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17
Section 1.4 - Quadratic Equations
Basic Complex Number
2 1i 1i 1 i
The number i is called the imaginary unit.
Example
8 2 2i 2 2i
7 7 7 7i i
22 7i
7
Complex number is written in a form: z a bi
a is the real part
b is the imaginary part
Conjugate of a complex number is a bi a bi
A quadratic equation in x is an equation that can be written in the general form:
2 0x xba c where a, b, and c are real numbers,
2 24 03x x 4 23 ba c
Solving Quadratic Equations by Factoring
The Zero-Product Principle
If AB = 0 then A = 0 or B = 0.
Example
Solve 26 7 3 0x x
Solution
(3 1)(2 3) 0x x
3 1 0x 2 3 0x
3 1x 2 3x
13
x 32
x
18
The Square Root Property
If u is an algebraic expression and d is a nonzero real number, then u2 = d has exactly two solutions:
2 , If u d then u d or u d Equivalently,
2 If u d u d .
Example
a) 3x2 – 21 = 0
23 21x
2 7x 7 x
b) 5x2 + 45 = 0
25 45 x
2 9 x
9 x x = 3i
c) (x + 5)2 = 11
x + 5 = 11 115 x
Completing the Square
If 2x bx is a binomial, then by adding 2
2b
which is the square of half the coefficient of x. a perfect
square trinomial will result. That is.
2 2
22 2
bx b bx x
2 2
22
12
bx bx xb
Example
Solve: 2 4 1 0x x
2 4 1x x
2 2
4 42 2
2 4 1x x
22 4 2 1 4x x
22 5x
x + 2 = 5
2 5x
19
Quadratic Formula
(Using Completing the Square)
2 0ax bx c
2ax bx c
2 b cx x
a a
2
22
1 12 2
b cxa
b ba
xaa
2 2
22 4
b c bxa a a
2
24
b caa
2
24
4
b ac
a
2
2
42
4
b acbxa
a
2 42 2
b acbxa a
2 42
b b acx
a
*** 2
2 0 42
cxbxa x ba
cb a
2 4 c 0 2
2 4 0 2
2 4 0 O ( )
b a Real numbers
b ac Complex numbers
b ac ne solution repeated
20
Example
Solve: 22 2 1 0x x
Solution
22 1a b c
2 4
2x
cb b a
a
22 4( )( )
2(
2
2)
2 1
= 4
842
2 12
4
122
4 4
2 2 3
4
2 31
2 4
2 1 3
4
312 2
1 3
2
3 31 1,
2 22 2
312 2
Example
Solve 2 4 2x x
Solution
2 4 2 0x x
41 2a b c
2 4
2x
cb b a
a
( 4) ( 4)2 4(1)
(1
2)
)2
(
4 16 8
2
4 8
2
4 2 2
2
21
2
2
2 2
2 2
The solution set is 2 2
Example
Solve: 2 2 2 0x x
Solution
21 2a b c
2( ) ( ) 4( )( )
2
2
(
2
1
21
)
x
2 4 8
2
2 4
2
42
2 2
2 2
2
i
2
12
i
2
2
(1 )i
1 i
1 i
Pythagorean Theorem
The sum of the squares of the lengths of the legs of a right triangle equals
the square of the length of the hypotenuse. If the legs have lengths a and
b, and the hypotenuse has length c, then:
2 2 2a b c
Example
A ladder that is 17 feet long is 8 feet from the base of a wall. How far up the wall does the ladder reach?
Solution
2 2 28 17y
2 2 217 8y
2 217 158y ft
17 ft
8 ft
y
22
Height of a Projected Object (Position Function)
An object that is falling or vertically projected into the air has its height above the ground, s(t), in feet,
given by
0 0
2( ) 16s t t v t s
0v is the original velocity (initial velocity) of the object, in feet per second
t is the time that the object is in motion, in second
0s is the original height (initial height) of the object, in feet
Example
If a projectile is shot vertically upward from the ground with an initial velocity of 100 ft per sec,
neglecting air resistance, its height s (in feet) above the ground t seconds after projection is given by
216 100s t t
a) After how many seconds will it be 50 ft above the ground?
b) How long will it take for the projectile to return to the ground?
