sbi associates (clerk) mock test - 157 (solution) · prpq rpp rrpqrq rpr pr qqr rpr qpr qrr qpr qpr...

1

==================================================================================

Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

SBI ASSOCIATES (Clerk) MOCK TEST - 157 (SOLUTION)

REASONING1. (5) Except it others can be written in

the form exactly.144 = 53 + 42 + 31;1089 = 103 + 92 + 81;245 = 63 + 52 + 41;567 = 83 + 72 + 61;But 386 = 73 + 82 + 51 + 2

2. (2) Original Sequence:prp qrp prr pqr qrp rpr qqr rprqpr qrr qpr qprAccording to question the newsequence would be:p r c q k p c r k p q r q k c r p k qq r k c r q p k q r k q c r q p k13th letter to the right from thesecond letter from the left means(13 + 2 =) 15th letter from the left,i.e. C.

3. (1) We have to look for no r – q – no pcombination in the givensequence. Underlined q's showthe required letters.pr pqr ppr r pqr qrp rpr qqr rprqpr qrr qpr qpr

4. (2) We have to look for r – p no qcombination in the givensequence.prpq rpp rrpqrq rpr pr qqr rpr qprqrr qpr qpr

5. (2) Sequence after inserting 'g'p r p q r g p r r p q g q r p r p g qq r r p g q p r q r g q p rq p gSequence after inserting 'n'p r p n r g p n r p q n q r p n p g qn r r p n q p r n r g q n r q p n6th to the left of 20th letter fromthe right means (20 + 6 =) 26thfrom the right, i.e. (36 – 26 + 1 =)11th letter from the left, i.e. q.

(6-10): We get the following table:

6. (1) G is sitting immediate right of D.

7. (2) A is the doctor.8. (3) E is the teacher.9. (3) Teacher and Entrepreneur are

sitting together.10. (3) ECB(11-15):

Populationwise RankK > R > D > M > W > N > J > T

11. (2) J12. (1) R, K and D13. (2) N14. (5) RJKD15. (4) J(16-20):16. (4) From I: Buy three dusters get one

free dd ee jj oo tt yy

From II: Purchase one sharpenerget three free

dd ee ll oo ww yy

From I and II: Code for 'Buydusters'

jj or ttStill we don't know the code of'dusters'.

17. (4)

From I:

In the above figure B can beplaced at any point towardsSouth-west of C. Thus, unless weget the specific position of B wecan't answer the question. Again,statement II alone is not sufficientbecause it lacks informationregarding B.

2

==================================================================================


Now,From I and II: we get

Still we are facing the same problem.18. (4) Comparisons of strike rates and

centuries alongwith fifties are notenough to answer the question. Westill need some more information.

19. (2) From I: We get the following twoseating arrangements:

In figure I, D is on the immediateright of B whereas in figure II, C ison the immediate right of B. Thegiven information is still inadequateto answer the question.From II: We get the followingarrangement

Obviously, C is on the immediateright of B.

20. (4) From I:

Still, we need more information toanswer the question.From II: The information given init does not lead us to answer.

(21-25):21. (1) T > U ... (i);

Q < R ... (ii);R < U ... (iii);Combining all these, we getT > U > R > Q T > Q and T > R.Hence, conclusion I (T > Q)follows. But conclusion II (R < T)is false.

22. (4) H < B ... (i);J > C ... (ii);H > J ... (iii);Combining all these, we getB > H > J > C B > C and H > C.Hence, Conclusion I (B > C) andConclusion II (C < H) do not follow.

23. (2) Q < T ... (i);W > X ... (ii);Q > X ... (iii);From (ii) and (iii), we can't ascertainthe relationship between W and Q.Hence, I does not follow. From (i)and (iii), we getT > Q > X T > XHence, Conclusion II (X < T) istrue.

24. (5) Y = Z ... (i);B > A ... (ii);Y < A ... (iii);Combining all these, we getB > A > Y = Z A > Z and B > YHence, Conclusion I (A > Z) andConclusion II (Y < B) are true.

