reliability and importance discounting of neutrosophic masses
DESCRIPTION
In this paper, we introduce for the first time the discounting of a neutrosophic mass in terms of reliability and respectively the importance of the source.TRANSCRIPT
1
Reliability and Importance Discounting
of Neutrosophic Masses
Florentin Smarandache, University of New Mexico, Gallup, NM 87301, USA
Abstract. In this paper, we introduce for the first time the discounting of a
neutrosophic mass in terms of reliability and respectively the importance of
the source.
We show that reliability and importance discounts commute when
dealing with classical masses.
1. Introduction. Let Ξ¦ = {Ξ¦1, Ξ¦2, β¦ , Ξ¦n} be the frame of discernment,
where π β₯ 2, and the set of focal elements:
πΉ = {π΄1, π΄2, β¦ , π΄π}, for π β₯ 1, πΉ β πΊπ·. (1)
Let πΊπ· = (π·,βͺ,β©, π) be the fusion space.
A neutrosophic mass is defined as follows:
ππ: πΊ β [0, 1]3
for any π₯ β πΊ, ππ(π₯) = (π‘(π₯), π(π₯), π(π₯)), (2)
where π‘(π₯) = believe that π₯ will occur (truth);
π(π₯) = indeterminacy about occurence;
and π(π₯) = believe that π₯ will not occur (falsity).
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Simply, we say in neutrosophic logic:
π‘(π₯) = believe in π₯;
π(π₯) = believe in neut(π₯)
[the neutral of π₯, i.e. neither π₯ nor anti(π₯)];
and π(π₯) = believe in anti(π₯) [the opposite of π₯].
Of course, π‘(π₯), π(π₯), π(π₯) β [0, 1], and
β [π‘(π₯) + π(π₯) + π(π₯)] = 1,π₯βπΊ (3)
while
ππ(Ρ) = (0, 0, 0). (4)
It is possible that according to some parameters (or data) a source is
able to predict the believe in a hypothesis π₯ to occur, while according to other
parameters (or other data) the same source may be able to find the believe
in π₯ not occuring, and upon a third category of parameters (or data) the
source may find some indeterminacy (ambiguity) about hypothesis
occurence.
An element π₯ β πΊ is called focal if
ππ(π₯) β (0, 0, 0), (5)
i.e. π‘(π₯) > 0 or π(π₯) > 0 or π(π₯) > 0.
Any classical mass:
π βΆ πΊΡ β [0, 1] (6)
can be simply written as a neutrosophic mass as:
π(π΄) = (π(π΄), 0, 0). (7)
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2. Discounting a Neutrosophic Mass due to Reliability of the
Source.
Let πΌ = (πΌ1, πΌ2, πΌ3) be the reliability coefficient of the source, πΌ β
[0,1]3.
Then, for any π₯ β πΊπ β {π, πΌπ‘},
where π = the empty set
and πΌπ‘ = total ignorance,
ππ(π₯)π = (πΌ1π‘(π₯), πΌ2π(π₯), πΌ3π(π₯)), (8)
and
ππ(πΌπ‘)πΌ = (π‘(πΌπ‘) + (1 β πΌ1) β π‘(π₯)
π₯βπΊπβ{π,πΌπ‘}
,
π(πΌπ‘) + (1 β πΌ2) β π(π₯), π(πΌπ‘) + (1 β πΌ3) β π(π₯)
π₯βπΊπβ{π,πΌπ‘}π₯βπΊπβ{π,πΌπ‘}
)
(9),
and, of course,
ππ(π)πΌ = (0, 0, 0).
The missing mass of each element π₯, for π₯ β π, π₯ β πΌπ‘ , is transferred to
the mass of the total ignorance in the following way:
π‘(π₯) β πΌ1π‘(π₯) = (1 β πΌ1) β π‘(π₯) is transferred to π‘(πΌπ‘), (10)
π(π₯) β πΌ2π(π₯) = (1 β πΌ2) β π(π₯) is transferred to π(πΌπ‘), (11)
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and π(π₯) β πΌ3π(π₯) = (1 β πΌ3) β π(π₯) is transferred to π(πΌπ‘). (12)
3. Discounting a Neutrosophic Mass due to the Importance of the
Source.
