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    Safety Inventories

    Chapter 11 of Chopra

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    Why to hold Safety Inventory?

    Desire for quick product availability

    Ease of search for another supplier

    I want it now culture

    Demand uncertainty

    Short product life cycles

    Safety inventory

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    Measures

    Measures of demand uncertainty Variance of demand

    Ranges for demand

    Delivery Lead Time, LMeasures of product availability

    Stockout, what happens? Backorder (patient customer, unique product or big cost advantage) or

    Lost sales. I. Cycle service level(CSL), % of cycles with no stockout

    II. Product fill rate (fr), % of products sold from the shelf

    Order fill rate, % of orders Equivalent to product fill rate if orders contain one product

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    Service measures: CSL and fr are different

    CSL is 0%, fill rate is almost 100%

    CSL is 0%, fill rate is almost 0%

    inventory

    inventory

    time

    time

    0

    0

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    Replenishment policies

    When to reorder?

    How much to reorder? Most often these decisions are related.

    Continuous Review: Order fixed quantity when totalinventory drops below Reorder Point (ROP).

    - ROP meets the demand during the lead time L.

    - One has to figure out the ROP.

    Information technology facilitates continuous review.

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    DemandDuring Lead time

    variance).(mean,or),,(Mostly

    i.periodindemand2

    NRNormalD

    D

    iii

    i

    jijijijjii

    jjiijiji

    dDdDDDfRDRD

    RDRDEDD

    ),())((

    )})({(),cov(

    ,

    2

    ,

    iiiiii dDDfDDER )()(

    DforfunctionsdensitycumulativeanddensityyprobabilitF, iiif

    iiiiiiiii dDDfRDRDEDVar )()(}){()(222

    nintegratiooflinearityby the)(11

    L

    i

    i

    L

    i

    i RDE

    ),cov(),cov()(1 11

    2

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    tcoefficienncorrelatio)/(2

    , jiji

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    Normal Density Function

    Mean

    95.44%

    99.74%

    x

    )1,_,,(normdist:at x(cdf)functionCumulative

    )0,_,,(normdist:at x(pdf)functionDensity

    :functionslstatisticaExcel

    devstmeanx

    devstmeanx

    normdist(x,.,.,0)

    Prob

    normdist(x,.,.,1)frequency

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    Cumulative Normal Density

    )_,,(norminv:prob""atcdfoffunctionInverse

    )1,_,,(normdist:at x(cdf)functionCumulative

    :functionslstatisticaExcel

    devstmeanprob

    devstmeanx

    0

    1

    x

    normdist(x,mean,st_dev,1)

    prob

    norminv(prob,mean,st_dev)

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    Demand During Lead Time Determines ROP

    Suppose that demands are identically and independently distributed.To mean identically and independently distributed, use iid.

    ),(then),(If

    )(and)(

    2

    1

    2

    2

    11

    LLRNDRND

    LDVarLRDE

    L

    i

    ii

    L

    i

    i

    L

    i

    i

    1,,,Normdist,;1

    LLRaLLRaFaDPL

    i

    i

    )(/)(:DofnvariatiooftCoefficien DEDVarcv

    F is the cumulative density function of the demand in a single period,

    say a day. The second equality above holds if demand is Normal.

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    Optimal Safety Inventory Levels

    Lead Times

    time

    inventory

    Shortage

    An inventory cycle

    ROP

    Q

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    I. Cycle Service Level: ROP CSL

    ),;(LevelServiceCycle LLRROPFCSL

    Cycle service level: percentage of cycles with stock out

    ROP]timeleadduring[Demandinventory]t[Sufficien

    inventorysufficienthascyclesingleay thatProbabilit0.7

    7.0

    otherwise1stockout,hascycleaif0Write10

    1010111011

    :cycles10considerexampleFor

    CSL

    CSL

    CSL

    ROP: Reorder point

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    I. Cycle Service Level for Normal Demands

    ondistributinormalstandardObtaining)1,0(

    StDevby theDividing),(

    meanout theTaking),(

    ),(

    notationvariance)(mean,Recall),,(

    )1,0(

    2

    2

    2

    R

    R

    N

    R

    R

    R

    R

    R

    L

    LRROPNP

    L

    LRROP

    L

    LRLLRNP

    LRROPLRLLRNP

    ROPLLRNP

    NLLRROPFCSL

    The last equality is a property of the Normal distribution.