25. (3) K > L ... (i);N < O ... (ii);L = O ... (iii);Combining (ii) and (iii), we getL = O > N L > N, i.e. L > N or L =NHence, either Conclusion I (L > N)or Conclusion II (N = L) is true.

(26-30):26. (4) All seats are hot + conversion of

'All belts are hot' = All seats arehot + Some hot are belts = A + I =No conclusion.

27. (2) No house is an apartment + Allapartments are flats = E + A = O *= Some flats are houses.Therefore, conclusion I does notfollow. All buildings are houses +No house is an apartment = A + E= E = No building is an apartment.Hence conclusion II follows.

3

==================================================================================


28. (1) All buildings are houses + Nohouse is an apartment + Allapartments are flats = A + E + A =(A + E) + A = E + A = O* = Someflats are not buildings.Now, look at the conclusions, herewe have to find possibilities. To findpossibilites, we should draw all thepossible venn-diagrams for the abovederived conclusion, i.e. 'Some flatsare not buildings' as given below:Possibility I:

[Some flats are building.]Possibility II:

[All buildings are flats.]Hence conclusion I follows.Possibility III:

[No flats are buldings.]Again, from Q.No. 27, we have 'Nobuilding is an apartment' as aconclusion. From this, conclusionII cannot be possible.

29. (4) Some papers are boards + Noboard is a card = I + E = O = Somepapers are not cards. Henceneither conclusion I norconclusion II follows.

30. (5) From Q. No. 27, we have "Somepapers are not cards" as a derivedconclusion. Now, we draw allpossible venn-diagrams for thisconclusion as given below:Possibility I:

[Some papers are cards.]

Possibility II:

[All cards are papers.]Hence conclusion I follows.Now, take the statement "Somepapers are boards." Draw allpossible venn-diagrams for thisstatement:Possibility I:

[Some papers are not boards.]Possibility II:

[All boards are papers.]Hence conclusion II follows.Therefore, conclusions I and IIboth follow.

(31-35):In the given arrangement the firstand the second places are occupiedby words; the third and fourth bynumbers; the fifth and the sixth bywords; and the seventh and theeighth by numbers.Words occupy place inalphabetical order while numbersoccupy place in desending order.Whenever a word or a numbergets arranged other elements shiftone place rightward.

31. (4) Since it is a case of 'Arrangement',previous steps can't be obtainedwith certainty.

32. (1)Input: bring home 42 73 15 goal 32 typeStep I: bring goal home 42 73 15 32 typeStep II: bring goal 73 home 42 15 32 typeStep III: bring goal 73 42 home 15 32 typeStep IV: bring goal 73 42 home type 15 32Step V: bring goal 73 42 home type 32 15

Since all the elements of Inputget arranged in Step V, it is thelast step.

4

==================================================================================


33. (5)Input: bench 47 63 advance 13 29

again betweenStep I: advance bench 47 63 13 29

again betweenStep II: advance again bench 47 63 13

29 betweenStep III: advance again 63 bench 47 13

29 between34. (3)Step II: desk eagle 12 28 41 69 foreign

landStep III: desk eagle 69 12 28 41 foreign

landStep IV: desk eagle 69 41 12 28 foreign

landStep V: desk eagle 69 41 foreign 12 28

landStep VI: desk eagle 69 41 foreign land 12

28Step VII: desk eagle 69 41 foreign land

28 1235. (1)Step III: again dark 83 sour 19 21 prey

39Step IV: again dark 83 39 sour 19 21

preyStep V: again dark 83 39 prey sour 19

21Step VI: again dark 83 39 prey sour 21

19Since step VI is the last step(because all elements of step IIIget arranged in Step VI), step Vis the required step (penultinatestep or last but one.)

(36-40):36. (3) Only III follows. After finding the

cause of the sickness, necessaryaction should be taken.

37. (5) To improve the standard inEnglish language, all the coursesof action are necessary.

38. (4) In order to save the people fromgetting drowned all the courses ofaction are necessary.

