relations & their properties: selected exercises
TRANSCRIPT
Relations & Their Properties: Selected Exercises
Copyright © Peter Cappello 2011 2
Exercise 10
Which relations in Exercise 4 are irreflexive?
A relation is irreflexive a A (a, a) R.
Ex. 4 relations on the set of all people:
a) a is taller than b.
b) a and b were born on the same day.
c) a has the same first name as b.
d) a and b have a common grandparent.
Copyright © Peter Cappello 2011 3
Exercise 20
Must an asymmetric relation be antisymmetric?
A relation is asymmetric a b ( aRb (b, a) R ).
Copyright © Peter Cappello 2011 4
Exercise 20Must an asymmetric relation be antisymmetric?
A relation is asymmetric a b ( aRb (b, a) R ).
To Prove:
(a b ( aRb (b, a) R ) ) (a b ( (aRb bRa ) a = b ) )
Proof:
1. Assume R is asymmetric.
2. a b ( ( a, b ) R ( b, a ) R ). (step 1. & defn of )
3. a b ( ( aRb bRa ) a = b ) (implication premise is false.)
4. Therefore, asymmetry implies antisymmetry.
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Exercise 20 continuedMust an antisymmetric relation be asymmetric?
(a b ( ( aRb bRa ) a = b ) ) a b ( aRb ( b, a ) R )?
Work on this question in pairs.
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Exercise 20 continued
Must an antisymmetric relation be asymmetric ?
(a b ( (aRb bRa ) a = b ) ) a b ( aRb (b, a) R ) ?
Proof that the implication is false:
1. Let R = { (a, a) }.
2. R is antisymmetric.
3. R is not asymmetric: aRa (a, a) R is false.
Antisymmetry thus does not imply asymmetry.
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Exercise 30
• Let R = { (1, 2), (1, 3), (2, 3), (2, 4), (3, 1) }.
• Let S = { (2, 1), (3, 1), (3, 2), (4, 2) }.
• What is S R?
1
2
34
R S1
2
34
S R
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Exercise 50
Let R be a relation on set A.
Show:
R is antisymmetric R R-1 { ( a, a ) | a A }.
To prove:
1. R is antisymmetric R R-1 { ( a, a ) | a A }
We prove this by contradiction.
2. R R-1 { ( a, a ) | a A } R is antisymmetric.
We prove this by contradiction.
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Exercise 50
Prove R is antisymmetric R R-1 { ( a, a ) | a A }.
1. Proceeding by contradiction, we assume that:
1. R is antisymmetric: a b ( ( aRb bRa ) a = b ).
2. It is not the case that R R-1 { ( a, a ) | a A }.
2. a b (a, b) R R-1, where a b. (Step 1.2)
3. Let (a, b) R R-1, where a b. (Step 2)
4. aRb , where a b. (Step 3)
5. aR-1b, where a b. (Step 3)
6. bRa, where a b. (Step 5 & defn of R-1)
7. R is not antisymmetric, contradicting step 1. (Steps 4 & 6)
8. Thus, R is antisymmetric R R-1 { ( a, a ) | a A }.
Copyright © Peter Cappello 2011 10
Exercise 50 continued
Prove R R-1 { ( a, a ) | a A } R is antisymmetric.
1. Proceeding by contradiction, we assume that:
1. R R-1 { ( a, a ) | a A }.
2. R is not antisymmetric: ¬a b ( ( aRb bRa ) a = b )
2. Assume a b ( aRb bRa a b ) (Step 1.2)
3. bR-1a, where a b. (Step 2s & defn. of R-1)
4. ( b, a ) R R-1 where a b, contradicting step 1. (Step 2 & 3)
5. Therefore, R is antisymmetric.