Solution
a) After how many seconds will it be 50 ft above the ground?
2 10 16 005 t t
216 100 50 0t t
28 50 25 0t t
2( 50) ( 50) 4(8)(25)
2(8)t
50 1700
16
50 1700
160.55t
50 1700
165.70t
b) How long will it take for the projectile to return to the ground?
20 16 100t t
0 4 (4 25)t t
4 0t
4 25 0t
0t
4 25t
254
6.25t
23
Exercises Section 1.4 - Quadratic Equations
1. Solve: 2 25x
2. Solve: 25 45 0x
3. Solve: 24 12x
4. Solve: 24 1 20x
5. Solve 2 6 7x x
6. Solve 26 3 2x x
7. Solve: 23 2 7x x
8. Solve: 23 6 10x x
9. Solve: xx 25 2
10. Solve: 25 2 3x x
11. Solve: 2 8 15 0x x
12. Solve: 2 5 2 0x x
13. Solve: 2 6 10 0x x
14. Solve: 22 3 4 0x x
15. Solve: 2 8 0x x
16. Solve: 22 13 1x x
17. Solve: 2 3 3 0r r
18. Solve: 3 8 0x
19. Solve for the specified variable 2
4, dA for d
20. Solve for the specified variable 2 0 ( 0), rt st k r for t
21. A rectangular park is 6 miles long and 2 miles wide. How long is a pedestrian route that runs
diagonally across the park?
22. What is the width of a 25-inch television set whose height is 15 inches?
24
23. A vacant rectangular lot is being turned into a community vegetable garden measuring 15 meters by
12 meters. A path of uniform width is to surround the garden. If the area of the garden and path
combined is 378 square meters, find the width of the path.
24. A pool measuring 10 m by 20 m is surrounded by a path of uniform width. If the area of the pool
and the path combined is 600 m2, what is the width of the path?
25. A boat is being pulled into a dock with a rope attached to the boat at water level. Where the boat is
12 ft from the dock, the length of the rope from the boat to the dock is 3 ft longer than twice the
height of the dock above the water. Find the height of the dock.
26. Logan and Cassidy leave a campsite, Logan biking due north and Cassidy biking due east. Logan
bikes 7 km/h slower than Cassidy. After 4 hr, they are 68 km apart. Find the speed of each bicyclist.
27. Towers are 1482 ft. tall. How long would it take an object dropped from the top to reach the ground?
Given s = 16t2
25
28. The formula P = 0.01A2+ 0.05A + 107 models a woman's normal Point systolic blood pressure, P,
an age A. Use this formula to find the age, to the nearest year, of a woman whose normal systolic
blood pressure is 115 mm Hg.
29. A rectangular piece of metal is 10 in. longer than it is wide. Squares with sides 2 in. long are cut
from the four corners, and the flaps folded upward to form an open box. If the volume of the box is
832 3in , what were the original dimensions of the piece of metal?
30. An astronaut on the moon throws a baseball upward. The astronaut is 6 ft., 6 in., tall, and the initial
velocity of the ball is 30 ft. per sec. The height s of the ball in feet is given by the equation
22.7 30 6.5t ts
Where t is the number of seconds after the ball was thrown.
a) After how many seconds is the ball 12 ft above the moon’s surface?
b) How many seconds will it take for the ball to return to the surface?
31. The bar graph shows of SUVs (sport utility vehicles0 in the US, in millions. The quadratic equation
2.00579 .2579 .9703S x x models sales of SUVs from 1992 to 2003, where S represents sales in
millions, and x = 0 represents 1992, x = 1 represents 1993 and so on.
a) Use the model to determine sales in 2002 and 2003. Compare the results to the actual figures of 4.2
million and 4.4 million from the graph.
b) According to the model, in what year do sales reach 3.5 million? Is the result accurate?
32. Cynthia wants to buy a rug for a room that is 20 ft wide and 27 ft long. She wants to leave a uniform
strip of floor around the rug. She can afford to buy 170 square feet of carpeting. What dimension
should the rug have?