Let π½ β [0, 1] be the importance coefficient of the source. This discounting
can be done in several ways.
a. For any π₯ β πΊπ β {π},
ππ(π₯)π½1= (π½ β π‘(π₯), π(π₯), π(π₯) + (1 β π½) β π‘(π₯)), (13)
which means that π‘(π₯), the believe in π₯, is diminished to π½ β π‘(π₯), and the
missing mass, π‘(π₯) β π½ β π‘(π₯) = (1 β π½) β π‘(π₯), is transferred to the believe in
πππ‘π(π₯).
b. Another way:
For any π₯ β πΊπ β {π},
ππ(π₯)π½2= (π½ β π‘(π₯), π(π₯) + (1 β π½) β π‘(π₯), π(π₯)), (14)
which means that π‘(π₯), the believe in π₯, is similarly diminished to π½ β π‘(π₯),
and the missing mass (1 β π½) β π‘(π₯) is now transferred to the believe in
πππ’π‘(π₯).
c. The third way is the most general, putting together the first and second
ways.
For any π₯ β πΊπ β {π},
ππ(π₯)π½3= (π½ β π‘(π₯), π(π₯) + (1 β π½) β π‘(π₯) β πΎ, π(π₯) + (1 β π½) β π‘(π₯) β
(1 β πΎ)), (15)
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where πΎ β [0, 1] is a parameter that splits the missing mass (1 β π½) β π‘(π₯) a
part to π(π₯) and the other part to π(π₯).
For πΎ = 0, one gets the first way of distribution, and when πΎ = 1, one
gets the second way of distribution.
4. Discounting of Reliability and Importance of Sources in General
Do Not Commute.
a. Reliability first, Importance second.
For any π₯ β πΊπ β {π, πΌπ‘}, one has after reliability Ξ± discounting, where
πΌ = (πΌ1, πΌ2, πΌ3):
ππ(π₯)πΌ = (πΌ1 β π‘(π₯), πΌ2 β π‘(π₯), πΌ3 β π(π₯)), (16)
and
ππ(πΌπ‘)πΌ = (π‘(πΌπ‘) + (1 β πΌ1) β β π‘(π₯)
π₯βπΊπβ{π,πΌπ‘}
, π(πΌπ‘) + (1 β πΌ2)
β β π(π₯)
π₯βπΊπβ{π,πΌπ‘}
, π(πΌπ‘) + (1 β πΌ3) β β π(π₯)
π₯βπΊπβ{π,πΌπ‘}
)
β (ππΌπ‘, πΌπΌπ‘
, πΉπΌπ‘ ).
(17)
Now we do the importance Ξ² discounting method, the third importance
discounting way which is the most general:
ππ(π₯)πΌπ½3= (π½πΌ1π‘(π₯), πΌ2π(π₯) + (1 β π½)πΌ1π‘(π₯)πΎ, πΌ3π(π₯)
+ (1 β π½)πΌ1π‘(π₯)(1 β πΎ))
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(18)
and
ππ(πΌπ‘)πΌπ½3= (π½ β ππΌπ‘
, πΌπΌπ‘+ (1 β π½)ππΌπ‘
β πΎ, πΉπΌπ‘+ (1 β π½)ππΌπ‘
(1 β πΎ)). (19)
b. Importance first, Reliability second.
For any π₯ β πΊπ β {π, πΌπ‘}, one has after importance Ξ² discounting (third
way):
ππ(π₯)π½3= (π½ β π‘(π₯), π(π₯) + (1 β π½)π‘(π₯)πΎ, π(π₯) + (1 β π½)π‘(π₯)(1 β πΎ)) (20)
and
ππ(πΌπ‘)π½3= (π½ β π‘(πΌπΌπ‘
), π(πΌπΌπ‘) + (1 β π½)π‘(πΌπ‘)πΎ, π(πΌπ‘) + (1 β π½)π‘(πΌπ‘)(1 β πΎ)).
