sbi associates (clerk) mock test - 158 (solution) · 2016-03-25 · centres at: mukherjee nagar...

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1 ================================================================================== Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) REASONING 1. (3) 2. (2) J + H ÷ R × L : Drawing family tree Hence, J is daughter-in-law of L. 3. (3) Total number of children = 11 + 1 + 3 + 1 + 21 = 37 4. (1) Ascending order : 582, 669, 796, 865, 937 Fourth number = 567 (5-9): A @ B A + B A B A × B A # B A ÷ B A $ B A – B 5. (1) Average age of all the boys and girls together (A) = X+Y 25 or, A = (X@Y)#25 6. (3) P 1 = 2 P 2 – 1,50,000 or, P 1 = (P 2 # 2)$ 1,50,000 7. (3) B = 4 × 3G = 3G 4 or, B =(3 G)#4 8. (2) S 1 = 0 100 × S 2 + 8000 or, S 1 =[S 2 (40#100)]@8000 9. (4) H = 85 100 × M or, H = (85#100) M 10. (1) Since there is no negative statement, hence conclusion II does not follow. Again, we have the statements 'Some mail are chats' and 'Some chats are updates' [Converse of the given statement 'All updates are chats']. Now, we have the following possibilities from the above two statements: 'All mails are chats' and 'All chats are updates' respectively. Therefore, All mails are chats + All chats are updates = A + A = A = All mails are updates. Hence, 'All mails being updates is a possibility', i.e. conclusion I follows. 11. (2) Some gases are liquids + All liquids are water = I + A = I = Some gases are water. Since this is a definite conclusion, no case of possibility exists in such cases. Again, from the conclusion 'Some gases are water', conclusion 'All such gases which are not water can never be liquids' follows. Since we have been given 'All liquids are water'. 12. (2) All seconds are hours (A) conversion Some hours are seconds (I) + No second is a day (E) = I + E = O = Some hours are not days. Therefore conclusion I does not follow. Again, All minutes are seconds + All seconds are hours = A + A = A = All minutes are hours conversion Some hours are minutes (I). Therefore, conlcusion II follows. 13. (1) From the statement 'Some teachers are professors' there are possibilities that 'All teachers are professors' and 'All professors are teachers'. Similarly, from the statement 'Some lectureres are teachers' there is a possibility that 'All teachers are lecturers. Again, All professors are teachers + All teachers are lecturers = A + A = A = All professors are lecturers. Hence, All teachers and professors are lecturers is a possibility. But conclusion II does not follow.

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Page 1: SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) · 2016-03-25 · centres at: mukherjee nagar munirka uttam nagar dilshad garden rohini badarpur jaipur gurgaon noida meerut varanasi

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION)

REASONING1. (3)2. (2) J + H ÷ R × L : Drawing family tree

Hence, J is daughter-in-law of L.3. (3)

Total number of children= 11 + 1 + 3 + 1 + 21 = 37

4. (1)

Ascending order : 582, 669, 796,865, 937Fourth number = 567

(5-9):A @ B A + BA B A × BA # B A ÷ BA $ B A – B

5. (1) Average age of all the boys and

girls together (A) = X + Y25

or, A = (X@Y)#25

6. (3) P1 = 2P2 – 1,50,000

or, P1 = (P2 # 2)$ 1,50,000

7. (3) B = 4 × 3G = 3G

4or, B =(3 G)#4

8. (2) S1 = 0

100

× S2 + 8000

or, S1 =[S2 (40#100)]@8000

9. (4) H =85

100 × M

or, H = (85#100) M

10. (1) Since there is no negativestatement, hence conclusion IIdoes not follow. Again, we have thestatements 'Some mail are chats'and 'Some chats are updates'[Converse of the given statement'All updates are chats']. Now, wehave the following possibilitiesfrom the above two statements: 'Allmails are chats' and 'All chats areupdates' respectively. Therefore,All mails are chats + All chats areupdates = A + A = A = All mails areupdates. Hence, 'All mails beingupdates is a possibility', i.e.conclusion I follows.

11. (2) Some gases are liquids + All liquidsare water = I + A = I = Some gasesare water. Since this is a definiteconclusion, no case of possibilityexists in such cases.Again, from the conclusion 'Somegases are water', conclusion 'All suchgases which are not water can neverbe liquids' follows. Since we havebeen given 'All liquids are water'.