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    Example: Finding CSL for given ROP

    R = 2,500 /week; = 500

    L = 4 weeks; Q = 10,000;ROP = 16,000

    ss =ROPL R =

    Cycle service level,

    Average Inventory =

    Average Flow Time =Average inventory/Thruput=

    LtimeleadduringdemandofStdev

    F ROP L R L( ; , )

    If you wish to compute Average Inventory = Q/2 + ss

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    Safety Inventory: CSL ROP

    L

    LCSLFLCSLF

    LRLLRCSLFss

    LRROPss

    LLRCSLFROPLLRROPFCSL

    R

    RR

    L,0,1)Norminv(CS

    )1,0;(),0;(

    ),,(

    :demandddistributenormallyFor

    :stockSafety

    ),,(or),,(

    11

    1

    1

    The last two equalities are by properties of the Normal distribution.

    Very important remark: Safety inventory is a more general concept.

    It exists without lead time. It is the stock held minus the expected demand.

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    Finding ROP for given CSL

    R = 2,500/week; = 500

    L = 4 weeks; Q = 10,000; CSL = 0.90

    Factors driving safety inventory

    Replenishment lead time

    Demand uncertainty

    ss F CSL L

    ROP L R ss

    1 0 1( ; , )

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    II. Fill rate:

    Expected shortage per cycle

    ESCis the expected shortage per cycle

    ESC is not a percentage, it is the number of units, also see next page

    ESC E

    ESC x ROP f x dxx ROP

    (max{

    ( ) ( )

    Demand during lead time- ROP,0})

    =

    ROPDemand

    ROPDemand

    if

    if

    0

    ROPDemandShortage

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    Inventory and Demand during Lead Time

    0

    ROP

    Demand

    During LT

    LT

    Inventory DLT: DemandDuring LT

    0

    0

    ROPInventory=

    ROP-DLTUpside

    down

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    Shortage and Demand during Lead Time

    0

    ROP

    Demand

    During LT

    LTShortage

    DLT:Deman

    dDuringLT0

    0

    ROP

    Shortage=

    DLT-ROP

    Upside

    down

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    Expected shortage per cycle

    First let us study shortage during the lead time

    DLT.ofpdfisfwhere)()(

    ))max(,0(shortageExpected

    D

    ROPD

    D dDDfROPD

    ROPDLTE

    Ex:

    4

    1

    4

    110)}-(11max{0,

    4

    210)}-(10max{0,

    4

    110)}-(9max{0,

    )()}(d)}(max{0,shortageExpected

    Shortage?Expected,

    1/4probwith11

    2/4probwith10

    1/4probwith9

    ,10

    11

    10d

    3

    1i

    33

    22

    11

    dDPROPpROPd

    pd

    pd

    pd

    DROP

    ii

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    Expected shortage per cycle

    If demand is normal:

    Does ESC decrease or increase with ss, L?

    Does ESC decrease or increase with expected value of demand?

    2170-172

    )10(102

    1061)12(10

    212

    6110

    261

    61)10(shortageExpected

    Shortage?Expected),12,6(,10

    2212

    10

    212

    10

    D

    DD

    DD

    dDD

    UniformDROP

    Ex:

    ESC ss normdistss

    LL normdist

    ss

    L

    1 0 11 010

    , , , , , ,

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    Fill Rate

    Fill rate: Proportion of customer demand satisfied from stock

    Q: Order quantity

    Q

    ESCfr 1

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    Finding the Fill Rate

    ss fr

    = 500;L = 2 weeks; ss=1000; Q = 10,000;

    Fill Rate (fr) = ?

    fr= (Q -ESC)/Q = (10,000 - 25.13)/10,000 = 0.9975.

    ESC ss normdistss

    LL normdist

    ss

    L

    ESC normdist

    nomdist

    ESC

    1 0 11 0 1 0

    1000 1 1000 707 0 11

    707 1000 707 0 1 0

    2513

    , , , , , ,

    ( ( / , , , )

    ( / , , , )

    .

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    Finding Safety Inventory for a Fill Rate:

    fr ss

    If desired fill rate isfr = 0.975, how much safety

    inventory should be held?

    Clearly ESC = (1 -fr)Q = 250

    Try some values of ss or use goal seek of Excel to solve

    0,1,0,7077071,1,0,7071250

    ssnormdist

    ssnormdistss

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    Evaluating Safety Inventory For Given Fill Rate

    Fill Rate Safety Inventory

    97.5% 67

    98.0% 18398.5% 321

    99.0% 499

    99.5% 767

    Safety inventory is very sensitive to fill rate. Is fr=100% possible?

