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Section 9 2 Solving Quadratic Equations by Graphing

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Main Ideas Solve quadratic equations by graphing. Estimate solutions of quadratic equations by graphing.

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Vocabulary Quadratic Equation: an equation of the form ax 2 + bx + c = 0,where a 0.

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Vocabulary The solutions of a quadratic equation are called the____________________. The roots of a quadratic equation can be found by graphing the related quadratic function f(x) = ax 2 + bx + c and finding the _____________________________.

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d.) Graph y = x 2 + 4x + 3 XY -43 -30 -2 0 03 Vertex

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f.) Solve x 2 + 4x + 3 = 0 by graphing To solve you need to know where the value of f(x) = 0. This occurs at the x-intercepts, (-3,0) and (-1,0). The solutions are x = {-3, -1}

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d.) Graph x 2 + 7x + 12 = 0 XY -52 -40 -3.5-0.25 -30 -22 Vertex

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f.) Solve x 2 + 7x + 12 = 0 by graphing To solve you need to know where the value of f(x) = 0. This occurs at the x-intercepts, (-3,0) and (-4,0). The solutions are x = {-4, -3}

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d.) Graph x 2 4x + 5 = 0 XY 05 12 21 3 2 4 5 Vertex

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f.) Solve x 2 4x + 5 = 0 by graphing To solve you need to know where the value of f(x) = 0. There is no x- intercepts, so there is no real roots Solution: {}

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d.) Graph x 2 6x + 9 = 0 XY 14 21 30 41 54 Vertex

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f.) Solve x 2 6x + 9 = 0 by graphing To solve you need to know where the value of f(x) = 0. This occurs at the x-intercepts (3,0). Solution: {3}

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Section 9 2 Day 2 Solving Quadratic Equations by Graphing

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Main Ideas Solve quadratic equations by graphing. Estimate solutions of quadratic equations by graphing.

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Estimate Solutions The roots of a quadratic equation may not be integers. If exact roots cannot be found, they can be estimated by finding the consecutive integers between which the roots lie.

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Example 2: Solve the equation by graphing x 2 + 6x + 6 = 0 a.) Write the equation of the axis of symmetry b.) Find the coordinates of the vertex of the graph of each function. c.) Identify the vertex as a maximum or a minimum. d.) Then graph the function. e.) State the Domain and Range f.) Determine what the x-intercept or zeros are to solve the quadratic equation.

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Solve x 2 + 6x + 6 = 0 by graphing a.) equation of axis of symmetry a = _____ b = ____ c = ____ b.) Find the vertex. y = x 2 + 6x + 6 when x = -3 y = (-3) 2 + 6(-3) + 6 y = 9 + -18 + 6 y = -3 Vertex (-3, -3) 616

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Solve x 2 + 6x + 6 = 0 by graphing c.) Identify the vertex as a maximum or a minimum. Since the coefficient of the x 2 -term is positive, the parabola opens upward, and the vertex is a minimum point.

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d.) Graph x 2 + 6x + 6 = 0 XY -51 -4-2 -3 -2 1 Vertex

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e.) Graph x 2 + 6x + 6 = 0 Domain: D: {x I x is all real numbers.} Range: R: {y I y -3}

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f.) Solve x 2 + 6x + 6 = 0 by graphing The x-intercepts of the graph are between -5 and -4 and between -2 and -1. So one root is between 5 and 4, and the other root is between 2 and 1. -5 < x < -4 -2 < x < -1

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Try 4: Solve the equation by graphing x 2 2x 4 = 0 a.) Write the equation of the axis of symmetry b.) Find the coordinates of the vertex of the graph of each function. c.) Identify the vertex as a maximum or a minimum. d.) Then graph the function. e.) Determine what the x-intercept or zeros are to solve the quadratic equation.

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Solve x 2 2x 4 = 0 by graphing a.) equation of axis of symmetry a = ____ b = ____ c = ____ b.) Find the vertex. y = x 2 2x 4 when x = 1 y = (1) 2 + -2(1) + -4 y = 1 + -2 + -4 y = -5 Vertex (1, -5) -21-4

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Solve x 2 2x 4 = 0 by graphing c.) Identify the vertex as a maximum or a minimum. Since the coefficient of the x 2 -term is positive, the parabola opens upward, and the vertex is a minimum point.

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d.) Graph x 2 2x 4 = 0 XY 0-4 1-5 2-4 3 Vertex

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e.) Domain and Range Domain: D: {x I x is all real numbers.} Range: R: {y I y -5}

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Solve x 2 + 6x + 6 = 0 by graphing The x-intercepts of the graph are between -2 and -1 and between 3 and 4. So one root is between - 2 and -1, and the other root is between 3 and 4. -2 < x < -1 3 < x < 4

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Use factoring to determine how many times the graph of each function intersects the x-axis. Identify the root. f(x) = x 2 + x 12 0 = x 2 + x 12 0 = (x 3)(x + 4) x 3 = 0 x + -3 + 3 = 0 + 3 x = 3 x + 4 = 0 x + 4 + -4 = 0 + -4 x = - 4 2 roots x = { -4, 3}