12. (2) All seconds are hours (A)conversionSome hours are seconds (I) + Nosecond is a day (E) = I + E = O = Somehours are not days. Thereforeconclusion I does not follow. Again,All minutes are seconds + All secondsare hours = A + A = A = All minutesare hours conversionSome hoursare minutes (I). Therefore, conlcusionII follows.

13. (1) From the statement 'Someteachers are professors' there arepossibilities that 'All teachers areprofessors' and 'All professors areteachers'. Similarly, from thestatement 'Some lectureres areteachers' there is a possibility that'All teachers are lecturers. Again,All professors are teachers + Allteachers are lecturers = A + A = A= All professors are lecturers.Hence, All teachers and professorsare lecturers is a possibility. Butconclusion II does not follow.

Page 2: SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) · 2016-03-25 · centres at: mukherjee nagar munirka uttam nagar dilshad garden rohini badarpur jaipur gurgaon noida meerut varanasi

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

14. (2) From the above, conclusion I doesnot follow. Again, from the above,we have the following possibilites'All lecturers are teachers' and 'Allteachers are professors.' Now, Alllecturers are teachers + All teachersare professors = A + A = A = Alllectureres are professors. Thereforeconclusion II, i.e. 'All lecturers beingprofessors is a possibility' follows.

(15-19):On the basis of information givenin the question, we have thefollowing table:-

15. (2) Village B has both school andpost-office.

16. (3) Village C.17. (3) Villages B and D have electricity.18. (5) Villages A, D and B are accessible

by road.19. (5) No village has population less

than 2000.(20-24):

In Step I the largest number occupiesthe leftmost position, pushing the restof the line rightwards. In the next stepthe word that comes last in thealphabetical order occupies the secondposition from the left and the remainingterms move rightwards. This goes onalternately till all the numbers getarranged in descending order and thewords in reverse alphabetical order atalternate positions. In case a term isalready arranged, the machine moveson to the next one.

20. (2)Step II: 53 window 42 50 door lock key

36Step III: 53 window 50 42 door lock key

36Step IV: 53 window 50 lock 42 door key

36Step V: 53 window 50 lock 42 key door

36Step VI: 53 window 50 lock 42 key 36

doorHence, four more steps are required.

21. (4) We cannot determined thearrangement in the reverse direction.

22. (1)Input: jockey firm 36 43 growth chart

22 45Step I: 45 jockey firm 36 43 growth

chart 22Step II: 45 jockey 43 firm 36 growth

chart 22Step III: 45 jockey 43 growth firm 36

chart 2223. (5)Step II: 63 sour 18 56 grapes healthy 32

riseStep III: 63 sour 56 18 grapes healthy 32

riseStep IV: 63 sour 56 rise 18 grapes

healthy 32Step V: 63 sour 56 rise 32 18 grapes

healthyStep VI: 63 sour 56 rise 32 healthy 18

grapesHence, step VI will be the laststep.

24. (3)Step I: 85 journey train 36 54 daily 28

mansionStep II: 85 train journey 36 54 daily 28

mansionStep III: 85 train 54 journey 36 daily 28

mansionStep IV: 85 train 54 mansion journey 36

daily 28Step V: 85 train 54 mansion 36 journey 36

daily 28(25-30): From the table we have the

following table:

Cost of a Chess Board = `500Cost of a Cricket Bat = `700Cost of a Record Player = `2000Cost of a Camera = `2500Cost of a Cycle = `1000Cost of a Walkman = `700

Page 3: SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) · 2016-03-25 · centres at: mukherjee nagar munirka uttam nagar dilshad garden rohini badarpur jaipur gurgaon noida meerut varanasi

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

25. (1) A did not have a Cricket bat atthe end of exchange of items.

26. (4) C has, at the begining, one cycleand one walkman= 1000 + 700 = ` 1700

27. (2) A recieves cycle from C.28. (4) At the beginning D has 2 cameras

costing `5000, which is the costliest.29. (1) B recieves a record players from

A.30. (3) B gets the record player and one

bat is left from three he had.31. (3) From I:

We get Sunita's rank is (15 – 5=)10thfrom the bottom, i.e. (45 – 10 + 1=)36thfrom the top.From II and III:We get,Radha's rank from top = 30thNeeta's rank from top = 45 – 4 + 1= 42nd

Now, Sunita's rank = 30 42

2

=36th (from top)

32. (5) From I and II:We getL > T > F > PJ > PFrom I, II and III:We getL > T > F > PL > J > PHence, 'L' scored the highest.