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    Factors Affecting Fill Rate

    Safety inventory: If Safety inventory is up,

    Fill Rate is up

    Cycle Service Level is up.

    Lot size: If Lot size Q is up, Cycle Service Level does not change. Reorder point,

    demand during lead time specify Cycle Service

    Level.

    Expected shortage per cycle does not change. Safetystock and the variability of the demand during the

    lead time specify the Expected Shortage per Cycle.

    Fill rate is up.

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    To Cut Down the Safety Inventory

    Reduce the Supplier Lead Time Faster transportation

    Air shipped semiconductors from Taiwan

    Better coordination, information exchange, advance retailerdemand information to prepare the supplier

    Textiles; Obermeyer case

    Space out orders equally as much as possible

    Reduce uncertainty of the demand Contracts

    Better forecasting to reduce demand variability

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    Lead Time Variability

    2222

    11

    :)()( L

    L

    i

    i

    L

    i

    i sRLDVarLRDE

    Suppliers lead time may be uncertain:

    timeleadofVariancetime.leadAverage 2 sL

    22211)1,0;()1,0;( sRLCSLFCSLFss

    L

    0,1,0;1,1,0;1

    L

    L

    L

    ssnomdist

    ssnormdistssESC

    The formulae do not change:

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    Impact of Lead Time Variability, s

    R = 2,500/day; = 500

    L = 7 days; Q = 10,000; CSL = 0.90

    StDev of LT ss Jump in ss

    0 1695 -

    1 3625 1930

    2 6628 3003

    3 9760 31324 12927 3167

    5 16109 3182

    6 19298 3189

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    Methods of Accurate Response to Variability

    Centralization

    Physical, Laura Ashley

    Information

    Virtual aggregation, Barnes&Nobles stores

    Specialization, what to aggregate

    Product substitution

    Raw material commonality - postponement

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    Centralization: Inventory Pooling

    K

    iji

    ji

    K

    ii

    CK

    ii

    CDDRR

    11

    22

    1

    ),cov(2)(;

    ),(111

    RD

    ),( CC

    R

    Which of two systems provides a higher level of service for a givensafety stock?

    Consider locations and demands:

    ),(333 RD

    ),(222

    RD

    ),(444 RD

    With k locations centralized, mean and variance of

    K

    i

    i

    CDD

    1

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    Sum of Random Variables Are Less Variable

    K

    i

    i

    K

    i

    i

    C

    11

    2

    K

    i

    i

    K

    i

    i

    K

    i

    K

    jii

    jii

    C

    1

    2

    11 1

    2 2

    When they are independent,cov(Di,Dj)=0

    When they are perfectly positively correlated,cov(Di,Dj)=i j

    When they are perfectly negatively correlated,cov(Di,Dj)= - ij

    K

    i

    i

    K

    i

    i

    K

    i

    K

    jii

    jii

    C

    11

    2

    1 1

    22

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    Factors Affecting Value of Aggregation

    When to aggregate? Statistical checks: Positive correlation and

    Coefficient of Variation.

    Aggregation reduces variance almost always except when products are

    positively correlated

    Aggregation is not effective when there is little variance to begin with.When coefficient of variation of demand is relatively small (variance w.r.t.

    the mean is small), do not bother to aggregate.

    In real life,

    Is the electricity demand in Arlington and Plano are positively or negativelycorrelated? Is there an underlying factor which affects both in the same

    direction? Note that a big portion of electricity is consumed for

    heating/cooling.

    Are the Campbell soup sales over time positively or negatively correlated?

    How many soups can you drink per day?

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    Impact of Correlation on Aggregated Safety

    Inventory (Aggregating 4 outlets)

    Safety stocks are proportional to the StDev of the demand.

    With four locations, we have total ss proportional to 4*

    If four locations are all aggregated, ss proportional to 4* with correlation 1

    ss proportional to 2* with correlation 0

    Benefit=SS before - SS after / SS before

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    Impact of Correlation on Aggregated

    Safety Inventory (Aggregating 4 outlets)

    0

    0.1

    0.2

    0.3

    0.4

    0.5

    0.6

    0 0.2 0.4 0.6 0.8 1

    Benefit

    Benefit=(SS before - SS after) / SS before

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    EX 11.8: W.W. Grainger a supplier of

    Maintenance and Repair products

    About 1600 stores in the US

    Produces large electric motors and

    industrial cleaners

    Each motor costs $500; Demand is iidNormal(20,40x40) at each store

    Each cleaner costs $30; Demand is iid

    Normal(1000,100x100) at each store

    Which demand has a larger coefficient ofvariation?

