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![Page 1: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/1.jpg)
Sample Presentation on Factoring Polynomials
By Paul BartholomewK12 International
Academy Applicant(856) 266-2634
After this presentation you should be able to
bull Explain the concept of factoring polynomialsbull Explain in simple terms why you would need to factor a
polynomialbull Factor polynomials that have a greatest common factor
between terms (ex x3 + 3x2 +x)bull Factor polynomials that have a leading coefficient of 1
(ex x2 + 2x +1)
bull Factor polynomials that have a leading coefficient other then 1 (ex 3x2 + 13x +4)
Factoring a polynomial is the same in concept to factoring a monomial
bull For the monomial 6x2y the prime factors are 23xxy
bull For the polynomial x3 + 2x2 + x the prime factors are x and (x2 + x + 1) written as x(x2 + x + 1)
This presentation will show you how to factor some basic polynomials
Why factor polynomials 1) To reduce expressions to their lowest terms like you do with monomials
6x2y = 23 xxy = 3xy 2x 2x
Monomial Example
Polynomial Examplex3 + 2x2 + x = x(x2 + x + 1) = xx2 + x + 1 (x2 + x + 1)
2) Factoring polynomials is key to solving quadratics and other higher order equations
Factoring a polynomial means expressing it as a product of other
polynomials
This can help you simplify expressions and solve higher order
equations
Summary
Factoring Method 1
Factoring polynomials with a Greatest Common Factor (GCF)
IMPORTANT - Always look for a GCF before using any other
factoring method
Steps1) Find the greatest common factor
(GCF)
2) Divide the polynomial by the GCF The quotient (answer from the division) is the other factor
3) Express the polynomial as the product of the quotient and GCF
3cd(2c2 4cd 1)
The answer should look like this
Ex 6c3d 12c2d 2 3cd
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 2: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/2.jpg)
After this presentation you should be able to
bull Explain the concept of factoring polynomialsbull Explain in simple terms why you would need to factor a
polynomialbull Factor polynomials that have a greatest common factor
between terms (ex x3 + 3x2 +x)bull Factor polynomials that have a leading coefficient of 1
(ex x2 + 2x +1)
bull Factor polynomials that have a leading coefficient other then 1 (ex 3x2 + 13x +4)
Factoring a polynomial is the same in concept to factoring a monomial
bull For the monomial 6x2y the prime factors are 23xxy
bull For the polynomial x3 + 2x2 + x the prime factors are x and (x2 + x + 1) written as x(x2 + x + 1)
This presentation will show you how to factor some basic polynomials
Why factor polynomials 1) To reduce expressions to their lowest terms like you do with monomials
6x2y = 23 xxy = 3xy 2x 2x
Monomial Example
Polynomial Examplex3 + 2x2 + x = x(x2 + x + 1) = xx2 + x + 1 (x2 + x + 1)
2) Factoring polynomials is key to solving quadratics and other higher order equations
Factoring a polynomial means expressing it as a product of other
polynomials
This can help you simplify expressions and solve higher order
equations
Summary
Factoring Method 1
Factoring polynomials with a Greatest Common Factor (GCF)
IMPORTANT - Always look for a GCF before using any other
factoring method
Steps1) Find the greatest common factor
(GCF)
2) Divide the polynomial by the GCF The quotient (answer from the division) is the other factor
3) Express the polynomial as the product of the quotient and GCF
3cd(2c2 4cd 1)
The answer should look like this
Ex 6c3d 12c2d 2 3cd
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 3: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/3.jpg)
Factoring a polynomial is the same in concept to factoring a monomial
bull For the monomial 6x2y the prime factors are 23xxy
bull For the polynomial x3 + 2x2 + x the prime factors are x and (x2 + x + 1) written as x(x2 + x + 1)
This presentation will show you how to factor some basic polynomials
Why factor polynomials 1) To reduce expressions to their lowest terms like you do with monomials
6x2y = 23 xxy = 3xy 2x 2x
Monomial Example