33. (2) From II and III:We getfood is adequate vo ji fa ... (i)food is delicious fa vo re ... (ii)From (i) and (ii), we get'vo fa' is the code of 'food is', hencethe code for 'adequate' is 'ji'

34. (2) From I and II:We get

Hence, Sanjeev is the cousin of Radha.From I and III:Sanjeev is either brother or cousinof Radha.

35. (3) From I and II:Sulabha's rank from top= 5 + 10 = 15thSulabha's rank from bottom= 25thTotal number of students in theclass = 15 + 25 – 1 = 39

36. (3) From I. Position of Y = 1st from left Position of K = 1 + 5 + 1 = 7thfrom left Position of R = 7 + 6 + 1 = 14thfrom leftNow, L may be either on the leftor on the right of R.Hence position of L = 14 - 4 - 1 =9th from leftor 14 + 4 + 1 = 19th from leftHence I alone is not sufficient.From II. Position of J = 10th fromleft Position of I = 10 - 2 - 1 = 7thfrom leftor, 10 + 2 + 1 = 13th from leftBut position of K = 10 - 3 = 7thfrom left.Hence I must be 13th from left. Position of L = 13 + 5 + 1= 19th from left. No. of persons between L and K= 19 - 7 - 1 = 11.Hence II alone is sufficient.

37. (5) From I,

Hence A is second to the left of E.Thus, I alone is sufficient toanswer the question.From II. Possibility (i)

Possibility (ii)

Thus A may be second to the leftor second to the right of E. HenceII alone is not sufficient.

Page 4: SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) · 2016-03-25 · centres at: mukherjee nagar munirka uttam nagar dilshad garden rohini badarpur jaipur gurgaon noida meerut varanasi
Page 5: SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) · 2016-03-25 · centres at: mukherjee nagar munirka uttam nagar dilshad garden rohini badarpur jaipur gurgaon noida meerut varanasi

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

91. (2) The given number series is basedon the following pattern:12 × 0.5 + 0.5 = 6.56.5 × 1 + 1 = 7.57.5 × 1.5 + 1.5 = 12.7512.75 × 2 + 2 = 27.527.5 × 2.5 + 2.5 = 71.25

? = 71.25 × 3 + 3= 213.75 + 3= 216.75

Hence, 216.75 will replace thequestion mark.

92. (5) 748 – 1 × 11 = 748 – 11 = 737737 – 2 × 11 = 737 – 22 = 715715 – 3 × 11 = 715 – 33 = 682682 – 4 × 11 = 682 – 44 = 638638 – 5 × 11 = 638 – 55 = 583

93. (4) 9 × 5 + 4 = 4949 × 4 + 5 = 201201 × 5 + 4 = 10091009 × 4 + 5 = 40414041 × 5 + 4 = 2020920209 × 4 + 5 = 80841

94. (3) The series is ×6, ×5, ×4, ×3, ×2 ...Hence, number= 7800 × 6= 46800

95. (1) The series is +12

96. (4) Let the length of the rectangle bex metres.then, perimeter = (2l + b)2(x + 84) = 364or, x + 84 = 182or, x = 182 – 84 = 98 metres

x + 84 = 182Now, radius= 98 + 7 = 105 metresCircumference

= 2 r = 2 × 227

× 105

= 2 × 22 × 15= 30 × 22= 660 metresCost of fencing the garden= 600 × 8= ` 5280

97. (5) Let Abhijit invested ` 2x, ` 3x and` 4x in three schemes A, B and Crespectively.