39. (1) Such institutes shouldimmediately be derecognised bythe university. Hence I course ofaction follows.

40. (2) Only II follows because providingrelief supplies to the affectedareas is necessary.

MATHS81. (1) [5 7 7 (4 7 8 7)] – (19)2 = ?

[6 7 12 7] – 361 = ? (72 × 7) – 361 = ? 504 – 361 = ? ? = 143

82. (5) 33124 2601 – (83)2 = (?)2 + (37)2

182 × 51 – 6889 = (?)2 + 1369 9282 – 6889 = (?)2 + 1369 (?)2 = 9282 – 6869 – 1369 (?)2 = 1024 = (32)2 ? = 32

83. (3) 534.596 + 61.472 – 496.708 = ? + 27.271586.068 – 496.708 = ? + 27.271

9 9.36 = ? + 27.271 99.36 – 27.271 = ? 72.089 = ?

84. (2) ? = 99.9 + 9.99 + 0.99 + 99.09 + 9.09 + 999 = 1218.06

85. (4) ? = (73425 – 33267 – 22418 – 17650) × 11025

= (73425 – 73335) × 11025 = 90 × 105 = 9450

86. (4)30

100 of 200 + ?

= 48

100 of 550 – 10

100 of 150

60 + ? = 264 – 15 ? = 264 – 15 – 60

= 189? = 189 × 189

= 3572187. (5) (?)2 = 25600 – 8100 – 7191 – 4225

= 6084? = 6084 = 78

88. (5) ? = 17956 24025

= 134 155

= 289= 17

5

==================================================================================


89. (3) 2( 7 11) = (?)1/3 + 2 847 + 122

7 + 121 + 22 7 – 22 7 – 122= (?)1/3

(?)1/3 = 6 ? = (6)3 = 216

90. (2) (0.064) × (0.4)7= (0.4)? × (0.0256)2

(0.4)3 × (0.4)7= (0.4)? × (0.4)8

(0.4)3+7 = (0.4)?+8

10 = ? + 8 ? = 10 – 8 = 2

(91-95):91. (2) The series is × 5 + 5, × 4 + 4, ×3

+ 3, ×2 + 2, ×1 + 1 ...So, (c) = 7 × 5 + 5 = 40; 40 × 4 +4 = 164; 164 × 3 + 3 = 495

92. (4) The series is ×2 + 1So, (e) = 11 × 2 + 1 = 23;23 × 2 + 1 = 47; 47 × 2 + 1 = 95;95 × 2 + 1 = 191; 191 × 2 + 1 = 383

93. (1) The series is (+1) × 0.5, (+1) × 1,+1(×1.5, (+1) × 2, (+1) × 2.5)So, (d) = (17 + 1) × 0.5 = 9;(9+1) × 1 = 10; (10 + 1) × 1.5 =16.5; (16.5 + 1) × 2 = 35

94. (3) The series is ×1 + 12, ×2 + 22, ×3+ 32, ×4 + 42, ×5 + 52

So, (c) = 5 × 1 + 12 = 6; 6 × 2 +22 = 16; 16 × 3 + 32 = 57

95. (5) The series is × 6 – 6, × 5 – 5, × 4– 4, ×3 – 3, × 2 – 2.So, (b) = 4 × 6 – 6 = 18; 18 × 5 – 5 = 85

96. (2) Let the length and the breadth ofthe rectangle be 3x and 2xrespectively.