26
33. Erik finds a piece of property in the shape of a right triangle. He finds that the longer leg is 20 m
longer than twice the length of the shorter leg. The hypotenuse is 10 m longer than the length of the
longer leg. Find the lengths of the sides of the triangular lot.
34. An open box is made from a 10-cm by 20-cm piece of tin by cutting a square from each corner and
folding up the edges. The area of the resulting base is 96 2cm . What is the length of the sides of the
squares?
23
Solution Section 1.4 - Quadratic Equations
Exercise
Solve: 2 25x
Solution
25x
5i
Exercise
Solve: 24 12x
Solution
4 12x
4 12x 12 4(3) 2 3
4 2 3x
Exercise
Solve: 25 45 0x
Solution
5x2 = 45
545x
x2 = 9
x = 3
Exercise
Solve: 24 1 20x
Solution
4 1 20x
4 1 2 5x
1 2 54
x
24
Exercise
Solve 2 6 7x x
Solution
)1(2
)7)(1(4)6()6( 2 x
2
86
2
226
2
232
23
Exercise
Solve 26 3 2x x
Solution
0236 2 xx
0236 2 xx
)6(2
)2)(6(433 2 x
12
393
39312 12
i
3914 12
i
Exercise
Solve: 23 2 7x x
Solution
2 a3 2 7 0 = , , = 3 b 2x x c = - 7
2 4
2
b b ax
a
c
2 4(3(2 )() (2
(3)
))
2
25
2 886
2 4(22)
6
2 2 226
2 1 22
6
1 223
2213 3
x
Exercise
xx 1063 2
Solution
23 10 6 0x x
2 4
2
b b ax
a
c
2( 10) ( 10)
32
3)
( )
4(
(6)
10 100 72
6
10 28
6 6
5 2 7
3 6
5 7
3 3
26
Exercise
xx 25 2
Solution
025 2 xx
)5(2
)2)(5(42)1()1( x
10
4011
10
391
10
391 i
39110 10
i
Exercise
Solve: 25 2 3x x
Solution
25 2 3 0x x
2( 2) ( 2) 4( )(3)
2( )
5
5x
2 4 60
10
2 56
10
2 4(14)
10
i
2 2 14
10
i
2 14210 10
i
1415 5
i
27
Exercise
Solve: 2 8 15 0x x
Solution
12 4(8 )(15)
2
8
1( )x
8 64 60
2
8 4
2
8 2
2
8 2 6 322
8 2 10 522
Exercise
Solve: 2 5 2 0x x
Solution
2 4( )5 (5 2)
2
1
(1)x
5 25 8
2
5 17
2
5 17
2 2
28
Exercise
Solve: 2 6 10 0x x
Solution
2 6 10x x
2
22
6 6102 2
6x x
22 2(3) 3 10 9x x
2( 3) 19x
3 19x
3 19x
Exercise
Solve: 22 3 4 0x x
Solution
22 3 4x x
2 32
2x x
2 2
3 31 12 2
2 322 2
2x x
22 3 3 9
2 4 162x x
2
3 414 16
x
3 414 16
x
4134 4
x
29
Exercise
Solve 2 8 0x x
Solution
2 4
2
b b acx
a
21 1 4 1 8
2 1
1 1 32
2
1 31
2
1 31
2
i
Exercise
Solve 22 13 1x x
Solution
22 13 1 0x x
2 4
2
b b acx
a
213 13 4 2 1
2 2
13 169 8
4
13 177
4
Exercise
Solve 2 3 3 0r r
Solution
23 3 4 1 3
2 1r
30
3 9 12
2
3 21
2
Exercise
Solve: 3 8 0x
Solution
2( 2) 2 4 0x x x 3 3 2 2( )a b a b a ab b
2 0x 2 2 4 0x x
2x 2
( 2) ( 2) 4(1)(4)
2(1)x
2 12
2
2 2 3
2
i
2
2
1 3i
1 3i
The solution set is 2, 1 3i
Exercise
Solve for the specified variable 2
4, dA for d
Solution
24 4
4dA
2
44 4 dA
24A d
24A d
2 4Ad
24A d
4Ad
2A
31
2A
2 A
Exercise
Solve for the specified variable 2 0 ( 0), rt st k r for t
Solution
2 4
2
cb ab
at
2( ) ( ) 4( )( )
2( )
s s r k
rt
24
2
s s rk
rt
Exercise
A vacant rectangular lot is being turned into a community vegetable garden measuring 15 meters by 12
meters. A path of uniform width is to surround the garden. If the area of the garden and path combined is
378 square meters, find the width of the path.