(21)
Now we do the reliability πΌ = (πΌ1, πΌ2, πΌ3) discounting, and one gets:
ππ(π₯)π½3πΌ = (πΌ1 β π½ β π‘(π₯), πΌ2 β π(π₯) + πΌ2(1 β π½)π‘(π₯)πΎ, πΌ3 β π(π₯) + πΌ3 β
(1 β π½)π‘(π₯)(1 β πΎ)) (22)
and
ππ(πΌπ‘)π½3πΌ = (πΌ1 β π½ β π‘(πΌπ‘), πΌ2 β π(πΌπ‘) + πΌ2(1 β π½)π‘(πΌπ‘)πΎ, πΌ3 β π(πΌπ‘) +
πΌ3(1 β π½)π‘(πΌπ‘)(1 β πΎ)). (23)
Remark.
We see that (a) and (b) are in general different, so reliability of sources
does not commute with the importance of sources.
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5. Particular Case when Reliability and Importance Discounting of
Masses Commute.
Letβs consider a classical mass
π: πΊπ β [0, 1] (24)
and the focal set πΉ β πΊπ ,
πΉ = {π΄1, π΄2, β¦ , π΄π}, π β₯ 1, (25)
and of course π(π΄π) > 0, for 1 β€ π β€ π.
Suppose π(π΄π) = ππ β (0,1]. (26)
a. Reliability first, Importance second.
Let πΌ β [0, 1] be the reliability coefficient of π (β).
For π₯ β πΊπ β {π, πΌπ‘}, one has
π(π₯)πΌ = πΌ β π(π₯), (27)
and π(πΌπ‘) = πΌ β π(πΌπ‘) + 1 β πΌ. (28)
Let π½ β [0, 1] be the importance coefficient of π (β).
Then, for π₯ β πΊπ β {π, πΌπ‘},
π(π₯)πΌπ½ = (π½πΌπ(π₯), πΌπ(π₯) β π½πΌπ(π₯)) = πΌ β π(π₯) β (π½, 1 β π½), (29)
considering only two components: believe that π₯ occurs and, respectively,
believe that π₯ does not occur.
Further on,
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π(πΌπ‘)πΌπ½ = (π½πΌπ(πΌπ‘) + π½ β π½πΌ, πΌπ(πΌπ‘) + 1 β πΌ β π½πΌπ(πΌπ‘) β π½ + π½πΌ) =
[πΌπ(πΌπ‘) + 1 β πΌ] β (π½, 1 β π½). (30)
b. Importance first, Reliability second.
For π₯ β πΊπ β {π, πΌπ‘}, one has
π(π₯)π½ = (π½ β π(π₯), π(π₯) β π½ β π(π₯)) = π(π₯) β (π½, 1 β π½), (31)
and π(πΌπ‘)π½ = (π½π(πΌπ‘), π(πΌπ‘) β π½π(πΌπ‘)) = π(πΌπ‘) β (π½, 1 β π½). (32)
Then, for the reliability discounting scaler Ξ± one has:
π(π₯)π½πΌ = πΌπ(π₯)(π½, 1 β π½) = (πΌπ(π₯)π½, πΌπ(π₯) β πΌπ½π(π)) (33)
and π(πΌπ‘)π½πΌ = πΌ β π(πΌπ‘)(π½, 1 β π½) + (1 β πΌ)(π½, 1 β π½) = [πΌπ(πΌπ‘) + 1 β πΌ] β
(π½, 1 β π½) = (πΌπ(πΌπ‘)π½, πΌπ(πΌπ‘) β πΌπ(πΌπ‘)π½) + (π½ β πΌπ½, 1 β πΌ β π½ + πΌπ½) =
(πΌπ½π(πΌπ‘) + π½ β πΌπ½, πΌπ(πΌπ‘) β πΌπ½π(πΌπ‘) + 1 β πΌ β π½ β πΌπ½). (34)
Hence (a) and (b) are equal in this case.
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6. Examples.
