction on your answer in c) above

32

272 22 CrIOCrI

OXIDATION

REDUCTION

Page 29: Redox presentation 11 july 2011

e) What substance is oxidized? Explain your answer in terms of electron transfer

Iodide ions

because it lose electron

Page 30: Redox presentation 11 july 2011

f) What substance is reduced? Explain your answer in terms of electron transfer

Dichromate ions

because it accept electrons

Page 31: Redox presentation 11 july 2011

g) Write half equations for:i)Oxidation

ii)Reduction

eII 22 2

OHCr

eHOCr

23

272

72

614

Page 32: Redox presentation 11 july 2011

h) Write overall equation

6I- + Cr2O72- + 14H+

2Cr3+ + 7H2O + 3I2

Page 33: Redox presentation 11 july 2011

i) State your observations during the experiment ati)Rod A

ii)Rod B

Dark brown solution formed

Orange solution turns to green solution

Page 34: Redox presentation 11 july 2011

j)How do you test the presence of iodine formed at rod A?

OR

Add 2 cm3 tetrachloromethane to iodine solution, shake well then purple solution formed at lower layer

Add a few drops of starch solution, a blue-black solution formed

Page 35: Redox presentation 11 july 2011
Page 36: Redox presentation 11 july 2011

• Test tube C, D. Presence of Fe 2+

• In C and D, silver and lead are less electropositive than iron.

• So,iron nail (Fe) is oxidised to Fe 2+.

• In test tube E, iron nail also

oxidised but takes longer time

After 3 days, which test tubes show blue colour?, why?

Page 37: Redox presentation 11 july 2011

Which test tubes show pink colour? Why?

• Test tube A and B.

• Presence of OH-

• Because Mg and Zn are more electropositive than Fe.

• So, Mg atom and Zn atom will lose electrons

• oxygen and water gain these electrons to form OH- This cause the pink colour of phenolphthalein

Page 38: Redox presentation 11 july 2011

What is the function of the jelly solution?

• To trap the colour formed during corrosion process

Page 39: Redox presentation 11 july 2011

Which of the above metals prevent rusting of iron nails?

• Metals above iron in ECS Magnesium and Zinc metals.

Which of the above metals increase the rusting of iron

• Metals below iron in ECS

• Lead metal and silver metal

Page 40: Redox presentation 11 july 2011

Why does the iron surface at the centre of water droplet behave as anode (negative electrode)?

Because here iron atom release electron

Page 41: Redox presentation 11 july 2011

Why does the iron surface at the edge of water droplet behave as

cathode( positive electrode)?

• Because oxygen and water gain the electrons here.

Page 42: Redox presentation 11 july 2011

What happen at the anode?

• Iron atom loses electron to form iron (II) ions.

• So Oxidation occur.

Page 43: Redox presentation 11 july 2011

Write half equation at the anode

Fe Fe 2+ + 2e

Where does the iron(II) ions formed from the reaction go to?

Iron (II) ions dissolve in water

Page 44: Redox presentation 11 july 2011

Where does the electrons released by the metal iron go

to?• Electron moves to the edge of

water droplet ( cathode)

What happens at the cathode?

At cathode, electrons are received by oxygen and water molecules to form hydroxide ions

Page 45: Redox presentation 11 july 2011

Write half equation at the cathode

• O2 + 2H2O +4e 4OH-

Page 46: Redox presentation 11 july 2011

Write equations to form rust when iron(II) ion formed at the anode combine with hydroxide ions formed at the cathode,  • Fe 2+ + 2OH- Fe(OH)2

Fe(OH)2 Fe2O3.xH2O