Solution
(15 2 )(12 2 )Area x x
378 (15 2 )(12 2 )x x
2378 180 30 24 4x x x
20 180 54 4 378x x
20 4 54 198x x
24 54 198 0x x
2(54) (54) 4(4)( 198)
2(4)x
54 6084
8
54 78
16.
54 78 8
54 7888
5
3 x
x
32
Exercise
A rectangular park is 6 miles long and 2 miles wide. How long is a pedestrian route that runs diagonally
across the park?
Solution
2 2 26 2d
2 40d
40 6.32 d miles
Exercise
A pool measuring 10 m by 20 m is surrounded by a path of uniform width. If the area of the pool and the
path combined is 600 m2, what is the width of the path?
Solution
A lw
600 (20 2 )(10 2 )x x
2600 200 40 20 4x x x
20 600 200 60 4x x
20 400 60 4x x
20 100 15x x
215 100 0x x
215 15 4(1)( 100)
2(1)x
15 6252
15 252
15 25 5
20
2
The width of the path is 5 m.
33
Exercise
A boat is being pulled into a dock with a rope attached to the boat at water level. Where the boat is 12 ft
from the dock, the length of the rope from the boat to the dock is 3 ft longer than twice the height of the
dock above the water. Find the height of the dock.
Solution
2 2 2(2 3) 12h h
2 24 12 9 144h h h
2 24 12 9 144 0h h h
23 12 135 0h h
2 4 45 0h h
( 9)( 5) 0h h
, 59 h
Height = 5 ft.
Exercise
What is the width of a 25-inch television set whose height is 15 inches?
Solution
2 2 215 25w
2 2 225 15w
2 225 15w
20 w in
34
Exercise
Logan and Cassidy leave a campsite, Logan biking due north and Cassidy biking due east. Logan bikes 7
km/h slower than Cassidy. After 4 hr, they are 68 km apart. Find the speed of each bicyclist.
Solution
22 24 4( 7) 68r r
2 216 16( 14 49) 4624r r r
2 216 16 224 784 4624r r r
232 224 784 4624 0r r
232 224 3840 0r r
2 7 120 0r r
8, 15r
' 15 /Cassidy s km h
' 8 /Logan s km h
Exercise
Towers are 1482 ft tall. How long would it take an object dropped from the top to reach the ground?
Given s = 16t2
Solution
1482 = 16t2
21482
16t
148216
t
t 9.624 sec
35
Exercise
The formula P = 0.01A2+ 0.05A + 107 models a woman's normal Point systolic blood pressure, P, an age
A. Use this formula to find the age, to the nearest year, of a woman whose normal systolic blood pressure
is 115 mm Hg.
Solution
0.01A2
+ 0.05A + 107 = 115
0.01A2
+ 0.05A – 8 = 0
A = 2.05 .05 4(.01)( 8)
2(.01)
.05 .0025 .32
.02
.05 .567
.02
2689.2502.
567.05.
) a (31 02.
567.05.SolutionNot
Exercise
A rectangular piece of metal is 10 in. longer than it is wide. Squares with sides 2 in. long are cut from the
four corners, and the flaps folded upward to form an open box. If the volume of the box is 832 3in , what
were the original dimensions of the piece of metal?
Solution
10 wl
Bottom width: 4w
Bottom length: 64104 wwl
2)4)(6( wwlwhV
)2464(2 2 www
4842 2 ww
22 4 48 832w w
22 4 880 0w w
2 2 440 0w w
( 22)( 20) 0w w
22 0w 20 0w
22w 20w
Width of the metal is 20 in by the length (20+10) 30 in.