The required ratio

= 2x ×120100 × 3x ×

116100 : 4x ×

115100

= 2 × 120 : 3 × 116 : 4 × 115= 60 : 87 : 115

98. (5) Time between 1:00 to 2:00= 60 mintuesHere, there are three quantities:Minutes, Page and Man.We have to find number of men.Let the required number of men be x.Here, relationships are given below:(i) More minutes, less men (Inverse)(ii) More pages, more men (Direct)

Hence,60 : 8

::1:1:1710

x

or, 60 × 1 : 8 × 1710 : : 1 : xor, 60 × x = 8 × 1710 × 1

x = 8 1710 1

60

= 22899. (3) Let the number of ducks and frogs

be 37x and 39x respectively.According to the question,37 39

2x x

= 152

76

2x

= 152 38x = 152

x = 15238 = 4

Number of frogs= 39x = 39 × 4 = 156

100. (3)Interest for 2 yrs

= 10 + 10 + 10 10

100

= 21%Interest for 3 yrs

= 21 + 10 + 21 10100

= 33.1%Now, (33.1 – 21)% of P = 12100or, 12.1% of P = 12100

or, P = 12100 10

12.1

= 1 lakh

Page 6: SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) · 2016-03-25 · centres at: mukherjee nagar munirka uttam nagar dilshad garden rohini badarpur jaipur gurgaon noida meerut varanasi

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

101. (1)Let their speeds x m/sec and ym/sec.Length of first train = 24x m andsecond train = 15y m24 15x y

x y

= 21

24x + 15y = 21x + 21y 3x = 6y

xy =

63 = 2

1 = 2 : 1

102. (3)In 12 mintutes the policeman

covers = 10 1000 12

60

= 2000 mSince in 12 mts the policemancovers a distance of 600 m morethan the theif, in 12 minutes thethief goes 2000 – 600 = 1400 m

103. (3)× B × B × B × B × B × B × B × B× B ×9 boys can sit 9! ways. For 7 girlsthere are 10 place, so girls can sitin 10P7 ways.Total number of ways

=10P7 × 9! = 10! 9!3!

104. (2)Voting list = xVoting = 90% xValid vote = x × 90% – 300Winner = 60% × xLosing candidate= valid – winner 90% x – 300 – 60% x 30% x – 300W – L = 90060% of x – 30% x + 300 = 90030% x = 600x = 2000

105. (1)CP × 20 = SP × 15CPSP =

520

= 34

P% = 13 × 100 = 33

13 %

means = 33.33%D × 10 = P × 5PD

= 105 = 2

1

D% = 0.54.5 × 100%

= 1119 %

= 11.11%P% – D% = 33.33% – 11.11%

= 22.22%(106-110):106. (3)Form Statement I:

Perimeter of the circle = 88 cmsor, 2r = 88 cms

r =882 =

44

cms.

The area of the circle

= r2 = × 244

sq. cm.

Hence, from statement I answercan be obtained.From Statement II:Diameter of the circle = 28 cmsor, 2r = 28 cms

r = 282 = 14 cms

The area of the circle= r2 = × (14)2 sq cm.Hence, from statement II also,question can be answered.

107. (3)From Statement I:2r

25000 × 1+ – 25000100

25000× r ×2100 =250

r can be found from the aboveequation.Hence, from statement I, rate ofinterest can be found.From Statement II:Let the sum be `x.

x = ×r ×10100

x

r = 10%Hence, from statement II, rate ofinterest can be found.

108. (4)

Page 7: SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) · 2016-03-25 · centres at: mukherjee nagar munirka uttam nagar dilshad garden rohini badarpur jaipur gurgaon noida meerut varanasi

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

109. (5)Form Statement I:Area of the right angled triangle

= 3

2 4x x

From Statement II:23

4x

+ (x)2 = (5)2

or, 29

16x + x2 = 25

or, 25x2 = 25 × 16or, x2 = 16 = (4)2

x = 4Hence, from the help of both thestatements I and II together canbe answered.

110. (5)From Statement I:Let the present age of son be xyears.

Present age of father = 5x yearsFrom Statement II:15 × (x – 5) = 5x – 5or, 15x – 75 = 5x – 5or, 10x = 70

x = 7010 = 7 yrs

Present age of father= 5x yrs = 5 × 7 = 35 yrs

(111-115):111. (4)Quicker Approach: Here your

approach should be simply dividein the % no. of candidatesenrolled in different institutes bythe % no. of successfulcandidates of the same institute.You find that institute E givingyou the maximum value.

112. (1)Reqd %

= 16% of 450020% of 6000 × 100 = 60%

113. (2)No. of enrolled candidates ininstiute D = 12% of 6000 = 720= 16% of 4500, i.e. eitherinstitute C or F satisfies ourcriteria.