Polynomial Examplex3 + 2x2 + x = x(x2 + x + 1) = xx2 + x + 1 (x2 + x + 1)
2) Factoring polynomials is key to solving quadratics and other higher order equations
Factoring a polynomial means expressing it as a product of other
polynomials
This can help you simplify expressions and solve higher order
equations
Summary
Factoring Method 1
Factoring polynomials with a Greatest Common Factor (GCF)
IMPORTANT - Always look for a GCF before using any other
factoring method
Steps1) Find the greatest common factor
(GCF)
2) Divide the polynomial by the GCF The quotient (answer from the division) is the other factor
3) Express the polynomial as the product of the quotient and GCF
3cd(2c2 4cd 1)
The answer should look like this
Ex 6c3d 12c2d 2 3cd
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 4: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/4.jpg)
Why factor polynomials 1) To reduce expressions to their lowest terms like you do with monomials
6x2y = 23 xxy = 3xy 2x 2x
Monomial Example
Polynomial Examplex3 + 2x2 + x = x(x2 + x + 1) = xx2 + x + 1 (x2 + x + 1)
2) Factoring polynomials is key to solving quadratics and other higher order equations
Factoring a polynomial means expressing it as a product of other
polynomials
This can help you simplify expressions and solve higher order
equations
Summary
Factoring Method 1
Factoring polynomials with a Greatest Common Factor (GCF)
IMPORTANT - Always look for a GCF before using any other
factoring method
Steps1) Find the greatest common factor
(GCF)
2) Divide the polynomial by the GCF The quotient (answer from the division) is the other factor
3) Express the polynomial as the product of the quotient and GCF
3cd(2c2 4cd 1)
The answer should look like this
Ex 6c3d 12c2d 2 3cd
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 5: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/5.jpg)
Factoring a polynomial means expressing it as a product of other
polynomials
This can help you simplify expressions and solve higher order
equations
Summary
Factoring Method 1
Factoring polynomials with a Greatest Common Factor (GCF)
IMPORTANT - Always look for a GCF before using any other
factoring method
Steps1) Find the greatest common factor
(GCF)
2) Divide the polynomial by the GCF The quotient (answer from the division) is the other factor
3) Express the polynomial as the product of the quotient and GCF
3cd(2c2 4cd 1)
The answer should look like this
Ex 6c3d 12c2d 2 3cd
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 6: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/6.jpg)
Factoring Method 1
Factoring polynomials with a Greatest Common Factor (GCF)
IMPORTANT - Always look for a GCF before using any other
factoring method
Steps1) Find the greatest common factor
(GCF)
2) Divide the polynomial by the GCF The quotient (answer from the division) is the other factor
3) Express the polynomial as the product of the quotient and GCF
3cd(2c2 4cd 1)
The answer should look like this
Ex 6c3d 12c2d 2 3cd
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 7: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/7.jpg)
Steps1) Find the greatest common factor
(GCF)
2) Divide the polynomial by the GCF The quotient (answer from the division) is the other factor
3) Express the polynomial as the product of the quotient and GCF
3cd(2c2 4cd 1)
The answer should look like this
Ex 6c3d 12c2d 2 3cd
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 8: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/8.jpg)
3cd(2c2 4cd 1)
The answer should look like this
Ex 6c3d 12c2d 2 3cd
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 9: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/9.jpg)
Ex 6c3d 12c2d 2 3cd
GCF 3cdSTEP 1
Step2 Divide
(6c3d 12c2d2 3cd) 3cd
2c2 4cd 1
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 10: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/10.jpg)
Factor these on your own looking for a GCF
1 6x3 3x2 12x
2 5x2 10x 35
3 16x3y4z 8x2 y2z3 12xy3z 2
3x 2x2 x 4 5 x2 2x 7
4xy2z 4x2 y2 2xz 2 3yz
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 11: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/11.jpg)