Now, 1.5 4

2 1.5 3xx

or, 9x + 4.5 = 8x + 6

or, x = 1.5 length and breadth of therectangle will be 3 × 1.5 = 4.5 mand 2 × 1.5 = 3 m respectively.original area= 4.5 × 3 = 13.5 m2

97. (1) The retailer purchases 60 pens forpaying the price of 51 pens and hefurther sells the pens on theirmarked price i.e. by selling 51 penshe gets a profit of the marked priceof 9 pens. So, by selling 100 pens

951 × 100 = 17.60%

98. (3) Correct average

= 241 1710 (1783 1873)

241

= 1710 – 0.37= 1709.63

99. (2) Speed of the train

= (200 -120)m(29 - 21)sec = 10m/sec

In the first case,Distance = Speed × Time

= 10 × 29 = 290 mlength of the train= 290 – 200 = 90 m

100. (3)Let the speed of the stream be xkm/h.From the question,

40 40 1212 12x x

or, 2

960 12144 x

or, 144 – x2 = 80 –x2 = –64x = 8 km/hr

101. (2)Let the time taken by B to do thejob = x daystime taken by A to do the job

= 4

4x

x days

From the question,

92( 4) 2

x xx

or, x2 – 18x + 72 = 0or, (x – 6) (x – 12) = 0x = 6 days or 12 daysSince B is less efficient he willtake more time than A to finishthe work.

102. (3)32.5%

6

==================================================================================


103. (2)If a sum becomes 'x' times in 'n'years at CI, then it will be (x)n

times in 'nx' years.Hence, Rs. 4000 becomes 5/4time in 4 yrs, so, in 'nx' (2 × 4)yrs amount wil l be xn =

25 254 16

times

Reqd amt = 4000 × 2516 = Rs. 6250

104. (2)R + S = S + M + 15 R – M = 15 ... (i)AndR + S + M R + S=

3 2or, 3R + 3S = 2R + 2S + 2M

M = R + S

2 ... (ii)

Putting (ii) in (i),

R – R + S

2

= 15

R – S = 30105. (2)9%

Direct formula (only for 2 years):

rate = 2× diff in interest ×100

S.I.

= 2 12.15 100

270

= 9%

(106-110):106. (2)Car sales in 1989-90

= 10,000 cars × ` 2,00,000 per car= ` 200 crore(100 lakh = 1 crore)

107. (3)10,000 cars sold in 1989-90 10,000 + 500 = 10,500 cars are

in 1990-91 (No. of cars soldincreased by 500 in 990-91)

108. (2)No. of cars sold= 10,000 + 10,500 + 11,500 +

11,550 + 12,000 + 12,250= 56,300

109. (3)Similarly price in 1992-93= ` 2,31,000= ` 2.31 lakh (as explained above)

110. (1)12,250 cars sold at a unit price of` 2.41

Sales = 122.5 × 2.41 crore= 295.225

(111-115):111. (5)Number of students passing from

Ahmedabad = 1000 × 125

Number of boys passing from Chennai

= 1000 × 125 × 100

7 ×

20100 ×

1324 = 3715

112. (3)Number of girl students passing

from Delhi = 9000 × 1615 ×

58 = 6000

113. (4)For answering this question, wedonot need the data provided inpie-chart. Simplify we find outwhich city shows the maximumpercentage of girls passing? Theanswer is 'Rest'.

114. (2)Let the total number of passingstudents be x.

Then, 18% of x × 9

16– 16% of x × 38

= 3630or, x = 88000

115. (2)Number of boys passing from therest part of the country in X

exam = 25% of 1.20 × 514 10720

(116-120):116. (2)In 2005 the average number of

companies registered

= (5 10 15 35) 10004

= 650004

= 16250In 2006, the average number ofcompanies registered

= (10 25 30 35) 10004

= 25000

In 2007, the average number ofcompanies registered

= (5 10 15 20) 10004

= 12500


= (30 25 20 15)4

= 904

= 22.5 = 22500

7

==================================================================================



= (5 20 25 35) 10004


= (10 20 25 30) 10004


= (5 15 25 30) 10004


= (10 15 30 35) 10004

= 22500Hence, in 2006, the averagenumber of companies registeredwas he maximum.

117. (4)Number of companies registeredin 2012 = 90000Number of companies registeredin 2005 = 65000Required %

= 90000 65000

75000

×100 = 33.33%Hence, 33.33% more.