114. (2)Reqd ratio = (16 +14)% of 4500(17 +18)% of 6000

= 30 4535 60

= 9 : 14115. (4)We do not know any relationship

between % no. of candidatesenrolled and the successful no. ofstudents. Therefore, cannot bedetermined is the correct choice.

(116-120) :116. (3)A quick look at the graph

indicates that the proportion ofexported wheat of totalproduction in 1996 and 1999 iszero w.r.t. the previous year. In1998 there is 5% increase.Between the remaining twooptions, in 2000 it increaseswhere as in 2001, the ratiodecreases. So, our answer is2000.

117. (1)Population in 1997

= 740 222

0.56

= 925 million

118. (2)Population of the country indifferent years:1995 = 789.471996 = 889.281997 = 9251998 = 9011999 = 9682000 = 750 and2001 = 800

119. (1)

120. (4)Reqd % = 700 520

520

× 100 35%

Page 8: SBI ASSOCIATES (Clerk) MOCK TEST - 158 (SOLUTION) · 2016-03-25 · centres at: mukherjee nagar munirka uttam nagar dilshad garden rohini badarpur jaipur gurgaon noida meerut varanasi

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Centres at: MUKHERJEE NAGAR MUNIRKA UTTAM NAGAR DILSHAD GARDEN ROHINI BADARPUR JAIPUR GURGAON NOIDA MEERUT VARANASI ROHTAK PANIPAT SONEPAT BAHADURGARH PATNA AGRA CHANDIGARH LUCKNOW ALLAHABAD

Note:-1. For any question paper related queries call/Whatsap/Message on8287900900.

2. For any issue related to RESULT Processing, kindly contact uson 8287200200.

3. If your opinion differs regarding any answer, please message themock test and question number to 8287500500.

1. (3)2. (2)3. (3)4. (1)5. (1)6. (3)7. (3)8. (2)9. (4)10. (1)11. (2)12. (2)13. (1)14. (2)15. (2)16. (3)17. (3)18. (5)19. (5)20. (2)21. (4)22. (1)23. (5)24. (3)25. (1)26. (4)27. (2)28. (4)29. (1)30. (3)31. (3)32. (5)33. (2)34. (2)35. (3)36. (3)37. (5)38. (3)39. (3)40. (2)

41. (3)42. (3)43. (2)44. (3)45. (5)46. (2)47. (3)48. (1)49. (4)50. (5)51. (5)52. (1)53. (3)54. (4)55. (2)56. (5)57. (3)58. (3)59. (1)60. (4)61. (4)62. (3)63. (3)64. (3)65. (2)66. (5)67. (2)68. (3)69. (2)70. (4)71. (4)72. (2)73. (1)74. (3)75. (1)76. (2)77. (5)78. (4)79. (5)80. (3)

SBI ASSOCIATES (Clerk) MOCK TEST - 158 [ANSWER KEY]

81. (3)82. (5)83. (1)84. (2)85. (3)86. (3)87. (2)88. (5)89. (3)90. (5)91. (2)92. (5)93. (4)94. (3)95. (1)96. (4)97. (5)98. (5)99. (3)100. (3)101. (1)102. (3)103. (3)104. (2)105. (1)106. (3)107. (3)108. (4)109. (5)110. (5)111. (4)112. (1)113. (2)114. (2)115. (4)116. (3)117. (1)118. (2)119. (1)120. (4)

121. (4)122. (3)123. (4)124. (4)125. (2)126. (2)127. (4)128. (4)129. (2)130. (2)131. (3)132. (3)133. (3)134. (4)135. (2)136. (4)137. (4)138. (5)139. (3)140. (3)141. (3)142. (1)143. (2)144. (4)145. (3)146. (2)147. (1)148. (2)149. (5)150. (3)151. (1)152. (5)153. (1)154. (4)155. (2)156. (2)157. (4)158. (4)159. (1)160. (2)

161. (3)162. (5)163. (1)164. (3)165. (2)166. (3)167. (4)168. (1)169. (2)170. (4)171. (2)172. (3)173. (3)174. (5)175. (2)176. (4)177. (4)178. (5)179. (2)180. (4)181. (2)182. (4)183. (5)184. (1)185. (4)186. (3)187. (3)188. (2)189. (3)190. (1)191. (1)192. (3)193. (3)194. (2)195. (4)196. (1)197. (3)198. (5)199. (3)200. (1)