A note Method 2 is a way of lsquoworking backwardsrsquo from the way one would multiply
two binomials together
NoticeThe first term of the answer is the product of the (first) variable terms
The last term of the answer is the product of the constant (last) terms
The middle term is the sum of the constant (last) terms
Please keep this in mind as we go forwardhellip
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 12: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/12.jpg)
Factoring Polynomials ndash Method 2
How do you factor a trinomial with a leading coefficient of 1
Example Factor x2 ndash 13x + 36
You can use a diamond
The factors are (x ndash 9)(x ndash 4)
Write the middle coefficient here
Write the last term here
ndash13
+36
Now find factors that will multiply to the bottom number and add to the top number
ndash9 ndash4
Example Factor x2 ndash 3x ndash 40 ndash3
ndash40ndash8 +5 The factors are (x ndash 8)(x + 5)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 13: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/13.jpg)
Try factoring these on your own
1) x2 + 2x ndash 15 =
2) x2 - 10 + 24 =
3) x2 + 6x + 9 =
(x - 3)(x + 5)
(x - 4)(x - 6)
(x + 3)(x + 3) = (x + 3)2
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 14: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/14.jpg)
Some polynomials are already prime there are no factors
Look at x2 + 5x + 1
Are there two numbers that multiply to get 1 and add to get 5
No - There are not two integers that will do this and so this quadratic doesnrsquot factor
Remember this as a possibility when factoring any polynomial
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 15: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/15.jpg)
How do you factor a trinomial whose leading coefficient is not 1
(3x + 1)(x + 4)
Example Factor 3x2 + 13x + 4We will make a T to determine the coefficients of the factors
Write factors ofthe first term inthis column
3
1
Write factors ofthe last term inthis column
2
2
Multiple diagonally and addSee if the sum matches themiddle term
2 + 6 ne 13
hellipif not try another combination of factors
3
1
1
4
1 + 12 = 13
( )
( )
These are thecoefficients ofthe factors
Factoring Polynomials ndash Method 3
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 16: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/16.jpg)
Example Factor 6d2 + 33d ndash 63
Remember look for the GCF first
GCF 3
3(2d2 + 11d ndash 21)
Now factor the trinomial (using a T)
3(2d ndash 3)(d + 7)
ndash3 + 14
1
2 ndash3
7
= 11
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 17: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/17.jpg)
Try factoring these on your own
1) 3x2 - 2x ndash 8 =
2) 5x2 ndash 17x + 6 =
3) 4x2 + 10x ndash 6 =
(3x - 4)(x + 2)
(x - 3)(x + 5)
(x - 3)(x + 5)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-
![Page 18: Sample Presentation on Factoring Polynomials By Paul Bartholomew K12 International Academy Applicant (856) 266-2634](https://reader038.vdocuments.net/reader038/viewer/2022110205/56649ccf5503460f9499b47d/html5/thumbnails/18.jpg)
Closing Notesbull Remember ndash whenever you factor any polynomial
your first step is to see if there is a greatest common factor
bull After completing an initial factorization check to see if any of the factors can be factored further (see example of slide 13)
bull Donrsquot get stuck on a polynomial that cannot be factored ndash there are prime polynomials just as there are prime numbers that cannot be factored Eliminate all possibilities then move on
- Sample Presentation on Factoring Polynomials
- Slide 2
- After this presentation you should be able to
- Factoring a polynomial is the same in concept to factoring a mo
- Why factor polynomials
- Factoring a polynomial means expressing it as a product of othe
- Factoring Method 1
- Steps
- Slide 9
- Slide 10
- Slide 11
- A note Method 2 is a way of lsquoworking backwardsrsquo from the way
- Factoring Polynomials ndash Method 2
- Slide 14
- Some polynomials are already prime there are no factors
- How do you factor a trinomial whose leading coefficient is not
- Example Factor 6d2 + 33d ndash 63
- Slide 18
- Closing Notes
-