1. Classical mass.
The following classical is given on π = {π΄, π΅} βΆ
A B AUB
m 0.4 0.5 0.1
(35)
Let πΌ = 0.8 be the reliability coefficient and π½ = 0.7 be the importance
coefficient.
a. Reliability first, Importance second.
A B AUB
ππΌ 0.32 0.40 0.28
ππΌπ½ (0.224, 0.096) (0.280, 0.120) (0.196, 0.084)
(36)
We have computed in the following way:
ππΌ(π΄) = 0.8π(π΄) = 0.8(0.4) = 0.32, (37)
ππΌ(π΅) = 0.8π(π΅) = 0.8(0.5) = 0.40, (38)
ππΌ(π΄ππ΅) = 0.8(AUB) + 1 β 0.8 = 0.8(0.1) + 0.2 = 0.28, (39)
and
ππΌπ½(π΅) = (0.7ππΌ(π΄), ππΌ(π΄) β 0.7ππΌ(π΄)) = (0.7(0.32), 0.32 β
0.7(0.32)) = (0.224, 0.096), (40)
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ππΌπ½(π΅) = (0.7ππΌ(π΅), ππΌ(π΅) β 0.7ππΌ(π΅)) = (0.7(0.40), 0.40 β
0.7(0.40)) = (0.280, 0.120), (41)
ππΌπ½(π΄ππ΅) = (0.7ππΌ(π΄ππ΅), ππΌ(π΄ππ΅) β 0.7ππΌ(π΄ππ΅)) =
(0.7(0.28), 0.28 β 0.7(0.28)) = (0.196, 0.084). (42)
b. Importance first, Reliability second.
A B AUB
m 0.4 0.5 0.1
ππ½ (0.28, 0.12) (0.35, 0.15) (0.07, 0.03)
ππ½πΌ (0.224, 0.096 (0.280, 0.120) (0.196, 0.084)
(43)
We computed in the following way:
ππ½(π΄) = (π½π(π΄), (1 β π½)π(π΄)) = (0.7(0.4), (1 β 0.7)(0.4)) =
(0.280, 0.120), (44)
ππ½(π΅) = (π½π(π΅), (1 β π½)π(π΅)) = (0.7(0.5), (1 β 0.7)(0.5)) =
(0.35, 0.15), (45)
ππ½(π΄ππ΅) = (π½π(π΄ππ΅), (1 β π½)π(π΄ππ΅)) = (0.7(0.1), (1 β 0.1)(0.1)) =
(0.07, 0.03), (46)
and ππ½πΌ(π΄) = πΌππ½(π΄) = 0.8(0.28, 0.12) = (0.8(0.28), 0.8(0.12)) =
(0.224, 0.096), (47)
ππ½πΌ(π΅) = πΌππ½(π΅) = 0.8(0.35, 0.15) = (0.8(0.35), 0.8(0.15)) =
(0.280, 0.120), (48)
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ππ½πΌ(π΄ππ΅) = πΌπ(π΄ππ΅)(π½, 1 β π½) + (1 β πΌ)(π½, 1 β π½) = 0.8(0.1)(0.7, 1 β
0.7) + (1 β 0.8)(0.7, 1 β 0.7) = 0.08(0.7, 0.3) + 0.2(0.7, 0.3) =
(0.056, 0.024) + (0.140, 0.060) = (0.056 + 0.140, 0.024 + 0.060) =
(0.196, 0.084). (49)
Therefore reliability discount commutes with importance discount of
sources when one has classical masses.
The result is interpreted this way: believe in π΄ is 0.224 and believe in
ππππ΄ is 0.096, believe in π΅ is 0.280 and believe in ππππ΅ is 0.120, and believe
in total ignorance π΄ππ΅ is 0.196, and believe in non-ignorance is 0.084.
7. Same Example with Different Redistribution of Masses Related to
Importance of Sources.
Letβs consider the third way of redistribution of masses related to
importance coefficient of sources. π½ = 0.7, but πΎ = 0.4, which means that
40% of π½ is redistributed to π(π₯) and 60% of π½ is redistributed to π(π₯) for
each π₯ β πΊπ β {π}; and πΌ = 0.8.
a. Reliability first, Importance second.