    How much savings if motors/cleaners

    inventoried centrally?

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    Use CSL=0.95

    Supply lead time L=4 weeks for motors and cleaners

    L L,0,1)Norminv(CSss:demandddistributenormallyForFor a single store

    Motor safety inventory=Norminv(0.95,0,1) 2 (40)=132

    Cleaner safety inventory=Norminv(0.95,0,1) 2 (100)=329

    Value of motor ss=1600(132)(500)=$105,600,000Value of cleaner ss=1600(329)(30)=$15,792,000

    Standard deviation of demands after aggregating 1600 stores

    Standard deviation of Motor demand=40(40)=1,600

    Standard deviation of Cleaner demand=40(100)=4,000

    For the aggregated store

    Motor safety inventory=Norminv(0.95,0,1) 2 (1600)=5,264

    Cleaner safety inventory=Norminv(0.95,0,1) 2 (4,000)=13,159

    Value of motor ss=5264(500)=$2,632,000

    Value of cleaner ss=13,159(30)=$394,770

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    EX. 11.8: Specialization: Impact ofcv on

    Benefit From 1600-Store Aggregation , h=0.25

    Motors Cleaner

    Mean demand/wk 20 1,000

    SD of demand 40 100

    Disaggregate cv 2 0.1

    Value/Unit $500 $30

    Disaggregate ss value $105,600,000 $15,792,000

    Aggregate cv 0.05 0.0025

    Aggregate ss value $2,632,000 $394,770

    Inventory cost savings $102,968,000 $15,397,230

    Holding Cost Saving $25,742,000 $3,849,308

    Saving / Unit 2574200/(1600*20*52)=$15.47 $0.046

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    Slow vs Fast Moving Items

    Low demand = Slow moving items, vice versa.

    Repair parts are typically slow moving items

    Slow moving items have high coefficient of variation, vice versa.

    Stock slow moving items at a central store

    Buying a best seller at Amazon.com vs. a Supply Chain book vs. a Banach spacesbook, which has a shorter delivery time?

    - Why cannot I find a driver-side-door lock cylinder for my 1994 ToyotaCorolla at Pep Boys?

    - Your instructor on March 26 2005.

    - Case Interview books are not in our s.k.u. list. You must check with ourcentral stores.

    - Store keeper at Barnes and Nobles at Collin Creek, March 2002.

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    Product Substitution

    Manufacturer driven Customer driven

    Consider: The price of the products substituted for each other and

    the demand correlations

    One-way substitution Army boots. What if your boot is large? Aggregate?

    Two-way substitution:

    Grainger motors; water pumps model DN vs IT. Similar products, can customer detect specifications.

    If products are very similar, why not to eliminate one of them?

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    Component Commonality. Ex. 11.9

    Dell producing 27 products with 3 components

    (processor, memory, hard drive)

    No product commonality: A component is used in only 1

    product. 27 component versions are required for eachcomponent. A total of 3*27 = 81 distinct components

    are required.

    Component commonality allows for component

    inventory aggregation.

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    Max Component Commonality

    Only three distinct versions for each component. Processors: P1, P2, P3. Memories: M1, M2, M3. Hard drives: H1, H2, H3

    Each combination ofcomponents is a distinct product. Acomponent is used in 9products.

    Each way you can go from left to right is a product.

    P1

    P2

    P3

    M1

    M2

    M3

    H1

    H2

    H3

    Left Right

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    Example 11.9: Value of Component Commonality

    in Safety Inventory Reduction

    0

    50000

    100000

    150000

    200000

    250000

    300000

    350000

    400000

    450000

    1 2 3 4 5 6 7 8 9

    SS

    # of products a component is used in

    Aggregation provides reduction in total standard deviation.

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    Standardization

    StandardizationExtent to which there is an absence of variety in a product,

    service or process

    The degree of Standardization?

    Standardized products are immediately available to

    customers

    Who wants standardization?