36
Exercise
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft., 6 in., tall, and the initial
velocity of the ball is 30 ft. per sec. The height s of the ball in feet is given by the equation
22.7 30 6.5t ts
Where t is the number of seconds after the ball was thrown.
a) After how many seconds is the ball 12 ft above the moon’s surface?
b) How many seconds will it take for the ball to return to the surface?
Solution
a) After how many seconds is the ball 12 ft above the moon’s surface?
21 2.7 30 6.2 5t t
20 2.7 30 6.5 12t t
20 2.7 30 5.5t t
230 (30) 4( 2.7)( 5.5) 30 29
2( 2.7) 5.4t
30 295.4
t
30 295.4
t
10.9sect
.12sect
b) How many seconds will it take for the ball to return to the surface?
22.7 30 6.0 5t t
230 (30) 4( 2.7)(6.5) 30 31.15
2( 2.7) 5.4t
30 31.155.4
t
30 31.155.4
t
11.32t
0.212t
It will take 11.32 sec.
37
Exercise
The bar graph shows of SUVs (sport utility vehicles0 in the US, in millions. The quadratic equation
2.00579 .2579 .9703S x x models sales of SUVs from 1992 to 2003, where S represents sales in millions,
and x = 0 represents 1992, x = 1 represents 1993 and so on.
a) Use the model to determine sales in 2002 and 2003. Compare the results to the actual figures of 4.2 million
and 4.4 million from the graph.
b) According to the model, in what year do sales reach 3.5 million? Is the result accurate?
Solution
a) For 2002 10x
2.00579 .2579(10) (1 9700) . 3S
4.1 million
For 2003 11x
2.00579 .2579(11) (1 9701) . 3S
4.5 million
b) 23. .00579 .257 95 9 . 703x x
20 .00579 .2579 .9703 3.5x x
20 .00579 .2579 2.5297x x
2.2579 (.2579) 4(.00579)( 2.5297)
2(.00579)x
.2579 .1251.01158
.2579 .3537.01158
x .2579 .3537.01158
x
52.8x 8.3x
According to the model, the number reached 3.5 million in the year 2000. The model closely
matches the graph, so it is accurate
38
Exercise
Cynthia wants to buy a rug for a room that is 20 ft. wide and 27 ft. long. She wants to leave a uniform
strip of floor around the rug. She can afford to buy 170 square feet of carpeting. What dimension should
the rug have?
Solution
x
x
x
x
27 ft
20 ft20 –
2 x
27 – 2 x
The area of the rug is:
27 2 20 2 170x x
2540 54 40 4 170x x x 2540 94 4 170 0x x
24 94 370 0x x Solve for x.
18.5x 5or x
20 2 20 2 5 10 17 2 2 2 5 72 7x and x
Therefore, the dimensions are: 10, 20 ft.
Exercise
Erik finds a piece of property in the shape of a right triangle. He finds that the longer leg is 20 m longer
than twice the length of the shorter leg. The hypotenuse is 10 m longer than the length of the longer leg.
Find the lengths of the sides of the triangular lot.
Solution
: l longer leg
: s shorter leg
Longer leg is 20 m longer than twice the length of the shorter leg
2 20l s
The hypotenuse is 10 m longer than the length of the longer leg
10h l
2 20 10s
2 30s
39
2 2 2l s h
2 2 2(2 20) (2 30)s s s
2 2 24 80 400 4 120 900s s s s s
2 2 24 80 400 4 120 900 0s s s s s
2 40 500 0s s
( 10)( 50) 0s s
10 0s 50 0s
10s 50s
The shorter length is 50 m.
The longer length is 2 20 2(50) 20 120l s
10 120 10 130 h l m
Exercise
An open box is made from a 10-cm by 20-cm piece of tin by cutting a square from each corner and
folding up the edges. The area of the resulting base is 96 2cm . What is the length of the sides of the
squares?
Solution
Area of the base = (10 – 2x)(20 – 2x)
244020200 xxx
200604 2 xx
96200604 2 xx
0104604 2 xx
026152 xx
0)2)(13( xx
202
13013
xx
xx )( 2 onlyx