A B AUB
m 0.4 0.5 0.1
ππΌ 0.32 0.40 0.28
ππΌπ½ (0.2240, 0.0384,
0.0576)
(0.2800, 0.0480,
0.0720)
(0.1960, 0.0336,
0.0504).
(50)
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We computed ππΌ in the same way.
But:
ππΌπ½(π΄) = (π½ β ππΌ(π΄), ππΌ(π΄) + (1 β π½)ππΌ(π΄) β πΎ, ππΌ(π΄) +
(1 β π½)ππΌ(π΄)(1 β πΎ)) = (0.7(0.32), 0 + (1 β 0.7)(0.32)(0.4), 0 +
(1 β 0.7)(0.32)(1 β 0.4)) = (0.2240, 0.0384, 0.0576). (51)
Similarly for ππΌπ½(π΅) and ππΌπ½(π΄ππ΅).
b. Importance first, Reliability second.
A B AUB
m 0.4 0.5 0.1
ππ½ (0.280, 0.048,
0.072)
(0.350, 0.060,
0.090)
(0.070, 0.012,
0.018)
ππ½πΌ (0.2240, 0.0384,
0.0576)
(0.2800, 0.0480,
0.0720)
(0.1960, 0.0336,
0.0504).
(52)
We computed ππ½(β) in the following way:
ππ½(π΄) = (π½ β π‘(π΄), π(π΄) + (1 β π½)π‘(π΄) β πΎ, π(π΄) + (1 β π½)π‘(π΄)(1 β
πΎ)) = (0.7(0.4), 0 + (1 β 0.7)(0.4)(0.4), 0 + (1 β 0.7)0.4(1 β 0.4)) =
(0.280, 0.048, 0.072). (53)
Similarly for ππ½(π΅) and ππ½(π΄ππ΅).
To compute ππ½πΌ(β), we take πΌ1 = πΌ2 = πΌ3 = 0.8, (54)
in formulas (8) and (9).
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ππ½πΌ(π΄) = πΌ β ππ½(π΄) = 0.8(0.280, 0.048, 0.072)
= (0.8(0.280), 0.8(0.048), 0.8(0.072))
= (0.2240, 0.0384, 0.0576). (55)
Similarly ππ½πΌ(π΅) = 0.8(0.350, 0.060, 0.090) =
(0.2800, 0.0480, 0.0720). (56)
For ππ½πΌ(π΄ππ΅) we use formula (9):
ππ½πΌ(π΄ππ΅) = (π‘π½(π΄ππ΅) + (1 β πΌ)[π‘π½(π΄) + π‘π½(π΅)], ππ½(π΄ππ΅)
+ (1 β πΌ)[ππ½(π΄) + ππ½(π΅)],
ππ½(π΄ππ΅) + (1 β πΌ)[ππ½(π΄) + ππ½(π΅)])
= (0.070 + (1 β 0.8)[0.280 + 0.350], 0.012
+ (1 β 0.8)[0.048 + 0.060], 0.018 + (1 β 0.8)[0.072 + 0.090])
= (0.1960, 0.0336, 0.0504).
Again, the reliability discount and importance discount commute.
8. Conclusion.
In this paper we have defined a new way of discounting a classical and
neutrosophic mass with respect to its importance. We have also defined the
discounting of a neutrosophic source with respect to its reliability.
In general, the reliability discount and importance discount do not
commute. But if one uses classical masses, they commute (as in Examples 1
and 2).
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Acknowledgement.
The author would like to thank Dr. Jean Dezert for his opinions about
this paper.
References.
1. F. Smarandache, J. Dezert, J.-M. Tacnet, Fusion of Sources of
Evidence with Different Importances and Reliabilities, Fusion 2010
International Conference, Edinburgh, Scotland, 26-29 July, 2010.
2. Florentin Smarandache, Neutrosophic Masses & Indeterminate
Models. Applications to Information Fusion, Proceedings of the International
Conference on Advanced Mechatronic Systems [ICAMechS 2012], Tokyo,
Japan, 18-21 September 2012.