    The day we sell standard products is the day we lose asignificant portion of our profit

    A TI manager on November 1, 2005

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    Advantages of Standardization

    Fewer parts to deal with in inventory & manufacturing Less costly to fill orders from inventory

    Reduced training costs and time

    More routine purchasing, handling, and inspectionprocedures

    Opportunities for long production runs, automation

    Need for fewer parts justifies increased expenditures on

    perfecting designs and improving quality controlprocedures.

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    Disadvantages of Standardization

    Decreased variety results in less consumer appeal.

    Designs may be frozen with too many imperfections remaining.

    High cost of design changes increases resistance to improvements

    Who likes optimal Keyboards?

    Standard systems are more vulnerable to failure

    Epidemics: People with non-standard immune system stop theplagues.

    Computer security: Computers with non-standard software stop the

    dissemination of viruses. Another reason to stop using Microsoft products!

    I T i C

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    InventoryTransportation Costs:

    Eastern Electric Corporation: p.427

    Major appliance manufacturer, buys motors from Westview motors in Dallas

    Annual demand = 120,000 motors

    Cost per motor = $120; Weight per motor 10 lbs.

    Current order size = 3,000 motors

    30,000 pounds = 300 cwt

    1 cwt =centum weight = 100 pounds; Centum = 100 in Latin.

    Lead time = 1 + the number of days in transit

    Safety stock carried = 50% of demand during delivery lead time

    Holding cost = 25%

    Evaluate the mode of transportation for all unit discounting based on shipment

    weight

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    AM Rail proposal:

    Over 20,000 lbs at 0.065 per lb in 5 days

    For the appliance manufacturer No fixed cost of ordering besides the transportation cost

    No reason to transport at larger lots than 2000 motors, whichmake 20,000 lbs.

    Cycle inventory=Q/2=1,000 Safety inventory=(6/2)(120,000/365)=986

    In-transit inventory

    All motors shipped 5 days ago are still in-transit

    5-days demand=(120,000/365)5=1,644

    Total inventory held over an average day=3,630 motors Annual holding cost=3,630*120*0.25=$108,900

    Annual transportation cost=120,000(10)(0.065)=$78,000

    I t T t ti t d ff E t

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    InventoryTransportation trade off: Eastern

    Electric Corporation, see p.426-8 for details

    Alternative(Lot size)

    TransportCost

    CycleInventory

    SafetyInventory

    TransitInventory

    InventoryCost

    TotalCost

    AM Rail(2,000)

    $78,000120000(0.65)

    1,000 986 1,644120000(5/365)

    $108,900 $186,900

    NortheastTrucking(1,000)

    $90,000 500 658 986 $64,320 $154,320

    Golden(500)

    $96,000120000(0.80)

    250 658 986120000(3/365)

    $56,820 $152,820

    Golden(2,500)

    $86,400 1,250 658 986 $86,820 $173,220

    Golden(3,000)

    $78,000 1,500 658 986 $94,320 $172,320

    Golden(4,000)

    $67,500 2,000 658 986 $109,320 $176,820

    If fast transportation not justified cost-wise, need to consider rapid response

    Ph i l I A i

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    Physical Inventory Aggregation:

    Inventory vs. Transportation cost: p.428

    HighMed Inc. producer of medical equipment

    sold directly to doctors

    Located in Wisconsin serves 24 regions in USA

    As a result of physical aggregation Inventory costs decrease

    Inbound transportation cost decreases

    Inbound lots are larger

    Outbound transportation cost increases

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    Inventory Aggregation at HighMed

    Highval ($200, .1 lbs/unit) demand in each of 24 territories

    H = 2, H = 5

    Lowval ($30/unit, 0.04 lbs/unit) demand in each territory

    L = 20, L = 5

    UPS rate: $0.66 + 0.26x {for replenishments}

    FedEx rate: $5.53 + 0.53x {for customer shipping}

    Customers order 1 H + 10 L

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    Inventory Aggregation at HighMed

    CurrentScenario

    Option A Option B

    # Locations 24 24 1

    Reorder Interval 4 weeks 1 week 1 week

    Inventory Cost $54,366 $29,795 $8,474

    Shipment Size 8 H + 80 L 2 H + 20 L 1 H + 10 L

    Transport Cost $530 $1,148 $14,464

    Total Cost $54,896 $30,943 $22,938

    If shipment size to customer is 0.5H + 5L, total cost of option B

    increases to $36,729.