118. (5)Number of companies registeredin Japan during 2005 to 2012 =(10 + 35 + 10 + 25 + 20 + 30 +35 + 35) × 1000 = 20000Number of companies registeredin China during 2005 to 2012 =(35 + 30 + 15 + 30 + 35 + 25 + 5+ 30) × 1000 = 205000Required ratio= 20000 : 20500 = 40 : 41

119. (2)Average number of companiesregistered in France = (15 + 25 +20 + 15 + 25 + 10 + 15 + 10) ×1000

8 = 135 × 1000

8 = 1687.5

Average number of companiesregistered in Germany = (5 + 10+ 5 + 20 + 5 + 20 + 25 + 15) ×1000

8 = 105 ×1000

8 = 1312.5

Average number of companiesregistered in Japan

= 200008 = 2500

Average number of companiesregistered in China

= 20500

8 = 2562.5Clearly, average number ofcompanies registered in China isthe maximum.

120. (3)Total number of companiesregistered in France = 135000Total number of companiesregistered in China = 20500

Therefore, 20500 13500

20500

× 100 =

34.14% less than the number ofcompanies registered in China.

8

==================================================================================


Note:-1. For any question paper related queries call/Whatsap/Message on8287900900.

2. For any issue related to RESULT Processing, kindly contact uson 8287200200.

3. If your opinion differs regarding any answer, please message themock test and question number to 8287500500.

1. (5)2. (2)3. (1)4. (2)5. (2)6. (1)7. (2)8. (3)9. (3)10. (3)11. (2)12. (1)13. (2)14. (5)15. (4)16. (4)17. (4)18. (4)19. (2)20. (4)21. (1)22. (4)23. (2)24. (5)25. (3)26. (4)27. (2)28. (1)29. (4)30. (5)31. (4)32. (1)33. (5)34. (3)35. (1)36. (3)37. (5)38. (4)39. (1)40. (2)

41. (2)42. (3)43. (3)44. (3)45. (2)46. (5)47. (3)48. (4)49. (4)50. (1)51. (4)52. (3)53. (2)54. (5)55. (3)56. (1)57. (4)58. (3)59. (1)60. (3)61. (2)62. (1)63. (3)64. (2)65. (1)66. (5)67. (5)68. (3)69. (3)70. (2)71. (1)72. (5)73. (4)74. (2)75. (3)76. (1)77. (5)78. (4)79. (2)80. (3)

SBI ASSOCIATES (Clerk) MOCK TEST - 157 [ANSWER KEY]

81. (1)82. (5)83. (3)84. (2)85. (4)86. (4)87. (5)88. (5)89. (3)90. (2)91. (2)92. (4)93. (1)94. (3)95. (5)96. (2)97. (1)98. (3)99. (2)100. (3)101. (2)102. (3)103. (2)104. (2)105. (2)106. (2)107. (3)108. (2)109. (3)110. (1)111. (5)112. (3)113. (4)114. (2)115. (2)116. (4)117. (5)118. (2)119. (3)120. (1)

121. (1)122. (3)123. (2)124. (1)125. (1)126. (2)127. (3)128. (2)129. (3)130. (1)131. (1)132. (2)133. (2)134. (1)135. (4)136. (2)137. (1)138. (1)139. (4)140. (2)141. (3)142. (4)143. (1)144. (2)145. (1)146. (4)147. (2)148. (3)149. (4)150. (4)151. (2)152. (1)153. (2)154. (3)155. (2)156. (1)157. (1)158. (4)159. (1)160. (4)

161. (2)162. (1)163. (3)164. (2)165. (1)166. (4)167. (1)168. (4)169. (3)170. (2)171. (2)172. (1)173. (3)174. (1)175. (3)176. (3)177. (4)178. (3)179. (4)180. (1)181. (1)182. (4)183. (4)184. (4)185. (4)186. (3)187. (1)188. (3)189. (1)190. (2)191. (1)192. (5)193. (1)194. (4)195. (1)196. (4)197. (1)198. (5)199. (3)200. (5)

sbi associates (clerk) mock test - 157 (solution) · prpq rpp rrpqrq rpr pr qqr rpr qpr qrr qpr qpr...

Documents