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    Summary of Cycle and Safety Inventory

    Reduce Buffer Inventory

    Economies of Scale

    Supply / Demand

    Variability

    Seasonal

    Variability

    Cycle Inventory Safety Inventory Seasonal Inventory

    Match Supply & Demand

    Reduce fixed cost

    Aggregate acrossproducts

    Volume discounts

    Promotion on Sell

    thru

    Quick Response measures

    Reduce Info UncertaintyReduce lead time

    Reduce supply

    uncertainty

    Accurate Response measuresAggregation

    Component commonalityand postponement

    M C t i ti

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    Mass customization:

    A strategy of producing standardized goods or services,

    but incorporating some degree of customization

    Modular design

    Delayed differentiation

    Mass Customization

    M C t i ti I C t i

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    Mass Customization I: Customize

    Services Around Standardized Products

    DEVELOPMENT PRODUCTION MARKETING DELIVERY

    Deliver customized services as

    well as standardized productsand services

    Market customized services with standardized

    products or services

    Continue producing standardized products or services

    Continue developing standardized products or services

    Source: B. Joseph PineWarranty for contact lenses:

    M C t i ti II C t

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    Mass Customization II: Create

    Customizable Products and Services

    DEVELOPMENT PRODUCTION MARKETING DELIVERY

    Deliver standard (but

    customizable) productsor services

    Market customizable products or services

    Produce standard (but customizable) products or services

    Develop customizable products or services

    Customizing the look of screen with windows operating systemGillette sensor adjusting to the contours of the face

    Mass C stomi ation III: Pro ide Q ick

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    Mass Customization III: Provide Quick

    Response Throughout Value Chain

    DEVELOPMENT PRODUCTION MARKETING DELIVERY

    Reduce Delivery Cycle Times

    Reduce selection and order processing cycle

    times

    Reduce Production cycle time

    Reduce development cycle time

    Skiing parkas manufactured abroad vs. in the U.S.A.:

    Mass Customization IV: Provide Point of

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    Mass Customization IV: Provide Point of

    Delivery Customization

    DEVELOPMENT PRODUCTION MARKETING DELIVERY

    Deliver standardize portion

    Market customized products or services

    Produce standardized portion centrally

    Develop products where point of delivery customization is feasible

    Point of delivery

    customization

    Paint mixingLenscrafters for glasses.

    Mass Customization V: Modularize

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    Mass Customization V: Modularize

    Components to Customize End Products

    DEVELOPMENT PRODUCTION MARKETING DELIVERY

    Deliver customized product

    Market customized products or services

    Produce modularized components

    Develop modularized products

    Computer industry, Dell computers:

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    Modular Design

    Modular designis a form of standardization in which component parts aresubdivided into modules that are easily replaced or interchanged.

    Goodexample: Dell uses same components to assemble variouscomputers.

    Bad example: Earlier Ford SUVs shared the lower body with Ford cars. Ugly example:

    It allows:

    easier diagnosis and remedy of failures

    easier repair and replacement

    simplification of manufacturing and assembly

    Types of Modularity for Mass

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    Types of Modularity for Mass

    Customization

    Component Sharing Modularity, Dell

    Cut-to-Fit Modularity,Gutters that do not require

    seams

    Bus Modularity, E-books

    Mix Modularity, Paints

    Sectional Modularity, LEGO

    + =

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    Periodic Review

    Order at fixed time intervals (T apart) to raise total inventory(on hand + on order) to Order up to Level (OUL)

    Inventory

    OUL

    LT

    T

    LT

    T+LT

    OUL must cover

    the Demand during

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    Periodic Review Policy: Safety Inventory

    T: Reorder interval

    R: Standard deviation of demand per unit time

    L+T: Standard deviation of demand during L+T periods

    OUL: Order up to level

    ssOUL

    CSLFss

    TL

    RLT

    R

    R

    LT

    LT

    LT

    LT

    )1,0;(

    )(

    1

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    Example: Periodic Review Policy

    R = 2,500/week; R = 500

    L = 2 weeks; T= 4 weeks; CSL = 0.90

    What is the required safety inventory?

    Factors driving safety inventory Demand uncertainty

    Replenishment lead time

    Reorder interval

    1570)1,0;(1

    LTCSLFss

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    Periodic vs Continuous Review

    Periodic review ss covers the uncertainty over

    [0,T+L], T periods more than ss in continuous case.

    Periodic review ss is larger.

    Continuous review is harder to implement, use it forhigh-sales-value per time products